2- given the velocity field ; u = y2-x2 , v = 2xy sketch the field, find the velocity and acceleration components at point (2,2) and (2,-2).
Answers
Answer:
To sketch the velocity field, we can plot a set of velocity vectors at various points in the domain. Here, we will plot the vectors at a grid of points in the xy-plane.
First, let's plot the vector field using Python:
import numpy as np
import matplotlib.pyplot as plt
# Define the velocity field functions
def u_func(x, y):
return y**2 - x**2
def v_func(x, y):
return 2*x*y
# Define the grid of points
x = np.linspace(-3, 3, 20)
y = np.linspace(-3, 3, 20)
X, Y = np.meshgrid(x, y)
# Compute the velocity components at each point in the grid
U = u_func(X, Y)
V = v_func(X, Y)
# Plot the vector field
fig, ax = plt.subplots(figsize=(6, 6))
ax.quiver(X, Y, U, V)
ax.set_xlabel('x')
ax.set_ylabel('y')
ax.set_xlim(-3, 3)
ax.set_ylim(-3, 3)
plt.show()
----------------------------
To find the velocity and acceleration components at points (2,2) and (2,-2), we first need to evaluate the velocity field functions at these points:
At (2,2):u = y^2 - x^2 = 2^2 - 2^2 = 0
v = 2xy = 2*2*2 = 8
So the velocity vector at (2,2) is (0, 8).
To find the acceleration components, we need to compute the partial derivatives of the velocity field functions with respect to x and y:
a_x = ∂u/∂x = -2x
a_y = ∂u/∂y = 2y
So at (2,2), the acceleration vector is (-4, 4).
At (2,-2):u = y^2 - x^2 = (-2)^2 - 2^2 = -4
v = 2xy = 2*2*(-2) = -8
So the velocity vector at (2,-2) is (-4, -8).
To find the acceleration components, we again need to compute the partial derivatives of the velocity field functions:a_x = ∂u/∂x = -2x
a_y = ∂u/∂y = 2y
So at (2,-2), the acceleration vector is (-4, -4).
Explanation:
Related Questions
Consider a condenser in which steam at a specified temperature is condensed by rejecting heat to the cooling water. If the heat transfer rate in the condenser and the temperature rise of the cooling water is known, explain how the rate of condensation of the steam and the mass flow rate of the cooling water can be determined. Also, explain how the total thermal resistance R of this condenser can be evaluated in this case.
Answers
Answer:
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
Explanation:
How will the rate of condensation of the steam and the mass flow rate of the cooling water can be determined
Q = [ mCp ( ΔT) ] \(_{cooling water }\)
(ΔT)\(_{cooling water}\) and Q is given
\(m_{cooling water}\) = \(\frac{Q}{Cp[ T_{out} - T_{in} ] }\)
next the rate of condensation of the steam
Q = [ m\(h_{fg}\) ]\(_{steam}\)
\(m_{steam} = \frac{Q}{h_{fg} }\)
Total resistance of the condenser is
R = \(\frac{Q}{change in T_{cooling water } }\)
A 4-pole, 3-phase induction motor operates from a supply whose frequency is 60 Hz. calculate: 1- the speed at which the magnetic field of the stator is rotating. 2- the speed of the rotor when the slip is 0.05. 3- the frequency of the rotor currents when the slip is 0.04. 4- the frequency of the rotor currents at standstill.
Answers
Answer:
The answer is below
Explanation:
1) The synchronous speed of an induction motor is the speed of the magnetic field of the stator. It is given by:
\(n_s=\frac{120f_s}{p}\\ Where\ p\ is \ the \ number\ of\ machine\ pole, f_s\ is\ the\ supply \ frequency\\and\ n_s\ is \ the \ synchronous\ speed(speed \ of\ stator\ magnetic \ field)\\Given: f_s=60\ Hz, p=4. Therefore\\\\n_s=\frac{120*60}{4}=1800\ rpm\)
2) The speed of the rotor is the motor speed. The slip is given by:
\(Slip=\frac{n_s-n_m}{n_s}. \\ n_m\ is\ the \ motor\ speed(rotor\ speed)\\Slip = 0.05, n_s= 1800\ rpm\\ \\0.05=\frac{1800-n_m}{1800}\\\\ 1800-n_m=90\\\\n_m=1800-90=1710\ rpm\)
3) The frequency of the rotor is given as:
\(f_r=slip*f_s\\f_r=0.04*60=2.4\ Hz\)
4) At standstill, the speed of the motor is 0, therefore the slip is 1.
The frequency of the rotor is given as:
\(f_r=slip*f_s\\f_r=1*60=60\ Hz\)
Plz help electrical technology
Answers
Answer:
OPTION A,Larger
HOPE IT HELPS
Johnston Implants is planning new online patient diagnostics for surgeons while they operate. The new system will cost $200,000 to install in an operating room, $5000 annually for maintenance, and have an expected life of 5 years. The revenue per system is estimated to be $40,000 in year 1 and to increase by $10,000 per year through year 5 . Determine if the project is economically justified using PW analysis and an MARR of 10% per year.
Answers
Answer:
To determine if the project is economically justified using present worth (PW) analysis and a minimum acceptable rate of return (MARR) of 10%, we need to calculate the present worth of the cash flows associated with the project.
The initial cost of the project is $200,000. The annual maintenance cost is $5,000, and we need to calculate the present worth of this cost for the five-year life of the project. Using a 10% discount rate, we can calculate the present worth as follows:
PW maintenance = $5,000 * [(1 - 1/(1 + 0.1)^5)/0.1] = $20,890
The annual revenue for the project is $40,000 in year 1, increasing by $10,000 each year through year 5. We need to calculate the present worth of these cash flows using a 10% discount rate.
PW revenue = [$40,000 * (1/(1 + 0.1)^1)] + [$50,000 * (1/(1 + 0.1)^2)] + [$60,000 * (1/(1 + 0.1)^3)] + [$70,000 * (1/(1 + 0.1)^4)] + [$80,000 * (1/(1 + 0.1)^5)] PW revenue = $227,025
The total present worth of the cash flows is the present worth of the revenue minus the present worth of the maintenance cost minus the initial cost of the project.
PW total = PW revenue - PW maintenance - initial cost PW total = $227,025 - $20,890 - $200,000 PW total = $6,135
Since the PW total is positive, the project is economically justified using PW analysis and a MARR of 10% per year. Therefore, the project is profitable and is expected to generate a positive return on investment.
Explanation:
what is the lighting load on a 120v circuit for six 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a, all operating continuously for 8 hours per day?
Answers
Note that the lighting load on a 120v circuit for six 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a, all operating continuously for 8 hours per day is: 10,560 Watts.
What is Lighting Load?A building's lighting loads are sometimes referred to in terms of "Lighting Power Density," which is measured in watts per square foot or square meter.
It is to be noted that a single calculation is used to compute lighting load:
W=VA.
Where
W = Watts
V = Volts; and
A = Amps
To determine the total wattage for the fluorescent fixtures we say:
4 fixtures x 1.5 amps x 120 volts = 720 watts
Next, we add the wattages for the incandescent lights and fluorescent fixtures to get the total wattage for the circuit. That is:
(6 x 100watts) + 720 watts
= 600 watts + 720 watts
= 1,320 watts
Thus the Load is 1,320 watts.
If all lighting will operate continuously for 8 hours/day, then:
Daily energy consumption will be:
1320 x 8
= 10,560 Watts.
Thus, the Lighting Load on a 120v circuit for 6 100w incandescent lights and four fluorescent fixtures with a ballast rating of 1.5a Operating at 8 hours per day is 10,560 Watts.
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A visual lead of ________ seconds or 1 city block is appropriate when driving in traffic in urban areas.
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The answer is
A visual lead of 12-15 seconds or 1 city block is appropriate when driving in traffic urban areas.
Urban driving involves a variety of complex driving situations.
when you driving in urban areas, look at least 12-15 seconds ahead of vehicle.
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Answer: 5
Explanation:
just took it
A 1310 nm digital optical receiver is operating at 2.2 Gb/s and has an effective noise bandwidth of 1.5 GHz. The pin photodiode has negligible dark current and 90% quantum efficiency. The equivalent input resistance is 100 Q and the equivalent noise current is 2.5 pA/(Hz)112. Calculate the receiver sensitivity corresponding to a BER of 10-9. How much does it change if the receiver is designed to operate reliably up to a BER of 10-12.
Answers
If the receiver is designed to operate reliably up to a BER of 10-12, the receiver sensitivity has increased by 2.4 dBm.
The formula for the maximum allowed bit error rate is given as:BER = 1 / 2Q where Q is the Q-factor. The BER level is reduced by lowering the Q factor. The Q-factor (Q) is defined as:
Q = E s /N 0, where E s is the bit energy and N 0 is the noise power spectral density.
BER = Q^2 / 2πe^(-Q^2/2)
For a BER of 10-12, solve for Q:
BER = Q^2 / 2πe^(-Q^2/2) 10-12 = Q^2 / 2πe^(-Q^2/2)
Q = 5.2.
For a given Q, the received signal level for a given BER is the same as it was previously.
SNRthreshold = 2Q − 1 = 9.4 dB.
The receiver sensitivity isReceiver sensitivity = Noise + SNRthreshold= −88.88 + 9.4= -79.48 dBm
The receiver sensitivity has increased as a result of the change in BER from 10-9 to 10-12.
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Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N/m, with a measured damping ratio of 0.2. The machine produces a harmonic force of 450 N at 13 rad/s during steady-state operating conditions. Determine
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Complete Question
Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N/m, with a measured damping ratio of 0.2. The machine produces a harmonic force of 450 N at 13 rad/s during steady-state operating conditions. Determine
(a) the amplitude of motion of the machine,
(b) the phase angle of the motion,
(c) the transmissibility ratio,
(d) the maximum dynamic force transmitted to the floor, and
(e) the maximum velocity of the machine.
Answer:
a) \(X=0.0272m\)
b) \(\phi=22.5 \textdegree\)
c) \(T_r=1.57\)
d) \(F=706.5N\)
e) \(V_{max}=0.35m/s\)
Explanation:
From the question we are told that:
Mass \(M=70kg\)
Total Stiffness \(\mu=30000\)
Damping Ratio \(r=0.2\)
Force \(F=450N\)
Angular velocity \(\omega =13rad/s\)
Generally the equation for vibration in an isolated system is mathematically given by
\(\omega_n=\sqrt{\frac{k}{m}}\)
\(\omega_n=\sqrt{\frac{30000}{70}}\)
\(\omega_n=20.7rad/s\)
a)
Generally the equation for Machine Amplitude is mathematically given by
\(X=\frac{F_O/m}{(\omega_n^2-\omega^2)^2-(2*r*\omega)*\omega_n*\omega^2)^{1/2}}\)
\(X=\frac{450}{70}}{(20.7^2-(137^2)^2-(2*0,2*(20.7(13)))^2)^{1/2}\)
\(X=0.0272m\)
b)
Generally the equation for Phase Angle is mathematically given by
\(\phi=tan^{-1}\frac{2*r*\omega_n*\omega}{\omega_n^2*\omega^2}\)
\(\phi=tan^{-1}\frac{2*0.2*20.7*13}{\20.7^2*13^2}\)
\(\phi=22.5 \textdegree\)
c)
Generally the equation for transmissibility ratio is mathematically given by
\(T_r=\sqrt{\frac{1+(2r\beta)^2}{(1-r^2)^2+(2*\beta*r)^2}}\)
Where
\(\beta=Ratio\ of\ angular\ velocity\)
\(\beta=\frac{13}{20.7}\\\beta=0.638\)
Therefore
\(T_r=\sqrt{\frac{1+(2*(0.2)(0.638))^2}{(1-(0.2)^2)^2+(2*0.2*0.638)^2}}\)
\(T_r=1.57\)
d)
Generally the equation for Maximum dynamic force transmitted to the floor is mathematically given by
\(F=(T_r)*F_o\)
\(F=(1.57)*450\)
\(F=706.5N\)
e)
Generally the equation for Maximum Velocity of Machine is mathematically given by
\(V_{max}=\omega*x\)
\(V_{max}=13*0.0272\)
\(V_{max}=0.35m/s\)
If the probability of a bit error is p, what is the probability of a single, double, and triple error in a 10-bit word? Express it in terms of p.
Answers
Answer:
single bit error: 10pdouble bit error: 45p²triple bit error: 120p³Explanation:
The probability of n bits being in error is 10Cn × p^n, where ...
10Cn = 10!/(n!(10-n!))
10C1 = 10
10C2 = 45
10C3 = 120
This is the product of the probability that n bits can be in error and the number of ways that n bits can be chosen from the 10 in the word.
n = 1: 10p
n = 2: 45p²
n = 3: 120p³
Imagine that you are given a large budget and a team of competent sysadmins/devops engineers. Your boss has requested that you develop a plan to deploy the company's latest web application in their on-site datacenter. You have the freedom to recommend servers, extra components (RAM, HDDs, SSDs, network cards, etc), and additional hardware purchases as needed. The primary goal is to design the overall system so that it can provide high levels of uptime even in the presence of minor maintenance (OS reboots, HDD hot-swaps) or major issues (motherboard failures, network card failure, power outages). Write a ½ page report (12pt font, double spaced, 1" margins) that provides your recommendations for creating a robust deployment which can attempt to mitigate the various failures that were mentioned. It's perfectly fine to discuss software architecture choices along with your suggested hardware design considerations.
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One can write the report under the title Deploying a Robust Web Application in an On-Site Datacenter by Design.
This report's recommendations for deploying the most recent web application of the business in the local datacenter are intended to guarantee high levels of uptime and reduce potential failures.
We can create a strong system that can resist both routine maintenance and significant problems while sustaining uninterrupted service if we have a sizable budget and a skilled staff of sysadmins and devops engineers.
We can develop a reliable deployment for the company's web application in the on-site datacenter by putting the suggested hardware and software design considerations into practise.
Thus, hardware failures will be less damaging because to redundant servers, RAID storage, network redundancy, and power backup systems.
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FILL IN THE BLANK. by early 1818 karl friedrich schinkel had produced a new design for the in berlin to sit atop the old foundations between existing french and german churches.
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By early 1818 Karl Friedrich Schinkel had produced a new design for the Altes Museum in berlin to sit atop the old foundations between existing french and german churches.
What do you mean by design template?
Customizable pre-made designs and documents are known as design templates. Templates are frequently created to adhere to strict guidelines or specifications in order to maintain consistency across users and media. You have the option of creating bespoke templates for later use or using pre-design templates from libraries and websites.
Design templates include color palettes, master slides and titles with personalized formatting, and styled fonts created for a specific "look." The slide master and color scheme of the new template is substituted for those of the previous presentation when a design template is applied to a presentation.
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A refrigeration system was checked for leaks. The system temperature and surroundings were 75°F when the system was charged with nitrogen to 100 psig. The temperature then dropped to 50°F. What should the pressure be if no nitrogen has escaped?
A) 9 psig
B) 94 psig
C) 100 psig
D) 90 psig
Answers
The temperature and pressure of an ideal gas are directly proportional
The pressure of the system should be in the range B) 94 psig
The given refrigerator parameters are;
The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K
The pressure to which the system was charged with nitrogen, P₁ = 100 psig
The temperature to which the system dropped, T₂ = 50 °F = 283.15 K
The required parameter;
The pressure, P₂, of the system at 50°F
Method:
The relationship between pressure and temperature is given by Gay-Lussac's law as follows;
At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin
Mathematically, we have;
\(\dfrac{P_1}{T_1} = \mathbf{\dfrac{P_2}{T_2}}\)
Plugging in the values of the variables gives;
\(\mathbf{\dfrac{100 \ psig}{297.0389}} = \dfrac{P_2}{283.15}\)
Therefore;
\(P_2 = \mathbf{283.15 \, ^{\circ}F \times \dfrac{100 \ psig}{297.0389\ ^{\circ}F} \approx 95.3 \, ^{\circ}F}\)
The closest option to the above pressure is option B) 94 psig
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develop a note on important alloys
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Alloys are mixtures of two or more metals, or a metal and a non-metal, that are created to enhance the properties of the individual metals. Alloys are used in a wide range of applications, from construction to electronics to transportation, and are essential to modern technology and industry.
Some important alloys include:
Steel: Steel is an alloy of iron and carbon, with small amounts of other elements such as manganese, silicon, and sulfur. Steel is strong, durable, and versatile, and is used in a wide range of applications, from construction to manufacturing to transportation.
Brass: Brass is an alloy of copper and zinc, with small amounts of other elements such as lead or tin. Brass is valued for its corrosion resistance, low friction, and attractive appearance, and is used in applications such as plumbing fixtures, musical instruments, and decorative items.
Bronze: Bronze is an alloy of copper and tin, with small amounts of other metals such as aluminum, silicon, or phosphorus. Bronze is strong, durable, and corrosion-resistant, and is used in applications such as sculptures, coins, and bearings.
Stainless steel: Stainless steel is an alloy of iron, chromium, and nickel, with small amounts of other metals such as molybdenum or titanium. Stainless steel is highly resistant to corrosion, heat, and wear, and is used in applications such as cutlery, medical equipment, and aerospace components.
Aluminum alloys: Aluminum alloys aremixtures of aluminum with other metals such as copper, zinc, or magnesium. Aluminum alloys are lightweight, strong, and corrosion-resistant, and are used in a wide range of applications, from aircraft and automobiles to construction and consumer goods.
Titanium alloys: Titanium alloys are mixtures of titanium with other metals such as aluminum, vanadium, or nickel. Titanium alloys are strong, lightweight, and corrosion-resistant, and are used in applications such as aerospace, medical implants, and sports equipment.
Nickel-based alloys: Nickel-based alloys are mixtures of nickel with other metals such as chromium, iron, or cobalt. Nickel-based alloys are heat-resistant, corrosion-resistant, and have high strength and toughness, and are used in applications such as jet engines, chemical processing, and power generation.
Copper-nickel alloys: Copper-nickel alloys are mixtures of copper with nickel and sometimes other metals such as iron or manganese. Copper-nickel alloys are highly resistant to corrosion and have good thermal and electrical conductivity, making them ideal for applications such as marine engineering, heat exchangers, and electrical wiring.
In conclusion, alloys are important materials that are used extensively in modern technology and industry. By combining the properties of different metals, alloys can be tailored to meet specific needs and applications, and have revolutionized the way we design and make things.
Tech A says that radial ply tires have much more flexible sidewalls than bias-ply tires because of their construction. Tech B says that bias-ply tires have a more durable construction than radial tires. Who is correct?
Answers
Answer:
Tech A and Tech B are correct
Explanation:
Tech A is correct because radial ply tires have more flexible sidewalls than radial tires due to the fact that radial tires make use of two or more layers of casing piles and are thus not much flexible.
Also, tech B is correct because bias-ply tires typically have more durable construction than radial tires
Dialogue must be very __________ in order to best offer the reader bite-size information that will propel the story along.
Answers
Dialogue must be very concise or succinct in order to best offer the reader bite-size information that will propel the story along.
In storytelling, dialogue serves multiple purposes, including conveying information, developing characters, and advancing the plot. By keeping the dialogue concise, the writer can deliver essential information efficiently, without overwhelming the reader with excessive details or unnecessary conversation. Bite-size dialogue allows for a faster pace and keeps the reader engaged, as they receive crucial information in a digestible manner. It also helps maintain the flow of the story by avoiding long-winded conversations that may slow down the narrative. Concise dialogue ensures that every word counts and serves a purpose, enhancing the overall impact of the story.
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Through engineering, human achievement continues to advance. Write about your favorite example of engineering, describing the technical aspects that are unique about it, and mention what impresses you about it from an engineering standpoint.
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Gas turbine engine is a great human achievement in Engineering and my personal favorite example of engineering.
Deatils of Gas Turbine Engine:
The gas turbine engine is a modern engineering marvel that is frequently overlooked. It has not only significantly shrunk the world, but it has done so in a cost-effective and safe manner.
There are no intuitive or common sense features at the outset. The modern engine is a jumble of disparate parts that appear to contradict one another. A compressor that moves incoming air in the direction of a pressure gradient. A combustor that increases flow while maintaining pressure. A turbine with compressor air cooling the blades.
There is nothing in nature that compares. It was created solely through the study and advancement of physics. It has profoundly altered the world and will continue to do so for decades to come.
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assessment of advanced rans models ability to predict a turbulent swept liquid metal flow over a wire in a channel
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Advanced Reynolds Averaged Navier Stokes (RANS) models have been extensively used in predicting complex turbulent flow in a variety of engineering applications.
This paper presents an assessment of advanced RANS models ability to predict a turbulent swept liquid metal flow over a wire in a channel.
The chosen case is representative of a range of practical engineering applications such as nuclear power reactors and liquid metal batteries.
The numerical simulations are carried out using the commercial finite-volume CFD software ANSYS Fluent. Four different turbulence models were employed in the simulations: the standard k-ε, shear stress transport (SST), realizable k-ε, and Reynolds stress model (RSM).
The numerical simulations were conducted on a fully swept turbulent liquid metal flow over a wire in a channel at Reynolds number 2400. Results of the numerical simulations were compared with the experimental data from previous research work.The results indicated that the SST turbulence model provided the best overall prediction of the liquid metal flow over a wire in a channel.
The SST model was found to be the most capable of capturing the complex physics involved in the flow, including separation, reattachment, and turbulence anisotropy. The standard k-ε model provided the poorest predictions, indicating the need for more advanced turbulence models to be employed in such applications.
Overall, the study has shown that advanced RANS models, particularly the SST model, are capable of providing accurate predictions of complex turbulent flow over a wire in a channel.
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A large plane wall has a thickness L=50 cm and thermal conductivity k = 25 W/m. K. On the left surface (x = 0), it is subjected to a uniform heat flux q_0 while the surface temperature T_0 is constant. On the right surface, it experiences convection and radiation heat transfer while the surface temperature is T_6 =225 degree C and the surroanding temperature is 25 degree C. The emissivity and the convection heat transfer coefficient on the right surface are 0. 7 and 15 W/m^2. K, respectively, (a) Obtain the variation of temperature in the wall (T(x) in terms of Also determine the value of heat flux (q_n) and the temperature of the left surface of the wall (at x = 0)
Answers
The variation of temperature in the wall is T(x)= (q_0x) /(kL) + T_0. The heat flux q_n is -28.1 W/m^2 and the temperature of the left surface of the wall is T_0 = 300 degree C.
B. To obtain the variation of temperature in the wall, we need to use the heat conduction equation, which states that the rate of heat flow through a solid is proportional to the temperature gradient.
The equation is given by q_x = -kdT/dx. Since we know the heat flux q_0 at the left surface, we can integrate this equation from x = 0 to x = L to obtain the temperature distribution T(x) in terms of q_0 and the thermal conductivity k.
On the right surface, we can use the equation for heat transfer by convection and radiation, which is given by
q_n = h(T_6 - T_surrounding) + esigma(T_6^4 - T_surrounding^4)
where h is the convection heat transfer coefficient, e is the emissivity, sigma is the Stefan-Boltzmann constant, T_6 is the surface temperature and T_surrounding is the surrounding temperature.
Plugging in the given values we can find out the value of heat flux q_n and the temperature of the left surface of the wall (at x = 0).
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What is the advantage of having the engine in the front of the car?
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For starters, most vehicles are front-wheel drive (FWD), so it makes sense to have the engine over the wheels that need traction. This makes the vehicle much more stable, and also helps maintain a relatively balanced weight distribution when accelerating.
The use of a front motor offers two main advantages: better engine cooling and more uniform weight distribution.
What are the advantage of having an engine in the front of the car?
In this problem we have the case of a car, whose motor is in the front of the car. Now we proceed to summarize advantages of a front motor:
Engine cooling - Better cooling of the engine, especially in critical parts such as radiators. Less risk of overheating.Weight distribution - Offers a more uniform mass distribution in the vehicle, critical when car accelerates.To learn more more on cars: https://brainly.com/question/33357158
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B/ Evaluate e^(πi/2)
Answers
You get a result immediately from Euler's formula:
e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i
Find the velocity and rate of flow of water through a rectangular channel of 6m wide and 3m deep when it's running full. The channel is having a bed slope of 1 in 2000. Take Chezy's coefficient, C=55
Answers
Answer:
V = 1.5062 m/s
Explanation:
look to the photos
A car manufacturing company decides to open a bid for a new part they need to install in order to improve the efficiency of the brakes. Multiple choices were available in the market. Knowing that: Time is important, technical expertise is required, the costs of the available parts are somewhat similar, and marketability is somewhat important. You can conclude that this is a: O a PMD and PED are easily distinguished by using the line-drawing technique O b. PMD/PED non-paradigmatic case Oc PMD Od. PED
Answers
A car manufacturing company decides to open a bid for a new part they need to install in order to improve the efficiency of the brakes. We can conclude that this is a PMD/PED non-paradigmatic case. The correct option is b.
A choice that should be made by engineers, or at the very least in accordance with professional engineering standards, is known as "proper engineering design" (PED). A choice that should be made by managers, or at the very least be controlled by management, is known as proper management design (PMD).
PED, or proper engineering decision. A decision should be made by engineers or at the very least follow professional engineering standards for a number of reasons, including: Involving complex technological issues that call for engineering knowledge and Adheres to the moral principles reflected in engineering codes, particularly those that demand engineers to safeguard the public's health and safety.
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are bonded to the system grounding conductor to provide a low impedance path for fault current that will facilitate the operation of over current devices underground fault conditions.
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In order to clear the ground fault, the system bonding jumper offers a low-impedance fault-current path to the electrical supply source.
It refers to service entry equipment and its connected and interconnected parts; in other words, one system conductor is grounded to stabilize the voltage to grounding during normal operation and to reduce voltages caused by lights, line surges, or unintended contact with higher voltage lines. The primary function of this wire is to guarantee the provision of a low-impedance conduit for ground-fault current to return to the utility supply transformer or source and to permit overcurrent device operation during a ground-fault occurrence. When the Code refers to a "low impedance path," The key concept is low opposition or impedance; it refers to a conduit for current to travel on that gives less resistance to current flow, whether it be fault current or normal current.
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17 Which is a key factor that has contributed to the growth and popularity of big data wered urol Select one: a. Mobile and wireless technology b. Implosion in data growth c. Brick and mortar businesses d. Exponential decay of organizational data
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The key factor that has contributed to the growth and popularity of big data is the implosion in data growth.
The growth and popularity of big data can be largely attributed to the implosion in data growth. The continuous advancement of technology, particularly mobile and wireless technology, has led to an exponential increase in the amount of data being generated and collected.
Mobile devices, such as smartphones and tablets, have become ubiquitous in today's society, enabling people to create and consume vast amounts of data on a daily basis. These devices are equipped with various sensors, cameras, and applications that generate data related to users' activities, preferences, locations, and more. Additionally, the widespread adoption of wireless connectivity has made it easier to capture and transmit data in real-time.
The implosion in data growth has revolutionized the way organizations operate and make decisions. The availability of large volumes of data has opened up new possibilities for data-driven insights, predictive analytics, and business intelligence. Companies can now analyze vast datasets to uncover patterns, trends, and correlations that were previously hidden. This has led to improvements in customer experiences, targeted marketing strategies, operational efficiencies, and innovation in various industries.
In summary, the implosion in data growth, driven by mobile and wireless technology, has played a significant role in the growth and popularity of big data, enabling organizations to harness the power of data for decision-making and competitive advantage.
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road crown is being discussed. technician a adds slightly more negative caster on the left side to compensate. technician b adds slightly more positive camber on the right side. who is correct?
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Problems with tire wear result from improper caster angles. The vehicle steers toward the side with more caster when the caster angles are not equal.
Tire tread wear with a one-sided shoulder signifies that the inner or outside shoulder rib is much more worn than the other ribs. This type of wear, also known as camber wear, frequently results from excessive positive or negative camber. The caster angle is positive if the steering axis tilts rearward, which means that the upper ball joint or strut mounting point is in front of the lower ball joint. The caster angle is negative if the steering axis tilts forward.
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difference between theory and practice?
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Answer:
There is a huge difference between theory vs. practice. Theory assumes an outcome, while practice allows you to test the theory and see if it is accurate.
Theory and Practice Explained
Practice is the observation of disparate concepts (or a phenomenon) that needs explanation. A theory is a proposed explanation of the relationship between two or more concepts, or an explanation for how/why a phenomenon occurs.
which professional uses practical knowledge of science to design and manufacture machines? engineer experimental scientist technician theoretical scientist
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Engineers - professionals who apply scientific knowledge to design and manufacture machines.
We have,
Engineers are professionals who use their practical knowledge of science, mathematics, and technology to design, develop, and manufacture machines, systems, and structures.
They apply scientific principles and theories to create practical solutions for various industries and sectors.
Engineers utilize their expertise to design, analyze, and improve machines, ensuring they meet specific requirements, functionality, safety standards, and efficiency.
They consider factors such as materials, cost-effectiveness, environmental impact, and feasibility while designing and manufacturing machines.
Overall, engineers combine scientific knowledge with practical skills to innovate and create technology and machinery that serves various purposes in society.
Thus,
Engineers - professionals who apply scientific knowledge to design and manufacture machines.
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Milton has been tracking the migrating patterns of whales in the northwest Atlantic Ocean for five years. He knows where and when to find them as well as how quickly they move. Which qualification makes Milton successful in his research?
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Answer:
knowledge of animal behavior and anatomy
Explanation:
the qualification that will make Milton successful in his research is a knowledge of animal behaviour and also their anatomy. the knowledge of whales behaviour has opened his eyes into their world so he knows to a great deal about them. it is through his knowledge of the behaviour of whales that he's able to get used to their migrating patterns to know where and when to find them. Also, through the body anatomy of whales he knows what their movement is like.
Answer:
knowledge of animal behavior and anatomy
Rt = R1 + R2 + R3
\( \frac{1}{rt} = \frac{1}{r1} + \frac{1}{r2} + \frac{1}{r3} \)
If R1 = 4Ω , R2 = 6Ω and R3 = 8Ω (Ω= ohm)
Calculate: 4.1.1 Rt (series)
4.1.2 Rt (parallel)
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Answer:
In series:
\( \frac{1}{r} = \frac{1}{r_{1} } + \frac{1}{r _{2} } + \frac{1}{r_{3} } \)
\( \frac{1}{r} = \frac{1}{4} + \frac{1}{6} + \frac{1}{8} \\ \\ \frac{1}{r} = \frac{13}{24} \\ \\ r = \frac{24}{13} \\ { \underline{r = 1.85 \: Ω}}\)
In parallel:
\(r = r _{1} + r _{2} + r _{3} \\ r = 4 + 6 + 8 \\ r = 18Ω\)
list the way of similerite and differ bitween magnetic field and electric field
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Similarities between magnetic field and electric field:Both magnetic fields and electric fields are fundamental concepts in electromagnetism.They are both vector fields, meaning they have both magnitude and direction.
Both fields are produced by a source. Electric fields are produced by electric charges, while magnetic fields are produced by moving charges (currents) or changing electric fieldsBoth fields exhibit the property of superposition, meaning that the total field at a point is the vector sum of the individual fields produced by each source.Both fields obey the principle of inverse square law, which states that the strength of the field decreases with the square of the distance from the source.Differences between magnetic field and electric field:Electric fields are produced by stationary electric charges, while magnetic fields are produced by moving electric charges or changing electric fields.
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