The horn on a fire truck sounds at a pitch of 350 hz a. what is the perceived frequency when the fire truck is moving toward you at 20m/s? b. What is the perceived frequency when the fire truck is moving away from you at 20m/s: assume the speed of sound in air is 343m/s.

Answers

Answer 1

The perceived frequency when the fire truck is moving toward you and away from you will be 370 Hz and 329.59 Hz respectively.

What is the Doppler effect?

A sudden change in the frequency due to the distance between the objects and source is explained by the doppler effect.

As the source and observer travel toward each other, the frequency of sound, light, or other waves increases or decreases.

The perceived frequency when the fire truck is moving toward you;

\(\rm r' = (\frac{v+v_0}{v}) V \\\\ \rm r' = (\frac{343+20}{343}) 350 \\\\ r' =370.4 \ Hz\)

The perceived frequency when the fire truck is moving away from you;

\(\rm r' = (\frac{v-v_0}{v}) V \\\\ \rm r' = (\frac{343-20}{343}) 343 \\\\ r' =329.59 \ Hz\)

Hence, the perceived frequency when the fire truck in cases 1 and 2 will be 370 Hz and 329.59 Hz.

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Related Questions

The mass of 25cm3 of ivory was found to be 0.045kg Calculate the density of ivory in Sl units.​

Answers

Answer:  the density of ivory in SI units is 1800 kg/m^3.

Explanation: To calculate the density of ivory in SI units, we use the formula density = mass/volume. We are given the mass of 25 cm^3 of ivory as 0.045 kg. Since volume is in cm^3, we need to convert it to SI units of m^3. 1 cm^3 is equal to 1 milliliter (ml), so 25 cm^3 is equal to 25 ml. To convert ml to m^3, we use the conversion factor 1 ml = 10^-6 m^3. We then substitute the values of mass and volume into the density formula and simplify. The resulting density is expressed in units of kg/m^3, which are the SI units for density. Therefore, the density of ivory in SI units is 1800 kg/m^3.

A fisherman and his young son are in a boat on a small pond. Both are wearing life jackets. The son is holding a large helium filled balloon by a string, holding a significant part of his weight. Consider each action below independently and indicate whether the level of the water in the pond, Rises, Falls, is Unchanged or Cannot tell.
The son pops the helium balloon.
The fisherman knocks the tackle box overboard and it sinks to the bottom.
The son finds a cup and bails some water out of the bottom of the boat
The fisherman lowers himself in the water and floats on his back.
The fisherman lowers the anchor and it hangs one foot above the bottom of the pond. (the anchor is initially inside the boat)
The son gets in the water, looses his grip on the string, letting the balloon escape upwards.

Answers

(a) The son pops the helium balloon (unchanged)

(b) The fisherman knocks the tackle box overboard and it sinks to the bottom (rises)

(c) The son finds a cup and bails some water out of the bottom of the boat (falls)

(d) The fisherman lowers himself in the water and floats on his back (unchanged)

(e) The fisherman lowers the anchor and it hangs one foot above the bottom of the pond (rises)

(f) The son gets in the water, looses his grip on the string, letting the balloon escape upwards (rises).

Displaced volume of water in the pond

According to Archimedes principle, when a body is partially or completely immersed in a fluid, it experiences an upthrust which is equal to weight of to fluid displaced.

F = ρVg

V = F/ρg

where;

V is volume of water displacedρ is density of the immersed objectg is acceleration due to gravity

When an object with a significant weight is dropped into the pond, the level of water in the pond will rise and vice versa.

The son pops the helium balloon

The water level in the pond will be Unchanged, since the weight of the balloon is almost insignificant.

Fisherman knocks the tackle box overboard and it sinks to the bottom

The water level will rise because the weight of the tackle box is significant.

Son finds a cup and bails some water out of the bottom of the boat

The water level will fall since some volume of water is being removed.

Fisherman lowers himself in the water and floats on his back

The water level will be unchanged, since nothing new is added into the pond.

Fisherman lowers the anchor and it hangs one foot above the bottom of the pond

The water level will rise because the anchor will displace some volume of water upwards when it is dropped inside the pond.

Son gets in the water, looses his grip on the string, letting the balloon escape upwards.

The water level will rise, because the balloon will displace the water upwards when it escape upwards.

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Can you help me with the blank part please I need it done today

Can you help me with the blank part please I need it done today

Answers

Measurement: Presure
Unit symbol:(Pa)
Tools used(this one Im a bit unsure about)
: pressure gauge

state the energy transfer that takes place as the ball changes shape during the contact between the racquet and the ball

Answers

When the ball hits the racquet, it gets squished, and it gains elastic energy, since it is compressed.

At what rate is power supplied by the 20-V emf shown below?
10 V
www.
10 Q2
O a.-10 W
O b. +10 W
c. +20 W
O d.zero
O e. -20 W
10 22
www
20 £2
P
20 V

At what rate is power supplied by the 20-V emf shown below?10 Vwww.10 Q2O a.-10 WO b. +10 Wc. +20 WO

Answers

We don't know which components of the circuit the 20-V emf is connected to. The circuit has a 10-ohm resistor, denoted by the symbol "10 Q2". The pace at which the 20-V emf supplies power is what is being questioned.

What does a circuit's emf mean?

When no current is flowing, electromotive force (EMF) equals the terminal potential difference. EMF and terminal potential difference (V) are not the same even though they are both stated in volts.

What causes a circuit's emf?

According to Faraday's law of induction, the electromagnetically induced emf for a particular circuit is solely governed by the rate at which the magnetic flux flows through the circuit.

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What are applications of zeroth law of thermodynamics?​

Answers

Answer:

Applications of zeroth law of thermodynamics:

1. When we get very hot food, we wait to make it normal. In this case, hot food exchanges heat with surrounding and brings equilibrium.

2. We keep things in the fridge and those things come equilibrium with fridge temperature.

3. Temperature measurement with a thermometer or another device.

4. In the HVAC system, sensors or thermostats are used to indicate temperature. It always comes in a thermal equilibrium with room temperature.

5. If you and the swimming pool you’re in are at the same temperature, no heat is flowing from you to it or from it to you (although the possibility is there). You’re in thermal equilibrium.

Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and a market economy? E.1.2
How Economic Decisions are Made
By the Government,
command
economy
By the Consumers
mixed
economy
market.
economy
O Consumers make all economic decisions in a mixed economy, while the government makes all economic decisions in a market economy.
Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.
Government makes all economic decisions in a mixed economy, while consumers make all economic decisions in a market economy.
O Consumers make economic decisions in a mixed economy, while consumers and government make economic decisions in a market economy.

Answers

Based on the diagram, the correct statement is: Government and consumers make economic decisions in a mixed economy, while consumers make economic decisions in a market economy.

How do we explain?

In a mixed economy, economic decisions are made by both the government and consumers.

The government plays a significant role in regulating and influencing economic activities through policies, regulations, and interventions.

In market economy, economic decisions are primarily made by consumers. The market forces of supply and demand dictate the allocation of resources, production levels, and pricing.

The freedom to buy and sell whatever they choose is what ultimately determines how commodities and services are produced and distributed.

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Based on the diagram, what is the difference in how economic decisions are made in a mixed economy and

Which of the following is not true about minerals?

A
They always include oxygen and silicon.

B
They are naturally occurring materials.

C
They each have unique properties.

D
They have a crystalline structure.

Answers

A the always include oxygen and silicon

It is not true about minerals, that they always include oxygen and silicon. Option (A) is correct.

Minerals are inorganic, naturally occurring substances with a crystalline structure and a particular chemical makeup. They are solid substances that are created over a long period of time by geological processes in the crust of the Earth.

Even while silicon and oxygen are frequently occurring components in many minerals, not all minerals necessarily contain these elements. Minerals are inorganic, naturally occurring substances with a crystalline structure and a particular chemical makeup. They can be made of a wide range of substances, including silicon and oxygen, among others.

Hence, It is not true about minerals, that they always include oxygen and silicon. Option (A) is correct.

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Complete the following statement: Momentum will be conserved in a two-body collision only if a both bodies come to rest. b the internal forces of the two body system cancel in action-reaction pairs. c the kinetic energy of the system is conserved. d the net external force acting on the two-body system is zero. e the collision is perfectly elastic.

Answers

Answer:

d the net external force acting on the two-body system is zero

Explanation:

The net external force acting on the two-body system is zero .

During a collision , two internal forces appear on two bodies in opposite directions separately . As they act on each object separately , they do not cancel each other . But the net force on two body system is zero . Total momentum is always conserved during collision because no external force is involved . Collision is not always elastic .

Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen if the spacing between the first and second dark fringes is to be 4.2 mm?

Answers

Answer:

The distance is \(D = 2.6 \ m\)

Explanation:

From the question we are told that

    The wavelength of the light is  \(\lambda = 476.1 \ nm = 476.1 *10^{-9} \ m\)

      The  distance between the slit is  \(d = 0.29 \ mm = 0.29 *10^{-3} \ m\)

       The  between the first and second dark fringes is  \(y = 4.2 \ mm = 4.2 *10^{-3} \ m\)

Generally  fringe width is mathematically represented as

       \(y = \frac{\lambda * D }{d}\)

Where D is the distance of the slit to the screen

   Hence

        \(D = \frac{y * d}{\lambda }\)

substituting values

       \(D = \frac{ 4.2 *10^{-3} * 0.29 *10^{-3}}{ 476.1 *10^{-9} }\)

        \(D = 2.6 \ m\)

A water rocket is launched with an initial velocity of 10m/s at an angle of 30. How far will it travel?

Answers

The water rocket is launched with an initial velocity of 10 m/s at an angle of 30° and reaches a height of 3.75m.

From the given,

the velocity of rocket = 10 m/s

angle = 30°

The distance/ height traveled by the rocket=?

H = u²sinθ² / 2g

u is the initial velocity of the rocket

g is the acceleration due to gravity = 10 m/s²

H = (10)²sin²(60°)/(2×10)

  = (100 ×3/4)×(1/20)

  =3.75 m

Thus the rocket covers a distance of 3.75 m.

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Two car (A) and (B) start from the rest at the same instant of time t=0 . From the points M and N respectively in uniformly accelerated rectilinear motion and in opposite directions as shownin the adjacent figure give acceleration of (A) is 4m/s² and that (B) is 2m/s² .MN 30km At the instant t the car (A) covered a distance d¹ and B covers a distance d² 1 determine as a function of t d¹and d² . 2 deduce the time meeting 2 cars . 3 answer the preceding questions but consider that car (B) in uniform rectilinear motion with a speed of 10 m/s​

Answers

To solve the problem, let's break it down into three parts:

1. Determining the distance covered by cars A and B as a function of time:

For uniformly accelerated rectilinear motion, we can use the following equation to calculate the distance covered:

distance = initial velocity * time + (1/2) * acceleration * time^2

For car A:

The initial velocity is 0 m/s, and the acceleration is 4 m/s².

So, the distance covered by car A at time t is:

d¹(t) = 0.5 * 4 * t^2 = 2t^2

For car B:

The initial velocity is 0 m/s, and the acceleration is -2 m/s² (opposite direction to car A).

So, the distance covered by car B at time t is:

d²(t) = 0.5 * -2 * t^2 = -t^2

2. Deducing the time of meeting for the two cars:

To find the time of meeting, we need to set the distances covered by both cars equal to each other:

2t^2 = -t^2

Simplifying the equation:

2t^2 + t^2 = 0

3t^2 = 0

Since the equation equals zero, the only solution is t = 0. This means that the two cars meet at the starting point at t = 0.

3. Considering car B in uniform rectilinear motion with a speed of 10 m/s:

If car B is moving at a constant speed of 10 m/s, it means its acceleration is 0 m/s². Therefore, the equation for car B's distance covered becomes:

d²(t) = initial velocity * time = 10 * t = 10t

Now, we can answer the preceding questions using this new equation for car B.

1. The distance covered by car A at time t is still d¹(t) = 2t^2.

The distance covered by car B at time t is now d²(t) = 10t.

2. The time of meeting for the two cars can be found by setting the distances equal to each other:

2t^2 = 10t

Simplifying the equation:

2t^2 - 10t = 0

2t(t - 5) = 0

From this equation, we have two solutions:

t = 0 (the initial meeting point)

t = 5 seconds (when the two cars meet again after 5 seconds)

Therefore, the cars meet again after 5 seconds.

Please note that the distances calculated above are in terms of t, the time elapsed since t = 0.

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The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds 
3)Is there any time interval in which no force acts on object.Justify

The velocity time graph of an object mass 50 g is shown in figure study graph and answer1)calculate force

Answers

1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Which of the following is not a metric base unit? *
Meter
Liter
Inch
Gram

Answers

Answer:

Liter

Explanation:

liter is the biggest answer

PLEASE HELP ME!!!1

Differentiate between the distance and displacement for an object that started at point A and traveled as shown to point B.


Distance: _____ units and Displace: _____ units to the left.

PLEASE HELP ME!!!1Differentiate between the distance and displacement for an object that started at point

Answers

"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.

"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.

PLEASE HELP ME!!!1Differentiate between the distance and displacement for an object that started at point

WILL GIVE 25 POINTS AND BRAINLIEST -

Check image for graph.



Serena Williams is returning a serve from her sister Venus. Below is the graph of the force of her racquet on the tennis ball. Use the following graph to answer questions 3 and 4



3. What is the impulse on the tennis ball when it is in contact with Serena’s racquet?



4. If the 0.06kg tennis ball is originally traveling at 56 m/s towards Serena, what is the ball’s velocity after Serena returns the serve?

WILL GIVE 25 POINTS AND BRAINLIEST -Check image for graph.Serena Williams is returning a serve from her

Answers

bd dmd she s he sus she she she’s h

Which of the following is not an example of energy transfer?
A. Riding a bike down a hill.
B. Sliding a table across a floor.
C. Holding a sign in the air.

Answers

Answer:

c.holding a sign in the air

Explanation:

because b is kinetic energy and a is also kinetic energy

C holding a sign in the air

Kepler's first law of planetary motion states that ________.

a. the Sun is at the center of the solar system
b. planets orbit the Sun in elliptical orbits, with the Sun located at one focus
c. planets orbit the Sun in circular orbits, with the Sun located at the center
d. gravity provides the force that holds the planets in orbit about the Sun

Answers

Answer:

Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)

Explanation:

Kepler's laws or laws of planetary motion are scientific laws that describe the movement of the planets around the Sun. The fundamental contribution of Kepler's laws was to show that the orbits of the planets are elliptical and not circular as was previously believed.

Kepler's laws are kinetic laws. This means that its function is to describe the planetary motion.

Kepler formulated three laws:

First Law: The planets move around the Sun describing elliptical orbits, the Sun being located in one of the focus. Second Law: The vector radius that joins the planet and the Sun sweeps equal areas in equal times. Third Law: For any planet, the square of its orbital period (time it takes to go around the Sun) is directly proportional to the cube of the mean distance from the Sun.

An ellipse is a closed curve that has two symmetrical axes, called foci or fixed points. In simpler words, an ellipse can be described as a flattened circle.

The degree of flattening of a closed curve is called eccentricity. When the eccentricity is equal to 0, the curve forms a perfect circle. On the other hand, when the eccentricity is greater than 0, the sides of the curve are flattened to form an ellipse.

Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)

An experimental electrical generator collects sunlight with mirrors and generates heat at a rate of 1.2 megawatts. The generator is mounted on the roof of an environmentally friendly building and is used to operate an elevator. The elevator has a maximum operating load of 8000 kg and a maximum velocity of 6 m/s.

A. Determine the power that the generator must supply to operate the elevator at its maximum operating

B. What is the efficiency of this system?

Answers

Answer:

a) 0.47MW

b) 39.24%

Explanation:

In order to find the power needed for the elevator to operate at its maximum capacity, we can make use of the following formula:

P=Fv

where P is the power, F is the force and v is the velocity.

The force the elevator must carry can be calculated with the following formula:

F=mg

where m is the mass of the elevator and g is the acceleration of gravity, so:

\(F=(8000 kg)(9.81 m/s^{2})\)

F=78 480 N

so now we can make use of the power formula:

P=Fv

P=(78 480N)(6 m/s)

P=470 880W

P=0.47W

b)

In order to find the efficiency, we will suppose that the generator can generate a maximum of 0.47 W so we use the following formula:

\(efficiency = \frac{P_{in}}{P_{out}}*100\%\)

\(efficiency=\frac{0.470880}{1.2}*100\%\)

efficiency=39.24%

Research Galileo’s work on falling bodies. What did he want to demonstrate? What opinions or theories was he trying to refute? What arguments did he use to persuade others that he was right? Did he depend on experiments, logic, findings of other scientists, or other approaches?

Answers

Answer:

Explanation:

Galileo's famous argument against the Aristotle's theory of falling bodies goes like this. "Let's say heavy objects do fall faster than light ones. Then it seems the heavier weight will fall with the lighter weight acting, as it were, a bit like a parachute. In that case, the two balls will together fall more slowly than the heavy weight would on its own. On the other hand, once the two weights are tied together and held out over the parapet, they have effectively combined their weights, becoming one greater weight... they must therefore fall even faster than the heavy weight would on its own." Contradiction. Hence weight has no effect on falling rates.

Some philosophers are very fond of this argument. Gendler uses it as a prototypical example of how "reasoning about particular entities within the context of an imaginary scenario can lead to rationally justified conclusions". Snooks goes further saying "it is striking that one leaves the falling balls example with something approaching certainty for its outcome". And Brown goes all the way and claims that Aristotle's theory is "self-contradictory", and we gain a priori knowledge here. The argument does give off that flavor of "synthetic a priori" reasoning, as in geometry but without images. But is it a proof or a fallacy? Even Gendler admits that some "obvious" premises are missing, and Atkinson even calls it a "non-sequitur" for similar reasons. But Galileo's logic is not questioned it seems. Shouldn't it be?

Galileo proved force causes acceleration. Galileo concluded from the law of parabolic fall that bodies fall on Earth at a constant acceleration and that gravity, which pulls all bodies down, is constant.

What is Galileo's law of falling bodies?

According to Galileo's law of free fall, in the absence of any resistance from the air, all bodies fall with the same acceleration, regardless of their mass. This law was developed by Galileo. The application of Newtonian mechanics demonstrates that this law is only a close approximation.

A water clock was utilized in the process of timekeeping. Galileo demonstrated that motion on an inclined plane had a constant acceleration, and that this acceleration was only dependent on the angle of the plane and not the mass of the rolling body. This demonstrated that the acceleration of free falling bodies is the same.

Galileo proposed that in the absence of air, all bodies, regardless of how much matter they contain, would fall at the same rate in relation to the earth. It appears that Aristotle considered all media to be viscous, and he argued that heavier bodies fall at a faster rate.

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A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?

Answers

The final velocity of the red ball is 18 m/s.

What is momentum?

The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.

Then;

Mass of the blue ball =  6 kg

Mass of the red ball =  1 kg

Initial velocity of the blue ball =  4 m/s

Initial velocity of the red ball = 0 m/s

Final velocity of the red ball = ??

Final velocity of the blue ball =  1 m/s

We now have;

(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)

24 = v + 6

v = 24 - 6

v = 18 m/s

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Which of the following involves an endothermic reaction?
A. Burning a candle
B. Lighting a gas stove
C. A chemical hand-warmer
D. Photosynthesis in plants

Answers

the answer would be c
It’s c :) A chemical hand warmer

An object A has a mass of 6kg and a heat capacity of 2 310j/°C. Another object B has a mass of 4.6kg and a heat capacity of 1771j/°C. Determine if the two objects A and B are made from the same substance.​

Answers

We can infer that item A is not composed of the same material as object B since its specific heat capacity is higher than object B's. As the specific heat capacities differ, we cannot assume that they are the same.

Determine if the two objects A and B are made from the same substance.​

The amount of heat needed to increase the warmth of one unit of mass of a substance by one degrees Celsius must be compared between two things in order to ascertain if they are made of the same material. The compounds are probably the same if the heat capacity capacities are the same. The following equation can be used to determine how much heat energy is needed to raise an object's temperature:

Q = mcΔT

Where Q is the heat received or released, m is the object's mass, c is the material's specific heat capacity, and T is the temperature change.

Let's figure out how much heat energy is needed to raise item A's temperature by one degree Celsius:

Q A = mcΔT

Q A equals 6 kg x 2,310 J/(kg°C) x 1°C.

Q A = 13,860 J/°C

Let's now determine how much heat energy is needed to raise item B's temperature by 1 degree Centigrade:

Q B = mcΔT

Q B is equal to 4.6 kg, 1,771 J/(kg°C), and 1°C.

Q B = 8,146.6 J/°C

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Show the relation among MA, VR and n.

Answers

Answer:

good luck!!! sorry I just needed the points xoxo

Explanation:

umm yeah no sorry I tried

George burnt his fingertips so badly that he can't feel anything with them anymore.
Which part of his skin must have been damaged?

O papillary layer

Hypodermis

hyperdemis

subcutaneous layer

Answers

the part tht is mostly damaged is papillary

George burnt his fingertips so badly that he can't feel anything with them anymore, then the papillary layer part of his skin must have been damaged, therefore the correct answer is option A.

What is thermal energy?

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

As given in the problem George burnt his fingertips so badly that he can't feel anything with them anymore.

Option A is the appropriate response since George must have injured the papillary layer of his skin if his fingertips were burned so badly that he can no longer feel anything with them.

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What course the colour of silt soil?

Answers

Answer:

Beige to black.

Explanation:

:)

Which best explains a difference between Einstein’s general theory of relativity and his special theory of relativity?


His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

His general theory includes uniform and accelerated motion, but his special theory applies only to accelerated motion.

His general theory applies only to accelerated motion, but his special theory includes uniform and accelerated motion.

His general theory applies only to uniform motion, but his special theory includes uniform and accelerated motion.

Answers

Answer:

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

Explanation:

According to Einstein's 1915 general theory of relativity, the force of gravity arises from the curvature of space and time.

According to theory of special relativity:

1. The laws of physics are the same for all non-accelerating observers

2. The speed of light in a vacuum was independent of the motion of all observers.

His general theory includes uniform and accelerated motion, but his special theory applies only to uniform motion.

Answer:

for those who dont like to read

the answer is A.

hope i helped

Explanation:

please help me - i beg u

please help me - i beg u

Answers

Answer:

516526.863 m

Explanation:

From the question given above, the following data were obtained:

Acceleration due to gravity (g) = 2.24 m/s²

Mass (M) = 8.96×10²¹ Kg

Gravitational constant (G) = 6.67×10¯¹¹Nm²/Kg²

Radius (r) =?

The radius of the planet can be obtained as follow:

g = GM/r²

2.24 = 6.67×10¯¹¹ × 8.96×10²¹ / r²

2.24 = 5.97632×10¹¹ / r²

Cross multiply

2.24 × r² = 5.97632×10¹¹

Divide both side by 2.24

r² = 5.97632×10¹¹ / 2.24

r² = 2.668×10¹¹

Take the square root of both side

r = √2.668×10¹¹

r = 516526.863 m

Thus, the radius of the planet is 516526.863 m

Electric dipole field] A positive point charge and a small electric dipole are arranged as shown in the figure. a) Find the exact formula for the total force exerted on the dipole by the charge Q. b) Derive an approximate formula for d« r. You should find that the force varies as x-3. [Use the Taylor expansion] c) What would be different if the dipole were oriented the other way? Give a qualitative explanation. Q -4 +9 X d

Answers

F = F1 - F2 = kQq/x^2 - kQ(-q)/x^2 = 2kQ*q/x^2

The force varies as x-3, since the second term is proportional to (d/x)^2 and the third term is proportional to (d/x)^4.

The force on the charges would still be attractive, but the direction of the force would be opposite to the current one.

What is dipole and derive the formula for total force?a)Coulomb's law, which states that the force a point charge exerts on another point charge is proportional to the product of the charges and inversely proportional to the square of the distance between them, can be used to determine the total force Q exerts on the electric dipole.The electric dipole consists of two point charges: a positive charge +q and a negative charge -q, separated by a small distance 2d.The force exerted on the positive charge by the charge Q is given by Coulomb's law as:F1 = kQq/x^2The force exerted on the negative charge by the charge Q is also given by Coulomb's law as:F2 = kQ(-q)/x^2The net force exerted on the dipole is the vector sum of the forces on the individual charges.F = F1 - F2 = kQq/x^2 - kQ(-q)/x^2 = 2kQ*q/x^2Where k is Coulomb's constant = 1/4πε, q is the magnitude of the charge on each point charge, x is the distance between the charge Q and the center of the dipole.b) To derive an approximate formula for d«r, we can use a Taylor series expansion of the function 2kQ*q/x^2.2kQq/x^2 = 2kQq*(1 - (d/x)^2 + (d/x)^4 - (d/x)^6 + ...)The first term (2kQ*q) is the force when the dipole is at point x = 0. The second term is the correction due to the displacement of the dipole along x-axis. The third term is the correction due to the displacement of the dipole along y-axis, and so on.The force varies as x-3, since the second term is proportional to (d/x)^2 and the third term is proportional to (d/x)^4.c) If the dipole were oriented the other way, the direction of the force would be reversed, but the magnitude of the force would be the same. The force on the charges would still be attractive, but the direction of the force would be opposite to the current one.

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A tank filled with water is moving down an inclined
surface with an angle of 15 degree. If
the tank decelerates (slows down) at a= 3.83 m/s2
determine the angle of the free surface relative to the
horizontal direction after deceleration.

Answers

The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.

Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:

KE = (1/2)mv²

where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:

PE = mgh

where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:

(1/2)mv² = mgh

Solving for v, we get:

v = √(2gh)

When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:

t = v/a

The distance traveled by the tank during this time is:

s = (1/2)at²

\(=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}\)

The angle of the free surface relative to the horizontal direction after deceleration is given by:

\(\theta' = tan^{-1}\dfrac{s}{h}\)

Substituting the values of v and s, we get:

\(\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}\)

Substituting the given values of h and a, we get:

\(\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2\)

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