Answer:The student should put time (in seconds or minutes) on the x-axis of her graph, since she measured the distance the car traveled at specific time intervals (every 20 seconds) for a total duration of 2 minutes.
Explanation:
explain why thermal energy is always transferred whenever work is done
Answer:
Heat
Explanation:
All materials have go some sort of heat.
Answer:Since the friction force is non-conservative as potential energy. All the work done by the friction forces results in a transfer of energy into thermal energy of the box floor system.
Explanation:
Au cours d'un orage le bruit de tonnerre met 7 secondes pour parvenir aux oreilles d'un observateur _1_ à quelle distance est tombée la foudre sachant que dans l'air le son se propage à la vitesse de 340 m/s . _2_ quel est le temps mis par la lumière de l'éclair pour franchir cette distance à l'aide de chronomètre courants
Answer:
\(2380\ \text{m}\)
\(7.93\times 10^{-6}\ \text{s}\)
Explanation:
t = Temps mis par la foudre pour parcourir la distance = 7 secondes
v = Vitesse du son dans l'air = 340 m / s
La distance est donnée par
\(s=vt\\\Rightarrow s=340\times 7\\\Rightarrow s=2380\ \text{m}\)
L'éclair est tombé à une distance de \(2380\ \text{m}\)
c = Speed of light = \(3\times 10^8\ \text{m/s}\)
Le temps est donné par
\(t=\dfrac{s}{c}\\\Rightarrow t=\dfrac{2380}{3\times 10^8}\\\Rightarrow t=7.93\times 10^{-6}\ \text{s}\)
Le temps mis par la lumière pour parcourir la distance est de \(7.93\times 10^{-6}\ \text{s}\).
A cup of coffee with cooling constant k = -0.09 is placed in a room temperature of 18°C. If the coffee is served at 93 °C, how long will it take to reach a drinking temperature of 73 °C?
The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
The cooling law is given by:
$$\frac{dQ}{dt}=-k(T-T_0)$$
where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.
We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.
Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.
Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:
dQ = - dQ where dQ is the heat energy gained by the environment.
We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.
We can rearrange the equation as follows:
$$-\frac{dQ}{dt}=k(T-T_0)$$
$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$
$$\frac{d}{dt}T=-k(T-T_0)$$
The differential equation above can be solved using separation of variables as follows:
$$\frac{d}{dt}\ln(T-T_0)=-k$$
$$\ln(T-T_0)=-kt+c_1$$
$$T-T_0=e^{-kt+c_1}$$
$$T=T_0+Ce^{-kt}$$
where C = e^(c1).
We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.
$$T=T_0+Ce^{-kt}$$
$$73=18+C\cdot e^{-0.09t}$$
$$55=C\cdot e^{-0.09t}$$
$$C=55e^{0.09t}$$
$$T=18+55e^{0.09t}$$
We can now solve for the value of t when T=93 as follows:
$$93=18+55e^{0.09t}$$
$$e^{0.09t}=\frac{93-18}{55}$$
$$e^{0.09t}=1.3636$$
$$t=\frac{\ln(1.3636)}{0.09}$$
Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.
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What is the potential energy of a stone of mass 10 kg that is lifted to a height of 8m?
The potential energy of a stone of mass 10 kg that is lifted to a height of 8m is -784 Joule.
Potential energy is essentially what it sounds like, though there are some nuances. An object's actual potential energy is determined by its position in relation to other objects. For example, a brick suspended from a two-story building has more potential energy than a brick resting on the ground. This is due to the brick's relative position to the Earth providing it with more energy. However, because there is no force acting on them, two bricks next to each other do not give each other more energy.
Given,
Mass of stone = 10kg
Height = 8m
Potential energy can be determined by formula,
P=mgh
Where, g= gravitational acceleration = \(-9.8 m/s^2\)
Here, gravitational acceleration is negative because stone is thrown against the gravitational pull
\(P=10*8*(-9.8)=-784 J\)
Hence, the potential energy is -784 J
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Examine the Porter's 5 forces and explain how the forces are interconnected? Use examples to explain your answers. No less than 100 words
Porter's Five Forces is a framework used to analyze the competitive intensity and attractiveness of an industry. The five forces are: Threat of New Entrants, Bargaining Power of Suppliers, Bargaining Power of Buyers, Threat of Substitute Products or Services and Intensity of Competitive Rivalry.
Threat of New Entrants: This force considers the ease or difficulty for new competitors to enter an industry. It includes barriers to entry such as high capital requirements, economies of scale, brand loyalty, and government regulations.
Example: The airline industry is known for its high barriers to entry due to the significant capital required to purchase aircraft, establish routes, and secure necessary licenses and permits. Additionally, established airlines often have loyal customer bases and strong brand recognition, making it challenging for new entrants to compete effectively.
Bargaining Power of Suppliers: This force assesses the power suppliers have over the industry in terms of pricing, quality, and availability of inputs. It considers factors such as the concentration of suppliers, uniqueness of their products, and their ability to forward integrate.
Example: In the smartphone industry, major suppliers of components like microchips and display screens hold significant bargaining power. These suppliers provide essential inputs, and their products may have limited alternatives or require specialized manufacturing processes. As a result, smartphone manufacturers must negotiate favorable terms with these suppliers to ensure a reliable supply chain and competitive pricing.
Bargaining Power of Buyers: This force examines the power customers have in influencing prices, demanding better quality or service, and potentially switching to alternative products or suppliers. It considers factors such as buyer concentration, product differentiation, and switching costs.
Example: The retail industry experiences strong buyer power, particularly in highly competitive markets. Customers have access to various options, and their ability to compare prices and products easily through online platforms empowers them to demand competitive pricing, promotions, and high-quality products and services.
Threat of Substitute Products or Services: This force looks at the availability of alternative products or services that can satisfy customer needs. It considers factors such as price-performance trade-offs, switching costs, and customer loyalty.
Example: The rise of streaming services such as Netflix, Amazon Prime Video, and Hulu posed a significant threat to traditional cable and satellite TV providers. These streaming platforms offer a wide range of content at competitive prices, allowing customers to switch from traditional TV services to streaming options, resulting in a decline in subscriber numbers for traditional providers.
Intensity of Competitive Rivalry: This force evaluates the level of competition among existing firms in the industry. It considers factors such as the number and size of competitors, industry growth rate, product differentiation, and exit barriers.
Example: The soft drink industry, dominated by major players like Coca-Cola and PepsiCo, experiences intense competitive rivalry. These companies fiercely compete for market share through advertising campaigns, new product launches, pricing strategies, and distribution channels. The rivalry is further intensified by the high market saturation and the limited scope for differentiation among similar products.
The interconnection of these forces lies in their collective influence on the competitive dynamics and profitability of an industry. Changes in one force can trigger a chain reaction that impacts the others. For instance, a high threat of new entrants may lead to increased competitive rivalry as existing firms strive to defend their market share. Similarly, a strong bargaining power of buyers can limit the pricing power of suppliers and impact their profitability. Understanding these interconnections helps businesses assess the overall attractiveness and competitive landscape of an industry and develop appropriate strategies to thrive within it.
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The graphic organizer compares energy transfer in two layers of the Sun. A venn diagram of 2 intersecting circles with the left circle labeled convection zone and the right circle labeled radiative zone. There is an X in the convection zone circle. There is a Y in the radiative zone. Which labels belong in the regions marked X and Y? X: Absorbs energy from the core Y: Takes longer for photons to move through X: Releases energy to the photosphere Y: Takes longer for photons to move through X: Takes longer for photons to move through Y: Absorbs energy from the core X: Takes longer for photons to move through Y: Releases energy to the photosphere
Answer:
X: Absorbs energy from the core.
Y: Releases energy to the photosphere.
Explanation:
Convection is a mode of heat transfer through fluids (liquids or gas), and it requires material medium for its propagation.
The energy absorbed from the core of the Sun, is transferred through X (convection zone) by convectional process, and it flows to Y (radiative zone). Since the regions X and Y have different functions, the heat propagates from X causing photons to traverse through Y where it get released into the photosphere or the Sun's surface.
Therefore;
X: Absorbs energy from the core.
Y: Releases energy to the photosphere.
Answer:
X: Takes longer for photons to move through
Y: Releases energy to the photosphere
Explanation:
the velocity of a body is increases from 10 m/s ti 15 m/s in 5seconds calculate its acceleration
Answer:
acceleration = v-u/ t
= 15-10/5
= 5/5
= 1 m/s2
Explanation:
hope this helped you.
Answer:
\(\boxed {\boxed {\sf 1 \ m/s^2}}\)
Explanation:
Acceleration is the change in velocity over the change in time. Therefore, the formula for calculating acceleration is:
\(a= \frac{v_f-v_i}{t}\)
Since the body's velocity increased from 10 meters per second to 15 meters per second 15 m/s is the final velocity and 10 m/s is the initial velocity. The time is 5 seconds.
\(v_f\)= 15 m/s \(v_i\)= 10 m/s t= 5 s\(a= \frac{ 15 \ m/s - 10 \ m/s}{5 \ s}\)
Solve the numerator.
15 m/s - 10 m/s = 5 m/s\(a= \frac{ 5 \ m/s }{5 \ s}\)
Divide.
\(a= 1 \ m/s/s\)
\(a= 1 m/s^2\)
The acceleration is 1 meter per second squared.
in an informative presentation—definitions, examples, facts, statistics and testimony are all forms of supporting materials (sources).
In an informative presentation, definitions, examples, facts, statistics, and testimony are all forms of supporting materials (sources).
What is an informative presentation? An informative presentation aims to educate and enlighten the audience on a particular subject matter. The purpose of an informative presentation is to provide the audience with accurate, clear, and concise information on a particular topic. The speaker provides the audience with information in a way that is interesting and understandable. Informative presentations are different from persuasive presentations. In persuasive presentations, the speaker tries to persuade the audience to accept a particular point of view. In an informative presentation, the speaker provides the audience with information to enhance their understanding of a particular topic. What are supporting materials/sources? Supporting materials are used to provide evidence and support to the main points of an informative presentation. These materials are crucial as they help to establish the credibility of the speaker, and the audience gets to understand the subject matter better. Examples of supporting materials/sources used in an informative presentation include: Definitions, Examples, Facts, Statistics, Testimony, Visual aids (such as charts and graphs)In conclusion, in an informative presentation, definitions, examples, facts, statistics, and testimony are all forms of supporting materials (sources). These materials are used to provide evidence and support to the main points of the presentation, and they help to enhance the understanding of the subject matter by the audience.
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A certain shade of blue has a frequency of 7.33×1014 Hz.7.33×1014 Hz. What is the energy ????E of exactly one photon of this light? Planck's constant ℎ=6.626×10−34 J⋅s.
When a certain shade of blue has a frequency of 7.33×10¹⁴ Hz. So, the energy will be 4.86×10⁻¹⁹ J,
To calculate the energy of one photon of a certain shade of blue light with a frequency of 7.33×10¹⁴ Hz, we can use the formula: E = hf, where E is the energy of one photon, h is Planck's constant, and f is the frequency of the light.
Using Planck's constant ℎ=6.626×10⁻³⁴ J⋅s, we can calculate the energy of one photon of the blue light as follows:
E = hf = (6.626×10⁻³⁴ J⋅s)(7.33×10¹⁴ Hz) = 4.86×10⁻¹⁹ J
Therefore, the energy of exactly one photon of this light is 4.86×10⁻¹⁹ J.
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Jupiter, the largest planet in the solar system, has an equatorial radius of about 7.1 x 10^4km (more than 10 times that of Earth). Its period of rotation, however, is only 9h, 50 min. That means that every point on Jupiter's equator "goes around the planet" in that interval of time. Calculate the average speed (in m/s) of an equatorial point during one period of Jupiter's rotation. Is the average velocity different from the average speed in this case?
Answer:
The average speed is \(v = 1260 \ km/s\)
The average speed is different from the average velocity in this question
Explanation:
From the question we are told that
The equatorial radius of Jupiter is \(R_j = 7.1*10^{4} \ km\)
The period of oscillation of Jupiter is \(T_J = 9 \ hours , 50 \ min = 35400 \ seconds\)
Generally the average speed is mathematically represented as
\(v = \frac{2 \pi * R_j }{T_J}\)
=> \(v = \frac{2 *3.142 * 7.1*10^{4} }{35400}\)
=> \(v = 1260 \ km/s\)
Generally in average speed the direction is not considered while in average velocity the direction is considered for the case of this question the movement equitorial point has no direction in that it start from one point and after its periodic motion it still remains at that point
On a visit to a science lab, Madison observes a blob of shiny material that is floating in the air.
The blob is not moving.
What can she conclude about the force(s) acting on the blob?
Answer:
Each force acting on the blob has another one to cancel it out
Explanation:
Answer:
well we know for sure that gravity is not affecting it because it is floating in the air.
Explanation:
find the mass of a wrecking ball at 6m/s and has a momentum of 3600kg x m/s
the mass must be in kilograms (kg)!
m/s means "meters per second"
kg x m/s is supposed to mean "kilograms times meters per second"
also, the equation to find this is force divided by acceleration
thank you!!!
Answer:
600kgExplanation:
MOMENTUMThis is a product of a mass and velocity of a moving or a rest body.
it is expressed as P(momentum)=M(mass) × V(velocity)
Its SI unit is kgm/s
From our question.
Given
Momentum=3600kgm/s
Velocity=6m/s
RTF=Mass
Solution
P=M×V
M=P/V
= 3600kgm/s
6m/s
= 600kgA bike is traveling at a speed of 15 m/s. The mass of the bike is 30 kg. What is the kinetic
energy of the bike?
Answer:
3375 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 30 \times {15}^{2} \\ = 15 \times {15}^{2} \\ = {15}^{3} \: \: \: \: \: \: \: \: \: \: \)
We have the final answer as
3375 JHope this helps you
Kabir covers by car a distance 25 km through 4 minutes and then he covers 40km through 12 minutes. Calculate his average speed.
Answer:
4.1 km/m
Explanation:
The average speed=Total distance/total time
so
Total distance=25+40=65
Total time=4+12=16
so
the average speed is 65/76=4.1 km/m
Waves pass energy through matter ,but not space. True or false?
Compare the signs of ƒ for lenses and mirrors.
Answer:
simple
Explanation:
CONCAVE MIRRORS AND LENSESf= negativeCONVEX MIRRORS AND LENSESf= positivePLEASE FOLLOW ME AND MARK IT BRAINLIESTBoth mirror and lenses have positive as well as negative focal length.
What is lense ?A lens is a transmissive optical device that employs refraction to concentrate or scatter a light beam. A simple lens is made up of a single piece of transparent material, whereas a compound lens is made up of numerous simple lenses organized along a common axis.
For lenses
A converging lens, also known as a convex lens, has a positive focal length (f > 0). It is a lens that, after passing through it, focuses parallel beams of light.
A diverging lens, commonly known as a concave lens, has a negative focal length (f 0). It is a lens that spreads parallel beams of light after they pass through it.
For mirrors
A concave mirror has a positive focal length (f > 0). It is a mirror that focuses parallel beams of light in front of it.
A convex mirror has a negative focal length (f 0). It's a mirror that spreads out parallel beams of light as though they're originating from a virtual focal point behind the mirror.
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A woman is pulling a trolley with a 27 N force along the 3.0 m aisle, how much work is done in pulling the cart from one end of the aisle to the other?
Answer:
Work done = 81 Nm
Explanation:
To calculate the work done by a force, we can use the following formula:
\(\boxed{\mathrm{Work \: done = \: Force \times Distance \: moved \: in \ direction \: of \: force}}\).
In this question, we are told that the woman applies a force of 27 N to pull a trolley 3.0 m along an aisle. Using this information, as well as the formula above, we can calculate the work done:
Work done = 27 N × 3.0 m
= 81 Nm
Therefore, 81 Nm (or 81 Joules) of work was done pulling the cart from one end of the aisle to the other.
nuisance static charges are more likely to occur when the air is
Nuisance static charges are more likely to occur when the air is dry.
When the air is dry, it is not able to hold a sufficient amount of moisture or humidity. When the moisture content of the air is low, the air has a low electrical conductivity, which increases the likelihood of static charges.Static electricity can be created by the rubbing of two objects. When these objects are separated after rubbing, they are left with a static electric charge. The strength of the electric charge is determined by the materials used to create the two objects. Some materials are better at holding static charges than others.
Dry air only exacerbates the situation. Static charges can be a nuisance for a variety of reasons. They can cause shocks, interfere with electronic devices, and can even cause damage to sensitive equipment. In order to reduce the occurrence of static charges, it is important to ensure that the air in your environment is sufficiently humid. This can be achieved by using a humidifier or by simply placing bowls of water around the room. Additionally, anti-static products, such as sprays and mats, can be used to reduce the occurrence of static charges.
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A 500kg car is driven forward with a thrust force of 1500N. Air resistance and friction acts against the motion of the car with magnitude 200N and 300N respectively. What is the acceleration of the car?
The acceleration of the car is 2m/s^2.
What are acceleration and its SI unit?
Speed, in physics, is the rate of change of object speed in relation to time. The acceleration of an object is the sum total of any force and all that is active in an object, as defined by Newton's Second Law. The SI acceleration unit is a meter per second (m s ^ −2).
What are acceleration and velocity?
Acceleration of the vector value is defined as the rate at which an object changes speed. An object is faster when it changes its speed. Since speed is a vector model, it has direction and magnitude.
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A rocket ship has several engines and thrusters. While the solid rocket booster (srb) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8. 5 minutes after the launch. Once the srbs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.
A rocket ship has several engines and thrusters. While the solid rocket booster (srb) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8. 5 minutes after the launch. Once the srbs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s. During the first two minutes of flight, the SRB and main engine accelerate at a rate of 52.16 m/s2.
Acceleration is the rate at which a moving object's speed and direction change over time. When something moves faster or slower, it is considered to be accelerating. The engine's initial velocity (u), final velocity (v), and time of motion (t), which is equivalent to two minutes, are the parameters given (2 x 60 s).
The calculations for the main engine's and SRB's acceleration are listed below.
a= Δv / Δt
a=7600-1341 /2*60s
a=52.16 m/s²
As a result, during the first two minutes of flight, the main engine and SRB accelerate at a rate of 52.16 m/s2.
Your question is incomplete but most probably your full question is
A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBS are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.
What is the height of the rocket when the rocket reaches the speed of 7600 m/s? Show your work.
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What is concentration gradient?
Answer:
The difference in the concentration of a substance between two areas is called the concentration gradient . The bigger the difference, the steeper the concentration gradient and the faster the molecules of a substance will diffuse. The direction of diffusion is said to be 'down' or 'with' the concentration gradient.
Explanation:
The removal of coal that is not close to earths surface through a horizontal opening in the side of a hill or mountain is called
A ball is thrown directly upward from a height 10 meters above the ground at time t = 0 (seconds). The location y(t) (in meters above the ground) of the ball at time t > 0 is given by y(t) = -2t² + t + 10. (a) Find the velocity of the object at time t.
(b) Find the acceleration of the object at time t.
(c) Find the velocity of the ball at the time when it hits the ground, i.e. the time t>0 when y(t) = 0. Hint: You could use the quadratic formula to find the value of t*.
(a) The velocity of the object at time t is given by finding the derivative of y (t):
y(t) = -2t2 + t + 10dy(t)/dt
= -4t + 1
Therefore, the velocity of the object at time t is -4t + 1.
(b) The acceleration of the object at time t is given by finding the derivative of the velocity function:
dy(t)/dt = -4t + 1d2y(t)/dt2
= -4
Therefore, the acceleration of the object at time t is -4 m/s2.
(c) The ball hits the ground when y(t) = 0, so we can solve for t by setting -2t2 + t + 10 = 0 and using the quadratic formula:
t = (-b ± (b2 - 4ac)) / (2a), where a = -2, b = 1, and c = 10.
Plugging these values into the formula, we get:
t = (-1 ± (12 - 4(-2)(10))) / (2(-2)) = (1 ± 81) / 4
We take the negative root because the positive root corresponds to the ball reaching its maximum height before falling back down. Thus,
t = (1 - 81) / 4
= -2/4
= -0.5 s
To find the velocity of the ball at this time, we plug t = -0.5 into the velocity function we found in part
(a):v = -4t + 1
= -4(-0.5) + 1
= 3 m/s
Therefore, the velocity of the ball at the time it hits the ground is 3 m/s.
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A force of 24 N will stretch a rubber band 12 cm(0.12 m) Assuming that Hooke's faw applies, how lar will a 20 - N lorce stretch the rubber band? How much wokk does if take fo stretch the nubber band this far? How lar will a 20.N torce stretch the rubber band? B) (Sirnplify your answed) How mach work does ia take la stretch the rubber band this far? (Stmplify your answer)
Work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
To determine how much the rubber band will stretch under a 20 N force and the work required to stretch it, we need to apply Hooke's Law. Hooke's Law states that the force applied to a spring or elastic material is directly proportional to the displacement it undergoes.
We can set up a proportion to find the stretch under Force 2:
(F1 / S1) = (F2 / S2)
Substituting the given values:
(24 N / 0.12 m) = (20 N / S2)
To find S2, we can rearrange the equation:
S2 = (20 N * 0.12 m) / 24 N
Simplifying:
S2 = 0.10 m
Therefore, a 20 N force will stretch the rubber band by 0.10 meters.
Now, let's calculate the work required to stretch the rubber band this far. The work (W) can be calculated using the formula:
W = (1/2) * k * (S2^2 - S1^2)
Where k is the spring constant.
However, we don't have the spring constant (k) given in the problem. So, we cannot determine the exact work without that information.
But, if we assume that the rubber band behaves as a linear spring and Hooke's Law applies, we can simplify the equation. Hooke's Law states that the force applied to a spring is equal to the spring constant (k) multiplied by the displacement (S).
F = k * S
Rearranging the equation:
S = F / k
Since the stretch (S) is directly proportional to the force (F), we can approximate the work required by assuming a constant k value:
W ≈ (1/2) * k * (S2^2 - S1^2)
W ≈ (1/2) * k * [(0.10 m)^2 - (0.12 m)^2]
Simplifying:
W ≈ (1/2) * k * (0.01 m^2 - 0.0144 m^2)
W ≈ (1/2) * k * (-0.0044 m^2)
Without the exact value of the spring constant, we cannot calculate the work precisely. However, we can still conclude that the work required to stretch the rubber band by 0.10 meters will be negative, indicating that work needs to be done against the force applied to stretch the rubber band.
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if you ran 3.1 miles in 0.5 hours. what was your speed
Answer:
speed= 6.2 m/hrExplanation:
distance= 3.1 mile
time=0.5 hours
s=d/t
s=3.1/0.5
speed= 6.2 m/hr
If you run for a distance of 3.1 miles in 0.5 hours, then the speed in miles per hour will be 6.2 m/hr.
What is Speed?A scalar quantity in kinematics and common usage, an object's speed is the size of the change in its position over time or the amount of change in its position per unit of time.
As the duration of the time interval approaches zero, the instantaneous speed is the maximum limit of the average speed. The distance traveled divided by the duration of the interval represents the average speed of an object over a period of time.
Given information,
Distance covered, d = 3.1 miles
Time taken, t = 0.5 hours
Speed = \(Distance/time\)
Speed = 3.1/0.5
Speed = 6.2 m/hr
Therefore, the speed while running is 6.2 m/hr.
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Find the tension in the two groups that are holding the 2.9 kg object in Pl., One makes an angle of 35.6° with respect to the vertical group 2 is pulling horizontally
Answer:
≈ 20.35 N [newton's of tension]
Explanation:
( (2.9 × 9.8) ÷ cos(35.6°) ) × sin (35.6°) =
( (28.42) ÷ (≈0.813) ) × (≈0.582) =
(≈34.96) × (≈0.582) = 20.3449446.... ≈ 20.35
the orbital angular momentum of an electron has a magnitude of 4.716×10−34kg⋅m2/s.
The angular-momentum quantum number l for this electron will be:
L= sqrt [l(l+ 1)]h
4.716e-34 J-s = sqrt[l(l+1)] (6.626e-34 J-s)/(2TT)
20 = l(l + 1)
l= 4
What is angular momentum?
In physics, angular momentum (rarely momentum or angular momentum) is the rotational analogue of linear momentum. It is an important physical quantity because it is conserved. The total angular momentum of a closed system remains constant. Angular momentum has both direction and magnitude, both of which are conserved.
A useful property of bicycles, motorcycles, frisbees, bullets, and gyroscopes is due to the conservation of angular momentum. Conservation of angular momentum is also why hurricanes spin in spirals and neutron stars spin at high speeds. Conservation generally limits the possible motion of the system, but does not explicitly determine it.
Therefore, The angular-momentum quantum number l for this electron will be 4.
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you observe a full moon rising at sunset. what will you see 6 hours later? view available hint(s)for part k you observe a full moon rising at sunset. what will you see 6 hours later? a first quarter moon a full moon on or near your meridian a waning gibbous moon a third quarter moon
Six hours after observing a full moon rising at sunset, you will see a full moon on or near your meridian. A full moon occurs when the moon is positioned opposite the sun, with the Earth in between.
The moon goes through different phases as it orbits around the Earth, and its appearance changes based on the relative positions of the sun, Earth, and moon. A full moon occurs when the moon is positioned opposite the sun, with the Earth in between. This is why a full moon rises at sunset.
As time passes, the moon continues its orbit around the Earth. After six hours, the Earth's rotation will cause the moon to move approximately one-quarter of the way around its orbit. Therefore, the full moon will be on or near your meridian, which means it will be directly overhead or at its highest point in the sky.
It's important to note that the moon's phase does not change significantly within a span of six hours, so it will still appear as a full moon during this time.
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what determines how many electoral votes a state gets
The number of electoral votes a state gets is determined by the number of senators and representatives it has in Congress.
Each state has two senators in the United States Senate, regardless of its population size. The number of representatives a state has in the United States House of Representatives is determined by its population size, as reported in the census.
The total number of electors in the electoral college is equal to the number of senators (which is 100, since there are 2 senators per state) plus the number of representatives (which is based on each state's population size and can range from 1 to 53).
For example, California, which has 2 senators and 53 representatives, has a total of 55 electoral votes, while Wyoming, which has 2 senators and 1 representative, has a total of 3 electoral votes.
This system ensures that each state has a minimum of 3 electoral votes, while larger states have more proportional representation based on their population.
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