Could you help me pls ?


What is the average potential difference across a coil of 100 turns and across sectional area 1000cm² when the magnetic field strength across the cross sectional of the coil changes from 10-3 wb/m² to 10-4 web/m3 in 0.1 se?

Answers

Answer 1

The average potential difference across the coil is: 9 × 10⁻³ volts or 9 millivolts when the magnetic field strength changes as described.

To find the average potential difference, we can use Faraday's law of electromagnetic induction, which states that the induced electromotive force (EMF) in a coil is equal to the rate of change of magnetic flux through the coil. The formula for Faraday's law is:

EMF = -N × (ΔΦ/Δt)

where EMF is the induced electromotive force, N is the number of turns in the coil, ΔΦ is the change in magnetic flux, and Δt is the time interval.

First, we need to convert the cross-sectional area from cm² to m²:

1000 cm² × (1 m / 100 cm)² = 0.1 m²

Next, we calculate the change in magnetic flux:

ΔΦ = (10^-4 Wb/m³ - 10^-3 Wb/m²) × 0.1 m² = -9 × 10⁻⁵ Wb

Now, we can plug the values into Faraday's law formula:

EMF = -100 × (-9 × 10⁻³ Wb / 0.1 s) = 9 × 10⁻³ V

Therefore, the average potential difference across the coil is 9 × 10⁻³volts or 9 millivolts when the magnetic field strength changes as described.

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Related Questions

5. Gravity is an attractive force betweenA. all massive objects.B. Earth and objects on Earth.C. Earth and Moon, and objects on Earth.D. all objects everywhere.
Background image

Answers

The correct answer is option D gravity is an attractive force between any objects in the universe i.e. gravitational force.

Is gravity a force that draws two items together?

A mass attracts a mass; the amount of the gravitational force is directly proportional to the masses of the two items and inversely proportional to the square of the distance between the two objects. Gravitational force is an attractive force that exists between all objects with mass.

We can see that the gravitational force is inversely proportional to the distance between masses and directly proportional to the product of the masses of two objects. As a result, any item in the cosmos can be attracted to another by the force of gravity.

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Which property of a transverse wave stays the same even as the wave's
energy and other properties change?
Wavelength
Frequency
Rest position
Amplitude
ent
1 of 8 QUESTIONS
SUBMIT

Answers

The property of a transverse wave that stays the same even as the wave's energy and other properties change is the wavelength.

The correct option to the given question is option a.

The wavelength is the distance between two successive points of the wave that are in phase. As the wave's energy and amplitude change, the distance between two successive points of the wave that are in phase remains the same.

This is because wavelength is determined by the frequency of the wave and the speed of propagation. The frequency of the wave is the number of cycles of the wave that occur in one second, while the speed of propagation is the rate at which the wave travels through a medium.

If the frequency of the wave and the speed of propagation remain the same, then the wavelength will also remain the same even as the wave's energy and other properties change. This property is known as the characteristic of the wave.The amplitude is the maximum displacement of a point on the wave from its rest position. The frequency is the number of cycles of the wave that occur in one second. The rest position is the position of the medium when it is not disturbed.

Hence, wavelength of a transverse wave remains same even as the wave's energy and other properties change.

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A sound wave leaves the loudspeaker. As it travels, it experiences a temporary increase in wavelength and then returns to its original wavelength. Which of the following scenarios could explain this change in wavelength? Select the TWO that apply.

A
The sound wave traveled through a helium balloon (helium is less dense than air).

B
The sound wave traveled into the rocky ground.

C
The sound wave traveled through a glass of water.

D
The sound wave reflected off of a rock wall nearby.

E
The sound wave traveled through a person walking along the shore.

Answers

The sound wave passed through a glass of water as well as a helium balloon because helium is less thick than air.

What changes do wavelengths make to sound?

Frequency is the number of full wavelengths in a certain amount of time (f). When a wavelength lengthens, its frequency and energy (E) decrease. You may conclude from these equations that the wavelength gets shorter as the frequency rises.

What happens to sound waves' energy as they depart from a loudspeaker?

As described in Waves, the strength drops as it gets farther away from the speaker. Moreover, because to the viscosity of the air, the energy is absorbed by things and transformed into heat energy.

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(please help ASAP!)
Choose the appropriate descriptor for the term meter.

A. mass
B. area
C. length
D. volume

Answers

Answer:

It's C. Length

Explanation:

Just think of a ruler. Hope I helped! :)

The term "meter" is the name chosen for the SI standard unit of length and distance. (C)

The SI standard unit of mass is called the "kilogram".

The unit of area is the square-meter or meter².

The unit of volume is the cubic meter or meter³.  

Which option below best explains why the second law of thermodynamics is
not violated when heat flows from a cold freezer and into the much warmer
room?
OA. The flow of internal energy out of the freezer is balanced by the
flow of energy into the room.
B. The freezer and room are not an isolated system, since electrical
energy flows in.
OC. The spontaneous flow of heat from a cool area and into a warmer
area is allowed.
O D. The electric motor on the freezer does work to remove the heat
from inside the freezer.

Answers

''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.

What is Second Law of Thermodynamics?

The Second Law of Thermodynamics says that "in all energy exchanges, if no energy enters or leaves the system, the potential energy of the state will always be less than the energy of the initial state."

So we can conclude that ''The freezer and room are not an isolated system, since electrical energy flows in.'' is the correct statement.

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can anyone plz answer this now?

can anyone plz answer this now?

Answers

Answer:

A

Explanation:

Can someone please explain these or help answer them? ​

Can someone please explain these or help answer them?

Answers

Answer:

41.57.

Explanation:

Sometimes if you type in google "area of a regular hexagon, it will give you a calculator you can use to solve your math questions.

Answer:41.57

Hope this help

Bowling ball rolls up a ramp 0.75 m high without slipping to storage. it has an initial velocity of its center of mass of 4.2 m/s. (a) what is its velocity at the top of the ramp? (b) if the ramp is 1 m high does it make it to the top?

Answers

(a) Using conservation of energy, the velocity of the ball at the top of the ramp is 3.9 m/s.
(b) When the height of the ramp is 1 m, the ball does not make it to the top of the ramp

Given,

Height of the ramp, h = 0.75 m
Initial velocity of the center of mass, u = 4.2 m/s

(a) What is its velocity at the top of the ramp?

The bowling ball rolls up a ramp of height 0.75 m without slipping to storage, and it has an initial velocity of its center of mass of 4.2 m/s. It is asked to determine the velocity of the ball at the top of the ramp.
Let the velocity of the ball at the top of the ramp be v.
By the law of conservation of energy, the potential energy of the ball at the bottom of the ramp is equal to the kinetic energy of the ball at the top of the ramp.
PE at the bottom of the ramp = KE at the top of the ramp

mgh = (1/2)mu² + (1/2)Iω²

where
m = mass of the ball
g = acceleration due to gravity
I = moment of inertia of the ball
ω = angular velocity of the ball

Assuming the ball is a solid sphere,

I = (2/5)mr²

where r is the radius of the sphere
At the bottom of the ramp,
PE = mgh
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
Substituting the given values,
PE = mgh = 0.75mg
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²

At the top of the ramp,

PE = KE
0.75mg = (7/10)mu²
v = u * √(7/10)
= 4.2 * √(7/10)
≈ 3.9 m/s

Therefore, the velocity of the ball at the top of the ramp is approximately 3.9 m/s.

(b) If the ramp is 1 m high does it make it to the top?

When the height of the ramp is 1 m,
PE = mgh = 1mg
At the top of the ramp,
KE = (1/2)mu² + (1/2)(2/5)mu²
= (1/2)(7/5)mu²
= (7/10)mu²

At the top of the ramp,

PE = KE
1mg = (7/10)mu²
u² = (10/7)gh
v = u * √(7/10)
= √(10gh/7)
≈ 3.96 √h m/s

Therefore, when the height of the ramp is 1 m, the ball does not make it to the top of the ramp.

Using the law of conservation of energy, the velocity of the ball at the top of the ramp is found to be approximately 3.9 m/s. When the height of the ramp is increased to 1 m, the ball does not make it to the top of the ramp.

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What is the impulse experienced by a 24kg dog as he speeds up from 2m/s to 6m/s

Answers

Given

m = 24kg

vi = 2 m/s

vf = 6 m/s

Procedure

Impulse = Change in momentum

\(\begin{gathered} I=m\Delta v \\ I=m(v_f-v_i) \\ I=24\cdot(6-2) \\ I=96\operatorname{kg}m/s \end{gathered}\)

The answer would be I = 96 kg*m/s

In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface you see. What kind of terrain did they land on for this, the second human Moon landing, and why ?

In the photo below, astronaut Alan Bean works at the Apollo 12 lander. Describe the horizon and the surface

Answers

Answer:

moon

Explanation:

I dont KNow

If you drop a rock from 490 meters high, how long will it take the hit the ground? (Remember to make height negative when solving because it is falling)

A. 12.88 Seconds
B. 7.88 Seconds
C. 5 Seconds
D. 10 Seconds

Answers

Answer:

C

Explanation:

Wich theorist believed in the collective consciousness

Answers

Answer:

I believe you are talking about Emile Durkheim

Explanation: Fun Fact:

He is most well known as the author of On the Division of Social Labor The Rules of Sociological Method, , and The Elementary Forms of Religious Life

You use a rope 2.00 m long to swing a 10 kg weight around your head. The tension in the rope is 20 N. In half a revolution how much work in J is done by the rope on the weight

Answers

Answer:

No work is done on the weight. :3

To solve this we must be knowing each and every concept related to work and its calculation. Therefore, 250J is the work done in joule by the rope on the weight.

What is work?

Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.

When a force is applied, it is said to produce positive work if it has a proportion in the orientation of the movement of a site of application. Work done is positive when the direction of force acting on the object and displacement of the object both are in the same direction.  

Mathematically,    

Work= force ×displacement

force =20 N

displacement=2.00 m

displacement=2×3.14×2=12.5m

substituting all the given values in the above equation, we get

Work= 20 ×12.5

Work =250J

Therefore, 250J is the work done in joule by the rope on the weight.

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A mineral scratches a piece of fluorite but cannot be scratched by a piece of glass. What is this mineral’s hardness?

Answers

Answer:

The mineral's hardness is greater than 4 but less than 5.5 on the Mohs hardness scale.

For an Ultrasonic Vaporizer Us Duty Rate 4.2%, valued in USD$750, transported via Air and no valid CUSMA certificate available calculate: - Duty Charge - MPF - HMF

2. Same Ultrasonic Vaporizer Us Duty Rate 4.2%, valued in USD$750, transported via Ocean and no valid CUSMA certificate available calculate:

Duty Charge

MPF

HMF

Answers

1. The duty charge, MPF and HMF for the Ultrasonic Vaporizer transported via air are USD$31.50, USD$2.60 and USD$0.94, respectively.

2. The duty charge, MPF and HMF for the Ultrasonic Vaporizer transported via ocean are USD$31.50, USD$0.94 and USD$0.94, respectively.

How to calculate duty charge, MPF and HMF

For the Ultrasonic Vaporizer transported via air

Duty Charge:

Given information;

Duty rate = 4.2%

Value of goods = USD$750

Duty charge = Value of goods x Duty rate

Duty charge = USD$750 x 4.2%

Duty charge = USD$31.50

Merchandise Processing Fee (MPF)

MPF rate = 0.3464% (as of 2021)

Value of goods = USD$750

MPF = Value of goods x MPF rate

MPF = USD$750 x 0.3464%

MPF = USD$2.60

Harbor Maintenance Fee (HMF)

HMF rate = 0.125% (as of 2021)

Value of goods = USD$750

HMF = Value of goods x HMF rate

HMF = USD$750 x 0.125%

HMF = USD$0.94

Therefore, the total import fees for the Ultrasonic Vaporizer transported via air are:

Duty charge = USD$31.50

MPF = USD$2.60

HMF = USD$0.94

For the Ultrasonic Vaporizer transported via ocean

Duty Charge:

Given information:

Duty rate = 4.2%

Value of goods = USD$750

Duty charge = Value of goods x Duty rate

Duty charge = USD$750 x 4.2%

Duty charge = USD$31.50

Merchandise Processing Fee (MPF)

MPF rate = 0.125% (as of 2021)

Value of goods = USD$750

MPF = Value of goods x MPF rate

MPF = USD$750 x 0.125%

MPF = USD$0.94

Harbor Maintenance Fee (HMF):

HMF rate = 0.125% (as of 2021)

Value of goods = USD$750

HMF = Value of goods x HMF rate

HMF = USD$750 x 0.125%

HMF = USD$0.94

Therefore, the total import fees for the Ultrasonic Vaporizer transported via ocean are:

Duty charge = USD$31.50

MPF = USD$0.94

HMF = USD$0.94

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Duty Charge=$31.50

The MPF will be $27.23.

The HMF rate is $0.125 per metric ton.

Ultrasonic Vaporizer transported via Air:

Duty Charge: $31.50

MPF: $26.79

HMF: Not applicable

Ultrasonic Vaporizer transported via Ocean:

Duty Charge: $31.50

MPF: $27.23

HMF: HMF rate and weight of the vaporizer are needed to calculate the HMF.

Ultrasonic Vaporizer transported via Air:

Duty Charge: The duty charge is calculated by multiplying the value of the product ($750) by the duty rate (4.2%): Duty Charge = \(\$750 * 4.2\%\)

= \(\$31.50.\)

MPF: The MPF for air transport is based on the value of the merchandise. As the value of $750 is below the maximum, the MPF will be $26.79.

HMF: The HMF is not applicable for air transport.

Ultrasonic Vaporizer transported via Ocean:

Duty Charge: The duty charge is calculated in the same way as for air transport: Duty Charge = \(\$750 * 4.2\%\)

= \(\$31.50\).

MPF: The MPF for ocean transport is also based on the value of the merchandise. As the value of $750 is below the maximum, the MPF will be $27.23.

HMF: The HMF is applicable for ocean transport. The HMF rate is $0.125 per metric ton. The weight of the Ultrasonic Vaporizer is needed to calculate the HMF.

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The largest presently known redshifts of quasars are close toA)65.B)3.C)10.D)0.96.E)7

Answers

The largest presently known redshifts of quasars are close to E) 7. This high redshift value indicates that these quasars are extremely distant and we are observing them as they were in the early universe.

The largest presently known redshifts of quasars are close to option A) 65. Redshift is a phenomenon that occurs when light from a distant object, such as a quasar, is stretched out as it travels through space and is detected by telescopes on Earth. The amount of redshift is directly proportional to the distance the light has traveled, with larger redshift values indicating greater distances.

Quasars are extremely luminous objects that emit vast amounts of energy, making them visible from great distances. As a result, they are often used as cosmological probes to study the early universe and the evolution of galaxies over time. The largest known redshift values for quasars indicate that they are located billions of light-years away from Earth, providing astronomers with valuable insights into the structure and history of the universe on a grand scale.

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If the boat goes from 30 km/h to 50 km/h over the next 4 h, what is its acceleration?
Please help me

Answers

Answer:

The acceleration is 5km/h

Explanation:

Given

Initial Velocity (u) = 30km/h

Final Velocity (v) = 50km/h

Time (t) = 4h

Required

Determine the acceleration

This question will be answered using the first equation of motion;

\(v = u + at\)

Substitute values for u, v and t

\(50 = 30 + a * 4\)

\(50 = 30 + 4a\)

Subtract 30 from both sides

\(50 - 30 = 30 - 30+ 4a\)

\(20 = 4a\)

Divide both sides by 4

\(\frac{20}{4} = \frac{4a}{4}\)

\(5 = a\)

\(a = 5\)

Hence;

The acceleration is 5km/h

28,800 C of charge flow through a lamp every hour. Calculate the current used by this lamp

Answers

This lamp's estimated current consumption is 8 amperes.

What is electric current ?

Electric current is the rate of charge (electron) passing in a conductor. The SI unit for electric current is the ampere. As current does not obey vector addition, it is a scalar quantity.

Given information:

amount of charge flowing through the lamp, Q = 28800 C;

The charge flow time was t = 1 hour = 3600 seconds.

Hence, the current passing through the bulb as a result.

I = Q/t

= 28800/3600 ampere,

= 8 ampere

Therefore, this lamp consumes 8 amperes of current.

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1. A 10-kg medicine ball is thrown at a velocity of 15 km/hr to a 50-kg skater who is at rest on ice. The skater catches the ball and subsequently slides with the ball across the ice. Consider the skater and the ball as two separate parts of an isolated system. (no external forces)

Answers

The medicine ball starts out with a momentum of 150 kgkm/h (10 kg x 15 km/h). Because the skater is at rest, the system's starting momentum is just 150 kg/km/hr.

A medicine ball is a weighted workout ball that is used for building core strength, endurance, and power. They range in size and weight from 1 kg to 10 kg, respectively. Typically fashioned of leather, rubber, or plastic, they contain sand or a sand-and-water mixture. When performing workouts like abdominal twists, sit-ups, push-ups, lunges, and squats, people frequently use medicine balls. The additional weight makes the activity more difficult and resistant, making it a more tough workout. They are a flexible and powerful tool for enhancing conditioning, strength, and general fitness.

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That minimum coefficient of static friction between the tyres and the road that will allow the car that will round safely.

Answers

Answer:

The answer is "\(0.13562748\)"

Explanation:

Please find the complete question in the attached file.

Using formula:

\(\bold{U_s=\frac{v^2}{rg}}\)

Given:

\(r=1.60 \times 10^2 \ m\\\\g=9.8\\\\v= 52.5\ \frac{km}{hr}= 14.583\ \frac{m}{s}\)

put the value into the above-given formula:

\(U_s= \frac{14.583^2}{160 \times 9.8}\)

    \(= \frac{212.663889}{1568}\\\\=0.13562748\)

That minimum coefficient of static friction between the tyres and the road that will allow the car that

When a ball is kicked, when does it start to feel the force of gravity acting on it? a. As soon as the ball hits the ground again. b. As soon as the ball reaches the peak in its trajectory. c. It is always feeling the force of gravity on it. d. As soon as the ball leaves the ground.

Answers

When a ball is kicked, it start to feel the force of gravity acting as soon as the ball leaves the ground. At the moment the ball leaves the ground, it becomes subject to the gravitational force.

The force of gravity acts on an object continuously, regardless of its motion or position. When a ball is kicked and leaves the ground, it immediately starts to feel the force of gravity acting on it. This is because gravity is a fundamental force that attracts objects with mass towards each other.

At the moment the ball leaves the ground, it becomes subject to the gravitational force. This force causes the ball to be accelerated downward throughout its trajectory. The ball's motion is a result of the combination of the initial kick and the influence of gravity.

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voyager 2 should reach the nearest stars (besides the sun) in about 500 years. T/F

Answers

The statement "voyager 2 should reach the nearest stars (besides the sun) in about 500 years" is false.

Voyager 2, launched in 1977, is currently traveling at a speed of about 34,000 miles per hour (54,700 kilometers per hour). At this speed, it would take tens of thousands of years for Voyager 2 to reach even the closest stars in our Milky Way galaxy, which are several light-years away.

The spacecraft's primary mission was to explore the outer planets of our solar system, and it is now on an interstellar trajectory, but its journey is primarily aimed at studying the space environment beyond our solar system rather than reaching specific stars.

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on a distant planet a freely falling object has an acceleration of 20 m/s.^2 what speed will a body dropped from rest on his planet avquire in 1.5s

Answers

Answer:

30 m/s

Explanation:

Vf = ?

Vi = 0 m/s

a = 20 m/s^2

t = 1.5 s

Plug those values into the equation: Vf = Vi + at

Vf = 0 + (20)(1.5)

Vf = 30 m/s

What will be the direction of current when north pole of coil is facing the norht pole of magnet according to lenz law?

Answers

The direction of the current when the north pole of the coil is facing the north pole of the magnet, according to Lenz's Law, will be counterclockwise. Lenz's Law states that the direction of an induced current in a conductor is always such that it opposes the change in magnetic field that caused it.


According to Lenz's Law, the direction of the induced current in a coil or circuit will be such that it opposes the change in magnetic field that is causing it.

When the north pole of a magnet is brought near the north pole of a coil, the magnetic field in the vicinity of the coil will increase. To oppose this increase, Lenz's Law states that the induced current will flow in such a direction that it produces a magnetic field that opposes the magnetic field of the approaching magnet.

Using the right-hand rule for the direction of induced current, if you extend your right hand with the thumb pointing in the direction of the approaching magnetic field (from the north pole of the magnet towards the north pole of the coil), then the curled fingers will indicate the direction of the induced current. In this case, the induced current will flow counterclockwise around the coil when viewed from above.

Therefore, the direction of the current when the north pole of the coil is facing the north pole of the magnet, according to Lenz's Law, will be counterclockwise.


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A bomb, initially at rest, explodes into several pieces.
(a) Is linear momentum of the system (the bomb before the explosion, the pieces after the explosion) conserved?
Yes
No
insufficient information

Answers

The linear momentum of the system the bomb before the explosion, the piece after the explosion is conserved. Therefore, while linear momentum is conserved, other forms of energy are not.

The explosion, the bomb was at rest, so its momentum was zero. After the explosion, the pieces will move in different directions with different velocities, but the sum of their momenta will still be zero. This means that the total momentum of the system is conserved. However, it should be noted that the kinetic energy of the system is not conserved as some of it is lost in the form of heat, sound, and other forms of energy during the explosion. Therefore, while linear momentum is conserved, other forms of energy are not.

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Use the SPSS output below to answer the following questions. The table shows happiness scores after completing one’s thesis (happiness is on a scale of 1-10). (10 pts)
happiness
Frequency
Percent
Valid Percent
Cumulative Percent
Valid
3
3
11.1
11.1
11.1
4
1
3.7
3.7
14.8
5
3
11.1
11.1
25.9
6
5
18.5
18.5
44.4
7
4
14.8
14.8
59.3
8
5
18.5
18.5
77.8
9
4
14.8
14.8
92.6
10
2
7.4
7.4
100.0
Total
27
100.0
100.0
What is the point for the 86 percentile? (5 pts)
What percentage of people received an 8 on the happiness scale? (3 pts)
How many students received higher than a 0 on the exam? (2 pts)

Answers

From the table, we can see that the frequencies for scores 3 through 10 (excluding 0) are given. By summing those frequencies, we can obtain the total number of students who received a score higher than 0.

To determine the number of students who received a score higher than 0 on the happiness scale, we need to sum up the frequencies for all the scores greater than 0.

To find the point for the 86th percentile, we need to determine the happiness score that corresponds to that percentile. From the given table, we can see the cumulative percent column, which represents the percentage of participants with a happiness score up to that point.

To find the point for the 86th percentile, we look for the cumulative percent that is closest to 86%. From the table, we can see that the cumulative percent at the 77.8% mark corresponds to the score of 8 on the happiness scale. Therefore, the point for the 86th percentile would fall between the score of 8 and 9.

To determine the exact point for the 86th percentile, we can interpolate. By calculating the difference between the cumulative percent at 77.8% and 92.6% (which represents the next available score of 9), and then proportionally adding that difference to the score of 8, we can estimate the score for the 86th percentile.

Regarding the percentage of people who received an 8 on the happiness scale, we can find this information directly from the table. The valid percent for the score of 8 is given as 18.5%, indicating that 18.5% of the participants received a score of 8.

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A tuning fork is stuck against a table. It vibrates at a frequency
of 300 Hz. At what frequency will you hear the sound of the
tuning fork? Hz

Answers

Answer:

300 Hz.

Explanation:

The frequency of a sound wave is the same as that of the source. For example, a tuning fork vibrating at a given frequency would produce sound waves that oscillate at the same frequency.

The frequency that you will hear when the tuning fork is stuck against a table is 300 Hz.

What is a frequency?

Frequency is a measurement of how often a repetitive event occurs in a given amount of time. It is commonly used to describe the rate at which waves oscillate or vibrate. The unit of frequency is hertz (Hz), which represents the number of cycles or oscillations per second.

For example, in the case of sound waves, frequency is related to the pitch of the sound. Higher frequency sound waves have a higher pitch, while lower frequency sound waves have a lower pitch. Similarly, in the case of electromagnetic waves such as light, frequency is related to the color of the light. Higher frequency electromagnetic waves correspond to colors such as blue and violet, while lower frequency electromagnetic waves correspond to colors such as red and orange.

The relationship between frequency, wavelength, and the speed of the wave is given by the formula:

frequency = speed of the wave / wavelength

This formula shows that the frequency of a wave is inversely proportional to its wavelength, assuming the speed of the wave remains constant. In other words, as the wavelength of a wave increases, its frequency decreases, and vice versa.

Frequency is an important concept in many fields, including physics, engineering, and communications. It is used to describe and analyze a wide range of phenomena, from the behavior of sound and light waves to the performance of electronic circuits and systems.

Here in the Question,

When a tuning fork is struck against a table, it vibrates at its natural frequency, which is determined by its physical properties such as its mass, shape, and material. The vibration of the tuning fork creates sound waves that travel through the air, and our ears perceive these waves as sound.

The frequency of the sound that we hear depends on the frequency of the sound waves that reach our ears. When the sound waves from the tuning fork travel through the air, they undergo a phenomenon called the Doppler effect, which causes the frequency of the sound waves to change depending on the relative motion between the source of the sound waves (the tuning fork) and the observer (our ears).

If the tuning fork is stuck against a table and is not moving relative to the observer, the frequency of the sound waves that reach our ears will be the same as the natural frequency of the tuning fork, which is given as 300 Hz in this case.

Therefore, the frequency that you will hear when the tuning fork is stuck against a table is 300 Hz.

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Gabriel is sledding down a snowy hill. At which of the following positions will Gabriel's potential energy be the least and his kinetic energy be the greatest?
A. 3
B. 2
C. 1
D. 4

Gabriel is sledding down a snowy hill. At which of the following positions will Gabriel's potential energy

Answers

Pretty sure the kinetic energy will be the least at C.1 and the greatest at D.4

Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg • m2. The father exerts a force on themerry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2.(a) How long (in s) does it take the father to give the merry-go-round an angular velocity of 2.29 rad/s? (Assume the merry-go-round is initially atrest.)S(b) How many revolutions must he go through to generate this velocity?revolutions(C) If he exerts a slowing force of 270 N at a radius of 1.25 m, how long (in s) would it take him to stop them?s

Answers

a)

Since we have a constant angular acceleration we have that:

\(\alpha=\frac{\omega-\omega_0}{t}\)

Plugging the values we know we have that:

\(\begin{gathered} 4.44=\frac{2.29-0}{t} \\ t=\frac{2.29}{4.44} \\ t=0.516 \end{gathered}\)

Therefore it will take 0.516 (rounded to three decimals) seconds to achive this angular velocity.

b)

To find how many revolutions he needs we first calculate the change in angular position using the formula:

\(\begin{gathered} \omega^2-\omega^2_0=2\alpha(\theta-\theta_0) \\ (\theta-\theta_0)=\frac{\omega^2-\omega^2_0}{2\alpha} \\ (\theta-\theta_0)=\frac{2.29^2-0^2}{2(4.44)} \\ (\theta-\theta_0)=0.590551801 \end{gathered}\)

Now we divide this change in angular position by 2pi (the angle equivalent to a revolution) to get the revolutions:

\(\frac{0.590551801}{2\pi}=0.094\)

Therefore it takes 0.094 (round to three decimals) revolutions to get to this angular velocity.

c)

The torque is the force by the radius, then we have:

\(\tau=(270)(1.25)=337.5\)

But the torque is also equal to the moment of inertia multiplied by the angular acceleration:

\(\tau=I\alpha\)

Then we have:

\(\begin{gathered} 337.5=84.4\alpha \\ \alpha=\frac{337.5}{84.4} \\ \alpha=3.998815166 \end{gathered}\)

Now we use the formula for angular acceleration to get the time:

\(\begin{gathered} -3.998815166=\frac{0-2.29}{t} \\ t=\frac{-2.29}{-3.998815166} \\ t=0.573 \end{gathered}\)

Therefore it takes 0.573 seconds to stop the merry go round.

If you calculate the horizontal velocity of a projectile to be 56 m/s east and its vertical velocity of to be 44 m/s south, what is the velocity of the projectile when it lands? __________ m/s (use no more than 3 decimal places for your answer).

Answers

The velocity of the projectile when it lands is 71.218 m/s.

What is the resultant velocity of the projectile?

The resultant velocity of the projectile when it lands is calculated by applying the following formula.

V = √ ( Vx²  + Vy² )

where;

Vx is the horizontal velocity of the projectileVy is the vertical velocity of the projectile

The given parameters include the following;

the vertical velocity of the projectile = 44 m/s

the horizontal velocity of the projectile = 56 m/s

V = √ ( Vx²  + Vy² )

V = √ ( 56²  + 44² )

V = 71.218 m/s

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