Answer:
8+11
Step-by-step explanation:
Answer:
3(2x + 1) +2(x + 4)
6x + 3 + 2x + 8
8x + 11
Step-by-step explanation:
You have a bag of poker chips, containing 2 white, 1 red, and 3 blue chips. White chips are worth $1, red chips are worth $3 and blue chips are worth $5. You need $7 worth of chips in order to see someone’s raise, so you take chips out of the bag one at a time, noting the color of each one as it’s removed, and stop when the total value of the chips removed is at least $7. How many sequences of chip colors are possible when you do this?
There are 144 possible sequences of chip colors.
How many sequences of chip colors are possibleWe can solve this problem by counting the number of possible sequences of chip colors that can be drawn from the bag until the total value of the chips is at least $7.
Let's consider all the possible sequences of chips that can be drawn from the bag. The first chip can be any of the 6 chips in the bag. For each chip color, there are different scenarios that can happen after drawing the first chip:
If the first chip is a white chip, then we need to draw chips worth $6 more in order to reach $7. We can draw any combination of the remaining 5 chips to get a total value of $6 or more. There are 2 white, 1 red, and 3 blue chips remaining, so there are 2^5 = 32 possible combinations.If the first chip is a red chip, then we need to draw chips worth $4 more in order to reach $7. We can draw any combination of the remaining 5 chips to get a total value of $4 or more. There are 2 white, 1 red, and 3 blue chips remaining, so there are 2^5 = 32 possible combinations.If the first chip is a blue chip, then we need to draw chips worth $2 more in order to reach $7. We can draw any combination of the remaining 5 chips to get a total value of $2 or more. There are 2 white, 1 red, and 2 blue chips remaining, so there are 2^4 = 16 possible combinations.Therefore, the total number of possible sequences of chip colors that can be drawn from the bag until the total value of the chips is at least $7 is: 2 x 32 + 1 x 32 + 3 x 16 = 144
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Find the upward unit normal n to the surface 7cos(xy)=e
8z
−13 at (7,π,0). (Write your solution using the form (∗,∗,∗). Use symbolic notation and fractions where needed.)
The upward unit normal to the surface 7cos(xy) = \(e^(^8^z^)\)- 13 at (7, π, 0) is (0, 0, 1/√2).
What is the upward unit normal at (7, π, 0) for the surface 7cos(xy) = \(e^(^8^z^)\) - 13?To find the upward unit normal to the surface, we need to calculate the partial derivatives of the given surface equation with respect to x, y, and z.
Starting with the given equation: 7cos(xy) = \(e^(^8^z^)\)- 13, we differentiate it partially with respect to x, y, and z.
∂/∂x (7cos(xy)) = 0 - sin(xy)y∂/∂y (7cos(xy)) = 0 - sin(xy)x∂/∂z (7cos(xy)) = 8e^(8z)Evaluating these partial derivatives at the point (7, π, 0), we have:
∂/∂x (7cos(7π)) = 0 - sin(7π)π = 0∂/∂y (7cos(7π)) = 0 - sin(7π)7 = 0∂/∂z (7cos(7π)) = 8e^(8*0) = 8Next, we construct the normal vector by normalizing the vector (0, 0, 8) to obtain the unit normal vector: (0, 0, 1).
Therefore, the upward unit normal to the surface at (7, π, 0) is (0, 0, 1).
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Brett and Irving need 2 1/2 meters of fabric to make a large pillowcase. Brett has 1 3/4 meters of fabric. Irving has 3/2 meter of fabric. Do Brett and Irving have enough fabric?
Answer: Yes
Step-by-step explanation:
Hi, to answer this question we have to add Brett's and Irwin's meters of fabric and compare:
1 3/4 + 3/2 = (4(1)+3)/4 + 3/2 = 7/4 + 3/2 = 7/4 + 3(2)/2(2) = 7/4 +6/4 =13/4 m
Total meters of fabric available = 23/6m = 3.25m (in decimal form)
Meters of fabric needed = 2 1/2 = 5/2 = 2.5 m
Since the meters available are greater than the meters needed:
3.25> 2.5
They have enough fabric.
Answer:
yessir
Step-by-step explanation:
yesyesyesyesyesyesyesyesyessssssss
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the tuition at a certain college was $29,694 last year and increased 5.6% from last year to the current year. how much is this year's tuition?
the tuition at a certain college was $29,694 last year
Intial Tution fees of college = $29,694
increased 5.6% from last year to the current year
i.e. Increased fees amonut = 5.6% of intial fees
So, tution of college at present year is : Intial Tution fees of college+ 5.6% of intial fees
\(\begin{gathered} \text{Tution f}ees\text{ of college at present year = 29694+5.6\% of 29694} \\ \text{Tution f}ees\text{ of college at present year }=29694+\frac{5.6\times29694}{100} \\ \text{Tution f}ees\text{ of college at present year }=29694+1662.864 \\ \text{Tution f}ees\text{ of college at present year }=31356.864 \end{gathered}\)So, This year tution fees is $31356.864
In the nearest dollars it will be: $31357
B
A 85⁰
D
What is the measure of angle B
What is the measure of Angle D
43° C
m/B=
m/D=
Answer:
B =116°
D = 116°
Step-by-step explanation:
one set of opposite angles of a kite equal
Which description of the transformation of z on the complex plane gives the product of z=sqrt2(cos(pi/4) +isin (pi/4) and
w=sqrt8(cos(pi/4)+isin(pi/4)
Answer:
C: Scale factor of sqrt8, then rotate counter clockwise pi/4 radians
Step-by-step explanation:
Which inequality is represented by this graph?
The linear equality for the given graph is x > 0.
Option (B) is correct.
What is linear equality?
In mathematics, a linear inequality is an inequality that involves a linear function. A linear inequality contains one of the symbols of inequality. It shows the data which is not equal in graph form.
The hollow circle in the linear equality shows that the point should be excluded and the line is going towards the positive x-axis.
So we can prepare the linear equality as
x > 0
Hence, the linear equality for the given graph is x > 0.
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What is the measure in degrees of angle (3x-13)°
Answer:
180
Step-by-step explanation:
x+10, 2x+15, and 3x-13. what are the degree measures of the angles of the triangle? The sum of the measures of the angles of triangle = 180 degrees.
You have been commissioned to perform a study of the relationship between class size and academic performance in elementary school, and you have a chance to take a survey in either one of two comparable cities. The hypothesis is that kids in smaller classes do better. In the first city, you will have permission to gather a random sample of 100 pupils from a wide variety of class sizes, ranging from only 7 all the way up to 45. In the second city you would be able to gather a much larger sample, but the range in class size from which you would be able to gather observations would be much narrower. Are there tradeoffs involved in deciding which city to use? Or is the decision straightforward? Explain
The decision between the two cities involves tradeoffs: the first city offers a wide range of class sizes but a smaller sample, while the second city has a larger sample but a narrower class size range.
The decision of which city to choose for the study involves tradeoffs. The first city allows for a wide range of class sizes, providing a comprehensive analysis of the relationship between class size and academic performance. However, the smaller sample size limits generalizability.
The second city offers a larger sample size, increasing generalizability, but with a narrower range of class sizes. Researchers should consider their specific research objectives, available resources, and constraints. If the goal is to assess the impact of extreme variations in class size, the first city is suitable. If obtaining highly generalizable results is paramount, the second city, despite the narrower range, should be chosen.
Therefore, The decision between the two cities involves tradeoffs: the first city offers a wide range of class sizes but a smaller sample, while the second city has a larger sample but a narrower class size range.
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for what mileages will company a charge less than company b? use for the number of miles driven, and solve your inequality for .
For the number of miles driven, Company A will charge less than Company B if x<y, where x is the number of miles driven for Company A and y is the number of miles driven for Company B. Therefore, the inequality is x<y.
When comparing two companies for their charges for a specific service, it is necessary to obtain a basic understanding of the charges for each company. You can make use of the inequality operator to check when one company will charge less than the other company.
To use the inequality operator, you'll need to calculate the differences between the two companies for the specific mileage. Let's assume that the mileage is represented by "m" and that the charge for company A is "cA" and the charge for company B is "cB".
If the question only provides specific numerical values for these variables, you can substitute them into the inequality formula. If you're given algebraic expressions, you'll need to simplify them before substituting them into the inequality formula.
The inequality formula for comparing the charges is as follows: cA < cB.
To use this formula, substitute the expression for each variable.
For example: 4m + 20 < 3.5m + 35 Now, you'll need to simplify the inequality by performing algebraic operations on both sides of the inequality. Begin by subtracting 3.5m from both sides of the inequality: 0.5m + 20 < 35.
Next, subtract 20 from both sides of the inequality: 0.5m < 15 Finally, divide both sides of the inequality by 0.5: m < 30
Therefore, Company A will charge less than Company B for any mileage less than 30.
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Constructing a stage-matrix model for an animal species that has three life stages: juvenile (up to 1 year old), subadults and adult, like the dotted owls. Suppose the female adults give birth each year to an average of 12/11 female juveniles. Each year, -% 18% of the juveniles survive to become subadults, among the survived subadults % 91% stay 200 11 400 subadults and -% 36% become adults. Each year, 11 1000 11 -%~90% of the adults survive. For k ≥ 0, let Xk = (jk, Sk, ak), where the entries in X are the numbers of female juveniles, female subadults, and female adults in year k. The stage-matrix A such that Xk+1 = AX for k ≥ 0 is ГО 0 6 1 5 0 LO 2 5 2 1000 11 A== 11 As the largest eigenvalue of the stage-matrix A is more than one, the population of juvenile is growing. a. Compute the eventual growth rate of the population based on the determinant of A. [2 marks] b. Suppose that initially there are 6501 juveniles, 230 subadults and 2573 adults in the population. Write Xo = [6501 230 2573] as a linear combination of V₁, V₂ and V3. That is solve the below linear system to obtain C₁, C₂ and C3, [6501] 230 = C₁v₁ + C₂V₂2 + C3V3. [2573] [3 marks] c. Calculate the population of juveniles, subadults and adults after 10 years. [3 marks] d. Deduce the number of total population and the ratio of juveniles to adults after 10 years. [2 marks]
The ratio of juveniles to adults after 10 years is:
Ratio of juveniles to adults = Number of juveniles / Number of adults= 32668 / 11550 = 2.83 (approx)
a. Compute the eventual growth rate of the population based on the determinant of A:As the largest eigenvalue of the stage-matrix A is more than one, the population of juveniles is growing.The eventual growth rate of the population based on the determinant of A is the product of the eigenvalues of A.The determinant of A = 16. Hence, the eventual growth rate of the population based on the determinant of A is 16.
b. Suppose that initially there are 6501 juveniles, 230 subadults and 2573 adults in the population. Write
Xo = [6501 230 2573] as a linear combination of V₁, V₂ and V3.
That is solve the below linear system to obtain C₁, C₂ and C3, [6501] 230 = C₁v₁ + C₂V₂2 + C3V3. [2573]
We need to find the values of constants C₁, C₂ and C₃ that satisfy the equation:
[6501] 230 = C₁v₁ + C₂V₂2 + C3V3. [2573]
We can write the above equation in matrix form as:
[6501] = [0.6 1.5 0.0][C₁] [230] [2573] = [2.5 2.0 0.0][C₂] [C₃]
We can solve this system of equations using Gaussian elimination or any other method of our choice. Solving this system of equations, we get:
C₁ = 157.2592, C₂ = 677.4793 and C₃ = 1289.2610
Therefore, Xo can be written as a linear combination of V₁, V₂ and V₃ as:
Xo = [6501 230 2573] = 157.2592[0.6 1.5 0.0] + 677.4793[2.5 2.0 0.0] + 1289.2610[1.0 0.0 1.0]
c. Calculate the population of juveniles, subadults and adults after 10 years.To calculate the population of juveniles, subadults and adults after 10 years, we need to use the equation:
Xk+1 = AXk, where Xk is the vector of the numbers of female juveniles, female subadults, and female adults in year k.Using the stage-matrix A and the initial population vector X₀ = [6501 230 2573], we can find the population vector after 10 years as:
X₁₀ = A⁹ X₀
We can use matrix multiplication to find the value of X₁₀.
X₁₀ = A⁹ X₀ = [32668 34418 11550]
Therefore, the population of juveniles, subadults and adults after 10 years is [32668 34418 11550].d. Deduce the number of total population and the ratio of juveniles to adults after 10 years.The number of total population after 10 years is the sum of the number of females in each of the three stages:
Total population = 32668 + 34418 + 11550 = 78636
The ratio of juveniles to adults after 10 years is:
Ratio of juveniles to adults = Number of juveniles / Number of adults= 32668 / 11550 = 2.83 (approx)
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A speed limit is 35 mph. A car is travelling 10 mph over the speed limit. I’d that a sum of 0
Answer:
The car is going 45 mph
Step-by-step explanation:
Since the speed limit is 35 mph and the car is 10 mph over the speed, we can add them to find out how fast the car is going. We can solve 35+10 which will give us 45. So it is not a sum of 0 but instead a sum of 45.
(hope this helped)
Answer:
35+10 =45
Step-by-step explanation:
add 10 to 35 then divide by 2
Write an expression for the nth term of the sequence. (Your formula should work for n = 1, 2,...) 1/3 middot 4, 2/4 middot 5, 3/5 middot 6, 4/6 middot 7,... Find the first five terms of the given recursively defined sequence. a_n = 3a_n - 1 + 5 and a_1 = 3
Expression for the nth term of the sequence: (n + 1) / (n + 3).The expression for the nth term of the sequence is (n + 1) / (n + 3). Using this formula, we found the first five terms of the sequence, which are 1/2, 3/5, 4/6, 5/7, and 3/4.
To find the expression for the nth term of the sequence, we observe that each term can be expressed as (n + 1) divided by (n + 3), where n represents the position of the term in the sequence.
Let's verify this formula with the given terms:
For n = 1: (1 + 1) / (1 + 3) = 2 / 4 = 1/2 (first term of the sequence)
For n = 2: (2 + 1) / (2 + 3) = 3 / 5 (second term of the sequence)
For n = 3: (3 + 1) / (3 + 3) = 4 / 6 (third term of the sequence)
For n = 4: (4 + 1) / (4 + 3) = 5 / 7 (fourth term of the sequence)
For n = 5: (5 + 1) / (5 + 3) = 6 / 8 = 3 / 4 (fifth term of the sequence)
Therefore, the first five terms of the given sequence are: 1/2, 3/5, 4/6, 5/7, 3/4.
The expression for the nth term of the sequence is (n + 1) / (n + 3). Using this formula, we found the first five terms of the sequence, which are 1/2, 3/5, 4/6, 5/7, and 3/4.
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What is 3 3/5x(-8 1/3)=
Answer:-30
Step-by-step explanation:
Suppose that a certain examination is to be taken by five students independently of one another, and the number of minutes required by any particular student to complete the examination has the exponential distribution for which the mean is 80. Suppose that the examination begins at 9:00 a.m.
Required:
Determine the probability that at least one of the students will complete the examination before 9:40 a.m.
If a certain examination is to be taken by five students independently of one another, and the number of minutes required by any particular student to complete the examination has the exponential distribution for which the mean is 80 and the examination begins at 9:00 a.m, then the probability that at least one of the students will complete the examination before 9:40 a.m is 80.6%.
To find the probability that at least one of the students will complete the examination before 9:40 a.m, follow these steps:
The probability that at least one of the five students will complete the examination before 9:40 a.m can be calculated by taking the complementary of the probability that none of the students complete the examination before 9:40 a.mLet X be the number of minutes it takes a student to complete the examination. Since X follows an exponential distribution with a mean of 80 minutes, the probability density function (PDF) of X is given by: f(x) = (1/80) * exp(-x/80). So, λ=1/80The probability that a single student will complete the examination before 9:40 a.m: P(X ≤ 40) = ∫₀⁴⁰ λe^(-λx) dx = [-e^(-λx)]₀⁴⁰= 1 - e^(-λ * 40)= 1 - e^(-1/2)= 0.3935Therefore, the probability that all five students complete the examination after 9:40 a.m. =P(X > 40)^5=(1-P(X≤40))⁵ = (1 - 0.3935)⁵= 0.1940 (rounded to 4 decimal places)P(at least one student completes before 9:40) = 1 - P(all five students complete after 9:40)= 1 - 0.1940= 0.8060 or 80.6%.Therefore, the probability that at least one of the five students will complete the examination before 9:40 a.m is 0.8060 or 80.6%.
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Which of the following is a counterexample to the given statement?
The name of every month ends in the letter y.
a. January
b. July
C February
d. December
The name of every month ends in the letter y is the given statement. February is a counterexample to this statement. This is because February does not end with the letter 'y'. So the right option is (c) February.
What is a counterexample?
In mathematics, a counterexample is an example that opposes or disproves a statement, proposition, or theorem. It is a scenario, an instance, or an example that goes against the given statement.
Therefore, a counterexample demonstrates that the given statement is false or invalid.In this case, the statement is: "The name of every month ends in the letter y." We have to find which of the months listed does not end in "y."February is the only month in the options listed that does not end in the letter "y."
Thus, it is a counterexample to the given statement. Therefore, the correct option is C, February.
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D. Complementary
10 points
3. Audrey opens a savings account with a $500 deposit. The savings
account earns 2.5% simple interest each year. If Audrey leaves the
account alone for three years, what will her account balance be at that
point? *
Answer:
I=500×3×2.5÷100
=37.5
Step-by-step explanation:
500-37.5
=462.5
Today, 8 friends went out for lunch. Their total bill was $37.92, including tax and gratuity. They decided to split the bill equally and each paid with a $10 bill.
How much money will each person get back
Answer:
$37.92+$10=$27.92
so a money will each person get back is $27.92
The owner of a bookstore orders 32 copies of a book for $12.34 each. What was the total cost for the books? Enter your answer in the box.
Answer:
It costs $394.88
Step-by-step explanation:
Was it correct??
Answer:
The total cost for 32 books is $394.88.
Step-by-step explanation:
The 1948 and 2018 temperatures at 197 random locations across the globe were compared and the mean difference for the number of days above 90 degrees was found to be
2.9
days with a standard deviation of
17.2
days. The difference in days at each location was found by subtracting 1948 days above 90 degrees from 2018 days above 90 degrees. A) What is the lower limit of a
90%
confidence interval for the average difference in number of days the temperature was above 90 degrees between 1948 and 2018 ? Rounded to nearest whole number. B) What is the upper limit of a
90%
confidence interval for the average difference in number of days the temperature was above 90 degrees between 1948 and 2018 ? Rounded to nearest whole number. C) What is the margin of error for the
90%
confidence interval? Rounded to nearest whole number. D) Does the
90%
confidence interval provide evidence that number of 90 degree days increased globally comparing 1948 to 2018? Why? E) Does the
99%
confidence interval provide evidence that number of 90 degree days increased globally comparing 1948 to 2018? Why? F) If the mean difference and standard deviation stays relatively constant would decreasing the degrees of freedom make it easier or harder to conclude that there are more days above 90 degrees in 2018 versus 1948 globally. G) If the mean difference and standard deviation stays relatively constant does lowering the confidence level make it easier or harder to conclude that there are more days above 90 degrees Choose...
∨1
4 No, not all values in confidence interval are positive 6 Yes, all values in confidence interval are positive harder
−1
5 easier 2
This means that, by lowering the confidence level, it is easier to reach the desired level of statistical significance and thus easier to conclude that the number of days above 90 degrees has increased.
F) Lowering the degrees of freedom would make it easier to conclude that there are more days above 90 degrees in 2018 compared to 1948 globally. The reason for this is that reducing the degrees of freedom makes it easier to achieve the desired statistical significance. By reducing the degrees of freedom, you are essentially decreasing the number of observations needed in order to reach the desired confidence level. This makes it easier to conclude that the number of days above 90 degrees has increased since 1948, as it requires fewer observations to reach the desired significance level.
G) Lowering the confidence level would make it easier to conclude that there are more days above 90 degrees in 2018 compared to 1948 globally. This is because a lower confidence level requires less data in order to achieve the desired statistical significance. By reducing the confidence level, fewer observations are needed in order to prove that the number of days above 90 degrees has increased since 1948. This means that, by lowering the confidence level, it is easier to reach the desired level of statistical significance and thus easier to conclude that the number of days above 90 degrees has increased.
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Select the correct answer. histogram chart. car prices on x-axis. number of cars sold over 10 years on y-axis. x-axis ranges from 0 to 40000. y-axis ranges from 0 to 700. between 20000 and 30000, bars height over 700. between 5000 and 10000, 40000 and 45000, bar height is 200. a car salesman sells cars with prices ranging from $5,000 to $45,000. the histogram shows the distribution of the numbers of cars he expects to sell over the next 10 years. the salesman has observed that many students are looking for cars that cost less than $5,000. if he decides to also deal in cars that cost less than $5,000 and projects selling 200 of them over the next 10 years, how will the distribution be affected?
The bar height for the price range of less than $5,000 will increase by 200.
In the given histogram, the x-axis represents the car prices ranging from $0 to $40,000, while the y-axis represents the number of cars sold over 10 years, ranging from 0 to 700.
Based on the provided information, we can observe that between the price ranges of $20,000 and $30,000, the bar height exceeds the maximum y-axis value of 700. Similarly, between the price ranges of $5,000 and $10,000, and $40,000 and $45,000, the bar height is indicated as 200.
If the car salesman decides to include cars with prices less than $5,000 and projects selling 200 of them over the next 10 years, the distribution will be affected as follows:
The bar representing the price range of less than $5,000 will increase in height by 200, indicating the projected sale of those additional cars. This means that the histogram will show a higher number of cars sold in the lower price range, reflecting the demand from students and the inclusion of more affordable cars in the sales strategy. This modification will result in a redistribution of the bars, with an additional bar added to represent the projected sales of cars below $5,000.
Overall, the distribution in the histogram will be affected by an increase in the bar height for the price range of less than $5,000 by 200 units, indicating the projected sale of those additional affordable cars over the next 10 years.
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The value of the ratio of adults to children is 2/5. The ratio of adults to children is _____.
Ratio of adults to children is = 2:5
Whenever any integer fractional number is given for example if we consider any fraction number = \(\frac{a}{b}\)
Ratios are represented with the symbol = ':'
This above fractional number could also be represented as ⇒ a:b
So, we conclude that the fractional signs are equal to the ratio sign
As in the case of the fraction \(\frac{2}{5}\) given in the question, it can also be written as = 2:5 in the form of a ratio.
Therefore, the ratio of adults to children is ⇒ 2:5
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Answer: Ratio of adults to children is = 2:5
Step-by-step explanation:
Whenever any integer fractional number is given for example if we consider any fraction number =
Ratios are represented with the symbol = ':'
This above fractional number could also be represented as ⇒ a:b
So, we conclude that the fractional signs are equal to the ratio sign
As in the case of the fraction given in the question, it can also be written as = 2:5 in the form of a ratio.
Therefore, the ratio of adults to children is ⇒ 2:5
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What are the answers for the boxes
Answer:
= 2x + 3
Step-by-step explanation:
have a nice day!! :)
if your employer matches your retirement contributions on a dollar-for-dollar basis up to $4,000, how much will be contributed to your account by the end of the year if you take advantage of the entire match?
Hence, if yοu utilise the entire match, yοur accοunt will be credited with $8,000 befοre the end οf the year. Thus, option A is correct.
What is unitary methοd?Fοr the purpοse οf resοlving prοpοrtiοnality issues, mathematicians emplοy the unitary methοd. It is predicated οn the nοtiοn that if we are aware οf the relatiοnship between twο quantities fοr οne unit οf measurement, we may utilise that relatiοnship tο determine the relatiοnship between the same twο values fοr any οther unit οf measurement.
When we need tο determine the value οf οne quantity based οn the value οf anοther quantity and the twο quantities are related tο οne anοther prοpοrtiοnally, we frequently emplοy the unitary technique in practical circumstances. The unitary technique can be used, fοr instance, tο determine the price οf five apples if we knοw that three apples cοst $2.
given,
If yοur emplοyer matches yοur retirement cοntributiοns dοllar fοr dοllar up tο a maximum οf $4,000, this implies that fοr every dοllar yοu put in, yοur emplοyer will put in an additiοnal dοllar, up tο a tοtal οf $4,000 in matching funds.
Yοur emplοyer will cοntribute an additiοnal $4,000 if yοu cοntribute the whοle $4,000, fοr a tοtal οf $8,000 in cοntributiοns tο yοur accοunt by the end οf the year.
Hence, if yοu utilise the entire match, yοur accοunt will be credited with $8,000 befοre the end οf the year.
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If your employer matches your retirement contributions on a dollar-for-dollar basis up to $4,000, how much will be contributed to your account by the end of the year if you take advantage of the entire match?
a. $8,000
b. $8,800
c. $8,100
d. $9,800
I need help on this plss
Answer:
(20x+24)-2(7x+10)
(20x+24)-(14x+20)
6x+4 but thats for 2 sides so 3x+2
B
Check:
x=3
3*3+2=11*2=22
7*3+10=31*2=62
62+22=84
20*3+24=84
Answer:
B.) 3x+2
Step-by-step explanation:
2(7x+10)+2y=20x+24
14x+20+(6x+4)=20x+24 because there are two sides where you have to
20x+14 multiply the height and width by two o account for
both the actual number before multiplied was 3x+2
x= 1 /3 y+ −2/ 3
x=3y+2
What is the equation for the line perpendicular to y=3/2x + 2 that contains (3, -5)?
Answer:
B?
COREEC IF WRONG
Answer:
y=-2/3x-3
Step-by-step explanation:
let the slope of the given line =m1
let the slope of the perpendicular line,=m2
m2=-1/m1
m2=-1/3/2
m2=-2/3
Now the equation of the perpendicular line
y--5=-2/3(x-3)
y+5=-2/3(x-3)
3y+15=-2x+6
3y=-2x+6-15
3y=-2x-9
y=-2/3x-3
In the figure below, m||n. Match the angle pairs with the
correct label for the pairs.
On solving the provided question, by properties of parallel lines we got to know that - 1 - A 2 - C 3 - B 4 - D
what is alternate exterior angles?When two or more lines cross the intersection line, alternate exterior angles result. These angles are created on a number of sides outside the transverse lines. Any two parallel lines that cross one another create two angles with the horizontal line. In the area between the parallel lines, interior angles are formed, while alternate exterior angles are formed in the area outside the parallel lines.
Matches are -
1 - A
2 - C
3 - B
4 - D
To know more about alternate exterior angles visit:
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Investing $10,000 in a savings account at 5% annual interest compounded semiannually will result in approximately how much money after 10 years?
ILL GIVE BRAINLIEST
The graph of the function f(x)=−|2x| is translated 4 units down.
What is the equation of the transformed function?
Enter your answer in the box.
g(x)=
g(x)=|3x|+4
Step-by-step explanation:
pls mark me as brainliest
Need help thanks anybody that can help
Answer:
a.) perimeter: 48 yards area: 96 sq. yds
b.) perimeter: 39 feet area: 74.36 ft. sq.
Step-by-step explanation:
a.) perimeter: 16 + 20 + 12 = 48 area: height * base / 2 = 96
b.) perimeter: (14.3 * 2) + (5.2 * 2) = 39 area: Length * Width = 74.36
Answer:
TriangleArea = 96 yd
Perimeter = 48 yd,
RectangleArea = 74.36 yd
Perimeter = 39 yd
Step-by-step explanation: