An expression is shown 1\3 × 2\5 what is the value of the expression​

Answer:

Step-by-step explanation:

Clara is incorrect. When you do the math, 4 squared is basically saying multiply four times four. Which equals Sixteen. When you divide Sixteen by two you get eight, not four. My math is listed below.

4^2 (4 • 4) = 16

16/2 = 8

Answer:

x=m+z

Step-by-step explanation:

its right

Answer:6

Step-by-step explanation:

there is a law for that:

5*12=x*(x+4)

60=x*x+4x

x*x+4x-60=0

(x+2)*(x+2)-64=0

(x+2)(x+2)=8*8

x+2=8

x=6

Answer:6

Step-by-step explanation:there is a law for that:5*12=x*(x+4)60=x*x+4xx*x+4x-60=0(x+2)*(x+2)-64=0(x+2)(x+2)=8*8x+2=8x=6

Yes, that's correct. When a figure is dilated from the origin, each ordered pair of the figure is transformed according to the rule

What is dilation in maths ?

A dilation is a function f from a metric space M into itself that fulfils the identity d=rd for all locations x, y in M, where d is the distance between x and y and r is some positive real number.

Yes, that's correct!

When a figure is dilated from the origin, each ordered pair of the figure is transformed according to the rule (x, y) → (kx, ky), where k is the scale factor. The scale factor determines the size of the dilation; if k > 1, the dilation increases the size of the figure, while if 0 < k < 1, the dilation decreases the size of the figure. If k = 1, the figure remains unchanged.

It's important to note that dilations preserve the orientation of the figure and can be thought of as a non-uniform scaling of the figure.

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Linear regression forecasting is an algorithm used for identifying and predicting the future values of a dependent variable based on the independent variable.

The major restriction in linear regression forecasting is that it only takes into account the linear relationship between the dependent and independent variables.

The model assumes that the relationship between the dependent and independent variable is linear and not nonlinear. This assumption may not always be true because there might be cases where the relationship between the variables is non-linear, which can result in inaccuracies in the forecast.

The model's reliability is also based on the quality of the data used for regression analysis. If the data is incorrect, outdated, or incomplete, the accuracy of the model can be negatively affected. Another limitation is that the model assumes that the relationship between the dependent and independent variables is constant over time, which may not be true in the real world.

Also, linear regression is a parametric method that requires certain assumptions about the data, including the normality of the residuals and constant variance of the errors.Linear regression forecasts require data to be independent and unbiased and may not work well if data contains outliers or noise.

Linear regression cannot identify causality or differentiate between correlation and causality. Hence, it is recommended to use linear regression along with other techniques for better accuracy.

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Answer:

13

Step-by-step explanation:

If 169 m² is the area of a square, then the length of the side is

√(169 m²) = 13 m

Answer:

sm like this hope this helps your welcome

Answer:

(1) The first quartile of standard normal distribution is -0.67.

(2) The third quartile of standard normal distribution is 0.67.

(3) The percentage of the observations in the standard normal distribution that are suspected outliers is, 0.74%.

Explanation:

A standard normal distribution has mean 0 and variance 1.

(1)

The first quartile of any data is the value below which 25% of the data lie.

That is, P (Z < z) = 0.25.

The value of z is -0.67.

Thus, the first quartile of standard normal distribution is -0.67.

(2)

The third quartile of any data is the value below which 75% of the data lie.

That is, P (Z < z) = 0.75.

The value of z is 0.67.

Thus, the third quartile of standard normal distribution is 0.67.

(3)

In case of a standard normal distribution values lying outside the range

(Q₁ - 1.5 IQR, Q₃ + 1.5 IQR)

are considered as outlier.

Compute the range as follows:

Compute the probability of (Z < -2.68) and P (Z > 2.68) as follows:

The probability of a value being an outlier is,

P (Outlier) = P (Z < -2.68) + P (Z > 2.68)

                = 0.0037 + 0.0037

                = 0.0074

The percentage of the observations in the standard normal distribution that are suspected outliers is, 0.0074 × 100 = 0.74%.

Step-by-step explanation:

Hope this helped...

Answer:

Y2-y1/x2-x1

=2-(-6)/2-(-2)

=8/4

=2

Step-by-step explanation:

Given two points of a line to find the slope we use the formula; y2-y1/x2-x1 Hence the answer above.

The statement that best describes the composition of most foods is: "They contain mixtures of the three energy nutrients, although only one or two may predominate."

Most foods contain mixtures of the three energy nutrients, namely carbohydrates, proteins, and fats. However, the relative proportions of these nutrients can vary significantly from one food to another. In some foods, one or two of these nutrients may predominate, while others may contain relatively equal amounts of all three.

Carbohydrates are a primary source of energy for the body and can be found in various forms such as sugars, starches, and fibers. Foods like grains (e.g., rice, wheat, oats), fruits, vegetables, and legumes tend to be rich in carbohydrates. However, the specific types and amounts of carbohydrates can vary widely.

Proteins are crucial for building and repairing tissues, as well as for various metabolic functions. Foods like meat, poultry, fish, eggs, dairy products, legumes, nuts, and seeds are excellent sources of protein. Again, the protein content in different foods can vary.

Fats, also known as lipids, are an important energy source and provide essential fatty acids. Foods such as oils, butter, avocados, nuts, and fatty meats are high in fats. Like carbohydrates and proteins, the fat content in foods can differ significantly.

It's worth noting that some foods may predominantly consist of one specific nutrient. For example, pure sugar is almost entirely composed of carbohydrates, while pure oil is almost entirely composed of fats. However, most whole foods, such as fruits, vegetables, grains, meats, and dairy products, contain a mixture of these energy nutrients.

Furthermore, a balanced diet typically includes a combination of these nutrients in appropriate proportions. A varied diet that incorporates a range of foods from different food groups helps ensure an adequate intake of carbohydrates, proteins, and fats, along with other essential nutrients required for optimal health.

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9514 1404 393

Answer:

Step-by-step explanation:

The formula for slope (m) of a line between two points is ...

  m = (y2 -y1)/(x2 -x1)

Pick two points from the table and fill in the values. Using the last two table entries, we have ...

  m = (7 -5)/(5 -2) = 2/3

The slope is 2/3.

(a) Find the dual of the LP.Primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\) subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n \leq\) \(b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n \leq b_m$ and $x_1, x_2,\)..., x_n\(\geq 0$\)

Let us find the dual of the above primal problem.

Dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq\)\(C_1$...$a_{1n}y_1+a_{2n}y_2+...+a_{mn}y_m \leq C_n$\)

and\($y_1, y_2, ..., y_m \geq 0$\)

(b) Find the standard form of the LP and dual.Standard form of the primal problem isminimize \($b_1y_1+C_1x_1+...+C_nx_n$\)subject to \($a_{11}x_1+a_{12}x_2+...+a_{1n}x_n +s_1 = b_1$...$a_{m1}x_1+a_{m2}x_2+...+a_{mn}x_n +s_m = b_m$\) and\($x_1, x_2, ..., x_n, s_1, s_2, ..., s_m \geq 0$\)

Standard form of the dual problem ismaximize \($b_1y_1+...+b_my_m$\)subject to \($a_{11}y_1+a_{21}y_2+...+a_{m1}y_m \leq 0$...$a_{1n}y\)

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The mean number of miles the hiker walked for the 6 days is 5.5. We can find it in the following manner.

To find the mean number of miles the hiker walked for the 6 days, we need to calculate the sum of the number of miles and then divide it by 6 (the number of days).

Sum of miles = 8 + 5 + 7 + 2 + 2 + 9 = 33

Mean = Sum of miles / Number of days = 33 / 6 = 5.5

Therefore, the mean number of miles the hiker walked for the 6 days is 5.5.

The closest option to this value is option C: 6.5. However, it is not the correct answer.

In mathematics, the mean is the average of a set of data, which is calculated by adding all the numbers together and then dividing the result by the total number of numbers. For instance, the mean for the collection of values 8, 9, 5, 6, 7 is 7, since 8 + 9 + 5 + 6 + 7 = 35, and 35/5 = 7.

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Answer:

Step-by-step explanation:

h(t) = t2 - 8t + 12

Putting value of t = 0

h(0) = (0)2 - 8(0) + 12

= 0 - 0 + 12

= 12

Answer:

i'm sorry i don't know it

Step-by-step explanation:

hope u have a good day

By greatest common divisor , we can say the most bags that may be produced are 12, and each of those 12 bags will include two pencils, three candy bars, and four erasers.

The biggest number that divides both of two integers is referred to as the greatest common divisor (gcd), or greatest common divisor. For instance, 5 is the largest common divisor of 20 and 15. This is so that 5 can divide both 20 and 15, which is a quality that higher numbers lack.

Since you have 36 candy bars, 24 pencils, and 48 erasers to divide among the gift bags and you want to divide the items evenly and not have any items left over, the calculation that follows must be done in order to determine, if you make the most gift bags possible, how many of each item would go in each bag:

It is necessary to find the three numbers' highest common divisor.

\(24 = 2, 3, 4, 6, 8, 12, 24\\36 = 2, 3, 4, 6, 9, 12, 18, 36\\48 = 2, 3, 4, 6, 8, 12, 24, 48\)

The maximum number of bags that may be produced is 12, as 12 is the largest common divisor of these integers.

Thus, there will be two pencils, three candy bars, and four erasers in each of the 12 bags.

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A plasmid used in both yeast and bacteria requires two different selection markers because the same selection may not work for both hosts and bacteria and yeast recognize different promoters.

When using a plasmid in both yeast and bacteria, it is important to have two different selection markers for several reasons. First, the same selection, such as the presence of an antibiotic, may not be effective in both hosts. Different organisms have varying sensitivities to antibiotics, so a marker that works in bacteria may not work in yeast or vice versa. Therefore, two different selection markers are needed to ensure successful selection in both hosts.

Additionally, bacteria and yeast recognize different promoters, which are DNA sequences that control the initiation of gene expression. Promoters are specific to each organism and play a crucial role in regulating gene expression. By incorporating two different selection markers into the plasmid, each marker can be driven by a promoter recognized specifically by the corresponding host. This ensures that the selection marker is effectively expressed in the appropriate host organism, enabling accurate selection and maintenance of the plasmid.

In summary, using two different selection markers in a plasmid intended for both yeast and bacteria is necessary because the same selection may not be effective in both hosts, and different promoters are recognized by bacteria and yeast. This approach allows for successful selection and maintenance of the plasmid in both organisms.

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Answer:

1) B

2) B

Step-by-step explanation:

The only two factors of 17 are 1 and 17

and a multiple of 8 is 48 (6x8)

have a great day, also can I please be brianliest :)

Answer:

Step-by-step explanation:

In similar triangles corresponding angles have the same measure.

Answer:

x = -6

Step-by-step explanation:

we can see that x=-6 when y=2 on the graph

Answer:

-4 should be the answer

good luck

a) The period is 6 months, which means C = 2π/6 = π/3.

b)The formula for A(t) in months is given by: A(t) = 800 + 100sin((π/3)(t - 3))

c) The estimated population on October 1 is approximately 826 antelope.

a) To graph the antelope population A with respect to time t over the year, we can use a sinusoidal function that models the population variation. The general form of a sinusoidal function is:

A(t) = A₀ + Bsin(C(t - D))

Where:

A₀ is the average value of the function (midpoint between the low and high points)

B is the amplitude (half the distance between the low and high points)

C affects the period of the function (controls how quickly it oscillates)

D represents a phase shift (horizontal translation of the function)

Given that the low point is 700 on January 1 and the high point is 900 on July 1, we can determine the values for A₀ and B:

A₀ = (700 + 900) / 2 = 800

B = (900 - 700) / 2 = 100

To find the period, we need to determine how many months it takes to go from January 1 to July 1:

January to July = 6 months

Therefore, the period is 6 months, which means C = 2π/6 = π/3.

To find D, we need to determine the phase shift. Since the low point occurs on January 1, we want to shift the function to the right by half a period (3 months):

D = 3

Thus, the formula for A(t) in months is:

A(t) = 800 + 100sin((π/3)(t - 3))

b) The formula for A(t) in months is given by:

A(t) = 800 + 100sin((π/3)(t - 3))

c) To calculate the population on October 1, we substitute t = 10 (October is the 10th month) into the formula:

A(10) = 800 + 100sin((π/3)(10 - 3))

      = 800 + 100sin((π/3)(7))

      ≈ 800 + 100sin((7π)/3)

      ≈ 800 + 100sin(7.33)

Using a calculator or a math software, we find:

A(10) ≈ 826.02

Therefore, the estimated population on October 1 is approximately 826 antelope.

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Answer:

FOIL

Step-by-step explanation:

" is just a mnemonic. It helps some people to remember all the steps needed to multiply two binomials. It "makes sense" because it's methodical and gives the right answer.

So, approximately 25% of mail deliveries are made after 6:00 p.m.

To determine the percentage of mail deliveries that are made after 6:00 p.m., we need to find the proportion of the continuous uniform distribution that lies between 6:00 p.m. and 7:00 p.m.

The total range of delivery times is 4 hours (from 3:00 p.m. to 7:00 p.m.), so the distribution has a uniform density of 1/4 over this range.

The proportion of deliveries made after 6:00 p.m. is the proportion of the area under the density curve that lies to the right of 6:00 p.m.

The area under the density curve from 3:00 p.m. to 6:00 p.m. is (6:00 - 3:00)/(7:00 - 3:00) = 3/4 of the total area.

Therefore, the proportion of deliveries made after 6:00 p.m. is (1 - 3/4) = 1/4, or 25%.

So, approximately 25% of mail deliveries are made after 6:00 p.m.

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Answer:

I believe that it is B. The line does not pass through the origin.

Step-by-step explanation:

I think that it is B because the line does not go directly through the middle.

The graph does not represent a proportional relationship because The line does not pass through the origin option (B) is correct.

It is defined as the relationship between two quantity as the one quantity increases the other quantity also increases and vice versa.

We have a graph of a straight line.

As we know, if two variables are in a proportional relationship then we can write the relation as follows:

y ∝ x

Removing proportional sign:

y = kx

The above equation represents a equation of the line that passes through the origin (0, 0)

As we know, If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

Thus, the graph does not represent a proportional relationship because The line does not pass through the origin option (B) is correct.

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Answer:(24+12\3)m

Step-by-step explanation:

Answer: D) a V shaped graph with vertex at(2,4) which opens up

Step-by-step explanation:

Answer:

d

any more help just ask :)

The value of the line integral ∫C (x+5y)dx + (4x-3y)dy along the curve

C is 0.

To evaluate the line integral ∫C (x+5y)dx + (4x-3y)dy along the curve C:

x = 6cost, y = 12sint (0 ≤ t ≤ 4π), we need to substitute the parametric equations for x and y into the given expression and integrate with respect to t.

Let's calculate the line integral step by step:

∫C (x+5y)dx + (4x-3y)dy

= ∫[0,4π] ((6cost + 5(12sint))(dx/dt) + (4(6cost) - 3(12sint))(dy/dt)) dt

= ∫[0,4π] ((6cost + 60sint)(-6sint) + (24cost - 36sint)(12cost)) dt

= ∫[0,4π] (-36costsint - 360sintsint + 288costcost - 432costsint) dt

= ∫[0,4π] (-360sintsint - 144costsint + 288costcost) dt

= ∫[0,4π] (-144costsint - 360sintsint + 288costcost) dt

Now we can integrate each term separately:

∫[0,4π] (-144costsint) dt = -144 ∫[0,4π] costsint dt

∫[0,4π] (288costcost) dt = 288 ∫[0,4π] costcost dt

∫[0,4π] (-360sintsint) dt = -360 ∫[0,4π] sintsint dt

The integrals of costsint and sintsint over the interval [0,4π] evaluate to zero since they are periodic functions with a period of 2π.

Therefore, the line integral simplifies to:

∫C (x+5y)dx + (4x-3y)dy = -144 ∫[0,4π] costsint dt + 288 ∫[0,4π] costcost dt - 360 ∫[0,4π] sintsint dt

= -144(0) + 288(0) - 360(0)

= 0

Hence, the value of the line integral ∫C (x+5y)dx + (4x-3y)dy along the curve C is 0.

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Answer:

\( \frac{3x}{2} \)