Piaget's Cognitive Approach: Object Permeance. Explain about the Object Permeance?

The airport board cannot legally exclude a second restaurant from the airport. Also, it cannot legally exclude a second FBO from the airport. The town’s grant agreement with the FAA prohibits discrimination against airport tenants.

As a requirement for accepting FAA grant funds, airports must comply with a set of terms and conditions known as "grant assurances." They assist airports in maintaining a secure, effective, and efficient airport system in accordance with federal laws and regulations. They're generally required in exchange for federal funding or for the use of federally controlled land. Grant assurances aim to assure that federal money used for airport construction is spent wisely and that airports operate in a manner that is consistent with federal objectives. They also guarantee that the airport will be open to the public and that it will operate on a non-discriminatory basis.In general, grant assurances relate to the following topics: the sale of surplus property, revenue use, fee and rental structure, operation and maintenance, airport layout plans, environmental compliance, and competition. The FAA requires airports that accept federal grants to be self-sufficient. They may do so by charging fair rents, fees, and other charges to those who use the airport's facilities and services. Additionally, FAA grant assurance prohibit airports from being biased against one tenant or industry or favoring another. Therefore, the board of the airport cannot legally exclude a second restaurant from the airport, or a second FBO from the airport.What is the recourse available to the applicant whose proposal was rejected by the board?An applicant whose proposal has been rejected by the airport board may take the following steps if they believe they have been treated unfairly:File a complaint with the FAA's Office of Civil Rights (ACR). If the complaint is accepted, ACR will investigate the matter.File a complaint with the Department of Transportation's (DOT) Office of Civil Rights. This is an option for those who don't think the FAA has handled their complaint correctly.Contact a private attorney to represent their interests in court. This is the only recourse for individuals who are dissatisfied with the results of the investigation conducted by ACR or DOT.

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The recommended wall thickness for a vessel containing 100 lbs of oxygen gas at 170°F and built of AISI C1020 steel with a diameter of 2 feet and a length of 3 feet, using a factor of safety of 3 based on the yield strength, is 0.51 inches.

AISI C1020 steel is utilized to build a vessel containing 100 lbs of oxygen gas at 170°F, with a diameter of 2 feet and a length of 3 feet.

The recommended wall thickness of the vessel can be determined using the formula below:σallowable = Sy/F Sσallowable = (0.4 * Sy)/FS Where, Sy is the yield strength of the material, and FS is the factor of safety.

Based on the given parameters, the weight density of oxygen at 170°F is 0.005 lb/ft3.

The volume of the vessel can be computed using the formula below:

V = π/4 × D2 × L= π/4 × 22 × 3 = 9.425 ft3

The mass of oxygen gas in the vessel can be calculated using the following formula:

Mass = Volume × Density= 9.425 × 0.005= 0.047125 lb

The internal pressure of the vessel can be determined using the ideal gas law as:

P = (mRT)/ V Where, m is the mass of oxygen gas in the vessel R is the gas constant T is the temperature in Rankine P is the internal pressure of the vessel Substituting the values:

R = 1545 ft.lb/R°T = (170 + 460) = 630°RP = (0.047125 × 1545 × 630)/9.425 = 467.6749 psi

The allowable stress can be determined by using a factor of safety of 3.

Therefore,σallowable = 33000/3 = 11000 psi

Based on the given parameters, the recommended wall thickness of the vessel can be computed as:

t = PD/2σt= (467.6749 × 2)/ (2 × 11000) = 0.04252 ft

Converting the thickness in feet to inches:0.04252 × 12 = 0.51 inches Hence, the recommended wall thickness of the vessel should be 0.51 inches.

Oxygen is a highly flammable gas that can be hazardous if not handled correctly. It is crucial to ensure that the vessel containing it is designed and constructed to withstand its internal pressure. AISI C1020 steel is frequently used in the construction of vessels because of its excellent strength-to-weight ratio. The thickness of the vessel's wall is a critical factor in determining its ability to handle the gas's internal pressure. To guarantee that the vessel is safe and dependable, it is critical to compute the recommended wall thickness accurately. The vessel's diameter, length, mass, temperature, and material are all required to calculate the wall thickness.

To determine the vessel's internal pressure, the mass and volume of the oxygen gas in the vessel must first be determined. Then, using the ideal gas law, the internal pressure can be determined.Finally, to obtain the recommended wall thickness, the allowable stress and the factor of safety are used in the calculation. A wall thickness of 0.51 inches is recommended for the vessel containing 100 lbs of oxygen gas at 170°F. This thickness is sufficient to ensure the vessel's safety while also allowing it to withstand the gas's internal pressure.

The recommended wall thickness for a vessel containing 100 lbs of oxygen gas at 170°F and built of AISI C1020 steel with a diameter of 2 feet and a length of 3 feet, using a factor of safety of 3 based on the yield strength, is 0.51 inches. It is critical to determine the correct wall thickness to ensure that the vessel is safe and dependable while being able to withstand the gas's internal pressure.

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Answer:

the temperature of the aluminum at this time is 456.25° C

Explanation:

Given that:

width w of the aluminium slab = 0.05 m

the initial temperature \(T_1\) = 25° C

\(T{\infty} =600^0C\)

h = 100 W/m²

The properties of Aluminium at temperature of 600° C by considering the conditions for which the storage unit is charged; we have ;

density ρ = 2702 kg/m³

thermal conductivity k = 231 W/m.K

Specific heat c = 1033 J/Kg.K

Let's first find the Biot Number Bi which can be expressed by the equation:

\(Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{h \dfrac{w}{2}}{k}\)

\(Bi = \dfrac{hL_c}{k} \\ \\ Bi = \dfrac{100 \times \dfrac{0.05}{2}}{231}\)

\(Bi = \dfrac{2.5}{231}\)

Bi = 0.0108

The time constant value \(\tau_t\) is :

\(\tau_t = \dfrac{pL_cc}{h} \\ \\ \tau_t = \dfrac{p \dfrac{w}{2}c}{h}\)

\(\tau_t = \dfrac{2702* \dfrac{0.05}{2}*1033}{100}\)

\(\tau_t = \dfrac{2702* 0.025*1033}{100}\)

\(\tau_t = 697.79\)

Considering Lumped capacitance analysis since value for Bi is less than 1

Then;

\(Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]\)

where;

\(Q = -\Delta E _{st}\) which correlates with the change in the internal energy of the solid.

So;

\(Q= (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]= -\Delta E _{st}\)

The maximum value for the change in the internal energy of the solid  is :

\((pVc)\theta_1 = -\Delta E _{st}max\)

By equating the two previous equation together ; we have:

\(\dfrac{-\Delta E _{st}}{\Delta E _{st}{max}}= \dfrac{ (pVc)\theta_1 [1-e^{\dfrac {-t}{ \tau_1}}]} { (pVc)\theta_1}\)

Similarly; we need to understand that the ratio of the energy storage to the maximum possible energy storage = 0.75

Thus;

\(0.75= [1-e^{\dfrac {-t}{ \tau_1}}]}\)

So;

\(0.75= [1-e^{\dfrac {-t}{ 697.79}}]}\)

\(1-0.75= [e^{\dfrac {-t}{ 697.79}}]}\)

\(0.25 = e^{\dfrac {-t}{ 697.79}}\)

\(In(0.25) = {\dfrac {-t}{ 697.79}}\)

\(-1.386294361= \dfrac{-t}{697.79}\)

t = 1.386294361 × 697.79

t = 967.34 s

Finally; the temperature of Aluminium is determined as follows;

\(\dfrac{T - T _{\infty}}{T_1-T_{\infty}}= e ^ {\dfrac{-t}{\tau_t}}\)

\(\dfrac{T - 600}{25-600}= e ^ {\dfrac{-967.34}{697.79}\)

\(\dfrac{T - 600}{25-600}= 0.25\)

\(\dfrac{T - 600}{-575}= 0.25\)

T - 600 = -575 × 0.25

T - 600 = -143.75

T = -143.75 + 600

T = 456.25° C

Hence; the temperature of the aluminum at this time is 456.25° C

The force on the wall due to shear stress between section 1 and 2 can then be expressed as: FT = (4 * pi * mu * L * Umax * ro) / D - (32 * pi * mu * L * Umax * ro³) / (3 * D²). We can calculate it in the following manner.

The shear stress on the pipe wall can be determined using the following formula:

To = (4 * mu * U) / D

where To is the wall shear stress, mu is the dynamic viscosity of the fluid, U is the mean velocity of the fluid, and D is the diameter of the pipe.

The force on the wall due to shear stress between section 1 and 2 can be calculated using the following equation:

FT = 2 * pi * L * To * ro

where L is the length of the pipe between section 1 and 2, and ro is the outer radius of the pipe at section 2.

The velocity distribution at section 2 is given by:

u = Umax[1 – (r/ro)²]

where r is the radial distance from the center of the pipe.

The mean velocity U can be calculated using the following equation:

U = (2 / 3) * Umax

The pressure drop between section 1 and 2 can be calculated using the following equation:

p1 - p2 = (32 * mu * L * U) / (pi * D²)

where p1 and p2 are the pressures at sections 1 and 2, respectively.

The force on the wall due to shear stress between section 1 and 2 can then be expressed as:

FT = (4 * pi * mu * L * Umax * ro) / D - (32 * pi * mu * L * Umax * ro³) / (3 * D²)

This formula shows that the force on the wall due to shear stress is proportional to the length of the pipe, the maximum velocity, and the outer radius of the pipe, and inversely proportional to the diameter of the pipe. The formula also takes into account the pressure drop between sections 1 and 2.

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Answer:

24 cans

Explanation:

The number of glycol solution needed to prevent water from freezing is 42 galloons. The glycol solution comes in cans of 1.75 gallons.

Therefore 1 can of glycol = 1.75 gallon.

Number of cans of glycol needed = Total gallons of glycol needed / number of gallon present in each can

Number of cans of glycol needed = 42 gallons / (1.75 gallon per can)

Number of cans of glycol needed = 24 cans

Therefore a total of 24 cans are needed.

Answer:

b. inversely proportional to radius of curvature

Explanation:

In curvilinear motions, the normal acceleration which is also called the centripetal acceleration is always directed towards the center of the circular path of motion. This acceleration has a magnitude that is directly proportional to the square of the speed of the body undergoing the motion and inversely proportional to the radius of the curvature of the motion path. The centripetal or normal acceleration a,  can be given by;

a = \(\frac{v^2}{r}\)

Where;

v = speed of the body

r = radius of curvature.

Answer:

A counter which counts from 0 to 255 with seven segment display

Timer Mode Control (TMOD)

Explanation:

Answer: it spread by winds has a strong effect on fire behavior due to the fanning effect on the fire.Wind increases the supply of oxygen.

Explanation:

Fires need three things to occur in order to start and grow: oxygen, a spark/heat, and fuel. Wildfires in forests have plenty of fuel and heat is never really an issue, therefore the wind can cause a fire to continue and even spread faster. Wind will not only increase the fire's supply of oxygen, but it will   also blow the fire in many different directions, now causing the flames to spread.

The appropriate dimensionless parameters for the given input power W to a large industrial fan are the Reynolds number, the Euler number, and the specific speed. These dimensionless parameters are used to describe the flow characteristics of the fluid and the performance of the fan impeller.

The Reynolds number (Re) is a dimensionless parameter that characterizes the flow of a fluid. It is defined as the ratio of inertial forces to viscous forces, and is given by:

\(Re = (p * D * o) / f\)

The Euler number (Eu) is a dimensionless parameter that characterizes the pressure difference across the fan impeller. It is defined as the ratio of the pressure difference to the dynamic pressure, and is given by:

\(Eu = (W / (p * Q)) / (o * D^2)\)

The specific speed (Ns) is a dimensionless parameter that characterizes the performance of the fan impeller. It is defined as the ratio of the volumetric flow to the square root of the pressure difference, and is given by:

\(Ns = (Q / o) / sqrt(W / (p * Q))\)

By using these dimensionless parameters, we can analyze the performance of the fan impeller and the flow characteristics of the fluid in a more meaningful way.

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To write a Python script that runs on double click, opens a terminal and displays "Hello world", follow the steps given below:Step 1: Create a new Python fileOpen your text editor and create a new Python file. Name your file anything you like, for example, "hello_world.py".Step 2: Write Python codeIn your Python file, write the code to print "Hello world" to the terminal.import osos.system("gnome-terminal -e 'bash -c \"echo Hello world; exec bash\"'")Note: You can also use 'xterm' instead of 'gnome-terminal' in the above code to open the Xterm terminal.Step 3: Save the fileSave the file with a .py extension. The final file should be named "hello_world.py".Step 4: Make the file executableOpen a terminal and navigate to the directory where the file is saved. Use the chmod command to make the file executable.chmod +x hello_world.pyStep 5: Double-click to run the scriptNow, double-click on the file to run it. A terminal window should open and display the message "Hello world".Congratulations, you have successfully written a Python script that runs on double click, opens a terminal and displays "Hello world".

Answer:

(The diagram of the question is given in Attachment 1)

The largest load which can be applied is:

P=67.62 kN

Explanation:

All the forces are shown in the diagram in Attachment 2.

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta-P=0\\\frac{4}{5}F_{BC} - P=0\\F_{BC}=\frac{5}{4}P\\\\F_{BC}=1.25P\)

∑ F(x)= 0 (Towards Right is positive)

\(N_{a-a} - F_{BC}cos\theta=0\\N_{a-a}-1.25P(\frac{3}{5})=0\\N_{a-a}=0.75P\)

∑ F(y)= 0 (Upwards is positive)

\(F_{BC}sin\theta- V_{a-a}= 0\\(\frac{4}{5})1.25P-V_{a-a}=0\\V_{a-a}=P\)

The cross sectional area of a-a:

\(A_{a-a}= \frac{(0.026)(0.026)}{3/5}\\A_{a-a}= 1.127\cdot10^{-3}\)

σ = N(a-a)/A(a-a)

Substitute values:

\(160\cdot10^6=\frac{0.75P}{1.127\cdot10^{-3}}\\P=240.42\cdot10^3 N\\P=240.42 kN\)

Т= V(a-a)/A(a-a)

Substitute values:

\(60\cdot10^6=\frac{P}{1.127\cdot10^{-3}}\\P=67.62\cdot10^{3}N\\P=67.62kN\)

To satisfy both the condition, we have to choose the lower value of P.

P=67.62 kN

The simplest circuit that can be used for the control circuit must produce an output of 1 if at least two of the conditions 1,2 and 3 are true is given below.

A special kind of circuit known as a control circuit is used to regulate the performance of a totally independent power circuit. Think about a water pump being driven by a 1,000 horsepower, large industrial motor. A high voltage electrical source with a 2,400 volt output is connected to the motor.

For the safety of the operator and the machinery, a control circuit is used to ensure that the motor is started and stopped safely.

The thermostat for a home's air conditioner is an illustration of a control circuit that is frequently used. The thermostat is a component of a low-voltage control circuit that manages a relay that actually activates and deactivates the power circuit to the air conditioner compressor.

See the given attachment below for the simplest circuit↓↓

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The maximum capillary rise and tube diameter for this maximum-rise case will be d=0.414× 10⁻⁴ m.

What do you mean by tube?

A tube, also known as tubing, is a long hollow cylinder that is used to transport fluids (liquids or gases) or to protect electrical and optical cables and wires.

Given that, P = 4 KPa

Contact angle = 6°

Surface tension = 1 N/m

Lets assume that atmospheric pressure = 100 KPa

Lets take that density of water = 1000kg/m³

So the capillarity rise h

h=ΔP/ρg

h= (100×1000-4×1000)/(1000×10)

h= 9.61 m

We know that for capillarity rise h

h=2σcosθ/rρg

r = 2σcosθ/hρg

r = (2×1cos4°)/(9.61×1000×10)

r = 0.207×10⁻⁴m

d=0.414× 10⁻⁴ m

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Answer:

Who care

Explanation:

Lol

yes it will

Explanation:

The common-emitter amplifier is current gain and voltage gain, but no power gain. The correct option is 2).

By inverting, a common emitter amplifier operates. The input impedance is low. It has a high output impedance despite having a low input impedance.

When it serves as a current buffer, the common base circuit operates at its peak efficiency. It has the capacity to accept a low input impedance input current and transfer almost the same current to a greater output impedance.

Therefore, the correct option is 2) current gain and voltage gain, but no power gain.

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The question is incomplete. Your most probably complete question is given below:

1) current gain and power gain, but no voltage gain 2) current gain and voltage gain, but no power gain 3) voltage gain, current gain, and power gain 4) voltage gain and power gain, but no current gain.

The temperature and pressure of an ideal gas are directly proportional

The pressure of the system should be in the range B) 94 psig

The given refrigerator parameters are;

The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K

The pressure to which the system was charged with nitrogen, P₁ = 100 psig

The temperature to which the system dropped, T₂ = 50 °F = 283.15 K

The required parameter;

The pressure, P₂, of the system at 50°F

Method:

The relationship between pressure and temperature is given by Gay-Lussac's law as follows;

At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin

Mathematically, we have;

\(\dfrac{P_1}{T_1} = \mathbf{\dfrac{P_2}{T_2}}\)

Plugging in the values of the variables gives;

\(\mathbf{\dfrac{100 \ psig}{297.0389}} = \dfrac{P_2}{283.15}\)

Therefore;

\(P_2 = \mathbf{283.15 \, ^{\circ}F \times \dfrac{100 \ psig}{297.0389\ ^{\circ}F} \approx 95.3 \, ^{\circ}F}\)

The closest option to the above pressure is option B) 94 psig

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Answer:

Explanation:

It appears that you are trying to solve a problem involving an insulated rigid tank containing saturated liquid water and water vapor. To determine the volume of the tank, you will need to know the mass of the liquid water and the mass of the water vapor. The mass of the liquid water can be calculated by multiplying the mass of the water and vapor mixture by the fraction of the mixture that is liquid water (1.4 kg * 0.25 = 0.35 kg). The mass of the water vapor can be calculated by subtracting the mass of the liquid water from the total mass of the mixture (1.4 kg - 0.35 kg = 1.05 kg).

To determine the final temperature of the tank, you will need to know the amount of heat added to the tank by the electric resistor and the specific heat capacity of the water and water vapor mixture. The specific heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. The specific heat capacity of water is 4.186 J/g°C, and the specific heat capacity of water vapor is 2.080 J/g°C.

To determine the electric power rating of the resistor, you will need to know the amount of heat added to the tank by the resistor and the time over which the heat was added. The power rating of the resistor is equal to the amount of heat added to the tank divided by the time over which the heat was added.

I hope this helps clarify the problem and provide some guidance on how to solve it. If you have any further questions or need additional help, please don't hesitate to ask.

Answer:

a) civil engineering.

Explanation:

Civil engineering is a professional engineering program that deals with the construction, design, and maintenance of all the natural and man-made environments including dams, buildings, railways, and roads.

Civil engineering is the branch of engineering that is the practice not restricted because civil engineer is not restricted to academic profession but practice in designing and construction can make someone a professional civil engineer.

Hence, the correct answer is "a)."

The branch of engineering in which the practice is not restricted is; Civil Engineering

             Civil Engineering is a branch of engineering that deals with the design, construction and maintenance of the physical and naturally built environment.

These physically and naturally built environment includes; houses, roads, bridges, airports, railways, canals, dams, sewage systems, pipelines e.t.c

             Now, mechanical engineering involves design, production, operation and maintenance of mechanical systems or machineries.

             In conclusion, we see that the mechanical branch of engineering is restricted to machinery unlike civil engineering that is not restricted to only buildings but also includes pipelines, bridges, roads, railways, dams, sewage systems e.t.c

             Finally, the nuclear engineering branch is also restricted to only nuclear fission and fusion applications.

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Intersections that have traffic signs or signals are called  uncontrolled intersections.

What is signals?
Signals are forms of communication used by living organisms and machines. They are the means by which messages are exchanged between two or more entities. Signals can be visual, auditory, chemical, electrical, and mechanical. They are used to convey information, instructions, and other data. In the context of computing, signals are the messages a computer sends and receives from external sources. Signals can be used to control the flow of data, detect errors, and initiate events. Signals can be used to send information from one unit to another, or from one system to another. Signals can also be used to control the operation of a system or device, or to alert an operator of an error or malfunction. Signals are an important part of communication and are used to transmit data, instructions, and other information between machines and living beings.

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Yes, the receiver will discard the frame. Let's perform the CRC calculation for the bit sequence 111001000 with the generator 1101. The first bit in the sequence is a 1, so we take the first 4 bits (1110) and XOR them with the generator (1101) to get the remainder 001.

We then drop the first bit (1) and append the remainder (001) to get the new bit sequence 110010001. We now perform the same process with this new sequence and the same generator. Taking the first 4 bits (1100) and XORing with the generator (1101) gives us the remainder 001. Dropping the first bit (1) and appending the remainder (001) gives us the new bit sequence 10010001.
b) The number of collisions after which, in CSMA/CD protocol, the NIC can make a binary exponential delay of at most 1536 bit times is 10. The binary exponential backoff algorithm doubles the delay time after each collision until a maximum delay time of 1023 slots is reached. After the 10th collision, the delay time would be 1024 slots, which is greater than 1536 bit times. Therefore, the NIC would make a delay of at most 1536 bit times.

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Answer:

See below

Explanation:

Check One-Sample T-Interval Conditions

Random Sample? √

Sample Size ≥30? √

Independent? √

Population Standard Deviation Unknown? √

One-Sample T-Interval Information

Problem 1

The critical t-value, as mentioned previously, would be \(t^*=2.0096\), making the 95% confidence interval equal to \(CI=\bar{x}\pm t^*(\frac{S_x}{\sqrt{n}})=390.25\pm2.0096(\frac{30.5}{\sqrt{50}})\approx\{381.5819,398.9181\}\)

This interval suggests that we are 95% confident that the true mean levels of lead in soil are between 381.5819 and 398.9181 parts per million (ppm), which satisfies the EPA's regulated maximum of 400 ppm.

Answer:

metal hub and the wire tension spokes?

Answer: metal hub and the wire tension spokes is correct

The absolute pressure in psia being measured is; 27.228 psia

Formula for absolute Pressure is;

Absolute pressure = Atmospheric pressure + Gauge pressure

P_{abs} = P_{atm} + P_g

We are given;

P_atm = 29.86 (in Hg) = 14.666 psia

Density of mercury at 70 °F; ρ = 13.543 g/cm³

Mercury Manometer reading; h = 25.62 in

Acceleration due to gravity; g = 32.243 ft/s²

Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243

When we multiply and covert to psia gives; P_g = 12.562 psia

Thus;

P_abs = 14.666 + 12.562

P_abs = 27.228 psia

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Answer:

The efficiency of a DC generator is maximum when those losses proportional to the square of the load current are equal to the constant losses of the DC generator. This relation applies equally well to all rotating machines, regardless of the type of machine.

Explanation:

Answer:

C) a winding connected in series with the armature.

Explanation:

In a series motor, an electromagnet is used as a stator to generate its magnetic field. The field coil of this stator are connected through a commutator in series with the rotor windings. This stator which is the armature windings will conduct AC even on a DC machine, due to the  periodically reverses current direction (commutation) or due to electronic commutation (as in brushless DC motors).

Answer:

Burj Khalifa

Explanation:

The world's tallest artificial structure is the 829.8-metre-tall (2,722 ft) Burj Khalifa in Dubai (of the United Arab Emirates). The building gained the official title of "tallest building in the world" and the tallest self-supported structure at its opening on January 9, 2010.

a brainliest would be appriciated

Answer:

Burj khalifa

Explanation:

829.8 meters tall