A vessel is filled with a gas at a temperature 30c and a pressure of 760mmhg calculate the final pressure if the volume of the gas is double while it's heated at 80c

If the wire is tipped at an angle of 15.0° with the horizontal, we need to determine the force it will now feel. The length of the wire that will be in the magnetic field is relevant to finding the answer.

When a wire carrying current is placed in a magnetic field, it experiences a force perpendicular to both the direction of current flow and the magnetic field. In this case, when the wire is tipped at an angle of 15.0° with the horizontal, only a component of the wire's length will be in the magnetic field.

To find the force, we need to consider the effective length of the wire in the magnetic field. This can be calculated by multiplying the actual length of the wire by the cosine of the angle between the wire and the magnetic field. Once we have the effective length, we can use the formula for the force on a current-carrying wire in a magnetic field, which is given by the equation F = BIL, where B is the magnetic field strength, I is the current, and L is the length of the wire in the field. By substituting the effective length into the equation, we can determine the force the wire will experience.

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The fundamental period (To) of a signal is the smallest T for which it repeats. Frequency (Wo) is the reciprocal of To. Example: To = 0.5s, Wo = 2Hz.

The fundamental period (To) of a periodic signal is the smallest positive value of T for which the signal repeats itself exactly. The frequency (Wo) of a periodic signal is the reciprocal of the fundamental period,

Wo = 1/To.

To find the fundamental period and frequency of a signal, we need to analyze its waveform.

First, let's identify the period of the signal. The period is the horizontal distance between two adjacent peaks (or troughs) of the waveform. If the signal repeats itself exactly, it is periodic.

Once we have identified the period, we can calculate the fundamental period (To) by measuring the distance between two adjacent peaks (or troughs) and taking the smallest positive value.

To calculate the frequency (Wo), we can use the formula Wo = 1/To. Here's an example to illustrate this process:

Let's say the signal waveform repeats itself every 2 seconds. This means the period is 2 seconds.

To calculate the fundamental period (To), we measure the distance between two adjacent peaks (or troughs) and find it to be 0.5 seconds.

Therefore, the fundamental period (To) is 0.5 seconds.

To calculate the frequency (Wo), we use the formula Wo = 1/To. In this case, Wo = 1/0.5 = 2 Hz. So, the fundamental period (To) of the signal is 0.5 seconds and the frequency (Wo) is 2 Hz.

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Given:

The mass on the table is,

The hanging mass is,

THe coefficient of friction is,

let the acceleration of the whole system is a (for the hanging mass it is downward and for the mass on the table it is rightward). the tension towards The fixed point of the pulley is T.

we can write,

Adding these equations we get,

Substituting the values we get,

Hence the acceleration is 6.66 m/s^2.

To determine the size of the copper conductor needed for a branch circuit, we need to consider the load and the allowable ampacity. The National Electrical Code (NEC) provides guidelines for selecting conductor sizes based on the expected load and the length of the circuit.

Here are the steps to calculate the conductor size:

1. Determine the load: Find out the total load that will be connected to the circuit. This includes all the devices and appliances that will be powered by the circuit.

2. Calculate the ampacity: Ampacity is the maximum current that a conductor can carry without exceeding its temperature rating. It is determined by the type of conductor and its size. Refer to the NEC tables to find the ampacity rating for the specific conductor size.

3. Consider the length of the circuit: Longer circuits experience more resistance, which affects the ampacity. Refer to the NEC tables to find the adjusted ampacity based on the length of the circuit.

4. Apply the derating factors: Depending on the type of installation and the number of conductors in the circuit, derating factors may be applied to the ampacity. Refer to the NEC for the specific derating factors.

5. Select the conductor size: Compare the adjusted ampacity with the load. Choose the conductor size that has an ampacity rating equal to or greater than the calculated load.

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Answer:

\(F=683.790939\)N

Explanation:

From the Question we are told that

Earth mass \(m_1= 5.98 * 10^2^4 kg\)

Students mass \(m_2=70kg\)

Distance of student from earth center Radius \(r=6.39 * 10^6 m\)

Generally the equation for Force of attraction b/w the earth and the boy is mathematically given by

 \(F=\frac{Gm_1m_2}{r^2}\)

 \(F=\frac{6.67.10^-^1^1*( 5.98 x 10^2^4)(70)}{(6.39 *10^6)^2}\)

Therefore the force of attraction b/w the student and the earth is

 \(F=683.790939N\)

 \(F\approx 684N\)

Explanation:

\(pe = mgh \: \\ taking \: g \: as \: 10ms^{ - 2} \\ 100 = 8.0 \times 10 \times h \\ h = 1.25m \\ \\ using \: newtons \: third \: equation \\ v^{2} = u^{2} + 2gh \\ where \: v \: is \: final \: velocity \: and \: u \: is \: initial \: velocity \: = 0 \\ v^{2} = 0 + 2 \times 10 \times 1.25 \\ = 25 \\ v = 5.0ms^{2} \)

A star with a mass like our Sun cannot fuse elements beyond carbon and oxygen because it does not have sufficient temperature and pressure in its core to overcome the strong electrostatic repulsion between the atomic nuclei of heavier elements.

Stars generate energy through nuclear fusion, where lighter elements combine to form heavier elements in their cores. In the case of a star like our Sun, it primarily fuses hydrogen into helium. As the hydrogen in the core depletes, the core contracts and heats up, allowing for helium fusion to occur. This process creates elements like carbon and oxygen.
However, fusing elements beyond carbon and oxygen requires much higher temperatures and pressures. This is due to the strong electrostatic repulsion between the positively charged atomic nuclei of these heavier elements, also known as the Coulomb barrier. To overcome this barrier, the core needs to have enough energy for the nuclei to come close enough together for the strong nuclear force to bind them.
In summary, a star with a mass like our Sun cannot produce elements beyond carbon and oxygen because its core does not reach the necessary temperature and pressure required to overcome the electrostatic repulsion between the nuclei of heavier elements.

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Answer:

Hey!

I did this question and have the answers/potential things you can write!

XD

Explanation:

Here!

structure

•alpha particle consists of a helium nucleus

•alpha particle consists of 2 protons and 2 neutrons

•a beta particle is an electron

•a beta particle comes from the nucleus  

penetration

•alpha particles are very poorly penetrating

•alpha particles can penetrate a few cm in air

•alpha particles are absorbed by skin

•alpha particles are absorbed by thin paper

•beta particles can penetrate several metres of air

•beta particles can pass through thin metal plate / foil

•beta particles can travel further than alpha particles in air

•beta particles can travel further than alpha particles in materials eg metals  

deflection

•alpha particles and beta particles are deflected in opposite directions in an electric field

•beta particles are deflected more than alpha particles

•alpha particles have a greater charge than beta particles but beta particles have much less mass or beta particles have a greater specific charge than alpha particles

Hope this helps!

Sorry if it's a bit too long!

Bulb A (60 W) will glow brighter than Bulb B (40 W) due to its lower resistance. Switching the bulbs does not change their relative brightness. Both bulbs operate at their power ratings without exceeding their design limits.

To determine which bulb glows brighter and analyze the effects of switching their order, we need to calculate the power and resistance for each bulb.

Let's start with the given information:

- Voltage (V) = 120 V

- First bulb (Bulb A): Power (P) = 60 W

- Second bulb (Bulb B): Power (P) = 40 W

To calculate the resistance (R) for each bulb, we can use Ohm's Law, which states that resistance is equal to voltage divided by current:

\(R = \frac{V^2}{P}\)

Let's calculate the resistance for each bulb:

For Bulb A:

\(\begin{equation}R_A = \frac{(120~\text{V})^2}{60~\text{W}} = 240~\Omega\)

For Bulb B:

\(\begin{equation}R_B = \dfrac{(120\text{ V})^2}{40\text{ W}} = 360\Omega\)

Now, to determine which bulb glows brighter, we can compare their resistances. The bulb with the lower resistance will have a higher current flowing through it, and thus, it will glow brighter.

Comparing the resistances:

\(R_A\) = 240 Ω (Bulb A)

\(R_B\) = 360 Ω (Bulb B)

Since the resistance of Bulb A (240 Ω) is lower than the resistance of Bulb B (360 Ω), Bulb A will glow brighter.

Now, let's switch the order of the bulbs and see how it affects their brightness. If we switch the bulbs, the new configuration will be: Bulb B (40 W) followed by Bulb A (60 W).

Calculating the resistances for the switched configuration:

For Bulb B (40 W):

\(\begin{equation}R_B = \frac{(120~\text{V})^2}{40~\text{W}} = 360~\Omega\)

For Bulb A (60 W):

\(\begin{equation}R_A = \frac{(120~\text{V})^2}{60~\text{W}} = 240~\Omega\)

Comparing the resistances:

\(R_B\) = 360 Ω (Bulb B)

\(R_A\) = 240 Ω (Bulb A)

Even after switching the bulbs, the resistance values remain the same. Therefore, Bulb A (60 W) will still glow brighter than Bulb B (40 W).

Both bulbs are operating at their respective power ratings. The power ratings (60 W and 40 W) indicate the maximum power each bulb can handle without exceeding their design limits.

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Answer:

C.Conflict often occurs over natural resources.

Explanation:

Conflict always occurs if two countries or groups fight over anything that both think is theirs.

UN seems to agree: https://peacekeeping.un.org/en/conflict-and-natural-resources

Answer:

B

Explanation:

The real weight of the fish is equal to 166.15 N

The acceleration brought on by gravity is another name for the constant g. This acceleration would be present if an object were falling toward the surface of a big body. The falling object would experience this acceleration at its maximum in free fall.

Weight strength and normal strength

Two forces—the weight force and the normal force—must be taken into account in order to find a solution to this problem.

The fish being weighed in the scenario of the question is moving upwardly in an elevator, hence the force that the balance will be measuring is:

                                 Fn = m * (g+a)

So, applying the given values we have:

                               200=m(9.81*1.2)

                                m= 16.93 kg

Finally, to find the weight of the fish, simply multiply the value of the mass by gravity, so that:

                      F= 16.93 * 9.81

                      F= 166.15 N

So, the real weight of the fish is equal to 166.15N.

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Answer:

True, but we dont know for sure because humans have only ever saw one side of the sun

Explanation:

The resultant of the forces is 29 N. Option D

The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.

Thus;

Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))

Resultant = 29 N

Thus, the resultant of the forces is 29 N.

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Missing parts;

Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force

A.17N

B. 19N

C. 23N

D. 29N

E. 37N​

Answer:

action = reaction

land accepts

reaction force acts on the apple

Answer:

15 Newton

Explanation:

According to Newton's third law of motion, "Every action has a reaction which is equal in magnitude but opposite in direction" (Right now, we're not talking about direction, so we'll ignore it)

So,

Action Force = Reaction Force

Reaction Force = 15 N

The action force is by the Earth on the Apple, So the reaction force will be by the Apple on the Earth.

The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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Coltan is likely to carelessly test the weight, length, and height variables haphazardly. However, Jason will most likely do systematic tests of the variables because this is when kids start to think scientifically.

What does auditing's haphazard sampling entail?

A nonstatistical method known as "haphazard sampling" is used to choose sample items without any deliberate bias and without giving a justification for adding or omitting any particular items.

What is an example of haphazard sampling?

The vox pop poll, in which the interviewer chooses any passerby, is an illustration of accidentally. Unfortunately, selection is susceptible to the biases of the interviewer and anybody who happens to pass by at the moment of sampling unless the population units are actually comparable.

What distinguishes haphazard sampling from random sampling?

By numbering each item in the population and using random number tables to determine which things to investigate, random selection ensures that every member of the population has an equal chance of being chosen. Haphazard refers to the way a person chooses things, probably in an effort to mimic randomness.

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The ball is dropped from rest from a height of 2h, it will reach a speed of v multiplied by sqrt(2) just before impact with the ground.

Given,The ball that is dropped from rest from a height 'h' reaches a speed 'v' just before impact with the ground. If the ball is dropped from rest from a height of 2h, instead, it will reach a speed of v multiplied by _______ just before impact with the ground.To find the missing value, we need to find the relation between h and v.As per the law of conservation of energy, the total energy remains conserved.

So, the potential energy of the ball at the initial point will be equal to the kinetic energy of the ball just before impact with the ground.Using the principle of conservation of energy, we can say that: Initial Potential Energy = Final Kinetic EnergyInitial potential energy of the ball = mgh1.

Final Kinetic energy of the ball = 1/2 m v1²where,m = mass of the ballh1 = height from which the ball is droppedv1 = velocity of the ball just before impact with the ground. When the ball is dropped from a height of 2h, thenInitial potential energy of the ball = mgh2

Final Kinetic energy of the ball = 1/2 m v2²where,h2 = 2hAs per the law of conservation of energy,Initial Potential Energy = Final Kinetic Energymgh2 = 1/2 m v2²v2 = sqrt(2gh2)......(i)

Also, when the ball is dropped from a height of h, then. Initial potential energy of the ball = mgh

Final Kinetic energy of the ball = 1/2 m v3²where,h = hSo, v3 = sqrt(2gh)........(ii)From equation (i),v2 = sqrt(2gh2) = sqrt(2g * 2h)v2 = sqrt(4gh).........(iii)Dividing equation (iii) by equation (ii), we get:v2/v3 = sqrt(4gh)/sqrt(2gh) = sqrt(2)

Hence, the ball is dropped from rest from a height of 2h, it will reach a speed of v multiplied by sqrt(2) just before impact with the ground.

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Answer:

The answer would be Front Line

The base line, service line, and the side lines are the part of the tennis court however front line is not a part of the tennis court. Thus, the correct option is D.

A tennis court is a 78ft long court, with a service line of 21ft from the net. The courts for singles tennis matches are 27ft wide in dimension, while the doubles matches courts are 36ft wide. The total playing area in tennis for a singles court is 2,106ft² and 2,808ft² for a doubles court.

The basic and important parts of a tennis court in both singles and doubles are the baseline, the center mark, the sidelines, the service lines, and the service boxes. The baseline is the boundary line at the ends of the tennis court, and the sidelines are the lines which mark the boundary line between in-bounds and out-of-bounds for both singles and doubles play.

Therefore, the correct option is D.

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Answer:

easy

Explanation:

Answer:

Explanation:

In a sonometer , expression for speed of wave produced can be given as follows .

v = \(\sqrt{\frac{T}{m} }\)

v is velocity , T is tension in wire , m is density per unit length .

Here v is inversely proportional to square root of m . So if m becomes m / 4

velocity changes as follows .

velocity = \(\sqrt{\frac{T}{\frac{m}{4} } }\)

= \(\sqrt{\frac{4T}{m} }\)

= 2v

velocity becomes two times . Hence to make velocity two times , mass per unit length  has to be changed to one fourth value , keeping tension constant .

The speed of the sound wave after the flash was seen, in the experiment for measuring the speed of sound gun is 110 m/s.

The speed of the sound wave can be determined by applying the principle of echoe as shown below;

v = 2d/t

where;

v = (2 x 715) / (13)

v = 110 m/s

Thus, the speed of the sound wave after the flash was seen, in the experiment for measuring the speed of sound gun is 110 m/s.

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To determine the mass moment of inertia (Iy) of the solid formed by revolving the shaded area around the y-axis, we need more specific information about the shaded area, such as its shape and dimensions.

To calculate the mass moment of inertia (Iy), we need to know the distribution of mass around the y-axis. This requires information about the shape and dimensions of the shaded area. Without this specific information, it is not possible to provide a precise calculation for Iy.

In general, the mass moment of inertia depends on the mass distribution and the axis of rotation. The formula for the mass moment of inertia varies depending on the shape of the object being rotated. For different shapes, such as a disc, cylinders, or irregular objects, specific formulas or integration methods are used to calculate the moment of inertia.

To accurately determine Iy, we would need to know the exact shape, dimensions, and mass distribution of the shaded area being revolved around the y-axis. With this information, appropriate formulas or integration techniques can be applied to calculate the mass moment of inertia.

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Answer:

A. the matter in the universe will slow the expansion to the point where it would finally come to a halt and then start to retract

Explanation:

Answer:

the matter in the universe will slow the expansion to the point where it would finally come to a halt and then start to retract

Explanation:

Plato/Edmentum

The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.

The freezing point is the temperature at which the substance changes its phase from liquid to solid.

The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.

Answer:

Just as images are reflected from the surface of a mirror, light reflected from a smooth water surface also produced a clear image. ... Consequently, the outgoing rays are reflected at many different angles and the image is disrupted. Reflection from such a rough surface is called diffuse reflection and appears matte.

Explanation:

hi po I hope it's help you

The greatest amount of gravitational potential energy at landing site X

To calculate the gravitational potential energy at each landing site, we can use the formula:

Gravitational Potential Energy (PE) = mass × acceleration due to gravity × height above surface

If the mass is assumed to be constant, we can ignore it and focus on the acceleration due to gravity and height above the surface.

From the table, we can see that the lander would have the greatest amount of gravitational potential energy at landing site X, with a value of 592.8 Joules.

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Answer:

m = 35 g

Explanation:

The specific heat of a material can be calculated by the following formula:

\(C = \frac{Q}{m}\\\)

where,

C = Specific Heat of Wax = 220 J/g

Q = Amount of Heat Supplied by the Heater = 7700 J

m = mass of wax melted = ?

Therefore,

\(220\ J/g = \frac{7700\ J}{m}\\\\m = \frac{7700\ J}{220\ J/g}\\\)

m = 35 g