Answers
Answer:
I think we need a graph to figure out this problem; the points need to be graphed. Otherwise, I do understand!
Related Questions
what is the greatest common factor (GCF) of 24 and 40?
A. 2
B. 4
C. 6
D. 8
Answers
Answer:
GCF = 8
Step-by-step explanation:
Question 7 of 10
A piece rate worker is paid
A. a fixed rate per hour worked
B. a fixed rate for each item produced or action performed
OC. a fixed rate per year
SUBMIT
Answers
The correct option is B. a fixed rate for each item produced or action performed.
A piece rate employee is paid a set amount for each item produced or action performed.
What is defined as the piece rate?Employees paid on the a piece rate or piecework reason are typically paid per task completed or the number of units produced. Here are a few examples of piece-rate contracts:
Nurses are paid by the number of procedures they perform; carpet layers are paid by the yard of carpet they lay;technicians are paid by the amount of cable units they install; factory workers are paid by the widget they complete; and carpenters are paid by linear foot on framing jobs.Pay rate during nonproductive work hours
Employers and employees may agree under the FLSA to compensate nonproductive work hours at a lower rate than the rate relevant to productive work, as long that it is at least the minimum wage. Take into account that each state may have its own set of rules.Some companies may be forbidden by state law from paying employees on a piece-rate basis. In California, for example, employers are generally prohibited from paying labourers on a piece-rate basis.
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Solve the formula 5x + y = 18 for y.
Answers
Answer:
y=18-5x
Step-by-step explanation:
Write the equation of the line in slope-intercept form.
PLEASDE HELP ME OUT ASAP
Answers
Answer:
y = 50x + 40
50 = slope
40 = intercept
begin{tabular}{|r|l|r|r|} \hline 3 & Below are your numerical inputs for the problem: \\ \hline 4 & Initial Cost (\$) & 390000 \\ \hline 5 & Year 1 Revenues (\$) & 192000 \\ \hline 6 & Year 1 Costs (\$) & 125000 \\ \hline 7 & Inflation & 2.75% \\ \hline 8 & Project Duration (years) & 6 \\ \hline 9 & Depreciation Method & \\ \hline 10 & Tax Rate & \\ \hline 11 & Net Working Capital (\% oft+1 Revenues) & MACRS \\ \hline 12 & Salvage Value (\$) & 28.00% \\ \hline 13 & Cost of Capital & 15.00% & 245000 \\ \hline \end{tabular} How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.
Answers
Information is needed to evaluate the project's financial viability, considering factors such as the initial investment, expected cash flows, cost of capital, and project duration.
To calculate the year 1 operating cash flows (OCF), we need to subtract the year 1 costs from the year 1 revenues:
OCF = Year 1 Revenues - Year 1 Costs
OCF = $192,000 - $125,000
OCF = $67,000
To find the depreciation expense in year 3, we need to determine the depreciation method. The provided information is incomplete regarding the depreciation method, so we cannot calculate the depreciation expense in year 3 without knowing the specific method.
The change in Net Working Capital (NWC) in year 2 can be determined by multiplying the Net Working Capital percentage (given as a percentage of t+1 revenues) by the year 1 revenues and subtracting the result from the year 2 revenues:
Change in NWC = (Year 2 Revenues - Net Working Capital percentage * Year 1 Revenues) - Year 1 Revenues
Without the specific Net Working Capital percentage or Year 2 Revenues values, we cannot calculate the exact change in NWC in year 2.
The net cash flow from salvage (ATSV) is calculated by multiplying the Salvage Value percentage by the Initial Cost:
ATSV = Salvage Value percentage * Initial Cost
ATSV = 28% * $390,000
ATSV = $109,200
To calculate the project's NPV, we need the cash flows for each year, the cost of capital, and the project duration. Unfortunately, the information provided does not include the cash flows for each year, so we cannot calculate the project's NPV.
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The complete question is:
Below are your numerical inputs for the problem: 4 & Initial Cost (\$) & 390000 5 & Year 1 Revenues (\$) & 192000 6 & Year 1 Costs (\$) & 125000 7 & Inflation & 2.75% 8 & Project Duration (years) & 6 9 & Depreciation Method & 10 & Tax Rate & 11 & Net Working Capital (\% oft+1 Revenues) & MACRS 12 & Salvage Value (\$) & 28.00% 13 & Cost of Capital & 15.00% & 245000 How much are the year 1 operating cash flows (OCF)? How much is the depreciation expense in year 3 ? What is the change in Net Working Capital (NWC) in year 2? What is the net cash flow from salvage (aka, the after-tax salvage value, or ATSV)? What is the project's NPV? Would you recommend purchasing the ranch? Briefly explain.
Simplify a/2b times bc/a
Answers
Answer:
\(\dfrac{c}{2}\)
Step-by-step explanation:
We can simplify the given expression by canceling like terms.
Remember that anything divided by itself is 1.
ex:
\(\dfrac{2x}{x} = 2 \cdot \dfrac{x}{x} = 2 \cdot 1 = 2\)
Applying this logic to the given expression:
\(\dfrac{a}{2b} \cdot \dfrac{bc}{a}\)
↓ simplify multiplication of fractions
\(\dfrac{a \cdot bc}{2b \cdot a}\)
↓ rewrite to align like variables
\(\dfrac{a \cdot b \cdot c}{a \cdot b \cdot 2}\)
↓ separate out variables that are divided by each other
\(\dfrac{a}{a} \cdot \dfrac{b}{b} \cdot \dfrac{c}{2}\)
↓ represent them as 1
\(1 \cdot 1 \cdot \dfrac{c}{2}\)
↓ rewrite without unnecessary 1's
\(\dfrac{c}{2}\)
Quick 15, anyone? Pease help out, thanks
Select all expressions that are equivalent to 16x−12−24x+4. Show or explain your reasoning.
1. 4+16x−12(1+2x)
2. 40x−16
3. 16x−24x−4+12
4. -8x−8
Answers
the answer choices are 39, 51, 70.5, 78 please help! i’ll give brainliest
Answers
Answer: 51 degrees
Step-by-step explanation:
The function f(x) is defined by the set of
ordered pairs {(5,-2), (-6, -2), (3,-2),
(4, -2)}.
What are the domain and range of f(x)?
A Domain: {-2}
Range: all real numbers
B)Domain: {-6, 3, 4, 5}
Range: {-2}
C )Domain: x2-6
Range: y = -2
D )Domain: {-2}
Range: {-6, 3, 4, 5}
Answers
The domain and range of f(x) are the domain is {-5, -6, 3, 4} and the range is {-2}
What are the domain and range of f(x)?From the question, we have the following parameters that can be used in our computation:
Set of ordered pairs {(5,-2), (-6, -2), (3,-2), (4, -2)}.
The domain is the set of x values
So, we have
Domain = {-5, -6, 3, 4}
The range is the set of y values
So, we have
Range = {-2}
Hence, the domain is {-5, -6, 3, 4} and the range is {-2}
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Of a squirrel's hidden nuts, for every 555 that get found, there are 333 that do not get found. A squirrel hid 404040 nuts all together.
How many of the nuts do not get found?
Answers
Answer: 151,515
Step-by-step explanation:
555+333= 888
333÷888 = .375
.375 × 404040 = 151,515
Answer:
its 15
Step-by-step explanation:
Apply De Morgan's law repeatedly to each Boolean expression until the complement operations in the expression only operate on a single variable. For example, there should be no xy¯ or x+y¯ in the expression. Then apply the double complement law to any variable where the complement operation is applied twice. That is, replace x¯¯ with x.
a. 1/ x + yz + u b. 1/x(y + 2)u c. 1/(x + y)(uv + x y) d. 1/xy + yz + xz
Answers
The simplified expression using De Morgan's law are a)x'y'z'u b)x'y'u c): x'y'u and d)x'y'z'+xy'z'+xyz.
The main idea is to simplify each Boolean expression by repeatedly applying De Morgan's law until each complement operation operates on a single variable.
Then, apply the double complement law to simplify the expression further. In the end, the simplified expression should contain only AND and OR operations without any complement operators acting on multiple variables.
a. 1/ x + yz + u can be simplified using De Morgan's law to: (x'y'z')u'. Then, applying the double complement law, we get the simplified expression as: x'y'z'u.
b. 1/x(y + 2)u can be simplified using De Morgan's law to: x'(y'+2')u'. Then, applying the double complement law, we get the simplified expression as: x'y'u.
c. 1/(x + y)(uv + xy) can be simplified using De Morgan's law to: (x'y')(u' + x'y'). Then, applying the double complement law, we get the simplified expression as: x'y'u.
d. 1/xy + yz + xz can be simplified using De Morgan's law to: (x'+y')(y'+z')(x'+z'). Then, applying the double complement law, we get the simplified expression as: x'y'z'+xy'z'+xyz.
In summary, to simplify Boolean expressions, we can apply De Morgan's law repeatedly and then use the double complement law to remove complement operators acting on a single variable twice.
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Customers can be served by any of three servers, where the service times of server i are exponentially distributed with rate mu_i, i = 1, 2, 3. Whenever a server becomes free, the customer who has been waiting the longest begins service with that server. a. If you arrive to find all three servers busy and no one waiting, find the expected time until you depart the system. b. If you arrive to find all three servers busy and one person waiting, find the expected time until you depart the system.
Answers
a. The expected time until departure from the system when arriving to find all three servers busy and no one waiting can be calculated as (3/2(mu_1+mu_2+mu_3)).
b. The expected time until departure from the system when arriving to find all three servers busy and one person waiting can be calculated as (5/2(mu_1+mu_2+mu_3)).
a. In order to calculate the expected time until departure from the system when arriving to find all three servers busy and no one waiting, we can use the following formula:
E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]
where E(T) represents the expected time until departure and mu_1, mu_2, and mu_3 represent the service rates of each server.
By substituting the given values into the formula, we get:
E(T) = 1/3 * [1/mu_1 + 1/mu_2 + 1/mu_3 + (1/(mu_1+mu_2+mu_3))]
= 1/3 * [1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3))]
= (1/μ_1 + 1/μ_2 + 1/μ_3 + (1/(μ_1+μ_2+μ_3)))/3
Simplifying this expression gives us:
E(T) = (3/2(mu_1+mu_2+mu_3))
Therefore, the expected time until departure from the system when arriving to find all three servers busy and no one waiting is (3/2(mu_1+mu_2+mu_3)).
b. When one person is already waiting in the system, the expected time until departure can be calculated using the following formula:
E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min
where μ_min is the smallest service rate among the three servers.
The reasoning behind this formula is that the customer who has been waiting the longest will begin service immediately when a server becomes free, while the customer who arrived most recently will wait until all the other customers ahead of them have been served.
Therefore, the expected time until departure in this case is the expected waiting time for the customer who has been waiting the longest plus the expected service time for the next customer in line.
Since the service times are exponentially distributed, the expected service time for a server with rate mu is 1/mu. Therefore, the expected service time for the customer who is next in line is 1/μ_min.
By substituting the given values into the formula, we get:
E(T) = 1/2(mu_1+mu_2+mu_3) + 1/μ_min
= (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min)
Therefore, the expected time until departure from the system when arriving to find all three servers busy and one person waiting is (μ_min/2(μ_1+μ_2+μ_3)) + (1/μ_min), or equivalently, (5/2(mu_1+mu_2+mu_3)) if we substitute μ_min = min(μ_1, μ_2, μ_3).
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A piling for a high-rise building is pushed by two bulldozers at exactly the same time. One bulldozer exerts a force of 1850 pounds in a westerly direction. The other bulldozer pushes the piling with a force of 3250 pounds in a northerly direction. What is the magnitude of the resultant force upon the piling, to the nearest ten pounds?.
Answers
The magnitude of the resultant force upon the piling is 3710 pounds.
To find the resultant force, we can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. In this case, the forces exerted by the bulldozers form the two sides of a right triangle.
The force exerted by the first bulldozer in the westerly direction is 1850 pounds, and the force exerted by the second bulldozer in the northerly direction is 3250 pounds.
Using the Pythagorean theorem, we can calculate the magnitude of the resultant force as follows:
Resultant force =\(√(1850^2 + 3250^2)= √(3422500 + 10562500)= √(13985000)≈ 3710 pounds.\)
Therefore, the magnitude of the resultant force upon the piling is approximately 3710 pounds.
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The expression x2y - 2xy - 24y can be factored by first factoring out a common factor of y.
After the common factor is removed, the remaining factor is a
.
Answers
The expression x²y - 2xy - 24y can be factored by first factoring out a common factor of y, After the common factor is removed, the remaining factors are, (x - 6) & (x - 4)
What are expressions?An expression is a sentence with at least two numbers or variables having mathematical operation. Math operations can be addition, subtraction, multiplication, division.
For example, 2x+3
Given that,
The expression x²y - 2xy - 24y
Now taking common factor y from all the terms,
⇒ y(x² - 2x - 24)
Now considering another factor (x² - 2x - 24)
⇒ (x² - 2x - 24)
⇒ x² - 6x + 4x -24
⇒ x(x - 6) + 4(x - 6)
⇒ (x - 6)(x - 4)
Hence, rest two factors are (x - 6) & (x - 4)
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Answer:
trinomial that is not a perfect square
Step-by-step explanation:
edgeeeeeeeeeeeeee
Stefan sells Jin a bicycle for $151 and a helmet for $17. The total cost for Jin is 140% of what Stefan spent originally to buy the bike and helmet. How much did Stefan spend originally? How much money did he make by selling the bicycle and helmet to Jin?
Answers
Answer:
a)$235.20
b) $67.20
Step-by-step explanation:
Stefan sells Jin a bicycle for $151 and a helmet for $17.
a) How much did Stefan spend originally?
Total cost for Jin = $151 + $17
= $168
The total cost for Jin is 140% of what Stefan spent originally to buy the bike and helmet.
Hence,
140% of $168 = $235.20
b) How much money did he make by selling the bicycle and helmet to Jin?
This is calculated as:
$235.20 - $168
= $67.20
=
NM=x-6 , ML=9,LK =2x-19, NK=23
Solve for X
Answers
For the function p(x) = (x - 2)/(sqrt(5 - 2x)) find the domain ?
Answers
May someone help me ✨
Answers
Answer:
Look down!
Step-by-step explanation:
1. 1/4*1/4*1/4
2. 1/4*1/2*1/2*1/4
A teacher has threee pieces of wood that measure 2 ft , 3 ft, and 6 ft, respectively. The teacher asks
Four students explain how many triangles they can make with the pieces of wood. The table shows the
S
The three pieces of wood will make me triangles because
23=amd 56
The three pieces of wood will make one triangle because
23=5 and 56
The three prices of wood will make many triangles because
23=5 and 56
The three pieces of wood will make one triangle because
23=5 and 56
3
which student is correct
Answers
Rewrite the equation using completing the square.
Answers
Answer: 8*8=64
6*6*=216
64-216+21=0
Step-by-step explanation:
PLEASE HELP WILL MARK BRAINLIEST!!!!
Answers
The solution to the inequality is x ≥ 2, given that x is not equal to -3/2, and the solution is x ∈ [2, ∞).
To find the domain of the inequality (3x - 1)/(2x + 3) ≥ 1, we need to look for values of x that make the denominator 2x + 3 equal to zero, since division by zero is undefined. We can set the denominator equal to zero and solve for x:
2x + 3 = 0
2x = -3
x = -3/2
Therefore, x cannot equal -3/2.
To solve the inequality, we can start by multiplying both sides by 2x + 3 to clear the denominator:
\((3x - 1)\div(2x + 3) \times (2x + 3) \geq1 \times (2x + 3)\)
3x - 1 ≥ 2x + 3
x ≥ 2
Therefore, the solution to the inequality is x ≥ 2, but we need to check that this solution is within the domain of the inequality. Since x cannot equal -3/2, the solution is:
x ∈ [-3/2, ∞) ∩ [2, ∞) = [2, ∞)
The domain of the inequality is x ∈ (-∞, -3/2) ∪ (-3/2, ∞).
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I really need help with this
Answers
Answer:
1/2 or .5
Step-by-step explanation:
you find 2 points that the line goes through, then you find the rise/run. lastly you simplify if you can, then you have the answer
Paul wants to find the center and radius of the circle defined by the equation x2+y2+10x−14y+40=2
Answers
Answer:
x-intercept(s):
None
y-intercept(s):
(0,7+√11),(0,7−√11)Step-by-step explanation:
What does the x intercept represent?
Answers
Answer:
the x intercept is the y and x combined together crossing each other
I need help finding the answer too Y= 2.82x + 25.1
Answers
Answer:
-8.9 is x and y is -25.1
Step-by-step explanation:
pla shop mathematics
Answers
The number of trees more than 10m tall but not more than 20m tall is 18 trees.
How many of the trees are more than 10m tall but not more than 20m tall?0 < h ≤ 5 = 5
height greater than 0m less than or equal to 5m
5 < h ≤ 10 = 9
height greater than 5m less than or equal to 10m
10 < h ≤ 15 = 13
height greater than 10m less than or equal to 15m
15 < h ≤ 20 = 5
height greater than 15m less than or equal to 20m
20 < h ≤ 25 = 1
height greater than 20m less than or equal to 25m
The number of trees that are more than 10m tall but not more than 20m tall are;
10 < h ≤ 15 = 13
15 < h ≤ 20 = 5
So,
13 + 5 = 18 trees
Therefore, the total number of trees which are 10m tall but not more than 20m tall is 18 trees.
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Write the expression without radicals, using only positive exponents.
Answers
Answer:
\((a^{2}+b^{2})^{1/3}\)
Step-by-step explanation:
(a² + b²)^1/3
Any number to the power 1/2 means to square root the number
Any number to the power 1/3 means to cube root the number etc.
Find the area of ABF. Round the area to the nearest whole number if necessary.
Answers
Answer:
\(6\)
Step-by-step explanation:
We see that the triangle is a right triangle. We need to find the lengths of the two legs to find the area, then. Let's start with AB.
\(AB=\sqrt{(3-1)^2+(0-(-2))^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt{2}\)
Now, we do the other leg.
\(\sqrt{(1-4)^2+(-2-(-5))^2}=\sqrt{3^2+3^2}=\sqrt{18}=3\sqrt{2}\).
That will make the area \(b*h/2=2\sqrt{2}*3\sqrt{2}/2=6*2/2=6\)
Find on nonhomogenous Diffrential eqaution whose ofeneral solution is y=c 1
e −2x
+c 2
e 6x
+x 2
+2x
Answers
The differential equation that matches the provided general solution is a nonhomogeneous equation expressed as y'' - 4y' + 12y = 4x + 2.
What is a nonhomogeneous differential equation?The nonhomogeneous differential equation that corresponds to the given general solution is:
y'' - 4y' + 12y = 4x + 2
This equation has a nonhomogeneous term (4x + 2) on the right-hand side, which leads to the presence of the particular solution (x² + 2x) in the general solution. The homogeneous part of the equation corresponds to the complementary solution \((c1e^{(-2x)} + c2e^{(6x)})\).
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by 8:00 a.m., the snack bar had made $3,256 in sales. By noon, the snack bar's total sales were $8,821. On average how much money did the snack bar take in each hour between 8:00 a.m. and noon?
Answers
Answer:
$1,391.25
Step-by-step explanation:
Noon would be 12:00 PM which would be 4 hours ahead of 8:00 AM
We subtract $8,821 by $3,256 to get the amount earned between 8:00 AM and 12:00 PM
$8,821 - $3,256
= $5,565
The find the average taken in within those 4 hours we will have to divide the money earned by the hours
$5,565/4
= $1,391.25