In this scenario, a refrigerator is being used to maintain a refrigerated space at a temperature of -30 degrees. The working fluid used in the refrigerator is refrigerant-134a. The waste heat generated by the refrigerator is rejected to cooling water that enters the condenser at 18 degrees and leaves at 26 degrees, with a flow rate of 0.25 kg/s.
The refrigerant enters the condenser at 1.2 MPa and 65 degrees and leaves at 42 degrees. The compressor, on the other hand, has an inlet state of 60 kPa and -34 degrees. It is estimated that the compressor gains a net heat of 450 W from the surroundings.
To maintain the refrigerated space at -30 degrees, the refrigerator needs to remove heat from the refrigerated space and reject it to the cooling water in the condenser. The compressor then compresses the refrigerant to a higher pressure and temperature, which releases heat to the surroundings. This heat is estimated to be 450 W.
Overall, this system operates on the principle of heat transfer and thermodynamics, with the refrigerant being the working fluid that transfers heat from the refrigerated space to the surroundings. The efficiency of the system can be improved by optimizing the compressor and the heat transfer in the condenser.
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The Ksp for Ag2CrO4 is 9.0 x 10-12. If 200 mL of 0.0050 M AgNO3 is combined with 300 mL of 0.0020 M K2CrO4, will a precipitate form?
Answer:
Qsp > ksp
Explanation:
given data
Ag2CrO4 = 9.0 × \(10^{-12}\)
solution
new [\(Ag^+\)] = \(\frac{0.005 \times 200}{200+300}\) = 0.002 M .................1
and
new [\(CrO^{2-}_4\)] = \(\frac{0.002 \times 300}{200+300}\) = 0.0012M ..............2
so here solubility equation will be as
\(Ag_2CrO_4(s)\) ⇄ 2\(Ag^+\) (aq) + \(CrO^{2-}_4\) (aq) ......................3
so
Qsp = \([Ag^+]^2\) [ \(CrO^{2-}_4\)]
put here value
Qsp = (0.002)² × (0.0012)
Qsp = 4.80 × \(10^{-9}\)
so that we can say that Qsp > ksp
The force that keeps you from sliding on an icy
sidewalk is
Select one:
kinetic friction
normal force
weight
static friction
The force that keeps you from sliding on an icy sidewalk is static friction. Thus the correct option is D.
What is static friction?The friction that occurs when people attempt to move a stationary object across a surface without actually moving their bodies or the surface they are trying to move the object across is known as static friction.
Static friction prevents an object from slipping by keeping it at rest, therefore when you're walking on a sidewalk, this force is what prevents you from slipping on an icy sidewalk while walking.
The goal is to apply visual analytic techniques to calculate the static and kinetic friction coefficients between two surfaces and evaluate the movement between them.
Therefore, option D static friction is appropriate.
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A Contractor Has A Job Which Should Be Completed In 100 Days. At Present, He Has 80 Men On The Job And It Is Estimated That They Will Finish The Work In 130 Days. Of The 80 Men, 50 Are Each Paid ₱120.00 A Day, 25 At ₱180.00 A Day, And 5 At ₱250.00 A Day. For Each Day Beyond The Original 100 Days, A Contractor Has To Pay ₱500.00 Liquidated Damages.A) How Many
A contractor has a job which should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00 liquidated damages.
a) How many more men should the contactor add so that he would complete the work on time?
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine?
A contractor has a job that should be completed in 100 days. At present, he has 80 men on the job and it is estimated that they will finish the work in 130 days. Of the 80 men, 50 are each paid ₱120.00 a day, 25 at ₱180.00 a day, and 5 at ₱250.00 a day. For each day beyond the original 100 days, a contractor has to pay ₱500.00.
liquidated damages.(a) How many more men should the contractor add so that he would complete the work on time?In the first case, we see that the contractor already has 80 men and they are working for 130 days to complete the job. So, we can use the following formula to determine the additional number of workers required to finish the work in 100 days.
b) If of the additional men, 2 are paid ₱180.00 a day, and the rest at ₱120.00 a day, would the contractor save money by employing more men and not paying the fine Let’s assume that the contractor adds 440 workers, of which 2 are paid ₱180.00 a day and the rest are paid ₱120.00 a day.
The total cost of the new workers is, therefore, ₱9600.00 + ₱4500.00 + ₱49800.00 = ₱63,900.00.The cost of liquidated damages would be calculated as follows: $$LD = (130-100) \cdot 500 = ₱15,000.00$$.
Therefore, the contractor would save money if he employs more men and not pays the fine. The contractor’s savings would be:$$Savings = LD - Additional cost$$$$= 15000.00 - 63900.00 $$$$= -48900.00$$
Thus, we can see that the contractor would save ₱48,900.00 by employing more men and not paying the fine.
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A major contributor to product defects in electronic modules relates to stresses induced during thermal cycling (intermittent heating and cooling). For example, in circuit cards having active and passive components with materials of different thermal expansion coefficients, thermal stresses are the principal source of failure in component joints, such as soldered and wired connections. Although concern is generally for fatigue failure resulting from numerous excursions during the life of a product, it is possible to identify defective joints by performing accelerated thermal stress tests before the product is released to the customer. In such cases, it is important to achieve rapid thermal cycling to minimize disruption to production schedules.
A manufacturer of circuit cards wishes to develop an apparatus for imposing rapid thermal transients on the cards by subjecting them to forced convection characterized by a relation of the form Nuj = CRemPr", where m=0. 8 and n=0. 33. However, he does not know whether to use air (k = 0. 026 W/mK, v= 1. 6x105m²/s, Pr=0. 71) or a dielectric liquid (k=0. 064 W/m-K, v= 109 m²/s, Pr=25) as the working fluid. Assuming equivalent air and liquid velocities and validity of the lumped capacitance model for the components, obtain a quantitative estimate of the ratio of the thermal time constants for the two fluids.
Required:
What fluid provides the faster thermal response?
A manufacturer of circuit cards aims to develop an apparatus for subjecting them to rapid thermal transients using forced convection, characterized by the relation Nuj = CRemPr^m, where m = 0.8 and n = 0.33.
To achieve rapid thermal cycling and minimize disruption to production schedules, the manufacturer needs an apparatus that can impose controlled thermal stresses on the circuit cards. Forced convection, which involves the movement of fluid (air or liquid) over the surface of the cards, is an effective method for achieving rapid heat transfer.
The relation Nuj = CRemPr^m is a dimensionless correlation equation known as the Nusselt number correlation. It relates the Nusselt number (Nu) to the Reynolds number (Re) and the Prandtl number (Pr). The Nusselt number represents the convective heat transfer coefficient, which determines the rate of heat transfer between the fluid and the surface. The Reynolds number characterizes the flow regime, indicating whether the flow is laminar or turbulent, while the Prandtl number represents the ratio of momentum diffusivity to thermal diffusivity of the fluid.
In the given relation, the values of m = 0.8 and n = 0.33 determine the correlation exponents. These values have been determined through experimental data and are specific to the system being studied. The manufacturer needs to determine the appropriate values of the constant C based on the specific conditions and characteristics of their apparatus and circuit cards.
By using the Nuj = CRemPr^m relation, the manufacturer can design and optimize their thermal cycling apparatus to achieve the desired rapid thermal transients. This will allow them to perform accelerated thermal stress tests on the circuit cards, identifying any defective joints or potential failure points before the product is released to the customer. Implementing such tests in the manufacturing process will help ensure the reliability and quality of the electronic modules, reducing the risk of failures caused by thermal cycling-induced stresses.
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I need help with these 2 questions, I am not sure what the answer is and would like to know the solution to them.
Based on the code given , the Step 1 is done by enforcing maximum() and min() in ARM7 assembly while Step 2 is done by enforcing the main while circle in ARM7 assembly.
What is the code about?To apply the maximum() and min() functions in ARM7 assembly, we can use some instructions to optimize the law and code speed. There is one possible way to do it based on the image attached.
Therefore, To apply the main while loop, we need to check if the left over of the division between result and d isn't zero, and if so, add c to affect. We can use the SWI 0x6 instruction to gain the balance of the division.
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See text below
We will translate the following C function, which calculates the Lowest Common Multiple (1cm) between two positive numbers, into ARM7 assembly:
unsigned int lcm(unsigned int a, unsigned int b)
{
(unsigned int c, d, result; // cannot be translated)
c = max(a, b); // i.e. c-a if a >= b, otherwise c=b d = min(a, b); // same, but vice-versa
result = c;
while ((result % d) != 0) {
}
result = result + c;
}
(return(result);
// cannot be translated)
In doing so, you are asked to optimize the assembly code for execution speed. i.e., a) fewest number of cycles, taking into account pipeline emptying/refilling on branch instructions for example, and b) fewest number of instructions.
Disregard the first/last lines of the lcm() function, which cannot be translated into assembly. This exercise is broken into these two steps:
1. First, implement the two successive lines min() and max() in ARM7 assembly:
c = max(a, b); // i.e. c-a if a>=b, otherwise c=b
d = min(a, b); // same, but vice-versa
[Hint 1]: Remember that the function's arguments, a and b, will be found in registers r0 and rl respectively. Every other register is free for you to use in your code. Remember to use conditional instructions whenever possible, to optimize code density and execution speed.
2. Implement the main while loop in ARM7 assembly.
[Hint 2]: The remainder of a division (i.e., the “modulo” operation %) can be obtained by relying on the BIOS, using the ARM7 instruction: SWI 0x6 (which cannot be conditional) after placing the input in the appropriate, predefined registers (see lecture notes), which cannot be selected/changed, and reading the output from the appropriate register.
Remember to comment each line of your program to explain what your code does.
Describe the changes to the memory and the registers, after the execution of each of the following five load/store instructions in the (five-lined) program below (i.e.. these five instructions are run as a sequence from the initial memory state shown below).
We assume big endian formatting.
Initial Memory State 0x420014 DE OC 63 20 0x420010 FF AE 10 00 0x42000c 13 46
FA 08
0x420008 0x420004 0x420000
24 AB
A0
22
00 00 CO
FF
00 1C OE 3B
Initial Registers
State
r0=0x00000000, r1=0x00000000, r2=0x00420008, 13=0x00000007,
r4=0x00000001
# Start of the program
LDR
r0, [r2, #-4]
LDRB
r1, [r2, r3]
STR
r1, [2], r4 LSL #2
SWP
STMDA
r4, r0, [r2]
# End of the program
r2!, (r4, r3, r0}
Calculate the minimum area moment of inertia for a rectangular cross-section with side lengths 6 cm and 4 cm.
Answer:
Minimum area of rectangle = 24 cm²
Explanation:
Given:
Length of rectangle = 6 cm
Width of rectangle = 4 cm
Find:
Minimum area of rectangle
Computation:
Area of rectangle = Length of rectangle x Width of rectangle
Minimum area of rectangle = Length of rectangle x Width of rectangle
Minimum area of rectangle = 6 x 4
Minimum area of rectangle = 24 cm²
brake shoes stop a car by exerting pressure on the
Answer:
brake drums or rotors
Explanation:
When the brake pedal is pressed, hydraulic pressure is applied to the brake system which in turn forces the brake shoes to press against the drum or rotor, slowing down or stopping the car.
Brake shoes are a type of braking system used in some older vehicles and heavy-duty applications. They are typically made of metal and lined with friction material, such as asbestos or ceramic, which provides the necessary stopping force. Brake shoes stop a car by exerting pressure on the brake drum or rotor, which is located behind the wheel and rotates with the wheel. When the driver applies the brake pedal, the brake shoes are pushed against the drum or rotor, creating friction and slowing down the wheel. This slows down the car as a whole, allowing it to come to a stop. Proper maintenance and regular replacement of brake shoes are crucial for safe and reliable braking performance.
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A high compression ratio may result in;
A high compression ratio may result in compressor failure.
What is a compressor?A compressor refers to a mechanical device that is designed and developed to provide power to refrigerators, especially by increasing the pressure on air or other applicable gases.
According to heating, ventilation, and air conditioning (HVAC) information, a high compression ratio of 8: 1 or higher is most likely to result in compressor failure.
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when servicing piston rods and pins it is important to always
Answer:
Pistons should be inspected and measured.
Explanation:
Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
I'd say number 4, number 3 looks like an exhaust valve
Based on the hardness values determined in Part 1, what is the tensile strength (in MPa) for each of the alloys?
(a) 0.25 wt%C with spheroidite,
(b) 0.25 wt%C with coarse pearlite,
(c) 0.60 wt%C with fine pearlite, and
(d) 0.60 wt%C with coarse pearlite.
The tolerance to all answers is +/-10 %.
Answer:
a. 115
b. 135
c. 220
d. 185
Explanation:
Spheriodite is microscopic constituents in some steels which is composed of spherically shaped cementide particle. It is most ductile and softest type of steel. Pearlite is two phased lamellar compose of alternating layer of ferrite and cementite. It is hard and strong but not tough. It is applied on cutting tools like chopper, blades and knives.
Polarization: Unpolarized light passes through three ideal polarizing filters. The first filter is oriented with a horizontal transmission axis, the second one has its transmission axis at 30° from the horizontal, and the third filter has a vertical transmission axis. What percent of the light gets through this combination?
Answer:
the percentage of light that gets through this combination is 9.38
Explanation:
Given the data in the question;
Let us represent the incident unpolarized light with \(I_0\).
So, the amount of light intensity passing through the first polarizer will be;
\(I_1\) = \(I_0\) / 2 ------ let this be equation 1
An the amount of light intensity passing through the second polarizer will be;
\(I_2\) = \(I_1\)cos²θ
given that; the second one has its transmission axis at 30°
so, we substitute;
\(I_2\) = \(I_1\) × cos²( 30° )
\(I_2\) = \(I_1\) × 0.75
\(I_2\) = 0.75\(I_1\)
from equation; \(I_1\) = \(I_0\) / 2
\(I_2\) = 0.75( \(I_0\) / 2 )
\(I_2\) = 0.375\(I_0\) .
Now, the amount of light intensity passing through the third polarizer will be;
\(I_3\) = \(I_2\)cos² ( 90° - 30° )
\(I_3\) = \(I_2\) × cos²( 60° )
\(I_3\) = \(I_2\) × 0.25
we substitute
\(I_3\) = 0.375\(I_0\) × 0.25
\(I_3\) = 0.09375\(I_0\)
∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100
⇒ 9.38%
Therefore, the percentage of light that gets through this combination is 9.38
250 grams of ice at −25°C is put in a pot on a burner on the stove. The burner transfers energy to
the water at a rate of 550 Joule/second. The ice melts, and eventually all the water boils away.
Given, (i) heat capacity of ice (cice) = 2060 /KK, (ii) latent heat of fusion (Lf), i.e., ice to
water = 3.33 × 105 J/Kg, (iii) heat capacity of water (cwater) = 4186 /K°, (iv) latent
heat of vaporization (Lv), i.e., water to vapor = 2.256 × 106 J/Kg
(a) Find the time (in second) needed for the following processes –
(I) Raising the temperature of the ice up to the melting point (i.e., 0°C).
(II) Melting the ice.
(III) Raising the water by 100°C.
(IV) Boiling the water.
(b) Plot a graph of the temperature (T) as a function of time (t), starting at t = 0, when the
temperature is at −25°C. In the plot, indicate when kinetic energy and potential energy of the
system increasing.
I. The time is 23.41 s.
ii The time is 151.36 s.
iii. The time is 190.27 s
How to solve for the time that it takesLet's calculate the time for each stage.
(I) Raising the temperature of the ice up to the melting point (i.e., 0°C):
To calculate the heat required, we use the formula Q = mcΔT, where Q is heat, m is mass, c is specific heat, and ΔT is change in temperature.
So, for the ice we have Q1 = m * c_ice * ΔT = 0.25 kg * 2060 J/kg°C * 25°C = 12,875 J.
The time taken can be found by dividing the heat required by the rate of heat transfer: t1 = Q1/P = 12875 J / 550 J/s ≈ 23.41 s.
(II) Melting the ice:
For this stage, we use the formula Q = mL, where L is the latent heat of fusion.
So, we have Q2 = m * Lf = 0.25 kg * 3.33 * 10^5 J/kg = 83,250 J.
The time taken is t2 = Q2/P = 83250 J / 550 J/s ≈ 151.36 s.
(III) Raising the water by 100°C:
Here, we use the formula Q = mcΔT again.
So, we have Q3 = m * c_water * ΔT = 0.25 kg * 4186 J/kg°C * 100°C = 104,650 J.
The time taken is t3 = Q3/P = 104650 J / 550 J/s ≈ 190.27 s.
(IV) Boiling the water:
For this stage, we use the formula Q = mL, where L is the latent heat of vaporization.
So, we have Q4 = m * Lv = 0.25 kg * 2.256 * 10^6 J/kg = 564,000 J.
The time taken is t4 = Q4/P = 564000 J / 550 J/s ≈ 1025.45 s.
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What is the basic requirement of measurements?
The basic requirement of measurements is to have a standard or reference point against which to compare the quantity being measured. This standard or reference point should be well-defined and stable, and the measurement process should be repeatable and consistent. Additionally, it is important to ensure that the measurement equipment is calibrated and in good working condition.
Answer:
The most basic requirement for measurements is the presence of a standard or reference point against which the quantity being measured can be compared. The measurement process should be repeatable and consistent, and the standard or reference point should be well-defined and stable. Furthermore, ensure that the measurement equipment is calibrated and in good working order.
Explanation:
(Giving Brainliest to 1st!)Which organelle acts as a temporary storage center, containing water, waste, and other products?
A. cell membrane
B. cytoplasm
C. vacuole
D. nucleus
What lives at layer 3 (the network layer) of the OSI model?
Layer 3 of the OSI (Open Systems Interconnection) model, known as the network layer, is responsible for providing end-to-end communication between hosts in different networks.
The network layer is responsible for routing and forwarding data packets across different networks, as well as handling addressing and logical connectivity.
The main entities that live at layer 3 (the network layer) of the OSI model include:
Routers: Routers are network devices that operate at the network layer and are responsible for forwarding data packets between different networks. They use routing tables and protocols to determine the best path for data packets to reach their destination across multiple networks.
IP (Internet Protocol): IP is a network layer protocol that provides logical addressing and routing functionality. It is responsible for assigning unique IP addresses to devices on a network, and for routing data packets based on those IP addresses.
ICMP (Internet Control Message Protocol): ICMP is a network layer protocol that is used for sending error messages and operational information about network conditions. It is often used for diagnostic purposes, such as ping and traceroute, to check the connectivity and status of network devices.
Network Addressing: Layer 3 is also responsible for assigning and managing IP addresses, which are used to uniquely identify devices on a network.
Subnetting and VLANs: Layer 3 may also involve subnetting and VLANs (Virtual Local Area Networks), which are used for network segmentation and management to improve efficiency and security.
In summary, layer 3 of the OSI model includes routers, IP, ICMP, network addressing, and other protocols and technologies that are responsible for routing, addressing, and logical connectivity in a network.
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Water flows through a straight 10-cm-diameter pipe at a Reynolds number of 250,000. If the pipe roughness is 0.06 mm, what is the approximate Moody friction factor? (a) 0.015 (b) 0.017 (c) 0.019 (d) 0.026 (e) 0.032
The approximate Moody friction factor is 0.019 which is (c) in the given options. Given parameters: Diameter of pipe (D) = 10 cm = 0.1 m Reynolds number (Re) = 250,000Roughness of pipe (ε) = 0.06 mm = 0.00006 m
Calculation: The formula for Moody friction factor is given by f = (0.79 log (Re) - 1.64) ^ {-2}. So, we can calculate the Moody friction factor using the formula mentioned above.
f = (0.79 log (Re) - 1.64) ^ {-2}= (0.79 log (250,000) - 1.64) ^ {-2} = 0.019 (Approximately)
Thus, the approximate Moody friction factor is 0.019 which is (c) in the given options.
The Moody chart is a graphical representation used to determine the friction factor in fluid dynamics for laminar and turbulent flow in pipes. The Moody chart uses the Reynolds number and the relative roughness of the pipe as inputs.
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(b) The individual sensitivities of different elements of temperature measuring systems are: transducer is 0.3 Ohm/°C; wheatstone bridge is 0.01 V/Q; amplifier is 80 v/v; pen recorder is 1.2 mm/V. Determine the: (1) overall sensitivity;
The overall sensitivity of the temperature measuring system is 0.288 units per degree Celsius.
How to calculate the valueOverall Sensitivity = Sensitivity of Transducer * Sensitivity of Wheatstone Bridge * Sensitivity of Amplifier * Sensitivity of Pen Recorder
Overall Sensitivity = 0.3 Ohm/°C * 0.01 V/Q * 80 V/V * 1.2 mm/V
By multiplying these values together, the units cancel out, leaving us with the overall sensitivity in terms of the desired output per degree Celsius change:
Overall Sensitivity = 0.3 * 0.01 * 80 * 1.2
= 0.288
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A swivel hoist ring has rated capacity at 90 degrees from horizontal as compared to its capacity at 45 degree
In many different industries, big weights are lifted using lifting points called swivel hoist rings.
What is a hoist ring's rating?A hoist ring's rated load might be anywhere between 800 and 250,000 pounds. Lifts may be carried out with the aid of one or more hoist rings positioned all over the surface of the load, depending on the size and shape of the load.
A swivel hoist ring is what?A hoist ring, also known as a swivel eye bolt, is a piece of rigging hardware used to attach a sling to a hoist by screwing it into an engineered lifting point on a load. A hoist ring serves a similar purpose to an eye bolt.
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How much horse power does a Lamborghini have
Answer:
Countach - 375 Huracan - 610 to 630Aventador - 729 to 759Urus - 641Gallardo - 543 to 562Centenario - 770 SCV12 - 830Explanation:
It really all depends, it varies from 375 to 830, you can't mark one as " Lamborghinis have this much hp always " seeing it fluctuates so much car to car
Draw a conceptual sketch of your laptop. Identify the keyboard, screen, power source, and storage device and etc. using arrows and labels.
Answer:
draw a picture of your computer and label it
Answer: You need to make a drawing for this problem
Explanation:
Make a simple sketch of a laptop, then draw an arrow and label the screen, keyboard, mouse pad, charging port, charging cord, and any extra parts you would like to label.
5 measurements per decade for frequencies between 1 khz and 100 khz. what frequenices values should be chosen
If you want to take 5 measurements per decade for frequencies between 1 kHz and 100 kHz, then the following frequencies should be chosen: 1 kHz, 10 kHz, 100 kHz, 1 MHz, and 10 MHz.
Taking multiple measurements per decade in the frequency range from 1 kHz to 100 kHz can be done in order to gain a better understanding of the behavior of a signal in a given frequency range. By taking multiple measurements, you can gain insight into the signal's spectral characteristics such as its frequency content, spectral magnitude, and spectral phase.
Additionally, taking multiple measurements per decade can provide more precise information about the signal's power spectral density, and is often used in applications such as signal processing and communications to accurately measure system performance.
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A vibration system consists of a mass 50 kg, a spring of stiffness 30 kN/m and a damper. The
damping provided is only 20% of the critical value. Determine (a) the damping factor, (b) the
critical damping coefficient, (c) the natural frequency of the damped vibrations, (d) the
logarithmic decrement and (e) the ratio of two consecutive amplitudes.
Answer:
20% of the critical value. Determine (a) the damping factor, (b) the
Explanation:
Determine (a) the principal stresses and (b) the maximum in-plane shear stress and average normal stress at the point. Specify the orientation of the element in each case. 60 45 30
Answer:
a) 53 MPa, 14.87 degree
b) 60.5 MPa
Average shear = -7.5 MPa
Explanation:
Given
A = 45
B = -60
C = 30
a) stress P1 = (A+B)/2 + Sqrt ({(A-B)/2}^2 + C)
Substituting the given values, we get -
P1 = (45-60)/2 + Sqrt ({(45-(-60))/2}^2 + 30)
P1 = 53 MPa
Likewise P2 = (A+B)/2 - Sqrt ({(A-B)/2}^2 + C)
Substituting the given values, we get -
P1 = (45-60)/2 - Sqrt ({(45-(-60))/2}^2 + 30)
P1 = -68 MPa
Tan 2a = C/{(A-B)/2}
Tan 2a = 30/(45+60)/2
a = 14.87 degree
Principal stress
p1 = (45+60)/2 + (45-60)/2 cos 2a + 30 sin2a = 53 MPa
b) Shear stress in plane
Sqrt ({(45-(-60))/2}^2 + 30) = 60.5 MPa
Average = (45-(-60))/2 = -7.5 MPa
TION 1
All of the following are components of the fixed caliper, EXCEPT:
Select the correct option and click NEXT.
O Pads
O Shims
O Discs
OSlide Pins
Slide Pins as the fixed caliper has components that are consider all of the following, excluding slide pins.
What is caliper mountings about?Caliper mountings is important to follow proper safety procedures when it is dealing with hazardous materials such as the asbestos dust. This may be include using the protective equipment, such as the gloves and the respirators, as well as following specific cleaning procedures to be minimize the risk of the exposure.
The hazardous dust has been properly dealt with it as it may be necessary to use a brake or the cleaning solvent to further clean the caliper mountings and slides or the pins. It has been important to follow the manufacturer's instructions and just to use caution when it is using any cleaning solvent.
Technician would says that one should clean the caliper mountings and slides or the pins using the equipment which is used in the procedures for dealing with asbestos or the hazardous dust. Technician b would says that once the dust has been taken care of one may need to use a brake cleaning solvent to clean the components further.
Therefore, Slide Pins as the fixed caliper has components that are consider all of the following, excluding slide pins.
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I'm interested in knowing if there are two adjacent strings in a list that are very similar to each other. For instance, "Zach" and "Zack" are only one character apart.
Write a function, named "CloseEnough" that takes a const reference to a vector of strings and an int. The vector is a list of strings (each of the same length). The int represents how many characters can be different between any two strings next to each other. This function should return the index (an int) of the string that is within the second arguments distance to the next string in the vector. If no index fulfills this criteria, it should return -1
Here's a function called Close Enough which takes a const reference to a vector of strings and an int. This function is used to check if there are two adjacent strings in a list that are very similar to each other by determining the number of characters that can be different between any two strings next to each other.
The function starts by iterating through the vector of strings from the first to the second to last string. For each string, it then counts the number of differences between it and the next string by comparing the characters at each position.
If the number of differences is less than or equal to the given integer n, the function returns the index of the current string. If there is no such index, the function returns -1.
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Using the correlation for the second virial coefficient (Pitzer correlation), find the molar volume of acetylene vapour at 247.1 K and 13.5 bar, giving your answer to the nearest cm3/mol. The critical temperature is 308.3 K and the critical pressure of acetylene is 61.39 bar. Take R = 8.314 J/mol-K and the acentric factor for acetylene is 0.187.
The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.
Explanation:
The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.
Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.
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With direct fuel injection the gasoline is injected:
Answer:
Gasoline is injected directly into the cylinder.
Explanation:
In a direct injection system, the air and gasoline are not pre-mixed. Rather, air comes in using the intake manifold, while the gasoline is injected directly into the cylinder.
Careful with this one. In order to relay a VOIP call to the public telephone system, what is required?A routerA firewallA gatewayA PBX
A gateway and gate keeper is necessary to relay a VOIP call to the public telephone system.
How do gateways work?A computer that obstructs two networks or software applications. Data, communications, and information are transformed by the gateway from one protocol or format to another. A router may perform some of the functions of a gateway. An Internet gateway can transport communications between a corporate network and the Internet.
How does VoIP operate and what is it?A VoIP phone system uses internet connectivity to place calls rather than a traditional landline or cellular network. Over your broadband connection, a VoIP system transforms analog speech impulses into digital ones. Calls are connected to different telephone networks via a VoIP server.
Who would use a VoIP phone and why?VoIP has advantages over conventional phone systems due to its ability to support multiple-party calls. Both large and small businesses frequently require a separate conference call provider that allows multiple participants to join the same call. Providers of business VoIP services have effective conference calling features integrated right into their service.
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A gateway is required to relay a VOIP call to the public telephone system. A gateway is a device that connects two networks, such as the public telephone system and a Voice over IP (VoIP) system.
What is VOIP?
Voice over Internet Protocol (VoIP) is a technology that allows users to make voice and video calls over the internet. It works by converting analog audio signals into digital data that is then sent over the internet. This data can travel to any device connected to the internet, allowing users to make calls from anywhere in the world. VoIP is becoming increasingly popular as it is more cost-effective than traditional landline phone services. It also offers features such as caller ID, call forwarding, voicemail, and conference calling. Additionally, VoIP services are often more reliable than traditional phone services, as they are not affected by power outages or other interruptions. As a result, many businesses are switching over to VoIP services to reduce costs and improve communication.
It acts as an interface between the two networks, allowing calls to be sent and received between them. A router and a firewall are also necessary to secure the connection between the networks, while a PBX (Private Branch Exchange) is required to manage the VoIP system.
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Whose responsibility is it to provide a safe and healthy workplace?
Answer:
Under the OSH law, employers have a responsibility to provide a safe workplace. This is a short summary of key employer responsibilities: Provide a workplace free from serious recognized hazards and comply with standards, rules and regulations issued under the OSH Act.
credits to google
Explanation:
Answer:
employers
Explanation:
because they are responsible.