The output from the differential pressure sensor used with an orifice


plate for the


measurement ollow


rate Is non-linear, the output


Voltage


being proportional to the square of the flow rate. Determine the form of


characteristic required for the element in the feedback loop of an operational


amplifier signal conditioner circuit in order to linearise this output.

Hotel Fire Safety Directors are not authorized to order a full building evacuation of guests. Therefore, option (C) is correct.

Hotel Fire Safety Directors are individuals who are responsible for ensuring the safety of guests and employees in the event of a fire emergency in a hotel or other hospitality establishment.

They are typically appointed by the hotel management and must have knowledge of fire safety regulations and protocols, as well as the ability to lead and manage a team during an emergency.

Hotel Fire Safety Directors are responsible for implementing and maintaining the Fire Safety Plan, which includes conducting fire drills, training and supervising the Fire Brigade, and distributing applicable parts of the Fire Safety Plan to all employees. They must also work closely with the local fire department to ensure compliance with local fire safety regulations and protocols.

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Answer:

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Answer:

Relative roughness = 0.04

Explanation:

Given that:

Diameter = 5 cm

roughness = 2 mm

At inlet:

Minor coefficient loss \(k_{L1} = 0.4\)

At exit:

Minor coefficient loss \(k_{L2} = 1\)

Height h = 4m

Length = 5 m

To find the relative roughness:

Relative roughness is a term that is used to describe the set of irregularities that exist inside commercial pipes that transport fluids. The relative roughness can be evaluated by knowing the diameter of the pipe made with the absolute roughness in question. If we denote the absolute roughness as e and the diameter as D, the relative roughness is expressed as:

\(e_r = \dfrac{e}{D}\)

\(e_r = \dfrac{0.2 }{5}\)

\(\mathbf{e_r = 0.04}\)

9514 1404 393

Answer:

  (x, y) = (5.76, 1 5/7)

Explanation:

The location of the centroid in the x-direction is the ratio of the first moment of area about the y-axis to the total area. Similarly, the y-coordinate of the centroid is the first moment of area about the x-axis, divided by the area.

For the moment about the y-axis, we can define a differential of area as ...

  dA = (y2 -y1)dx

where y2 = √(x/k2) and y1 = k1·x^3

The distance of that area from the y-axis is simply x.

So, the x-coordinate of the centroid is ...

  \(\displaystyle c_x=\frac{a_x}{a}=\frac{\int{x\cdot dA}}{\int{dA}}\\\\a_x=\int_0^{12}{x(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{5k_2^{1/2}}\cdot12^{5/2}-\frac{k_1}{5}12^5\\\\a=\int_0^{12}{(k_2^{-1/2}\cdot x^{1/2}-k_1x^3)}\,dx=\frac{2}{3k_2^{1/2}}\cdot12^{3/2}-\frac{k_1}{4}12^4\\\)

For k1 = 4/12^3 and k2=12/4^2, these evaluate to ...

  \(a_x=115.2\\a=20\\c_x=5.76\)

The y-coordinate of the centroid requires we find the distance of the differential of area from the x-axis. We can use (y2 +y1)/2 for that purpose. Then the y-coordinate is ...

  \(\displaystyle c_y=\frac{a_y}{a}\\\\a_y=\int_0^{12}{(\frac{y_2+y_1}{2}(y_2-y_1))}\,dx=\frac{1}{2}\int_0^{12}{(\frac{x}{k_2}-(k_1x^3)^2)}\,dx\\\\a_y=\frac{12^2}{4k_2}-\frac{k_1^212^7}{14}=\frac{240}{7}\\\\c_y=\frac{12}{7}\approx1.7143\)

The centroid of the shaded area is ...

  (x, y) = (5.76, 1 5/7)

Answer:

Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.

Answer:

this is answer

Explanation:

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Answer:

The velocity component v is \(-6axy+2by^2+f(x)\)

Explanation:

Given that,

The velocity component of a steady, two-dimensional

\(u=3ax^2-2bxy\)

We need to calculate the function of x

Using given equation

\(u=3ax^2-2bxy\)

Where, a and b is constant

On differential

\(\dfrac{du}{dx}=6ax-2by\)

We need to calculate the velocity component v

Using equation of velocity

\(\dfrac{dv}{dy}=-\dfrac{du}{dx}-\dfrac{dw}{dz}\)

Put the value into the formula

\(\dfrac{dv}{dy}=-6ax+2by-0\)

Now, on integration w.r.t y

\(v=-6axy+2by^2+f(x)\)

Hence, The velocity component v is \(-6axy+2by^2+f(x)\)

Answer:

"cool"

Explanation:

Answer:

a) civil engineering.

Explanation:

Civil engineering is a professional engineering program that deals with the construction, design, and maintenance of all the natural and man-made environments including dams, buildings, railways, and roads.

Civil engineering is the branch of engineering that is the practice not restricted because civil engineer is not restricted to academic profession but practice in designing and construction can make someone a professional civil engineer.

Hence, the correct answer is "a)."

The branch of engineering in which the practice is not restricted is; Civil Engineering

             Civil Engineering is a branch of engineering that deals with the design, construction and maintenance of the physical and naturally built environment.

These physically and naturally built environment includes; houses, roads, bridges, airports, railways, canals, dams, sewage systems, pipelines e.t.c

             Now, mechanical engineering involves design, production, operation and maintenance of mechanical systems or machineries.

             In conclusion, we see that the mechanical branch of engineering is restricted to machinery unlike civil engineering that is not restricted to only buildings but also includes pipelines, bridges, roads, railways, dams, sewage systems e.t.c

             Finally, the nuclear engineering branch is also restricted to only nuclear fission and fusion applications.

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a) The molecular diameter of ethylene is 4.09 × 10^-10 m. (approximately 0.409 Å)

b) The mean free path of ethylene is 5.04 × 10^-8 m (approximately 50 nm).

a) Molecular diameterThe viscosity of ethylene is given as 9.33 × 10^-6 kg/ms at a temperature of 25 °C and a pressure of 101.325 kPa.To calculate the molecular diameter of ethylene, we need to use the equation:f = (π * p * d^2 * V)/ (8 * k * T)where:f is the frictional forcep is the pressurek is the Boltzmann constantT is the temperatured is the diameterV is the average velocity of the moleculesSolving for d, we get:d = √[(8 * k * T * f)/(π * p * V)]Substituting the values, we get:d = √[(8 * 1.38 × 10^-23 * 298 * 9.33 × 10^-6)/(π * 101325 * 464)]d = 4.09 × 10^-10 m

\b) Mean free path

The mean free path is the average distance that a molecule travels between two consecutive collisions. It is given as:λ = [√(2) * V]/ [π * d^2 * N * σ]where:λ is the mean free pathV is the average velocity of the moleculesd is the diameter

N is the number of molecules per unit volumeσ is the collision cross-section

Substituting the values, we get:λ = [√(2) * V]/ [π * d^2 * N * σ]λ = [√(2) * 464]/ [π * (4.09 × 10^-10)^2 * 3.76 × 10^25 * 0.96 × 10^-19]λ = 5.04 × 10^-8 m

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Answer:

Among all three tools, the ceramic tool is taking the least time for the production of a batch, however, machining from the HSS tool is taking the highest time.

Explanation:

The optimum cutting speed for the minimum cost

\(V_{opt}= \frac{C}{\left[\left(T_c+\frac{C_e}{C_m}\right)\left(\frac{1}{n}-1\right)\right]^n}\;\cdots(i)\)

Where,

C,n = Taylor equation parameters

\(T_h\) =Tool changing time in minutes

\(C_e\)=Cost per grinding per edge

\(C_m\)= Machine and operator cost per minute

On comparing with the Taylor equation \(VT^n=C\),

Tool life,

\(T= \left[ \left(T_t+\frac{C_e}{C_m}\right)\left(\frac{1}{n}-1\right)\right]}\;\cdots(ii)\)

Given that,  

Cost of operator and machine time\(=\$40/hr=\$0.667/min\)

Batch setting time = 2 hr

Part handling time: \(T_h=2.5\) min

Part diameter: \(D=73 mm\) \(=73\times 10^{-3} m\)

Part length: \(l=250 mm=250\times 10^{-3} m\)

Feed: \(f=0.30 mm/rev= 0.3\times 10^{-3} m/rev\)

Depth of cut: \(d=3.5 mm\)

For the HSS tool:

Tool cost is $20 and it can be ground and reground 15 times and the grinding= $2/grind.

So, \(C_e=\) \(\$20/15+2=\$3.33/edge\)

Tool changing time, \(T_t=3\) min.

\(C= 80 m/min\)

\(n=0.130\)

(a) From equation (i), cutting speed for the minimum cost:

\(V_{opt}= \frac {80}{\left[ \left(3+\frac{3.33}{0.667}\right)\left(\frac{1}{0.13}-1\right)\right]^{0.13}}\)

\(\Rightarrow 47.7\) m/min

(b) From equation (ii), the tool life,

\(T=\left(3+\frac{3.33}{0.667}\right)\left(\frac{1}{0.13}-1\right)\right]}\)

\(\Rightarrow T=53.4\) min

(c) Cycle time: \(T_c=T_h+T_m+\frac{T_t}{n_p}\)

where,

\(T_m=\) Machining time for one part

\(n_p=\) Number of pieces cut in one tool life

\(T_m= \frac{l}{fN}\) min, where \(N=\frac{V_{opt}}{\pi D}\) is the rpm of the spindle.

\(\Rightarrow T_m= \frac{\pi D l}{fV_{opt}}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 47.7}=4.01 min/pc\)

So, the number of parts produced in one tool life

\(n_p=\frac {T}{T_m}\)

\(\Rightarrow n_p=\frac {53.4}{4.01}=13.3\)

Round it to the lower integer

\(\Rightarrow n_p=13\)

So, the cycle time

\(T_c=2.5+4.01+\frac{3}{13}=6.74\) min/pc

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times6.74+\frac{3.33}{13}=\$4.75/pc\)

(e) Total time to complete the batch= Sum of setup time and production time for one batch

\(=2\times60+ {50\times 6.74}{50}=457 min=7.62 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times4.01}{457}=0.4387=43.87\%\)

Now, for the cemented carbide tool:

Cost per edge,

\(C_e=\) \(\$8/6=\$1.33/edge\)

Tool changing time, \(T_t=1min\)

\(C= 650 m/min\)

\(n=0.30\)

(a) Cutting speed for the minimum cost:

\(V_{opt}= \frac {650}{\left[ \left(1+\frac{1.33}{0.667}\right)\left(\frac{1}{0.3}-1\right)\right]^{0.3}}=363m/min\) [from(i)]

(b) Tool life,

\(T=\left[ \left(1+\frac{1.33}{0.667}\right)\left(\frac{1}{0.3}-1\right)\right]=7min\) [from(ii)]

(c) Cycle time:

\(T_c=T_h+T_m+\frac{T_t}{n_p}\)

\(T_m= \frac{\pi D l}{fV_{opt}}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 363}=0.53min/pc\)

\(n_p=\frac {7}{0.53}=13.2\)

\(\Rightarrow n_p=13\) [ nearest lower integer]

So, the cycle time

\(T_c=2.5+0.53+\frac{1}{13}=3.11 min/pc\)

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times3.11+\frac{1.33}{13}=\$2.18/pc\)

(e) Total time to complete the batch\(=2\times60+ {50\times 3.11}{50}=275.5 min=4.59 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times0.53}{275.5}=0.0962=9.62\%\)

Similarly, for the ceramic tool:

\(C_e=\) \(\$10/6=\$1.67/edge\)

\(T_t-1min\)

\(C= 3500 m/min\)

\(n=0.6\)

(a) Cutting speed:

\(V_{opt}= \frac {3500}{\left[ \left(1+\frac{1.67}{0.667}\right)\left(\frac{1}{0.6}-1\right)\right]^{0.6}}\)

\(\Rightarrow V_{opt}=2105 m/min\)

(b) Tool life,

\(T=\left[ \left(1+\frac{1.67}{0.667}\right)\left(\frac{1}{0.6}-1\right)\right]=2.33 min\)

(c) Cycle time:

\(T_c=T_h+T_m+\frac{T_t}{n_p}\)

\(\Rightarrow T_m=\frac{\pi \times 73 \times 250\times 10^{-6}}{0.3\times 10^{-3}\times 2105}=0.091 min/pc\)

\(n_p=\frac {2.33}{0.091}=25.6\)

\(\Rightarrow n_p=25 pc/tool\; life\)

So,

\(T_c=2.5+0.091+\frac{1}{25}=2.63 min/pc\)

(d) Cost per production unit:

\(C_c= C_mT_c+\frac{C_e}{n_p}\)

\(\Rightarrow C_c=0.667\times2.63+\frac{1.67}{25}=$1.82/pc\)

(e) Total time to complete the batch

\(=2\times60+ {50\times 2.63}=251.5 min=4.19 hr\).

(f) The proportion of time spent actually cutting metal

\(=\frac{50\times0.091}{251.5}=0.0181=1.81\%\)

Tailgating is one of the most common methods of social engineering, in which an attacker gains entry into a secure location or system by following a legitimate individual through a secure door or into a restricted area, making it appear that they have the right to be there.

Tailgating is a form of social engineering in which an attacker follows a legitimate person into a secured area or system in order to gain access. The attacker could be a thief, a spy, a con artist, or a malicious insider. Social engineering is the art of manipulating people in order to obtain sensitive or confidential information that can be used to gain unauthorized access to computer systems, data networks, or physical facilities.

Tailgating is a method of social engineering in which an attacker gains access to a restricted area by following an authorized individual through a secure door or gate. It may also be known as piggybacking or "tagging along." Tailgating is the act of following someone through a secured door or gate without providing proper identification or authorization.

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Answer:

She wrote and delivered a speech in 1873, which came to be known as the “Women's Rights to the Suffrage” speech. In her address, she lets the audience know of her “crime” of voting. She reminds the listener that the Constitution of the United States says “we the people” and does not exclude women as people

Answer:

D. To show why she was justified in voting.

Explanation:

Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

Heat energy is the known to be a product of the movement of tiny particles called atoms, molecules or ions. The true statement is by Technician A.

Internal combustion engine is dependent on the heat of combustion so as to make torque to move the vehicle and power the system.

A lot of heat made during combustion is not often used productively and therefore need to be removed to avoid overheating of the engine.

The heat energy that is not used for is wasted in three ways: They are:

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Wheelbase, trackwidth, and tire load data can be used to determine the longitudinal CG location. The distance in inches between the center of gravity and the front wheel.

Wheelbase, trackwidth, and tire load data can be used to determine a car's longitudinal center of gravity (CG) location. The distance between the centers of the front and rear wheels is known as the wheelbase, while the distance between the left and right tire centerlines is known as the trackwidth. The amount of weight on each of the four tires that are in contact with the ground is known as the tire load. The entire weight of the vehicle is divided by the wheelbase and trackwidth, and the resulting number is multiplied by the wheelbase to determine the longitudinal center of gravity (CG) location. The resultant measurement, taken from the front wheel, is the longitudinal CG location in inches.

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Answer:

Slopping or slanting roofs are found in houses where there are snow or rain, because it helps the water or the snow to skid down easily. It minimizes the chances of waterlogging because water cannot rest on the roof surface for long.

Explanation:

Brainliest pls.

For milestone two workbook, memo to management  is due in module five.

What is management?

Management is the process of achieving goals through the efficient use of resources, such as people, money, and time. It involves planning, organizing, leading, and controlling activities to reach a desired goal. Effective management requires clear objectives, effective communication, and accurate decision-making. Management is a skill that can be acquired and developed over time, and it is an essential tool for successful organizations.

The workbook will also include a discussion of the potential implications of the differences in lease and postretirement benefit accounting standards, such as the potential effect on the balance sheet, income statement, and cash flow statement of the company. This memo is to provide management with the key impacts of accounting for leases and postretirement benefits under both current GAAP and International Financial Reporting Standards (IFRS).

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The temperature and pressure of an ideal gas are directly proportional

The pressure of the system should be in the range B) 94 psig

The given refrigerator parameters are;

The temperature of the system and the surrounding, T₁ = 75 °F = 237.0389 K

The pressure to which the system was charged with nitrogen, P₁ = 100 psig

The temperature to which the system dropped, T₂ = 50 °F = 283.15 K

The required parameter;

The pressure, P₂, of the system at 50°F

Method:

The relationship between pressure and temperature is given by Gay-Lussac's law as follows;

At constant volume, the pressure of a given mass of gas is directly proportional to its temperature in Kelvin

Mathematically, we have;

\(\dfrac{P_1}{T_1} = \mathbf{\dfrac{P_2}{T_2}}\)

Plugging in the values of the variables gives;

\(\mathbf{\dfrac{100 \ psig}{297.0389}} = \dfrac{P_2}{283.15}\)

Therefore;

\(P_2 = \mathbf{283.15 \, ^{\circ}F \times \dfrac{100 \ psig}{297.0389\ ^{\circ}F} \approx 95.3 \, ^{\circ}F}\)

The closest option to the above pressure is option B) 94 psig

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Answer:

forced convection

Explanation:

When a fan, pump or suction device is used to facilitate convection, the result is forced convection. Everyday examples of this can be seen with air conditioning, central heating, a car radiator using fluid, or a convection oven.

Defining the circumstances that require research action, as well as a comprehensive examination of the history and references.

A rigorous and methodical study and inquiry of some area expertise is referred to as research.

A "systematic inquiry" is a planned activity that includes data gathering (mathematical or subjective) and analysis in order to discuss the issue.

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Answer:

you know you could use like quora or yahoo answers

Option B is accurate since it indicates that after opening a two-pipe system, the system must be bled to remove any air in the fuel line. This is a false assertion.

There are distinct pipes in a two-pipe fuel delivery system for feeding fuel to the burner and returning surplus fuel to the tank. This method is frequently utilized in oil-fired heating systems.

When the system is first loaded or when it runs out of fuel, bleeding may be required to remove any air that has entered the fuel line. Bleeding entails removing all air from the system and ensuring that only fuel remains in the lines.

Therefore, option B is false because a properly functioning two-pipe system should not require bleeding every time it is opened.

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The complete question:

Which of the following statements regarding two-pipe fuel delivery systems is false?

A. A two-pipe system is self-priming.

B. If a two-pipe system is opened, the system must be bled to get rid of any air in the fuel line.

C. A two-pipe system’s fuel unit pumps more fuel oil in a given time than is burned in that time.

D. All of the above.

Answer:

10

Explanation:

True. When a control line is on level ground and contains unburned fuel, there is a possibility that the  fuel could ignite.  

When a control line is on level ground and contains unburned fuel, there is a possibility that the fuel could ignite. and reach a high temperature, causing the emission of radiant heat. The magnetic waves, without the need for direct contact between objects.

If the unburned fuel within the control line ignites and becomes hot enough, it can radiate intense heat energy. This heat can then be transferred across the line to the fuels present on the other side. Depending on the intensity and duration of the radiant heat, the fuels on the opposite side may reach their ignition point, resulting in the spread of fire beyond the control line.

To prevent this scenario, firefighters and fire management teams employ various strategies. They may widen the control line, removing any combustible materials and creating a buffer zone. Additionally, they might conduct backburning operations to eliminate the unburned fuel within the control line, reducing the risk of ignition and radiant heat transfer.

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Answer:

Engineer A results will be more accurate

Explanation:

Analytical method is better than numerical method. Engineer A has used analytical method and therefore his results will be more accurate because he used simplified method. Engineer B has used software to solve the problem related to heat transfer his results will be approximate.