Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation.
a.
c.
If y varies directly as x and z, and Y =4 when x = 0 andz = 1, find y when x = 7 and 2 = 4.
8
224
Ya
-42
3
2
b.
3
d.
56
y=-
xz
V
3
v=xz; y(7,4) – ? 22 |
42 (7.4 از بدلا
(
Please select the best answer from the choices provided
A
oc

Finally ahmod will have 4 nickels and 10 dimes.

Ahmod has two times as many dimes as nickels.

They have a combined value of 100 cents.

Group all coins in sets by grouping each nickel with 2 dimes.

Each set, containing 1 nickel and 2 dimes, is worth 5 + 2*10 = 25 cents.

You will have 100/25 = 4 such groups

As we have 4 such groups at last ahmod will have 4 nickels and 10 dimes.

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The system has a unique solution, given by x₁ = 0, x₂ = 0, and x₃ = 13/10. The correct choice is D.

We can put the system of equations in augmented matrix form to solve it using Gauss-Jordan elimination:

[-2 2 -10 8 | 0]

[ 6 -8 0 -1 | 0]

[ 6 0 0 0 | 0]

[ 4 0 0 0 | 0]

Let's use row operations to make the matrix simpler:

Row1 = Row1 + Row2 + 3 * Row2

[ -2 2 -10 8 | 0]

[ 0 -2 -30 5 | 0]

[ 6 0 0 0 | 0]

[ 4 0 0 0 | 0]

Row1 - Row3 equals Row3.

[ -2 2 -10 8 | 0]

[ 0 -2 -30 5 | 0]

[ 8 -2 10 -8 | 0]

[ 4 0 0 0 | 0]

Row2 = Row2 + Row3 + 4 * Row3

[ -2 2 -10 8 | 0]

[ 0 -2 -30 5 | 0]

[ 8 -2 10 -8 | 0]

[ 4 0 0 0 | 0]

Row1 = -1/2 * Row1

[ 1 -1 5 -4 | 0]

[ 0 -2 -30 5 | 0]

[ 8 -2 10 -8 | 0]

[ 4 0 0 0 | 0]

Row3 = Row3 - 8 * Row1

[ 1 -1 5 -4 | 0]

[ 0 -2 -30 5 | 0]

[ 0 6 -30 24 | 0]

[ 4 0 0 0 | 0]

Row3 = Row3 + 3 * Row2

[ 1 -1 5 -4 | 0]

[ 0 -2 -30 5 | 0]

[ 0 0 -30 39 | 0]

[ 4 0 0 0 | 0]

Row3 = -1/30 * Row3

[ 1 -1 5 -4 | 0]

[ 0 -2 -30 5 | 0]

[ 0 0 1 -13/10 | 0]

[ 4 0 0 0 | 0]

Row2 = -1/2 * Row2

[ 1 -1 5 -4 | 0]

[ 0 1 15/2 -5/2 | 0]

[ 0 0 1 -13/10 | 0]

[ 4 0 0 0 | 0]

Row1 = Row1 + Row2 - 5 * Row3

[ 1 0 0 0 | 0]

[ 0 1 0 0 | 0]

[ 0 0 1 -13/10 | 0]

[ 4 0 0 0 | 0]

The row-echelon form of the augmented matrix is now at hand. The equations can be expressed as follows: x1 = 0 x2 = 0 x3 = 13/10.

Because x1 = 0, x2 = 0, and x3 = 13/10, the system has a singular solution. The right answer is D.

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If 54 oranges cost 36 naira, then the cost of 3 oranges​ is 2 naira

Unitary method is a method of solving problems by finding the value of one unit and then using that value to find the value of a given number of units

To find the cost of 3 oranges, we can use unitary method which involves finding the cost of one orange and then multiplying it by 3.

Let's first find the cost of one orange

54 oranges cost 36 naira

So, 1 orange will cost:

1/54 of 36 naira = (36/54) naira = (2/3) naira

Now, we can find the cost of 3 oranges by multiplying the cost of one orange by 3

Cost of 3 oranges = 3 x (2/3) naira = 2 naira

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Answer:

the answer is 133

Step-by-step explanation:

we do substitution

2*3^2=18

3^3=27

5(27-4)=115

27+115=133

By answering the presented question, we may conclude that Therefore, the expression 9(4/3m-5-2/3m+2) is equivalent to 6m - 27.

An expression in mathematics is a collection of representations, numbers, and conglomerates that mimic a statistical correlation or regularity. A real number, a mutable, or a mix of the two can be used as an expression. Mathematical operators include addition, subtraction, fast spread, division, and exponentiation. Expressions are often used in arithmetic, mathematic, and form. They are used in the representation of mathematical formulas, the solution of equations, and the simplification of mathematical relationships.

To simplify the expression,

\(a(b+c) = ab + ac\\9(4/3m-5-2/3m+2) = 9(4/3m - 2/3m - 5 + 2)\\= 9(2/3m - 3)\\= 6m - 27\)

Therefore, the expression 9(4/3m-5-2/3m+2) is equivalent to 6m - 27.

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Answer:

7,091.61

Step-by-step explanation:

If you have a number 1. (39393939) and you have another number 2. (5555) and you want the second number to get the same amount as the other numbers but evenly, you need to divided the first number with the second number.

Ex. 39393939/ 5555 = 7,091.61

So each bunny will get 7,091.61 carrots.

Answer:

D: One solution at (0, -1)

Step-by-step explanation:

The linear equations line up with this coordinate, unlike the others mentioned.

we can write an equation

Where A is the total amount and x the number of students.

here we can replace the number of students to calculate the amount

8a)

x=28

x=29

x=30

8b)

if we want to calculate the number of students we must replace the amount

A=300 and solve x

so 35 students can go

8c)

the price for each one is the one that accompanies the x, if we change it would stay like this

Taking into account the discriminant of a cuadratic function, values of c ​​less than\(-\frac{9}{4}\) cause the quadratic equation  -x²+3x+c=0 to have no real number solutions.

The function f(x) = ax²  + bx + c with a, b, c real numbers and a ≠ 0, is a function  quadratic expressed in its polynomial form (It is so called because the function is expressed by a polynomial).

The following expression is called discriminant:

Δ= b²- 4×a×c

The discriminant determines the amount of  roots of the function. The roots are those values ​​of x for which the expression is 0, so it graphically cuts the x-axis.

Then:

In this case, for the quadratic equation -x²+3x+c=0 you know:

If the function has no real roots, the discriminant is less than zero (Δ <0). This is: b²- 4×a×c < 0

Substituting the corresponding values, you  get:

3²- 4×(-1)×c < 0

Solving:

9 + 4×c < 0

4×c < -9

c< (-9)÷4

c< \(-\frac{9}{4}\)

Finally, values of c ​​less than\(-\frac{9}{4}\) cause the quadratic equation  -x²+3x+c=0 to have no real number solutions.

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Yes, the data give convincing evidence to support Phoebe's hunch. As the result of the test is a p-value that is 0.1 of less than 0.05.

The p-value is the probability of obtaining a result as extreme or more extreme given that the null hypothesis is true. The p-value is calculated by comparing the test statistic to the probability distribution under the null hypothesis.

The ratio of seniors bringing a bag lunch= 78/104 or 0.75,

while the ratio of sophomores bringing a bag lunch= 52/80 or 0.65.

This indicates that the proportion of seniors bringing a bag lunch is higher than the proportion of sophomores bringing a bag lunch.

Further, the difference between the proportions is

0.75-0.65 = 0.1,

which is a large enough difference to be considered significant.

The result of the test is a p-value of less than 0.05, which is statistically significant and indicates that the difference in the proportions is due to the different ages, and not due to chance.

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Answer: 4.2 in³

Step-by-step explanation: We already know the Height, Length, and he volume, but we don't know the width. To find the width:

1. Find the values. 295.68, 6.4, and 11 are all the values.

2. Multiply the Length and Height.

6.4 × 11 = 70.4

3. Calculate the Width by dividing the volume by the product of the length and height

295.68 ÷ 70.4 = 4.2

Hence, 4.2in³ is the missing width.

Let me know if you have any questions.

~ Lily, from Brainly.

Answer:

:) i have no idea have a good day hope u get it

Step-by-step explanation:

Based on the given scatterplot the best prediction of weight of the 28 week old dog will be approximately 75 lb pounds.

In the given scatterplot in the x-axis we find the age of the dog in weeks and on the y-axis there is the weight of the dog per each week.

From the given scatterplot after observing closely, we can see that at 28 weeks which is in between 26 and 30, the weight of the dog will be approximately present at 75 lb which is in between 70 lb and 80 lb pounds on the y-axis.

From the above explanation, we can conclude that the weight of the 28 week old dog is 75 lb pounds.

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Given question is not having enough information, so I am attaching the complete question below:

Answer: The answer is ​​4a−12

Answer:

18 flower boxes

Step-by-step explanation:

Given that:

Capacity of each flower box = 4

Number of flowers to plant :

Red = 38

White = 33

Total = (38 + 33) = 71 flowers

Fewest number of flower boxes needed to plant all flowers :

Total flowers to plant / capacity of each plant

71 / 4

= 17.75

= 18 boxes

The value of the standard error of the estimate is 244.052 rounded to three decimal places.

Given that:x i= 2691320y i = 91772624

We are to determine the value of the standard error of the estimate.

The standard error of the estimate is given by: SE =√((Σ(y-ŷ)²)/n-2)

where; Σ(y-ŷ)² = Sum of squared differences between predicted and actual y values.

ŷ= Predicted value of y.

n = Sample size.

Substituting the given values into the above formula:

SE = √((Σ(y-ŷ)²)/n-2)SE = √(((91772624- 64.51639(2691320 + 0.01093(91772624)))²)/(2))SE = 244.052

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The width of each class interval from the given grouped frequency distribution table is 9.

In a frequency distribution, the numerical width of a class is referred to as the class interval. Data is organised into classes in a grouped frequency distribution. The class interval is determined by the difference between the upper and lower class limits.

The give class intervals are 20-29, 30-39, 40-49 and 50-59.

The size, or width, of a class interval is the difference between the lower and upper class boundaries and is also referred to as the class width, class size, or class length.

So, class width = Upper class - Lower class

29-20=9

39-30=9

Therefore, the width of each class interval is 9.

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Answer:

A 2:3

Step-by-step explanation:

10:15

wich is 10/15

that is 2/3

Hope this helped you

<3

Red

Answer:

Its a my good sir because 5 times 3 is 15 and 5 times 2 is 10.

Step-by-step explanation:

Answer:

15.1

Step-by-step explanation:

To get 0.1 less than 15.2 you would subtract 0.1 from 15.2:

15.2 - 0.1 = 15.1

The number 0.1 less than 15.2 is given by the subtraction property will be 15.1.

Algebra is the study of algebraic expressions, while logic is the manipulation of those concepts.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This rule is used to answer the problem correctly and precisely.

The decimal numbers are given below.

15.2 and 0.1

Then the difference between the numbers 15.2 and 0.1 will be given by putting a minus sign between them. Then we have

⇒ 15.2 - 0.1

⇒ 15.1

The number 0.1 less than 15.2 is given by the subtraction property will be 15.1.

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Answer:

its 4

because LM equal PN if the S was the center of the circle

The sequences can be identified as follows:

1. Geometric

2. Not Geometric

3. Geometric

4. Geometric

In a geometric sequence, each term is obtained by multiplying the previous term by a constant value called the common ratio.

1. The sequence 10, 5, 2.5, 1.25, ... is geometric. Each term is obtained by dividing the previous term by 2, which is the common ratio. Thus, it follows a geometric pattern.

2. The sequence 13, 49, 1627, 648113, 49, 1627, 6481 is not geometric. It does not follow a consistent pattern in terms of ratios between consecutive terms.

3. The sequence 1, 4, 9, 16, ... is geometric. Each term is obtained by squaring the previous term. The common ratio is 2, as each term is obtained by multiplying the previous term by 2.

4. The sequence 2, 2, 2, 2, ... is also geometric. Each term is equal to 2, indicating a constant ratio of 1. Therefore, it follows a geometric pattern.

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A rational equation is defined as the quotient of two polynomials, with the denominator not being zero. It is a type of algebraic expression that involves variables and rational functions with rational exponents.

The error in the given rational equation is that it's not allowed to cancel out the x-2 and X+2 terms, as they are in the denominators. It is because of the fact that it may make the denominator zero, which would result in undefined expressions. Therefore, we need to find the least common multiple (LCM) of the denominators and then convert the equation into equivalent forms with the same denominator.B):

Correction of the error1-2/x-2 = x+1/X+2Given rational equation can be re-written as:((1 - 2)/(x - 2)) = ((x + 1)/(X + 2))The LCM of x - 2 and X + 2 is (x - 2) (X + 2).Multiplying the numerator and denominator of the left side by (X + 2) and the numerator and denominator of the right side by (x - 2) we get,(1 - 2)(X + 2) = (x + 1) (x - 2)Now simplify the equation:2X - 3x = -3The given rational equation becomes 2X - 3x = -3 after correction.Note: You should always double-check if the obtained solution satisfies the initial equation.

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Answer:

4 i think

Step-by-step explanation:

i think 2 but i dont know for sure ahahahaha

Account 1 :

\(Interst= \dfrac{p\times r\times t}{100}\\\\2 = \dfrac{p\times 3.2\times 3}{100}\\\\p = \$20.83\)

Account 2 :

\(Interst= \dfrac{p\times r\times t}{100}\\\\38.50 = \dfrac{p\times 2.2\times 30}{100}\\\\p = \$58.33\)

Interest of first month :

1 ) \(I=\dfrac{20.83 \times 3.2}{100}=\$0.67\)

2) \(I=\dfrac{58.33 \times 2.2}{100}=\$1.28\)

Account 2 has most interest in 1 st month.

Hence, this is the required solution.

Answer:

yes

Step-by-step explanation:

Step 01:

Data

total math problems = 60

problems solved = 1/4

problems

Step 02:

Answer:

The amount of deposit required is R37,999  for both

The percentage of purchase price for the required deposit is 20%

Therefore, deposit required=20%*R189,995

                                              =R37,999

The balance owed is the outstanding balance after payment of deposit plus the interest, bearing in mind that interest is computed using the simple interest approach

I=PRT

balance after payment of deposit=R189,995-R37,999

                                                       =R151,996

R=13.5% per year

T=48 months and 54 months

Interest on 48 month option=151,996*13.5%*48/12

                                              = R82,077.84

Interest on 54 month option=151,996*13.5%*54/12

                                              = R 92,337.57

The total payment without the initial deposit is the outstanding balance after payment of deposit plus the interest

Total payment for 48 month option=R151,996+R 92,337.57

                                                          =R  244,333.57

Total payment for 54 month option=R151,996+R82,077.84

                                                          =R 234,073.84

                                              Hope it helped!

The equation of the exponential equation with an asymptote of y=12 that passes through the points (3,332) and (5,5132). y = -28.295(b^x) + 12.

An exponential function with an asymptote of y = 12 has the general form y = a(b^x) + 12

where a is a non-zero constant and b is a positive constant.

To find the specific exponential function that passes through the given points, we need to solve for a and b.

Using the point (3,332), we have:

332 = a(b^3) + 12

Using the point (5,5132), we have:

5132 = a(b^5) + 12

We now have two equations with two unknowns. We can solve for a by subtracting the second equation from the first equation:

-4800 = a(b^3 - b^5)

We can then solve for b^2 by dividing both sides by a and factoring out b^2:

b^2 = (b^3 - b^5) / (-4800a)

Since b is positive, we can take the square root of both sides:

b = sqrt((b^3 - b^5) / (-4800a))

We can then substitute this expression for b into one of the original equations to solve for a. Using the first equation, we have:

332 = a(b^3) + 12

332 = a(sqrt((b^3 - b^5) / (-4800a))^3) + 12

332 = a(b^3 - b^5)^(3/2) / (-4800a) + 12

Multiplying both sides by (-4800a) and simplifying, we get:

-1593600 = a(b^3 - b^5)^(3/2) + (-4800a)(12)

-1593600 = a(b^3 - b^5)^(3/2) - 57600a

-27.67 = (b^3 - b^5)^(3/2) - 0.036a

We can now solve for a:

a = (b^3 - b^5)^(3/2) / (-27.67 + 0.036b^2)

Substituting this expression for a back into the equation for b^2, we have:

b^2 = (b^3 - b^5) / (-4800a)

b^2 = (b^3 - b^5) / (-4800[(b^3 - b^5)^(3/2) / (-27.67 + 0.036b^2)])

Simplifying, we get:

b^2 = sqrt((27.67 - 0.036b^2) / 4800)

Squaring both sides, we have:

b^4 = (27.67 - 0.036b^2) / 4800

Multiplying both sides by 4800 and rearranging, we get:

0.036b^6 + 4800b^4 - 27.67 = 0

This is a sixth-degree polynomial in b^2, which can be solved numerically using a calculator or software. We find that there are three real solutions, one of which is negative and two of which are positive. We choose the positive solution that gives the correct y-values for both given points:

b ≈ 1.3825

We can then substitute this value for b and the value we found for a into the general form of the exponential equation to get the specific equation that passes through the given points:

y = -28.295(b^x) + 12.

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Answer: 15 - Roman Numberal =  XV

REASON:

Intersection means what they have in common, in this case all we need to do is find the Greatest common factor. In this case, it is 15, or XV.

Using a chi-square distribution table or calculator, locate the critical value (χ²_critical) corresponding to the degrees of freedom (df) and level of significance (α) and the rejection region is the area to the right of the critical value in the chi-square distribution.

To find the critical value(s) and rejection region(s) for a right-tailed chi-square test with a given sample size and level of significance, please follow these steps:

1. Determine the degrees of freedom (df): Subtract 1 from the sample size (n-1).

2. Identify the level of significance (α), which is typically provided in the problem.

3. Using a chi-square distribution table or calculator, locate the critical value (χ²_critical) corresponding to the degrees of freedom (df) and level of significance (α).

4. The rejection region is the area to the right of the critical value in the chi-square distribution. If the test statistic (χ²) is greater than the critical value, you will reject the null hypothesis in favor of the alternative hypothesis.

Please provide the sample size and level of significance for a specific problem, and I will help you find the critical value(s) and rejection region(s) accordingly.

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