write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.

40 yd to 64 yd

Answer:There are 6 possible amounts.

Step-by-step explanation:

It's 4 Choose 2 meaning 4 coins choosing two which translates to 4C2 on your calculator

We can easily calculate the conversion of 245 l to ml by multiplying 1000 by the number of litres we have, which is 245. So, the answer to the question "what is 245 litres in millilitres?" is 245000 ml. Answer is A

Answer:

A Multiply by 1000

Step-by-step explanation:

1 liter = 1000 milliliter

245 liters multiply by 1000 gives 245000 milliliters.

Answer:

sin D = 118/119

Step-by-step explanation:

sin = opposite side/hypotenuse

sin D = 118/119

The average speed for the first part of the trip is 60 miles.

Given:

1st leg DATA:

distance = 120 miles ;

rate = x mph ;

time = d/r = 120/x hrs

2nd leg DATA:

distance = 220 miles ;

rate = x-5 mph ;

time = 220/(x-5) hrs

hence the equation we frame is:

Equation:

120/x + 220/(x-5) = 6

120(x-5) + 220x = 6x(x-5)

120x - 600 + 220x = 6x² - 30x

-6x² + 340x + 30x - 600 =0

-6x² + 370x - 600 = 0

-3x² - 185x + 300 = 0

(3x-5)(x-60)

3x = 5 or x-60=0

x = 5/3 or x = 60

hence x-5 = 60-5

= 55 miles per hour.

Hence we get the answer as 60 miles.

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The kinetic energy of the Mars Climate Orbiter spacecraft is approx    3.31 x 10^7 joules.

To determine the kinetic energy of the Mars Climate Orbiter spacecraft, we can use the formula:

Kinetic energy = (1/2) * mass * velocity^2

Given:

Mass of the spacecraft (m) = 629 kg

Velocity of the spacecraft (v) = 1.20 x 10^4 km/h

First, we need to convert the velocity from km/h to m/s:

1 km = 1000 m

1 h = 3600 s

Velocity in m/s = (1.20 x 10^4 km/h) * (1000 m/km) / (3600 s/h) ≈ 333.33 m/s

Now, we can calculate the kinetic energy:

Kinetic energy = (1/2) * (629 kg) * (333.33 m/s)^2

Kinetic energy ≈ 3.31 x 10^7 joules

Therefore, the kinetic energy of the Mars Climate Orbiter spacecraft is approximately 3.31 x 10^7 joules.

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Answer:

D

Step-by-step explanation:

The sum to infinity of a geometric sequence is calculated as

\(S_{infinity}\) = \(\frac{a}{1-r}\) | r | < 1

where a is the first term and r the common ratio

Here a = 1 and r = \(\frac{1}{5}\) , thus

\(S_{infinity}\) = \(\frac{1}{1-\frac{1}{5} }\) = \(\frac{1}{\frac{4}{5} }\) = \(\frac{5}{4}\) → D

Answer:

here is the answer I simply don't the answer to

Step-by-step explanation:

a) 2 square.

b)because there is two k's

In Herrnstein's matching equation, the letters and numbers to the left of the equals sign refer to behaviour.

THE MATCHING LAW

Herrnstein's Experiment Herrnstein (1961) conducted an experiment with pigeons in a room with two response buttons, red and white. Each key was assigned its own VI gain schedule. For example, under one condition, the left button pick was boosted on a VI 135 second schedule, and the right button pick was boosted on a VI 270 second schedule.

After the birds have learned as much as possible about this electoral situation, how do they distribute their responses? We trained them for days and then measured their reactions. As is often the case with VI schedules, birds returned many responses for each reinforcer received. Most interesting, however, is that in this condition, where two-thirds of the reinforcers came from the left button, the birds performed about two-thirds of the responses with the left button. That is, the proportion of left button responses equaled or matched the proportion of reinforcers delivered by the left button. In another condition, two birds received only about 15% of reinforcers from the left key and responded about 15% to that key.

Based on these results, Herrnstein proposed the following general principle for individual behavior when presented with alternative sequences. So, what you think makes sense rather than other options available at that particular moment.

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By the congruence postulate, we have shown that the quadrilateral is  ΔAED ≅ ΔCED.

Let's start by showing that AD = CD. Since AB = AD and BC = CD, we can rewrite AB + BC as AD + CD. This means that AD = AB + BC - CD. But we know that AB = AD, so we can substitute AD for AB to get AD + BC = 2AD + CD. Simplifying this equation, we get AD = CD.

Next, we can show that AE = CE. Since AC is a diagonal of the kite, we know that AC bisects angle BAD and angle BCD. This means that angle BAC = angle DAC and angle BDC = angle CDC. Since AD = CD, we know that triangle ACD is isosceles, so angle ACD = angle CAD.

Using these angle equalities, we can conclude that angle CAE = angle CDE. Since AC ⊥ BD, we know that angle CAD = angle CDE, so we can conclude that triangle ACE is isosceles, which means that AE = CE.

Finally, we need to show that angle AED = angle CED. Since AD = CD and AE = CE, we know that triangles AED and CED have two pairs of congruent sides. Additionally, we know that AC is a common side of the triangles.

Since AC is perpendicular to BD, we know that angle ACD and angle BDC are complementary angles.

This means that angle ACD = 90 - angle BDC and angle CAD = 90 - angle BAC. Using these angle equalities, we can conclude that angle AED = angle CED.

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Answer:

Step-by-step explanation:

If the PROE is a rhombus, each of two pairs of it will be same so EP=OE

And E is like the interception of it.

so we can get SE=EV

The linear model for the number of purchases over time is:

p = 0.043t + 3.726

We have,

Let's assign the variable t as the number of months since January 2007, where t = 0 corresponds to January 2007.

Given data:

June 2007: p = 4,500 (in thousands, so p = 4.5)

September 2008: p = 5,100 (in thousands, so p = 5.1)

We can use these data points to set up a system of equations to solve for the slope (r) and the intercept (i) in the linear model p = rt + i.

Using the data points,

4.5 = r(18) + i (June 2007 corresponds to 18 months after January 2007)

5.1 = r(32) + i (September 2008 corresponds to 32 months after January 2007)

Solving this system of equations will give us the values of r and i.

Subtracting the second equation from the first equation:

4.5 - 5.1 = r(18) - r(32)

-0.6 = -14r

r = -0.6 / -14

r = 0.043

Substituting the value of r into one of the equations:

4.5 = 0.043(18) + i

4.5 = 0.774 + i

i = 4.5 - 0.774

i = 3.726

Therefore,

The linear model for the number of purchases over time is:

p = 0.043t + 3.726

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Answer:

20

Step-by-step explanation:

The correct option is for the value of c,  such that f(c) is the average value of the function on the interval [0, 2], is D.

The average value of a function on an interval [a, b] is given by:

R = (f(b) - f(a))/(b - a)

Here the interval is [0, 2], then:

f(2) = √(2 + 2) = 2

f(0) = √(0 + 2) = √2

Then here we need to solve the equation:

√(c + 2) = (f(2) - f(0))/(2 - 0)

√(c + 2) = (2 + √2)/2

Solving this for c, we will get:

c = [ (2 + √2)/2]² - 2

c = 0.9

Them tjhe correct option is D.

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Answer: $270

Step-by-step explanation:

Cost of heating last year = $120

The amount that they will expect to pay this January if their bill increased by 125% will be the addition of $120 and 125% of $120. This can be mathematically expressed as:

= $120 + (125% × $120)

= $120 + (1.25 × $120)

= $120 + $150

= $270

Answer:

1 9/50

Step-by-step explanation:

1.18 = 1 18/100

1 18/100 = 1 9/50

The fourth answer is correct.

Hope this helps!

Answer:

Hope this helped you a little

Step-by-step explanation:

Answer:

An easy way to finish this problem even if you don't know the correct mathematical approach would be to plug in each ordered pair into both equations and see whether they are true/false. You can even graph both lines and see where the intersect (the solution).

I got (-7,23), which appears to not be one of the available answer choices. Try using the graphing calculator in desmos.

Answer:

The maximum number of mosquitoes is 7

Step-by-step explanation:

Given

\(m(x)= x^2 + 14x\)

Required

Determine the maximum number of the function

First, we differentiate the given function w.r.t x

\(m'(x) = -2x + 14\)

Then, we equate m'(x) to 0

\(0 = -2x + 14\)

Lastly, we solve for x

\(0 = -2x + 14\)

Make 2x the subject

\(2x = 14\)

Make x the subject

\(x = 14/2\)

\(x = 7\)

Answer:

49 Million

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let the first integer be x, then the next is x+1.

x(x + 1) = 3(x + 1) + 4

x^2 + x = 3x+ 3 + 4

x^2 + x - 3x - 7 = 0

x^2 - 2x - 7 = 0

Solving this does not give an integer so maybe there's something wrong with the question??

There are approximately 11.25 cups of granulated sugar in a 5 pound bag.

To determine the number of cups of granulated sugar in a 5 pound bag, we can use the conversion factor of 2.25 cups per pound.

First, we multiply the number of pounds (5) by the conversion factor:

5 pounds * 2.25 cups/pound = 11.25 cups

Therefore, there are approximately 11.25 cups of granulated sugar in a 5 pound bag.

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Answer:

C. n||p

Step-by-step explanation:

Parallel means will never cross. Like sidewalks on opposite sides of the road. They will always be parallel to each other because they are going in the same direction, and they will never cross each other.

Answer:

Step-by-step explanation:

6 is 4xd

and can u plz can u plz clarify what 5 is asking so i can answer it for u

Answer:

No they are not

Step-by-step explanation:

6.23x10^2=623

62,300/10^3=62.3

623>62.3

-Hope this helped

Answer:

1/20

Step-by-step explanation:

The stochastic process for the function G = G(S, t) is given by:

\(\[dG = \frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\]\)

The stochastic process for G^2 is given by:

\(\[d(G^2) = \left[2G\frac{\partial G}{\partial t} + \left(\frac{\partial G}{\partial t}\right)^2 + 2G\frac{\partial G}{\partial S} + \left(\frac{\partial G}{\partial S}\right)^2\right]dt + 2G\frac{\partial^2 G}{\partial S^2}(dS) + \left(\frac{\partial G}{\partial t}\right)^2(dt)^2 + \left(\frac{\partial G}{\partial S}\right)^2(dS)^2\]\)

Let us now analyze each section in a detailed way:

i) Using Ito's lemma, we can find the stochastic process \($dG$\) followed by \($G^2$\) as follows:

Applying Ito's lemma to \($G(S, t)$\), we have:

\(\[dG = \frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2.\]\)

For \($G = G(S, t)$\), the first term \($\frac{\partial G}{\partial t}dt$\) is straightforward as it is the partial derivative of \($G$\) with respect to \($t$\) multiplied by \($dt$\).

The second term \($\frac{\partial G}{\partial S}dS\) can be obtained by taking the partial derivative of $G$ with respect to \($S$\) and multiplying it by \($dS\).

The third term \($\frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\) involves the second partial derivative of \($G$\) with respect to \($S$\), and it is multiplied by \($(dS)^2\).

ii) To find the stochastic process for $G^2$, we substitute $G = G(S, t)$ into the equation derived above:

\(\[d(G^2) = 2GdG + (dG)^2.\]\)

Expanding and substituting the value of $dG$, we get:

\(\[d(G^2) = 2G\left(\frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\right) + \left(\frac{\partial G}{\partial t}dt + \frac{\partial G}{\partial S}dS + \frac{1}{2}\frac{\partial^2 G}{\partial S^2}(dS)^2\right)^2.\]\)

Simplifying the above expression, we can write:

\(d(G^2) &= \left[2G\frac{\partial G}{\partial t} + \left(\frac{\partial G}{\partial t}\right)^2 + 2G\frac{\partial G}{\partial S} + \left(\frac{\partial G}{\partial S}\right)^2\right]dt &\quad+ 2G\frac{\partial^2 G}{\partial S^2}(dS) + \left(\frac{\partial G}{\partial t}\right)^2(dt)^2 + \left(\frac{\partial G}{\partial S}\right)^2(dS)^2.\)

The above equation represents the stochastic process for $G^2$.

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Answer:

Step-by-step explanation

Kf i help u wojld u help me

Answer: your answer will be 72 divided by 8

Step-by-step explanation: because they wanna know how many pages she put stickers on in if you divide it will tell you how many pages she put stickers on witch is 9

~Kindly see the attached picture!

✧ Hope I helped ! ✧

Have a wonderful day / night ! ♡

Let me know if you have any questions regarding my answer ツ

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The bag has 2 yellow cubes, 5 green cubes,and 3 red cubes. The probability of selecting a yellow cube at random is 0.2 or 20%.

The probability of an event is determined by dividing the number of favorable outcomes by the total number of possible outcomes. There are a total of 2 + 5 + 3 = 10 cubes in the bag. The probability of selecting a yellow cube at random can be calculated as:

number of yellow cubes / total number of cubes

So the probability of selecting a yellow cube at random is:

2 / 10 = 1/5 or 0.2

Therefore, the probability of selecting a yellow cube is 0.2 or 20%.

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Answer:

The value of x is 6.66

Step-by-step explanation:

For answer refer to the attachment

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