what is gravitatinal force ?​

Answer:

  B)  100 J

Explanation:

Assuming the distance given is measured along the incline, the vertical change in height is (5 m)(sin 30°) = 2.5 m. Then the change in potential energy is ...

  ∆PE = mg(∆h) = (4 kg)(10 m/s^2)(2.5 m) = 100 J

The force is defined as the product of the mass and the acceleration. The energy stored in an object which is converted into kinetic energy is called potential energy.

The formula for the potential energy is mgh.

The correct answer is B that is 100J.

As the surface is inclined the vertical change in height is\((5 m)(sin 30^o) = 2.5\)m.

Therefore the potential energy after solving it is as follows:-

\(PE = mg(h) \\= (4 kg)(10 m/s^2)(2.5 m)\\\\= 100 J\)

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Answer:

b

Explanation:

The buoyant force on the cannon stays the same as long as it is fully under water because the buoyant force is determined by the volume of fluid that the cannon displaces and not by the weight or mass of the cannon itself.

Archimedes' Principle states that the buoyant force on an object in a fluid is equal to the weight of the fluid that the object displaces. This means that as long as the cannon remains fully submerged in the water and does not change its volume, the amount of water it displaces and thus the buoyant force on the cannon will also remain the same.

In other words, the buoyant force is dependent on the fluid's density and the volume of the object, not its weight. So, as long as the volume of the cannon and the density of the fluid surrounding it remain constant, the buoyant force will also stay constant.

The buoyant force on the cannon will stay the same as long as it is fully under water.

The buoyant force on an object is equal to the weight of the fluid displaced by the object. The buoyant force is always directed upwards, and it opposes the force of gravity. As long as the cannon is fully under water, the amount of water displaced by the cannon will stay the same. This means that the buoyant force on the cannon will also stay the same.

The buoyant force on an object depends on the density of the fluid, the volume of the object, and the acceleration due to gravity. The density of water is constant, so the buoyant force on the cannon will only change if the volume of the cannon changes or if the acceleration due to gravity changes.

Neither of these factors change. The volume of the cannon does not change as it is being recovered from the shipwreck. The acceleration due to gravity also does not change, as it is the same on Earth's surface as it is underwater.

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Answer:

6.1 cm

61 N

35°

Explanation:

Given scale:  1 cm = 10 N

Parallelogram method (attachment 1)

When two vectors are represented by two adjacent sides of a parallelogram by direction and magnitude, the resultant of these vectors is represented (in magnitude and direction) by the diagonal of the parallelogram starting from the same point.

F₁ = 30 N = 3 cm

F₂ = 40 N = 4 cm

Draw a 3 cm horizontal line from the head of vector F₂ that is parallel to and the same length as vector F₁.

Draw a 4 cm line from the head of vector F₂ that is parallel to and the same length as vector F₁.

You have now constructed a parallelogram.

The diagonal of the parallelogram represents the resultant force vector.

Measure the length of the diagonal:

Measure the angle between the x-axis and the resultant force vector:

Polygon method (attachment 2)

If a number of vectors can be represented in magnitude and direction by the sides of a polygon taken in the same order, then their resultant is represented in magnitude and direction by the closing side of the polygon taken in the opposite order.

F₁ = 30 N = 3 cm

F₂ = 40 N = 4 cm

Draw a 3 cm horizontal line from the origin along the x-axis.  This is vector F₁.

Draw a 4 cm line at 60° to the x-axis from the head of F₁.  The is vector F₂.

Close the polygon by drawing a line that connects the tail of vector F₁ to the head of vector F₂.  This is the resultant force vector.

Measure the length of the closing side of the polygon:

Measure the angle between the x-axis and the resultant force vector.

Note: The resultant vector length, force and direction are the same for both methods.

Using parallelogram method for vector addition of two vectors with magnitude 40 Newton and 30 Newton at an angle of 60 degree the resultant vector is equal to 60.8 Newton and its length is equal to 6.08 cm.

The parallelogram rule says that on placing two vectors such that they have the same initial point, and complete into a parallelogram, then the sum of the vectors is the directed diagonal that starts at the same point as the vectors.

Polygon law of vector addition states that if a number of vectors can be represented in magnitude and direction by the sides of a polygon taken in the same order, then their resultant is represented in magnitude and direction by the closing side of the polygon taken in the opposite order.

Given:

Magnitude of first vector (a) = 30N

Magnitude of second vector (b) = 40N

Direction between two vectors= 60°

Using the law of parallelogram vector addition we get the value of resultant vector (R)-

\(R = \sqrt{(900+1600+1200)}\)

R = 60.8 newton

Now it is given that 1 cm in graph represents 10 newton.

Therefore, 60.8 newton will comprise a length = 60.8/10

60.8 newton will comprise a length = 6.08cm

The direction of the resultant vector is equal to 34.7° .

Here only two vectors are given therefore polygon law of vector addition becomes exactly like parallelogram vector addition.

Therefore,

\(R = \sqrt{(900+1600+1200)}\)

R = 60.8 newton

60.8 newton will comprise a length of 6.08cm.

Vector addition of two vectors with magnitude 40 Newton and 30 Newton at an angle of 60 degree the resultant vector is equal to 60.8 Newton and its length is equal to 6.08 cm.

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Temperature is most closely related to molecular Kinetic energy. Hence, option (A) is correct.

The kinetic theory of gases is a theory that can be used to deduce many of the gas's macroscopic features from a simplified molecular or particle description of the gas.

The most basic kinetic model is predicated on the following premises:

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The velocity of the second marble after the collision is 0.47 m/s

According to conservation of linear momentum

The law of conservation of momentum states that in an isolated system the total momentum of two or more bodies acting upon each other remains constant unless an external force is applied. Therefore, momentum can neither be created nor destroyed

M1u1 + M2u2 = M1v1 + M2v2

0.018 x 0.42 + 0.018 x 0.32 = 0.018 x 0.27 m/s + 0.018 x v2

0.00756 + 0.00576 = 0.00486 + 0.018 x v2

0.01332 = 0.00486 + 0.018 x v2

0.00846/0.018 = v2

v2 = 0.47 m/s

Hence, velocity of the second marble after the collision is 0.47 m/s

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Answer:

7.77

Explanation:

F=μ*m

n=w which also means n=mg

14.7=0.193*n

n=76.2

76.2=m*9.8

m=7.77

Friction is the resistance to motion of one object moving relative to another. The friction will be 7.77

According to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab), it is not treated as a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Scientists began piecing together the laws governing friction in the 1400s, according to the book Soil Mechanics(opens in new tab), but because the interactions are so complex.

F=μ*m, n=w which also means n=mg, 14.7=0.193*n, n=76.2, 76.2=m*9.8, m=7.77.

Therefore, Friction is the resistance to motion of one object moving relative to another. The friction will be 7.77.

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Answer:

its sulfur

Explanation:

Sulfur is the least reactive nonmetal among the options provided.

ELECTRONEGATIVITY:

F → Cl → O → S

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1) It is to be noted that a person standing behind the reflecting source is unlikely to hear an echo. If the time delay between when a sound wave hits the ear and when the reflected wave reaches the ear is shorter than 0.1 seconds, the individual cannot distinguish the echo from the original sound.

2) The materials that would be least efficient in soundproofing a room will be: Clay tile would be the least efficient because it has the lowest absorption coefficient (3%).

3) Juxtaposing infrasonic and ultrasonic vibrations, we see that Humans cannot hear infrasonic and ultrasonic vibrations because they are outside the range of frequencies that may be perceived. [Similarity]

Infrasonic vibrations have a lower frequency than what the human ear can hear; ultrasonic vibrations have a higher frequency than the human ear. If the amplitude is large enough, infrasonic vibrations can be felt. Sonar equipment and applications use ultrasonic vibrations to identify faults in steel castings and to remove grease or other material from machine-part surfaces. [Contrast]

4) With regard to the response of the human ear, if the sound is coming from the right, the waves will reach the right ear before the left. If the sound is coming from the left, the waves will reach the left ear before the right. The difference in phase between waves reaching both ears is sensed by the ears and processed by the brain. If the sound originates from directly above, directly below, directly ahead, or directly behind, the sound waves hit both ears in phase, which the brain interprets.

Ultrasonic or supersonic vibrations are those that are perceptible to the human ear (which senses vibrations ranging from 20 to 20,000 cps). These vibrations have intriguing applications in the realm of dermatological research.

Infrasonic waves, on the other hand, are vibrational or stress waves in an elastic medium with frequencies lower than that of sound waves detectable by the human ear—that is, below 20 hertz. The frequency range extends all the way down to geologic vibrations that complete one cycle in 100 seconds or more.

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1. An echo can be heard only if the person is in the range of both the sound waves coming directly from the source and the reflected waves and at a distance of more than 16.6 meters in front of the reflecting source.

A person behind the reflecting source will likely not hear an echo. If the interval of time between the instant a sound wave reaches the ear and the instant the reflected wave reaches the ear is less than 0.1 second, the person can’t hear the echo separately from the original sound. Finally, the person can’t be too close to the reflecting surface.

2. Clay tile would be the least efficient because it has the lowest coefficient of absorption (3%). This means that the energy remaining in a reflected wave is 97%, which is very high. (Remember that this is equal to 100 minus the coefficient of absorption). Very little of the sound energy would be absorbed.

3. Infrasonic and ultrasonic vibrations can’t be heard by humans because they’re outside of the range of frequencies that can be detected. Infrasonic vibrations have a lower frequency than can be heard by the human ear; ultrasonic vibrations have a higher frequency than can be heard by the human ear. Infrasonic vibrations can be felt if the amplitude is great enough. Ultrasonic vibrations are utilized in sonar equipment and in applications to detect flaws in steel castings and to remove grease or foreign material from machine-part surfaces.

4. If the sound comes from the right side, the waves reach the right ear before the left ear. If the sound comes from the left side, the waves reach the left ear before the right ear. The difference between the phases of waves reaching both ears is detected by the ears and then interpreted by the brain. If the sound comes from directly above, directly below, directly ahead, or directly behind, the sound waves reach both ears in phase and is interpreted as such by the brain.

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

Answer:

proton and neutrons

Explanation:

electron has negligible mass

Neighborhood, familial, and sociodemographic factors make up the three contextual factors.

Developmental theory and research emphasize a variety of contexts for children's development, including families, peers, schools, and neighborhoods. 1 These contexts are distinct from the other child development and well-being categories and should be assessed separately. Knowing whether or not a child is overweight or exercises enough, for example, can help describe the physical health of the child in a meaningful way.

Children from homes where the parents may or may not exercise frequently or actively encourage their children to exercise represent family situations that affect children's development and welfare. The family's level of money has an impact on the child's access to food as well (socio-demographic context).

In early life, gender is one of the clearest and most reliable signs that allows us to categorize our social environment. In the early stages of development, a person's ethnic origin does not provide the infant with any information beyond his perceptible characteristics; however, age can be a reliable indicator of expertise, competence, reliance, and authority, and gender can provide accurate information about potential areas of interest. Therefore, unlike someone who just shares the same hue, infants and children may have expectations regarding shared knowledge with someone who has or does not have the same competence (age) and interest (gender).

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Charge : q = 0.0036 * \(10^{-2}\)C

The magnetic force on a free moving charge is perpendicular to both the velocity of the charge and the magnetic field with direction given by the right hand rule. The magnetic force is given by the charge times the vector product of velocity and magnetic field.

Magnetic Force = q*v*B*sin*(theta)

given

Magnetic Force = 2.89 * \(10^{-7}\) N

velocity = 288 m/s

theta = 90 °

B =   2.77 * \(10^{-5}\) T

q = ?

Magnetic Force = q * 288 m/s * 2.77 * \(10^{-5}\) T

2.89 * \(10^{-7}\) N = q * 288 m/s *  2.77 * \(10^{-5}\) T

q = 2.89 * \(10^{-7}\) N / 797.76 * \(10^{-5}\)

q = 0.0036 * \(10^{-2}\) C

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Answer:

Chaos.

Explanation:

Plate Boundaries on Earth assignment involves identifying and illustrating different types of plate movements at the Earth's contact points.

Here are the steps to be followed:

Step 1: Understanding the Assignment Requirements

Read through the assignment instructions carefully to ensure a clear understanding of the tasks and expectations.

Step 2: Research

Start by conducting research on plate boundaries, their types, movements, and associated geological processes. Use reliable and valid resources such as scientific journals, textbooks, and reputable websites. Take notes on the different plate movements, their characteristics, and examples of each.

Step 3: Worksheet Setup

Create a table or chart with six rows corresponding to the six categories specified in the assignment instructions: Plate Boundary (Movement), Diagram, Lithosphere (Created or Destroyed), Geologic Process, Real World Example, and References.

Step 4: Fill in Row 1 - Plate Boundary (Movement)

In the first row, list the three types of plate boundaries: convergent, divergent, and transform. Next to each type, write the correct description in parentheses: sliding, separating, or colliding.

Step 5: Fill in Row 2 - Diagram

In the second row, draw a diagram or illustration for each type of plate movement. Use arrows to indicate the direction of movement and whether the plates are colliding, separating, or sliding past each other.

Step 6: Fill in Row 3 - Lithosphere (Created or Destroyed)

In the third row, identify whether the Earth's crust is created or destroyed at each type of plate boundary. Note the corresponding effects of plate movement on the lithosphere.

Step 7: Fill in Row 4 - Geologic Process

In the fourth row, provide at least one example of a geologic process or event that occurs as a result of plate movement at each type of boundary. This could include processes like subduction, seafloor spreading, or earthquakes.

Step 8: Fill in Row 5 - Real World Example

In the fifth row, give at least one real-world example of a location where each type of plate movement is demonstrated along a plate boundary. Include the name of the location and its corresponding plate boundary type.

Step 9: Fill in Row 6 - References

In the final row, provide the references for your research in APA format. Include the sources you used to gather information on plate boundaries, plate movements, and related geological processes.

Step 10: Review and Proofread

Review the completed assignment, ensuring that all information is accurate and properly cited. Proofread for any grammatical or spelling errors.

Note: The specific format and layout of the worksheet may vary based on your preference or instructor's instructions. Make sure to follow any specific formatting guidelines provided by your instructor.

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Answer:

40m/s

Explanation:

144km/h

1km=1000m

1hr=3600secs

144×1000/3600=

40m/s

Work (W) done by a force(F) is given by

Final answer is 600 Joule

Since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

For an electron moving in a uniform magnetic field, the force on the electron is given by

F = Bev where

Also, this magnetic force equals the centripetal force on the electron, F'

F' = mv²/r where

Since both forces are equal,

F = F'

Bev = mv²/r

Be = mv/r

We know that angular speed, ω = v/r. So,

Be = mω

Also, angular speed, ω = 2π/T where T = period of revolution of electron

So, Be = m2π/T

Making T subject of the formula, we have

T = 2πm/Be

so, since T = 2πm/Be the period of revolution of the electron is independent of velocity and radius of path

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According to Newton's Third Law:

This means forces always occur in pair and they are equal and opposite in nature.

Answer:

C in pairs

Answer:

the last option is correct

Explanation:

see I won't explain all the points but will tell you the concept being used.

since, the rest of the options are violating the above rules they're incorrect

Answer:

Explanation:

Pressure due to water column as deep as 10994 meters can be given by the following expression

Pressure = h d g , where h is depth of water , d is density of water and g is acceleration due to gravity .

Pressure = 10994 x 10³ x 9.8

= 10.77 x 10⁷ N / m²

Pressure will act on curved surface of the spherical shell , the effective surface area will be π R² where R is radius of the surface .

Effective surface = 3.14 x 0.1²

= .0314 m²

Total force = pressure due to water column x effective surface

= 10.77 x 10⁷  x .0314 N.

= 33.82 x 10⁵ N .

The angle of the red line (λ = 656 nm) in the ∅₁ 1st order is 0.0321 radians.

An optical lattice is a periodic structure formed by interfering laser beams, which creates a spatially varying pattern of light and dark regions. The lattice serves as a diffraction grating that can split light into its constituent wavelengths, enabling scientists to study the properties of light and matter. Optical lattices are widely used in experiments involving cold atoms, quantum optics, and condensed matter physics.

The angle of the red line (λ = 656 nm) in the ∅₁ 1st order can be calculated using the formula:

sin(θ) = mλ/d

where θ is the angle between the incident light and the diffracted light, m is the order of the diffraction (m = 1 for the ∅₁ 1st order), λ is the wavelength of the light, and d is the spacing between the diffracting elements of the grating (d = 1/560 mm in this case).

Substituting the values given, we get:

sin(θ) = (1)(656 nm)/(1/560 mm)

sin(θ) = 0.0005596

Taking the inverse sine of both sides, we get:

θ = sin⁻¹(0.0005596)

θ = 0.0321 radians

Therefore, the angle of the red line (λ = 656 nm) in the ∅₁ 1st order is 0.0321 radians.

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Hence, R = 28.97 m, 24.5 degrees is the vector sum of T and U.

A vector's direction is frequently stated as a rotation of the vector's "tail" anticlockwise with respect to due East. In accordance with this practise, a vector having a direction of 30 degrees is a vector that has been anticlockwise rotated 30 degrees with respect to due east.

Let's begin by separating the components of the vector T:

T~ = 40 m, 30 degrees

T_x = 40 cos(30) = 34.64 m

T_y = 40 sin(30) = 20 m

Let's now decompose the vector U into its constituent parts:

U~ = 12 m, 225 degrees

U_x = 12 cos(225) = -8.49 m

U_y = 12 sin(225) = -8.49 m

It is possible to combine elements of the same type (x and y):

R_x = T_x + U_x = 34.64 m - 8.49 m = 26.15 m

R_y = T_y + U_y = 20 m - 8.49 m = 11.51 m

The Pythagorean theorem can be used to determine the size of the resulting vector R:

|R~| = sqrt(R_x² + R_y²) = sqrt((26.15 m)² + (11.51 m)²) = 28.97 m

The inverse tangent function can be used to determine the direction of the resulting vector R:

theta = tan⁻¹(R_y/R_x) = tan⁻¹(11.51 m/26.15 m) = 24.5 degree.

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Answer:

20.00

Explanation:

a. The force should be applied 5 m from the fulcrum

b. The issue is that deformation of the rod will occur.

In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.

The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.

Mathematically;

The moment of a force is the product of the force and the perpendicular distance from its point of action.

From the data provided:

Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.

Let d be the perpendicular distance of the applied force from the fulcrum

5000 * 2 m = 2000 * d

d = 5 m

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Determine the magnitude of B-A is 53.68

1.4

Magnitude is a term used to describe size or distance. We can relate the magnitude of the movement to the size and movement speed of the object. The magnitude of a thing or an amount is its size. A car moves at a faster pace than a motorcycle, just in terms of speed.

Magnitude is the relative size of an object (mathematics). The mathematical term for a vector's length or size is the norm. By using the symbol |v|, the magnitude of a vector formula can be utilized to determine the length of a given vector (let's say v). This amount is essentially the distance between the vector's beginning point and ending point.

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Answer:

The time taken by the projectile to hit the ground is 6.85 sec.

Explanation:

Given that,

Vertical height of cliff = 230 m

Distance = 300 m

Suppose, determine the time taken by the projectile to hit the ground.

We need to calculate the time

Using second equation of motion

\(s=ut+\dfrac{1}{2}gt^2\)

Where, s = vertical height of cliff

u = initial vertical velocity

g = acceleration due to gravity

Put the value in the equation

\(230=0+\dfrac{1}{2}\times9.8\times t^2\)

\(t=\sqrt{\dfrac{230\times2}{9.8}}\)

\(t=6.85 sec\)

Hence, The time taken by the projectile to hit the ground is 6.85 sec.

Answer:

157.36 N

Explanation:

Contact force is the force which is created due to contact and it is applied on the contact point . The force applied by body on the surface is its weight .

If R be the reaction force of the ground

R = mg + F son30

= 12 x 9.8 + 75 sin 30

= 117.6 + 37.5

= 155.10 N .

friction force = f

Net force in forward direction = F cos 30 - f  = ma

75cos 30 - f = 12 x 3.2

f = 65 - 38.4

= 26.6 N  

Total force on the surface =√( f² + R² )

√ (26.6² + 155.1²)

= √707.56 + 24056²

=√ 24763.57

= 157.36 N.

contact force = 157.36 N .