PLEASE HELP 45 POINTS + BRAINLIEST
please help, this is for chemistry and i've been absent a lot. this is due tomorrow
begging for help.
please show work for all questions
1.) How many moles of neon are in 7.53 x 10^23 atoms of neon?
2.) How many moles on tungsten are in 6.31 x 10^24 atoms of tungsten?
3.) How many atoms of hydrogen are in 54 grams of water?
4.) How many grams are in 12.3 moles of dinitrogen pentoxide?
5.) What is the molar mass of carbon dioxide?
6.) How many grams are in 0.87 moles of aluminum oxide?
7.) How many moles are in 6 L of hydrogen gas at STP?
8.) How many liters are in 10.26 moles of neon at STP?
9.) When a wasp stings you, it releases into the wound histamine (C5H9N3) which causes an allergic reaction. Assuming a threshold of 3.4 x 1015 molecules of histamine are necessary to cause a reaction, is a human at risk of a reaction if they were stung with a 0.00056-gram amount of histamine?
10.) A compound is composed of 23.3% magnesium, 30.7% sulfur, and 46.0% oxygen. What is its empirical formula?
1. 7.53 x 10^23 moles of neon.
2. 6.31 x 10^24 atoms of tungsten is equal to 1 mole of tungsten.
3. In 54 grams of water, there are approximately 4.5 x 10^23 atoms of hydrogen.
4. How many grams are in 12.3 moles of dinitrogen pentoxide?
5. The molar mass of carbon dioxide is 44.01 g/mol.
6. Aluminum oxide has a molar mass of 101.96 g/mol. Therefore, 0.87 moles of aluminum oxide would be 87.17 g.
7. At STP (standard temperature and pressure), 6 L of hydrogen gas contains 0.024 moles of hydrogen.
8. At STP, 10.26 moles of neon will occupy a volume of 24.03 liters.
9.
No, a human is not at risk of a reaction if they were stung with a 0.00056-gram amount of histamine. 0.00056 grams of histamine is only 8.64 x 1010 molecules, which is far less than the threshold of 3.4 x 1015 molecules necessary to cause a reaction.
10. MgS2O6
i gotchu bro here you go
Name a property of liquids that they do not share with solids.
Answer:
a solid has definite volume and shape, a liquid has definite volume but no definite shape, and a gas has neither a definite volume nor shape the change from solid to liquid usually does not significantly change the volume of a substance
after ten years, 75 grams remain of a sample that was
originally 100 grams of some unknown radio isotope. find the half
life for this radio isotope
The half-life of the radioisotope, calculated based on the given information that after ten years only 75 grams remain from an initial 100 grams, is approximately 28.97 years.
To find the half-life of the radioisotope, we can use the formula for exponential decay:
N(t) = N₀ × (1/2)^(t / T₁/₂)
T₁/₂ is the half-life of the substance.
In this case, we know that the initial amount N₀ is 100 grams, and after ten years (t = 10), 75 grams remain (N(t) = 75 grams).
We can plug these values into the equation and solve for T₁/₂:
75 = 100 × (1/2)^(10 / T₁/₂)
Dividing both sides of the equation by 100:
0.75 = (1/2)^(10 / T₁/₂)
Taking the logarithm (base 2) of both sides to isolate the exponent:
log₂(0.75) = (10 / T₁/₂) × log₂(1/2)
Using the property log₂(a^b) = b × log₂(a):
log₂(0.75) = -10 / T₁/₂
Rearranging the equation:
T₁/₂ = -10 / log₂(0.75)
Using a calculator to evaluate the logarithm and perform the division:
T₁/₂ ≈ 29.13 years
Therefore, the half-life of the radioisotope is approximately 28.97 years.
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How do we classify a solution that has many ions in solution and turns pH paper orange?
A solution that has many ions in solution and turns pH paper orange is likely to be an acidic solution with a pH between 3 and 5.
The presence of many ions in solution indicates that the solution is likely to be a strong electrolyte, meaning that it contains a high concentration of ions that dissociate completely in water.
This could be due to the presence of a strong acid or a strong salt in the solution. The orange color on the pH paper indicates that the solution has a pH in the acidic range, which is consistent with the high concentration of H+ ions in an acidic solution.
Therefore, the solution can be classified as a strong acidic solution.
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Electric field lines /Conductor/ Electroscope/ Insulator Elementary charge/ Electric field/ Charging by conduction/ Charging by induction/ Potential difference
1. Separation of charges in an object without touching it is____________.
2. The work done moving a positive test charge between two points in an electric field divided by the magnitude of the test charge is the electric _________.
3. An electric __________ is a material through which charges move about easily. ___________ is giving a neutral object a charge by touching it with a charged object.
4. A material through which electrical charges does not move easily is an electrical _____.
5. The lines providing a picture of the size and strength of the field around a charged object are called the ________.
6. The property of the space around a charged object that exerts a force on other charged objects is the ______.
7. A device that helps determine charge using pieces of metal foil is a(n) _______.
8. The magnitude of the charge of an electron is the ________.
Answer: See explanation
Explanation:
1. Separation of charges in an object without touching it is (charging by induction).
2. The work done moving a positive test charge between two points in an electric field divided by the magnitude of the test charge is the electric (potential difference).
3. An electric (conductor) is a material through which charges move about easily. (Charging by conduction) is giving a neutral object a charge by touching it with a charged object.
4. A material through which electrical charges does not move easily is an electrical (insulator).
5. The lines providing a picture of the size and strength of the field around a charged object are called the (electric field lines).
6. The property of the space around a charged object that exerts a force on other charged objects is the (electric field).
7. A device that helps determine charge using pieces of metal foil is an (electroscope).
8. The magnitude of the charge of an electron is the (elementary charge)
right
a force of 20 newtons (N).
Mass 10 kg
Force
20 N
22. Using the equation below, calculate the acceleration of
the cart in meters per second squared (m/s 2)
Force = Mass X Acceleration
m/s 2
Question 11
Which formula represents a hydrocarbon?
C₂H6
C₂H5OH
C₂H5Cl
C₂H6O
Answer:
C₂H6
Explanation:
Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). Option A
A hydrocarbon is a compound that consists of only carbon and hydrogen atoms. It is important to identify the formula that represents a hydrocarbon among the given options:
A) C₂H6: This formula represents ethane, which is a hydrocarbon. Ethane consists of two carbon atoms bonded together with single bonds and six hydrogen atoms.
B) C₂H5OH: This formula represents ethanol, which is not a hydrocarbon. Ethanol contains a hydroxyl group (-OH), indicating the presence of oxygen in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.
C) C₂H5Cl: This formula represents ethyl chloride, which is not a hydrocarbon. Ethyl chloride contains a chlorine atom (Cl) in addition to carbon and hydrogen atoms. It is a haloalkane, not a hydrocarbon.
D) C₂H6O: This formula represents ethanol, which, as mentioned before, is not a hydrocarbon. Ethanol contains an oxygen atom (O) in addition to carbon and hydrogen atoms. It is an alcohol, not a hydrocarbon.
Among the given options, the formula A) C₂H6 represents a hydrocarbon (specifically, ethane). It consists only of carbon and hydrogen atoms, making it a suitable representation of a hydrocarbon.
In summary, the formula C₂H6 (option A) represents a hydrocarbon, while the other options contain additional elements (oxygen or chlorine) that make them non-hydrocarbon compounds. Option A
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A 5.0 mole sample of gas has 54 mmHg of pressure at 273K. What is the volume of the gas?
(Round your answer to the correct number of significant figures)
Answer:
here's the answer hope it helps
Suppose the formation of nitrogen dioxide proceeds by the following mechanism step elementary reaction rate constant Suppose also ktxk,. That is, the first step is much slower than the second Write the balanced chemical equation for the overall chemical reaction: 2N0(g) +02(g ? 2NO2(g) Write the experimentally- observable rate law for the overall chemical reaction rate = k [2NO] Note: your answer should not containthe concentrations of any intermediates Express the rate constant kfor the overall chemical reaction in terms of k1, k2,and (if necessary) the rate | k = 2N constants k. 1 and k-2for the reverse of the two elementary reactions in the mechanism
The slowest step in a reaction mechanism is known as the rate-determining step. The rate-determining step limits the overall rate and therefore determines the rate law for the overall reaction.
Overall reaction equation:
2NO (g) + O2(g) ---------> 2NO2(g)
Overall rate= k1 [NO]^2
Overall reaction equation:
2NO (g) + O2(g) ---------> 2NO2(g)
The overall reaction equation is obtained by adding the two equations. This now gives the actual overall equations when intermediates must have been cancelled out.
Since k1<<k2 which me as that the first step is much slower than the second step, then the first step is the rate determining step, being the slowest step in the non elementary reaction sequence.
Therefore overall rate;
Overall rate= k1 [NO]^2
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Li²O, # of Elements and Atoms
Answer:Lithium atomic orbital and chemical bonding information. There are also tutorials on the first thirty-six elements of the periodic table includes: Li²O
After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone. Use the information from the diagram to answer. In which crash did the cone experience a stronger force? How do you know?
The crash where the cone experience a stronger force is option D because: Crash 1: the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.
Does it take a stronger force to slow something down?The ball is drawn back to Earth by gravitational force. The ball returns to Earth as a result of friction. The ball is forced back toward Earth by magnetic force.
A puck's velocity changes when a player makes contact with it when it is still. He causes the puck to speed up, in other terms. The hockey stick's force, which causes the acceleration, is responsible. The velocity grows as long as this force is in motion.
Therefore, the force applied to an object must be larger than what is required for a progressive slowing down if the object must be slowed down quickly. For instance, a bicycle's brakes will slow or stop it more quickly the more force is given to it.
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See full question below
After hockey practice, Carissa and Keenan were playing a game where they were pushing some objects to get them to crash. They were using a cone and two different pucks—a black one with more mass for Crash 1 and a blue one with less mass for Crash 2. They want to know what happened to the cone.
Use the information from the diagram to answer.
In which crash did the cone experience a stronger force? How do you know?
answer choices
There was no force on the cone. In both crashes, only the hockey puck experienced a force.
The diagram doesn’t tell you anything about the force on the cone. It only gives information about the force on the pucks.
It was the same force in both crashes; the hockey puck changed speed by the same amount in each crash, so the force on the cone was the same each time.
Crash 1; the force on the black hockey puck was stronger in this crash, so the force on the cone was also stronger.
For the balanced equation shown below, how many moles of O₂ will be produced, if 0.7784 moles of H₂O are produced? 2C4H10O2 + 1102-8CO2 + 10H₂0
0.85moles of O₂ will be produced, if 0.7784 moles of H₂O are produced for the given balanced equation.
What is balanced equation?A balanced equation is indeed a chemical reaction equation in which the overall charge and the amount of atoms for every element inside the reaction are the same for both the products and the reactants.
In these other terms, the mass as well as charge along both sides of both the reaction are balanced.
2C\(_4\)H\(_{10}\)O\(_2\)+ 11O\(_2\)→ 8CO\(_2\) + 10H₂O
moles of H₂O =0.7784 moles
the mole ratio between O\(_2\) and H₂O is 11:10
moles of O\(_2\) = (11/10)×0.7784 =0.85moles
Therefore, 0.85moles of O₂ will be produced, if 0.7784 moles of H₂O are produced.
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What is the standard reduction potential, E, for the half-reaction Al3+ (aq)
3e- -> Al(s)?
Answer:
E° = -1.66 V
Explanation:
The standard reduction potential is also known as the standard electrode potentials and it tries to find the probability that an element will be reduced or undergo reduction.
From activation series online showing the standard reduction potentials for half cells, the standard reduction potential of Al3+ (aq) + 3e- -> Al(s) is;
E° = -1.66 V
A
The reaction below is exothermic.
3C + 4H₂ = C3H8
What is the correct way to write the
thermochemical equation?
Energy + 3C + 4H₂ = C3H8
3C + 4H2 C3H8 + Energy
The correct way to write the thermochemical equation for the given exothermic reaction is: \(C_3H_8\)= 3C + 4H₂ + Energy Option A
In a thermochemical equation, the energy term is typically written on the product side of the equation. This is because in an exothermic reaction, energy is released as a product. The product side of the equation represents the lower-energy state of the system after the reaction has occurred.
In the given reaction, propane (\(C_3H_8\)) is the product, and energy is released during its formation. Therefore, the correct representation of the thermochemical equation is \(C_3H_8\) = 3C + 4H₂ + Energy.
Option B) 3C + 4H2 \(C_3H_8\) + Energy is incorrect because it incorrectly places the energy term on the reactant side of the equation. The energy term should always be placed on the product side to indicate the energy released during the exothermic reaction.
Option A) Energy + 3C + 4H₂ = \(C_3H_8\) is also incorrect because it places the energy term at the beginning of the equation. The energy term should be placed after the products to signify that it is released during the reaction, rather than being consumed.
Therefore, the correct way to write the thermochemical equation for the given exothermic reaction is \(C_3H_8\) = 3C + 4H₂ + Energy Option A
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1) If I have 4 moles of a gas at a pressure of 5.6 atm and a volume of 12 liters, what is the temperature?
Answer:
204.8 K
Explanation:
We use the ideal gas equation:
PV = nRT
where R is the gas constant (0.082 L.atm/K.mol).
We have the following data:
n= 4 moles
P = 5.6 atm
V = 12 L
So, we introduce the data in the ideal gas equation to calculate the temperature (T):
T = PV/nR = (5.6 atm x 12 L)/(4 mol x 0.082 L.atm/K.mol) = 204.8 K ≅ -68 °C
Answer: 204.63 K
Explanation: Because it makes the most sense
when you receive fluid in the hospital, it is often 0.9% saline solution. what would happen if the nurse used distilled water instead?
Answer:
The distilled water solution would be hypotonic to your blood cells, so they would gain water, swell, and possibly burst.
a gaseous mixture of oxygen and nitrogen is maintained at a constant temperature. which of the following must be true regarding the two gases? (1 point)
Answer:
When a gaseous mixture of oxygen and nitrogen is maintained at a constant temperature, the following statements must be true regarding the two gases:
Each gas will have its own partial pressure: In a mixture of gases, each gas exerts a pressure known as its partial pressure. This means that oxygen and nitrogen will have their respective partial pressures in the mixture.
The total pressure of the mixture is the sum of the partial pressures: According to Dalton's law of partial pressures, the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each gas in the mixture. Therefore, the total pressure of the oxygen-nitrogen mixture will be the sum of the partial pressures of oxygen and nitrogen.
The ratio of the partial pressures remains constant: At a constant temperature, the ratio of the partial pressures of oxygen and nitrogen will remain the same, provided the composition of the mixture remains unchanged. This is known as Dalton's law of partial pressures.
It's important to note that the specific properties and behaviors of oxygen and nitrogen can vary in different situations, but the above statements hold true for a gaseous mixture of oxygen and nitrogen at a constant temperature.
If we start with 1.000g of strontium 90 0.953 grams will remain after 2.0 years (a) what is the half life of strontium 90 (b) how much strontium 90 will remain after 5.00 years Please show the necessary step
Answer:
a) 29.0 years
b) 0.89 g
Explanation:
Using the formula
t1/2= t×ln2/ln(No/Nt)
Where
Nt= mass of radioactive isotope at time= t =0.953g
No= initial mass of radioactive isotope present= 1.000g
t= time taken for N mass of radioactive isotope to remain = 2 years
t1/2 = half-life of radioactive isotope= ???
Substituting the values
t1/2= 2 × ln2/ln(1.000/0.953)
t1/2= 2× 0.693/0.048
t1/2= 29 hours
b)
N= No(1/2)^t/t1/2
Where t= 5 years
N= 1.000(1/2)^5/29
N= 1.000(1/2)^0.17
N= 0.89g
A molecule in which central atom has 12 electrons after sharing.
Answer:
SF6
Explanation:
Octet Rule
The central atom covalent bounds with 6 flourine atoms.
4. When the speed of the following water increases it cuts into the
surface of the soil.
O Soil erosion
O Sheet erosion
Rill erosion
O Gully erosion
Answer:
Option 1, Soil erosion
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quzilet what are the carbon cycle processes that control the annual rise and fall or carbon dioxide in the mauna loa (keeling) curve?
The carbon cycle processes that control the annual rise and fall of carbon dioxide in the Mauna Loa (Keeling) curve are photosynthesis, respiration, and decomposition. The carbon cycle is the process by which carbon dioxide enters and exits the Earth's atmosphere.
Carbon dioxide is a gas that aids in the retention of heat in the Earth's atmosphere, contributing to global warming. Carbon dioxide is consumed by plants during photosynthesis and then released back into the atmosphere through respiration and decomposition.
The carbon cycle can be broken down into four main steps: photosynthesis, respiration, decomposition, and combustion. Photosynthesis is the process by which plants consume carbon dioxide and sunlight to generate glucose, which is used as food. Oxygen is released as a byproduct of photosynthesis.
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if the temperature of a radiator is increased from 27ºc to 54ºc, by what factor does the radiating power change?
The power radiated by the radiator changes by a factor of 14.1573 when the temperature is increased from 27°C to 54°C.
The formula that relates the power radiated by an object with the fourth power of the temperature is known as the Stefan-Boltzmann Law. It is stated as follows: P = σA(T⁴), where P is the power radiated, σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴), A is the surface area of the radiator, and T is the temperature in Kelvin.
We must first convert the temperature to Kelvin:
TK = T°C + 273.15
TK1 = 27°C + 273.15 = 300.15 K
TK2 = 54°C + 273.15 = 327.15 K
The factor by which the power radiated changes is the ratio of the power at the new temperature to the power at the original temperature. The equation is as follows:
P2/P1 = (T2/T1)⁴
Substituting the given values:
P2/P1 = (327.15/300.15)⁴
P2/P1 = 1.8856⁴
P2/P1 = 14.1573
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according to solubility rules, which compound should not dissolve in water?
According to solubility rules, water insoluble compound should not dissolve in water.
What is solubility?Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.
The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.
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Identify the element(give it's symbol) from the following information: a. an element with a completely filled 4p orbital and 9 valence electrons b. an element with a completely filled d orbital and 6 valence electrons c. an element with a partially filled d-orbtial, no f-orbital and 6 valence electrons
Identifying the elements:
a. an element with a completely filled 4p orbital and 9 valence electrons is Rh.b. an element with a completely filled d orbital and 6 valence electrons is Se.c. an element with a partially filled d-orbtial, no f-orbital and 6 valence electrons is Cr.A chemical compound that cannot be converted into another chemical substance is known as an element. Atoms are the fundamental building blocks of chemical elements. Each chemical element is identified by the atomic number, or the quantity of protons in its atoms' nucleus. For instance, the atomic number 8 of oxygen indicates that each oxygen atom's nucleus has 8 protons. As opposed to chemical compounds and mixtures, which include atoms with multiple atomic numbers, this is not the case.
The majority of the universe's baryonic stuff is made up of chemical elements; neutron stars are one of the very few exceptions. Atoms are rearranged into new compounds linked together by chemical bonds when various elements undergo chemical reactions. A small number of relatively pure native element minerals, including silver and gold, are discovered uncombined. Nearly every other element that exists naturally on Earth is found in compounds or mixtures. Although it does contain other substances like carbon dioxide and water, the main constituents of air are the elements nitrogen, oxygen, and argon.
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A 35.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1272 M KOH solution. A volume of 42.22 mL of KOH was required to reach the equivalence point.
The concentration of the H2SO4 solution is 0.1466 mol/L.
In this problem, we are given information about the titration of an H2SO4 solution with an unknown concentration using a 0.1222 M KOH solution. At the equivalence point, the moles of H2SO4 will be equal to the moles of KOH. We can use this fact to determine the concentration of the H2SO4 solution.
First, we need to determine the number of moles of KOH that reacted with the H2SO4 solution. We can do this using the concentration of the KOH solution and the volume of KOH used:
moles of KOH = concentration of KOH × volume of KOH used
moles of KOH = 0.1222 mol/L × 0.04222 L
moles of KOH = 0.00516 mol
At the equivalence point, the number of moles of KOH will be equal to the number of moles of H2SO4. Since we know the volume of the H2SO4 solution used (35.00 mL), we can calculate the concentration of the H2SO4 solution:
moles of H2SO4 = moles of KOH
concentration of H2SO4 × volume of H2SO4 = concentration of KOH × volume of KOH used
concentration of H2SO4 = (concentration of KOH × volume of KOH used) / volume of H2SO4
concentration of H2SO4 = (0.1222 mol/L × 0.04222 L) / 0.03500 L
concentration of H2SO4 = 0.1466 mol/L
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COMPLETE QUESTION
A 35.00 mL sample of an H2SO4 solution of unknown concentration is titrated with a 0.1222 M KOH solution. A volume of 42.22 mL of KOH was required to reach the equivalence point. Need to find concentration for H2SO4
in a constant-volume process, 208 J of energy is transferred by heat to 1.04 mol of an ideal monatomic gas initially at 294 K. (a) Find the work done on the gas. ) (b) Find the increase in internal energy of the gas. J (c) Find its final temperature. K
Therefore, the final temperature of the gas is 311.7 K.
Given data:
Number of moles (n) = 1.04
Ideal monatomic gas
Transfer of heat (Q) = 208 J
Initial temperature (T1) = 294 K
To find:
(a) Work done by the gas
(b) Increase in internal energy of the gas
(c) Final temperature of the gas
(a) Work done by the gas
When a gas undergoes a constant-volume process, then the work done by the gas is given as:
W = 0
Here, since the volume of the gas remains constant, the work done on the gas is 0.
(b) Increase in internal energy of the gas
The increase in internal energy of the gas is given by the formula:
ΔU = Q
Since the heat energy is transferred to the gas, therefore ΔU = 208 J.
(c) Final temperature of the gas
To find the final temperature of the gas, we can use the following formula which relates the energy transferred, the number of moles and the change in temperature:
Q = nCvΔT
Here,Cv = Specific heat at constant volume of an ideal monatomic gas = 3/2 RΔT
= Change in temperature
Final temperature = T2
= T1 + ΔT
Putting all the values in the above formula we get:
ΔT = Q/nCvΔT
= (208 J)/(1.04 mol × 3/2 R)ΔT
= (208 J)/(1.04 mol × 3/2 × 8.31 J/mol K)ΔT
= 17.7 K
Now, T2 = T1 + ΔTT2
= 294 K + 17.7 KT2
= 311.7 K
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The roller coaster is your favorite ride! But the line is always long! Having just studied potential and kinetic energy in physics, you evaluate the energy changes of the cars as they move on the tracks. Compare the potential energy of the cars if they are stopped at points A to point D.
The comparison of the potential energy of the cars if they are stopped at points A to point D is C. Potential energy is stored energy, point D is taller so it has more stored energy.
What is a potential energy?Potential energy is the energy held by an object as a result of its position relative to other objects, internal stresses, electric charge, or other factors. Because any object lifted from its resting position has stored energy, it is referred to as potential energy because it has the potential to do work when released.
Kinetic energy is the energy that an object has as a result of its movement. If we want to accelerate an object, we must apply force to it. Using force requires us to put in effort. After work is completed, energy is transferred to the object, and the object moves at a new constant speed.
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The roller coaster is your favorite ride! but the line is always long! having just studied potential and kinetic energy in physics, you evaluate the energy changes of the cars as they move on the tracks. Compare the potential energy of the cars if they are stopped at points A to point D.
A. Neither have potential energy.
B. The potential energy is the same.
C. Potential energy is greatest at point D.
D. Potential energy is greatest at point A.
why is it a problem of habitat destruction?
Answer:
because he must be not healthy person
Answer:
people find that 5hey are self sabotaging them selves to move forward
someone explain it plz
Only possible with alkaline earth metals
Let's see an example
\(\\ \sf\longmapsto X(OH)_2\)
X belongs to group || i.e alkaline earth metalsThe elements are
Magnesium (Mg)Calcium (Ca)Beryllium(Be)Scandium(Sc)Barium (Ba)Renedium (Rn)Option C is correct
\(\rule{300pt}{1000000pt}\)