Answer:
80⁰+ 105⁰+ 75⁰+ x = 360
260⁰+ x =360
x= 360 - 260
x= 100⁰
AC is the diameter of the circle. Angle AWB is 120 degrees. How big is arc BC
Answer:
60°
Step-by-step explanation:
Arc BC and Angle BWC are the same number of degrees.
When the vertex of an angle is at the center of a circle, its called a Central Angle. A central angle and the arc it "cuts off" have the same number of degrees.
Angle AWB and Angle BWC lay together on a straight line, so they add up to 180°.
180° - 120° is 60°
Angle BWC is 60° so Arc BC is 60°
HELP PLEASE URGENT!!!
A Ferris wheel is 50 meters in diameter and boarded from a platform that is 4 meters above the ground. The six o'clock position on the Ferris wheel is level with the loading platform. The wheel completes 1 full revolution in 2 minutes. How many minutes of the ride are spent higher than 38 meters above the ground?
answer in minutes.
The number of minutes spent higher than 38 meters above the ground on the Ferris wheel ride is approximately 1.0918 minutes.
To solve this problem, we need to determine the angular position of the Ferris wheel when it is 38 meters above the ground.
The Ferris wheel has a diameter of 50 meters, which means its radius is half of that, or 25 meters.
When the Ferris wheel is at its highest point, the radius and the height from the ground are aligned, forming a right triangle.
The height of this right triangle is the sum of the radius (25 meters) and the platform height (4 meters), which equals 29 meters.
To find the angle at which the Ferris wheel is 38 meters above the ground, we can use the inverse sine (arcsine) function.
The formula is:
θ = arcsin(h / r)
where θ is the angle in radians, h is the height above the ground (38 meters), and r is the radius of the Ferris wheel (25 meters).
θ = arcsin(38 / 29) ≈ 1.0918 radians
Now, we know the angle at which the Ferris wheel is 38 meters above the ground.
To calculate the time spent higher than 38 meters, we need to find the fraction of the total revolution that corresponds to this angle.
The Ferris wheel completes one full revolution in 2 minutes, which is equivalent to 2π radians.
Therefore, the fraction of the revolution corresponding to an angle of 1.0918 radians is:
Fraction = θ / (2π) ≈ 1.0918 / (2π)
Finally, we can calculate the time spent higher than 38 meters by multiplying the fraction of the revolution by the total time for one revolution:
Time = Fraction \(\times\) Total time per revolution = (1.0918 / (2π)) \(\times\) 2 minutes
Calculating this expression will give us the answer in minutes.
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Solve for the following if x = 6: (Hint: substitute 6 for the letter x and work the problem. You will work more with substitution later.) Example: 10x = 10*6 = 60 9. x - 6 ( if x = 6) 10. 7 + x ( if x = 6) 11. 3x - 9 ( if x = 6) 12. 63/x ( if x = 6) 13. 5 + 5x + 10 ( if x = 6)
Using PEMDAS and substituting 6 for x, the results of the mathematical operations are as follows:
1) 482) 763) 1894) 1265) 105.What is PEMDAS?PEMDAS is the order of mathematical operations that explains the correct sequential steps for evaluating mathematical expressions.
PEMDAS means that mathematical operations must follow the following order:
ParenthesesExponentsMultiplicationDivisionAdditionSubtraction.1) 9. x - 6 ( if x = 6)
= 9 x 6 - 6
= 54 - 6
= 48
2) 10. 7 + x ( if x = 6)
= 10 x 7 + 6
= 70 + 6
= 76
3) 11. 3x - 9 ( if x = 6)
= 11 x 3(6) - 9
= 11 x 18 - 9
= 198 - 9
= 189
4) 12. 63/x ( if x = 6)
= 12 x 63/6
= 126
5) 13. 5 + 5x + 10 ( if x = 6)
= 13 x 5 + 5(6) + 10
= 65 + 30 + 10
= 105
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Which graph represents 12 = 3x + 4y line a, line b, line c
Answer:
green line or "b"
Step-by-step explanation:
we can set this up into the slope intercept form
y=mx+b
where m is the slope and b is y intercept
12=3x+4y
-3x -3x
-3x+12=4y
/4. /4. /4
-3/4x+3=y
we can see the only line with a negative slope and a y intercept at 3 is the green line or "b"
hopes this helps please mark rainliest
how to find n if sn=969 of A.p,a1=9 and d=6
what should be subtracted from 7/12+7/8 to obtain the multiplicated inverse of (4/3-4/9)
To find the subtracted value, we need to calculate the multiplicative inverse of (4/3 - 4/9) and then subtract it from the sum of 7/12 and 7/8.
First, let's find the multiplicative inverse of (4/3 - 4/9):
Multiplicative inverse = 1 / (4/3 - 4/9)
To simplify the expression, we need a common denominator:
Multiplicative inverse = 1 / ((12/9) - (4/9))
= 1 / (8/9)
= 9/8
Now, we need to subtract the multiplicative inverse from the sum of 7/12 and 7/8:
Subtracted value = (7/12 + 7/8) - (9/8)
To perform this calculation, we need a common denominator:
Subtracted value = (7/12 * 2/2 + 7/8 * 3/3) - (9/8)
= (14/24 + 21/24) - (9/8)
= 35/24 - 9/8
To simplify further, we need a common denominator:
Subtracted value = (35/24 * 1/1) - (9/8 * 3/3)
= 35/24 - 27/24
= 8/24
= 1/3
Therefore, subtracting 1/3 from the sum of 7/12 and 7/8 will give you the multiplicative inverse of (4/3 - 4/9).
Directions - Multiply the binomials using the box method.
(y+3) (y-6)
The product of the binomials (y + 3)(y - 6) gives y² - 3y - 18
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.
The product of the binomial is:
(y + 3)(y - 6)
= y(y) + y(-6) + 3(y) + 3(-6)
= y² - 3y - 18
The product of the binomials (y + 3)(y - 6) gives y² - 3y - 18
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12. Quadrilateral ABCD is congruent to quadrilateral EFGH. If mZA = 6x - 8 and mZE = 4x + 1, find m2A. Choose: © 19° O 24° O 40° 0 51°
Let's draw the figures to better understand the scenario:
The figure appears that ∠A and ∠E are pairs of corresponding angles. Since it was given that the two quadrilaterals are congruent, ∠A and ∠E must also be congruent.
With this relationship, let's first determine the value of x to be able to determine the measure of ∠A.
We get,
\(\text{ 6x - 8 = 4x + 1}\)\(\text{ 6x - 8 + 8 - 4x = 4x + 1 + 8 - 4x}\)\(\text{ 6x - 4x = 1 + 8}\)\(\text{ 2x = 9}\)\(\text{ }\frac{\text{2x}}{2}\text{ = }\frac{\text{9}}{2}\)\(\text{ x = }\frac{9}{2}\)Let's determine the measure of ∠A.
\(\text{ }\angle A\text{ = 6x - 8 = 6(}\frac{9}{2})\text{ - 8}\)\(\text{ = 3(9) - 8}\)\(\text{ = 27 - 8}\)\(\text{ }\angle A=19^{\circ}\)Therefore, the measure of ∠A is 19°. The answer is letter A or the 1st option.
Use calculus to find the area A of the triangle with the given vertices. (0, 6), (2, −3), (3, 4)
The area of the triangle with the given vertices is 11.5 square units.
Define the area of triangle by vertices?The area of a triangle can be calculated using the coordinates of its vertices using the following formula.
To find the area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃), we can use the following formula:
A = (x₁(y₂ − y₃) + x₂(y₃ − y₁) + x₃(y₁ − y₂))/2
Using this formula with the given vertices (0, 6), (2, −3), and (3, 4), we get:
A = (0(-3 − 4) + 2(4 − 6) + 3(6 − (-3)))/2
A = (0 - 4 + 27)/2
A = 23/2
A = 11.5
Therefore, the area of the triangle with the given vertices is 11.5 square units.
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Find the area of the rectangle with length 27 inches and width 40 inches. (1 point)
67 in. 2
134 in. 2
1,080 in. 2
10,800 in. 2
Answer:
1,080 square inches
Step-by-step explanation:
27 inches * 40 inches = 1,080 square inches
ALGEBRA please put a very small explanation to the awnser
Certainly! The problem can be solved using the Pythagorean theorem,
which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the ladder acts as the hypotenuse, and we need to find the length of the vertical side (height) it reaches up the wall.
The ladder forms the hypotenuse, and its length is given as 12 meters. The distance from the foot of the ladder to the base of the wall represents one side of the triangle, which is 4.5 meters.
By substituting the given values into the Pythagorean theorem equation: (12m)^2 = h^2 + (4.5m)^2, we can solve for the unknown height 'h'.
Squaring 12m gives us 144m^2, and squaring 4.5m yields 20.25m^2. By subtracting 20.25m^2 from both sides of the equation, we isolate 'h^2'.
We then take the square root of both sides to find 'h'. The square root of 123.75m^2 is approximately 11.12m.
Therefore, the ladder reaches a height of approximately 11.12 meters up the wall.
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HELP ME IM TOTALLY LOST AND HAVE A HARD TIME ASKING PEOPLE FOR HELP
Answer:
a. 1,323,002
Step-by-step explanation:
What has no solutions in common with 6x+2y=12
Answer:
-6x - 2y = 12
Step-by-step explanation:
[ it's a fraction but i can't write it as such. ]
Solve for M.
m/5 = 4
9
20
-9
-20
Answer:
the value of m will be 20
Find the LCM of A= 3^2 x 5^4 x 7 and B= 3^4 x 5^3 x 7 x11
The LCM of A = 3² × 5⁴ × 7 and B = 3⁴ × 5³ × 7 × 11 is 3898125 using Prime factorization.
Given are two numbers which are showed in the prime factorized form.
A = 3² × 5⁴ × 7
B = 3⁴ × 5³ × 7 × 11
Prime factorization is the factorization of a number in terms of prime numbers.
In order to find the LCM of these two numbers, we have to first match the common primes and write down vertically when possible and then bring down the primes in each column.
A = 3² × 5³ × 5 × 7
B = 3² × 3² × 5³ × 7 × 11
Bring down the primes in each column.
LCM = 3² × 3² × 5³ × 5 × 7 × 11
= 3898125
Hence the LCM is 3898125.
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Consider this equation
1/x-1 = | x-2 |
Using three iterations of successive approximation, what is the approximate solution to the equation? Use the graph as a starting point.
A. x ≈ 43/16
B. x ≈ 21/8
C. x ≈ 41/16
D. x ≈ 19/8
The approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.
To solve the equation 1/x-1 = |x-2| using three iterations of successive approximation, we will start with an initial guess and refine it using an iterative process.
Given that the equation involves absolute value, we will consider two cases:
Case 1: x - 2 ≥ 0
In this case, |x-2| simplifies to x-2, and the equation becomes 1/(x-1) = x-2.
Case 2: x - 2 < 0
In this case, |x-2| simplifies to -(x-2), and the equation becomes 1/(x-1) = -(x-2).
Now, let's perform the successive approximation:
Iteration 1:
Let's start with an initial guess, x = 2.
Case 1: When x - 2 ≥ 0,
1/(2-1) = 2-2,
1/1 = 0,
which is not true.
Case 2: When x - 2 < 0,
1/(2-1) = -(2-2),
1/1 = 0,
which is not true.
Since our initial guess did not satisfy the equation in either case, we need to choose a different initial guess.
Iteration 2:
Let's try x = 3.
Case 1: When x - 2 ≥ 0,
1/(3-1) = 3-2,
1/2 = 1,
which is not true.
Case 2: When x - 2 < 0,
1/(3-1) = -(3-2),
1/2 = -1,
which is not true.
Again, our guess did not satisfy the equation in either case.
Iteration 3:
Let's try x = 2.5.
Case 1: When x - 2 ≥ 0,
1/(2.5-1) = 2.5-2,
1/1.5 = 0.5,
which is true.
Case 2: When x - 2 < 0,
1/(2.5-1) = -(2.5-2),
1/1.5 = -0.5,
which is not true.
Our guess of x = 2.5 satisfies the equation in Case 1.
Therefore, the approximate solution to the equation 1/x-1 = |x-2| after three iterations of successive approximation is x ≈ 5/2 or x ≈ 2.5.
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A cafeteria sold 36 cartons of regular flavored milk. If the ratio of regular milk sold to chocolate milk sold was 9:4, what is the combined amount of chocolate and regular milk sold?
Answer:
The combined amount of chocolate and regular milk sold was 52 cartons.
Step-by-step explanation:
1. Divide
36 ÷ 9 = 4
(This means that the ratio has a unit rate of 4. That means):
2. Second ratio rate
4 x 4 = 16
(Because the unit rate is 4).
3. Add
(Now, we add the original 36 cartons with the 16 cartons we found because the first step was just for finding the unit rate).
36 + 16 = 52 cartons.
May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I only need 3 more brainliest to become a genius! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!
Given the following five-number summary, find Q₁.
2.9, 5.7, 10.0, 13.2, 21.1
OA. 5.7
OB. 2.9
OC. 10.0
Given the following five-number summary: 2.9, 5.7, 10.0, 13.2, 21.1, so Q₁ = 5.7. This can be solved using the concept of quartile.
What is quartile?A kind of percentile is a quartile. The first quartile (Q₁, or the lowest quartile), which corresponds to the 25th percentile of the data, is below which 25% of the data are found. The second quartile (Q₂, or the median), which represents the 50th percentile, indicates that 50% of the data are below this quartile.
There are 5 data points, and the middle value of the lower half of the data set will represent the first quartile. So the second data value is the first quartile. So, Q₁ = 5.7
There are 5 data points, and the middle value of the upper half of the data set will represent the third quartile. The fourth data value is the third quartile. So,
Q₃ = 13.2
SO IQR will be:
= Q₃ - Q₁
= 13.7 - 5.1
= 7.5
Thus, Q₁ = 5.7
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The amount of pollutants that are found in waterways near large cities is normally distributed with mean 9.4 ppm and standard deviation 1.7 ppm. 40 randomly selected large cities are studied. Round all answers to 4 decimal places where possible.What is the distribution of X ? X ~ N(,)What is the distribution of ¯x ? ¯x ~ N(,)What is the probability that one randomly selected city's waterway will have less than 9.1 ppm pollutants? For the 40 cities, find the probability that the average amount of pollutants is less than 9.1 ppm. For part d), is the assumption that the distribution is normal necessary? YesNoFind the IQR for the average of 40 cities.Q1 = ppmQ3 = ppmIQR: ppm
Given
mean = 9.4 ppm
standard deviation = 1.7 ppm
40 randomly selected large cities are studied.
Find
a) What is the distribution of X?
b) What is the distribution of ¯x?
c) What is the probability that one randomly selected city's waterway will have less than 9.1 ppm pollutants?
d) For the 40 cities, find the probability that the average amount of pollutants is less than 9.1 ppm.
e) For part d), is the assumption that the distribution is normal necessary?
f) Find the IQR for the average of 40 cities.
Q1 , Q3 , IQR:
Explanation
a) distribution of X = X ~ N(9.4 ,1.7)
b) distribution of ¯x
\(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}=\frac{1.7}{\sqrt{40}}=0.26879360111\approx0.2688\)so , distribution of ¯x =
\(\bar{x}(9.4,0.2688)\)c)
Demi has 221 songs on her phone. The songs take up 884 megabytes of storage . Each song takes up same amount of space . How many megabytes do 135 of these songs take up?
Answer:
540 megabytes
Step-by-step explanation:
We will first need to find out how much space a singular song will take up. We will do this by the storage taken up (884) by the number of songs she has:
884 / 221 = 4 mb taken up per song
Then we want to find out how many megabytes 135 of these songs take up, so we will multiply the mb taken up per song (4) by the number of songs we want to find (135):
4 x 135 = 540 megabytes
Edit: made a mistake in my original answer, apologies!
A farmer purchased 480 meters of fencing, and will build a rectangular pen with it. To enclose the largest possible area, what should the
pen's length and width be? Model the pen's area with a function, and then find its maximum value.
To enclose the largest possible area, the pen's length should be__and width should be__.
The largest possible area will be 14400 meters², the pen's length should be 120 meters, and the width should be 120 meters.
What is the perimeter of the rectangle?The perimeter of a rectangle is defined as the addition of the lengths of the rectangle's four sides.
Let's assume that the length of the pen would be x.
We have been given the perimeter as 480 meters.
Let w be the width of the rectangle and l be the length of the rectangle
The perimeter of a rectangle = 2(l+w)
So, 480= 2(x + w)
240 = x + w
w = 240 - x
Length = x and width = (240 – x)
Area = x(240 - x) = 240x - x²
To get the maximum area, we equate the first derivative of the area to zero.
A = 240x - x²dA/dx = 240 - 2x = 0
2x = 240
x = 120
So, width = 240 – x = 240 – 120 = 120.
Maximum area = length × width
Maximum area = 120 × 120 = 14400 meters²
Thus, the pen should be 120 meters long and 120 meters wide, with a maximum possible area of 14400 meters².
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The diagram shows a right-angled triangle.
24 cm
18 cm
_Not to scale
Calculate the value oft. Give your answer correct to 1 decimal place.
Answer:
can i have a photo, please?
Step-by-step explanation:
PLZ PLZ HELP
Mark is investing $47,000 in an account paying 5.26% interest compounded continuously.
What will Mark's account balance be in 17 years?
O $114,932.80
$114,925.39
$114,921.47
$114.925.46
===============================================
Work Shown:
A = P*e^(r*t)
A = 47000*e^(0.0526*17)
A = 114,932.799077198
A = 114,932.80
Notes:
P = 47,000 is the principal or amount depositedr = 0.0526 is the decimal form of 5.26%The "e" refers to the special constant e = 2.718... which is similar to pi = 3.14... I would let your calculator handle this constant. There should be a button labeled "e".Mark's account balance after 17 years would be $114,932.8
What is the formula for the continuous compounding?\(A=Pe^{rt}\)
where,
A = Accrued amount
P = Principal amount
r = interest rate as a decimal
R = interest rate as a percent
r = R/100
t = time in years
For given question,
P = $47000, t = 17 years
R = 5.26%
\(\Rightarrow r =\frac{5.26}{100}\\\\\Rightarrow r = 0.0526\)
Using the Continuous Compounding Formula,
\(\Rightarrow A=Pe^{rt}\\\\\Rightarrow A=47000\times e^{0.0526\times 17}\\\\\Rightarrow A=114932.8\)
Therefore, Mark's account balance after 17 years would be $114,932.8
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Plz help i am timed
Find the missing exponent: 36 = 67.
A.-2
B.2
C.-1/2
D.1/2
Answer:
b.2
Step-by-step explanation:
thats ur answer
Answer:
B. 2
Step-by-step explanation:
Enter the leftover distance as a fraction. Javon is helping his dad build a tree house. He has a piece of trim that is 16 feet long. How many pieces can Javon cut that are 1 yard long? How much of a yard will he have left over?
Javon will have 1 and 1/3 yards (or 4 feet) of trim leftover.
To answer this question, we need to convert the length of the trim from feet to yards. Since there are 3 feet in 1 yard, we can divide 16 by 3 to get 5 and 1/3 yards.
Next, we need to determine how many pieces of trim Javon can cut that are 1 yard long. Since there are 3 feet in 1 yard, each piece of trim will be 3 feet long. We can divide 5 and 1/3 yards by 1 yard to get 5 pieces of trim.
Finally, we need to find out how much of a yard Javon will have left over. We can multiply the leftover distance in yards by 3 to convert it back to feet. The leftover distance is 1 and 1/3 yards, so multiplying by 3 gives us 4 feet.
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Optimal Chapter-Flight Fare If exactly 212 people sign up for a charter flight, Leisure World Travel Agency charges $292/person. However, if
more than 212 people sign up for the flight (assume this is the case), then each fare is reduced by $1 for each additional person. Determine how
many passengers will result in a maximum revenue for the travel agency. Hint: Let x denote the number of passengers above 212. Show that the
revenue function R is given by R(x) = (212+x)(292-x).
passengers
What is the maximum revenue?
$
What would be the fare per passenger in this case?
dollars per passenger
Answer:
Dollars per passenger would be $252.
The maximum revenue is $63,404.
Step-by-step explanation:
Let's define the number of passengers above 212 as x.
The revenue function is given by R(x) = (212 + x)(292 - x).
We can expand and simplify the revenue function:
\(R(x) = 212 * 292 + 212 * (-x) + x * 292 + x * (-x)\)
= \(61804 - 212x + 292x - x^2\)
= \(-x^2 + 80x + 61804\)
The revenue function is a quadratic function in the form\(R(x) = -x^2 + 80x + 61804\), representing a downward-opening parabola.
To find the x-coordinate of the vertex (which gives the number of passengers for maximum revenue), use the formula \(x = -b/2a\), where \(a = -1\) and \(b = 80\).
\(x=\frac{-80}{2*(-1)}\)
\(= \frac{80}{2}\)
\(= 40\)
Therefore, the number of passengers above 212 for maximum revenue is 40.
Substitute x = 40 into the revenue function to find the maximum revenue:
\(R(x) = -(40)^2 + 80(40) + 61804\)
\(= -1600 + 3200 + 61804\)
\(= 61804 + 1600\)
\(= 63404\)
Hence, the maximum revenue is $63,404.
To determine the fare per passenger, subtract x from the base fare of $292:
Fare per passenger = Base fare - x
\(= 292 - 40\)
\(= 252\) Dollars per passenger.
There are 25 students and one teacher in class. After an exam, everyone high-fives
everyone else to celebrate how well they did. How many high-fives were there?
Answer:
300
Step-by-step explanation:
I think it will be 300 because
People High-Fives
2. 1
3. 3
4. 6
5. 10
6. 15
7. 21
8. 28
9. 36
10. 45.
There fore 10 people's high five will be 45 keep repeating and finding out the high fives I got 300 but I'm not sure if it's correct
The required number of high fives is 300.
Given that,
There are 25 students and one teacher in the class. After an exam, everyone high-fives everyone else to celebrate how well they did. How many high-fives were there is to be determined.
In arithmetic, combination and permutation are two different ways of grouping elements of a set into subsets. In a combination, the components of the subset can be recorded in any order. In a permutation, the components of the subset are listed in a distinctive order.
Here,
There are 25 students
n = 25
For each high five, there would be at least 2 students,
r = 2
The number of high five is given by combination,
= 25 C 2
= 25 * 24 / 2
= 600 / 2
= 300
Thus, the required number of high fives is 300.
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Let C(t) be the amount of U.S. cash per capita in circulation at time 1. The table, supplied by the Treasury Department, gives values of C(t) as of June 30 of the specificd year. Interpret and estimate the value of C'(1980).
Answer:
Following are the solution to this question:
Step-by-step explanation:
C'(t) was its time, in years, or t shift of cash per unit. That C'(1980) meaning, therefore, becomes the change of cashier's population to t = 1980.
They could either use t = 1970 or t = 1990 to approximate the C'(1980) price. When using t = 1970:
\(C'(1980) = \frac{[C(1980) - C(1970)]}{[1980 - 1970]}\\\\\)
\(= \frac{(571 - 265)}{10}\\\\ = \$ \ 30.6 \\\)
t = 1990:
\(C'(1980) = \frac{[C(1980) - C(1990)]}{[1980 - 1990]}\)
\(= \frac{(571 - 1063)}{ -10} \\\\= \$ \ 49.2\)
Slope intercept form that passes through (-2,2) and perpendicular to y=1/2x-3
\(▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪\)
The equation of line that passes through (-2,2) and perpendicular to y=1/2x-3 is :
\(y = - 2x - 2\)
\( \large \boxed{ \mathfrak{Explanation}}\)
The equation of given line is :
\(y = \dfrac{1}{2} x - 3\)here, we can infer that slope of the given line is \(\dfrac{1}{2}\) by comparing it with the general equation of line.
Let the slope of line perpendicular to it be m, now as we know if the lines are perpendicular then the product of their slopes will be equal to -1,
that is :
\(m \times \dfrac{1}{2} = - 1\)let's solve for m (slope of perpendicular line) ~
\(m = - 1 \times 2\)\(m = - 2\)now, let's find the equation of line perpendicular to y=1/2x-3 using the point - slope form, ( by using point (-2 , 2) and slope (-2))
\( \mathrm{y - y_1 = m(x - x_1)}\)\(y - 2 = - 2(x - ( - 2))\)\(y - 2 = - 2(x + 2)\)\(y - 2 = - 2x - 4\)\(y = - 2x - 4 + 2\)hence, the required equation is :
\(y = - 2x - 2\)\(\mathrm{✌TeeNForeveR✌}\)
Integration of ∫(cos3x+3sinx)dx integration
Answer:
\( I = \dfrac{1}{3}sin(3x) - 3cos(x) + C\)
Step-by-step explanation:
We need to integrate the given expression. Let I be the answer .
\(\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx \)
Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .Rewrite using du and u .\(\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}\)
Answer:
\(\displaystyle \large{\frac{\sin 3x}{3} - 3\cos x + C}\)
Step-by-step explanation:
We are given the indefinite integral:—
\(\displaystyle \large{\int (\cos 3x + 3\sin x) \ dx}\)
Important Formulas
\(\displaystyle \large{\int f(ax+b) \ dx = \frac{1}{a} F(ax+b) + C}\\\displaystyle \large{\int \cos(ax) \ dx = \frac{1}{a} \sin (ax) + C \ \ \tt{(a \ \ is \ \ a \ \ constant.)}}\\\displaystyle \large{\int \sin x \ dx = - \cos x + C}\\\displaystyle \large{\int [f(x) \pm g(x)] \ dx = \int f(x) \ dx \pm \int g(x) \ dx}\\\displaystyle \large{\int kf(x) \ dx = k \int f(x) \ dx \ \ (\tt{k \ \ is \ \ a \ \ constant.})}\)
Therefore, from the integral, apply the properties above:—
\(\displaystyle \large{\int (\cos 3x + 3\sin x) \ dx = \int \cos 3x \ dx + \int 3 \sin x \ dx}\\\displaystyle \large{\int (\cos 3x + 3\sin x) \ dx = \int \cos 3x \ dx + 3 \int \sin x \ dx}\\\displaystyle \large{\int (\cos 3x + 3\sin x) \ dx = \frac{1}{3} \sin 3x + 3\cdot -\cos x + C}\\\displaystyle \large{\int (\cos 3x + 3\sin x) \ dx = \frac{\sin 3x}{3} - 3\cos x + C}\)
Hence, the solution is:—
\(\displaystyle \large \boxed{\frac{\sin 3x}{3} - 3\cos x + C}\)