The frequency of the fundamental mode of vibration of a steel piano wire depends on its tension and linear density.
The frequency of the fundamental mode of vibration, also known as the first harmonic, can be determined using the formula:
f = (1/2L) * sqrt(T/μ)
where f is the frequency, L is the length of the wire, T is the tension in the wire, and μ is the linear density of the wire.
In the case of a steel piano wire, the tension and linear density can vary depending on the specific wire. However, for a typical steel piano wire, the tension is usually in the range of 1000 N to 2000 N, and the linear density is around 0.3 kg/m.
To calculate the frequency, we need to know the length of the wire. Let's assume a length of 2 meters for example purposes.
Plugging in the values into the formula, we have:
f = (1/2 * 2) * sqrt(T / μ)
f = sqrt(T / μ)
Using the typical values mentioned earlier, we can estimate the frequency. However, without knowing the specific tension and linear density of the steel piano wire, we cannot provide an exact frequency. Steel piano wires are carefully tuned to specific frequencies to produce the desired musical notes.
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is there any way u can help me
Answer:
get help with your work
try understand your work
ask your teacher for assistance or class
or maybe cheat but understand the work first if you wanna
Details The force on a particle is described by 10x³ - 5 at a point x along the x-axis. Find the work done in moving the particle from the origin to x = 2.
Answer:
To find the work done in moving the particle from the origin to x = 2, we need to integrate the force over the given interval.
The work done (W) is calculated by integrating the force function with respect to displacement (dx) from the initial position (0) to the final position (2):
W = ∫(0 to 2) (10x³ - 5) dx
Integrating the force function, we get:
W = ∫(0 to 2) (10x³ - 5) dx = [2.5x⁴ - 5x] evaluated from 0 to 2
Now, substituting the upper limit (2) and lower limit (0) into the equation:
W = [2.5(2)⁴ - 5(2)] - [2.5(0)⁴ - 5(0)]
= [2.5(16) - 10] - [0 - 0]
= 40 - 10
= 30
Therefore, the work done in moving the particle from the origin to x = 2 is 30 units of work.
Explanation:
please help! need a answer as quick as possible please. i need help with questions 1 and 2 ! thank you
Answer:
1.)When you arrive from school and you smell cookies baking in the kitchen your brain will tell you that you are hungry and that you should go to the kitchen at that point your sense organs like your nose helps you to detect that something is baking(cookies)and your nervous system (brain)will tell you that you are hungry and it will command/direct your brain to go to the kitchen then for you to eat the cookies and drink the milk the digestive system is going go help you to chew,swallow and digest the food which has been taken and when you also run to the kitchen at the beginning your brain will direct your skeletal and muscular system because the skeletons and muscles work hand in hand,and when you finish your meal the body will circulate some nutrients or minerals from the food or snack taken to other parts of the body for energy.
2.)When you sleep the whole body is asleep except the heart which needs to continue circulating blood around the whole system and sometimes the brain may not rest when you are sleeping it may continue to do it's work that's why some people usually sleep walk or sleep talk,it means the brain is not at rest and still doing some things....Thank you for the question I hope it is very useful to you.
Suppose that a 200-gram mass is swung around a circular path on the end of a 40-cm long string. The mass is swung faster and faster. When the period of revolution becomes 0.25 seconds, the string breaks. What is the maximum tension this string can withstand
The maximum tension the string can withstand is approximately 50.265 Newtons.
To find the maximum tension the string can withstand, we can use the centripetal force equation:
F = \((m * v^2) / r\)
where F is the tension in the string, m is the mass, v is the linear velocity, and r is the radius of the circular path.
First, we need to find the linear velocity (v) of the mass. The linear velocity is given by the formula:
v = (2πr) / T
where T is the period of revolution.
Given that the period of revolution is 0.25 seconds and the radius of the circular path is 40 cm (0.4 m), we can calculate the linear velocity:
v = (2π * 0.4 m) / 0.25 s
v ≈ 10.053 m/s
Now, we can substitute the values into the centripetal force equation:
F =\((m * v^2) / r\)
Given that the mass is 200 grams (0.2 kg) and the radius is 40 cm (0.4 m), we can calculate the maximum tension:
F = \((0.2 kg * (10.053 m/s)^2) / 0.4 m\)
F ≈ 50.265 N
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7. A 6 kg bug traveling east at 45 m/s is hit head on by a west bounc 67 kg
bicyclist on a 11 kg bike who is going 32 m/s. The biker swallows the bug.
What is the resulting velocity of the bug-bike-biker system?
The initial momentum and initial momentum of colliding system is the same. Hence, the final velocity of the bug-bike-biker system will be 32.92 m/s.
What is conservation of momentum ?The momentum of an object is the product of its mass and velocity. The total momentum of the a system is constant during a collision. Hence total initial momentum is equal to the total final momentum.
Initial momentum of bug = mass × Velocity
p1 = 6 kg × 45 m/s = 270 kg m/s
initial momentum of bike+ biker = 11 kg + 67 kg) × 45 m/s = 2496 kgm/s.
Then total initial momentum = 270 + 2496 kg m/s. = 2766 kg m/s.
Then total final momentum = (m1 + m2)v = 2496 kgm/s.
p2 = (78 kg + 6 kg)v = 2496 kgm/s.
v = 32.92 m/s.
Therefore, the momentum of the bug-bike-biker system after collision is 32.92 m/s.
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With the 100-inch telescope, Harlow Shapley could not resolve variable stars in the more distant globular clusters of the Milky Way. What basic assumption did Shapley make about the faraway globular clusters that allowed their distances to be found?
O Distant globular clusters have the same average size as nearby globular clusters.
O The Milky Way is a disk of stars with the Sun near the center.
O Half of the globular clusters are in or near the constellation Sagittarius.
O The distance to a star near the Galaxy's outer edge.
Harlow Shapley assumed that the faraway globular clusters have the same average size as nearby globular clusters.
Shapley used the period-luminosity relationship of Cepheid variable stars to determine the distances to globular clusters in the Milky Way. He made a basic assumption that distant globular clusters have the same average size as nearby globular clusters. However, with the 100-inch telescope, he could not resolve variable stars in the more distant globular clusters. Therefore, he made the basic assumption that the faraway globular clusters have the same average size as nearby globular clusters. This allowed him to use the period-luminosity relationship to estimate their distances and to map the overall structure of the Milky Way galaxy.
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What two factors does speed depend on?
Ques. 3 Due to applying force upon a toy car of weight 3.92N, it starts to move with an acceleration 0.5ms2 on the floor where frictional force is 0.5N.
c. Calculate the force acting upon the car.
d. Will you get any change in acceleration due to the frictional and frictionless floor? Evaluate mathematically
The force acting upon the car is 0.691N. Yes, the frictional force will cause a change in acceleration; the presence of friction reduces the acceleration from 9.8 m/s^2 to 8.3 m/s^2.
What is Newton's second law of motion?Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. This law is expressed mathematically as F = ma, where F is the net force acting on an object, m is its mass, and a is its acceleration.
c. The force acting upon the car can be found using Newton's Second Law. In this case, we know the weight of the car is 3.92N, which is equal to its mass times the acceleration due to gravity (9.8 m/s^2). Therefore, the mass of the car is 3.92N / 9.8 m/s^2 = 0.4 kg.
To calculate the force acting upon the car, we need to consider the forces acting on it. The force applied to the car is the driving force, which is causing the car to move forward. The force of friction, which is equal to the coefficient of friction (µ) multiplied by the normal force (N), is acting in the opposite direction to the driving force, and is reducing the car's acceleration. The normal force is equal to the weight of the car, which is 3.92N.
The force of friction is given as 0.5N, and the coefficient of friction is not given. We can use the equation of motion to calculate the force acting upon the car:
F = ma + µN
F = (0.4 kg)(0.5 m/s^2) + µ(3.92N)
F = 0.2N + µ(3.92N)
To find µ, we can use the fact that the car is just about to move, so the force of friction is equal to the maximum static friction force, which is µsN. Therefore, µsN = 0.5N, and µs = 0.5N / 3.92N = 0.128.
Substituting this value into the equation for force, we get:
F = 0.2N + (0.128)(3.92N) = 0.691N
Therefore, the force acting upon the car is 0.691N.
d. Yes, the frictional force will cause a change in acceleration. This can be calculated mathematically by subtracting the force of friction from the driving force and dividing by the mass of the car:
a = (F - µN) / m
a = (3.92N - 0.5N) / 0.4 kg
a = 8.3 m/s^2
If the car were on a frictionless surface, the acceleration would be equal to the driving force divided by the mass of the car, which would be:
a = F / m
a = 3.92N / 0.4 kg
a = 9.8 m/s^2
Therefore, the presence of friction reduces the acceleration from 9.8 m/s^2 to 8.3 m/s^2.
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Which skateboarder has greater momentum?
a) Skateboarder A: mass = 60 kg; velocity = 1.5 m/s
b) Skateboarder B: mass = 50 kg; velocity = 2.0 m/s
Answer:
skateboard b
Explanation:
p=mv
skateboard a
p=(60kg)(1.5m/s)=90kg*m/s
skateboard b
p=(50kg)(2m/s)=100kg*m/s
Skateboarder B has the greater momentum because the momentum of A is 90 kg m/s and the momentum of B is 100 kg m/s so B has the greater momentum.
What is momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum. Check out Newton's laws of motion.
According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum. On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.
According to the question,
For Skateboarder A :
momentum = 60 × 1.5
momentum = 90 kg m/s
For Skateboarder B :
momentum = 50 × 2
momentum = 100 kg m/s.
Hence, B has greater momentum than A.
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Tenemos un Cable de cobre de 1 km de longitud cuya sección es de 2 milímetros al cuadrado y queremos saber la resistencia que señalara el ohmetro , su temperatura es de 20°
Answer:
8.5 Ω
Explanation:
La resistencia de un material es directamente proporcional a su longitud e inversamente proporcional al área de la sección transversal.
La fórmula de la resistencia (R) viene dada por:
R = ρL/A
Donde ρ es la resistividad del material, L es la longitud del material y A es el área de la sección transversal del material.
Dado que:
L = 1 km = 1000 m, A = 2 mm² = 2 * 10⁻⁶ m², ρ (cobre) = 1.7 * 10⁻⁸ Ωm
Sustituyendo da:
R = 1,7 * 10⁻⁸ * 1000/2 * 10⁻⁶
R = 8.5 Ω
An object starts at position 12 on a horizontal line with a reference point of 0. What is the position of the object if it
moves 14 units to the left?
O-26
O-2
0000
2
O26
Answer:
-2
Explanation:
12 - 14 = -2
Its new position will be at -2
paper by itself catches fire easily whereas a piece of paper wrapped around an alluminium pipe does not.
Answer:
The paper does not catch fire when wrapped around aluminium pipe because aluminium absorbs the heat, so paper does not attain its ignition temperature.
Explanation:
If the wind is blowing from north to south, where are the areas of high and low pressure?
Answer:
Wind is caused by differences in the atmospheric pressure. When a difference in atmospheric pressure exists, air moves from the higher to the lower pressure area, resulting in winds of various speeds.
Our Earth is a rotating planet. Fast moving air is deflected by the Coriolis effect, except exactly on the equator. This defines the direction of cyclones, hurricanes, and typhoons rotation. The wind flow around a large cyclone is counterclockwise in the Northern Hemisphere and clockwise in the Southern Hemisphere.
Wind forms when the sun heats one part of the atmosphere differently than another part. This causes expansion of warmer air, making less pressure where it is warm than where it is cooler. Air always moves from high pressure to lower pressure, and this movement of air is wind.
The high is west of you, and the low is east of you. (If you're in the northern Hemisphere.)
which light will produce white
Answer:
Yellow light is a combination of red and green light. So combining blue with yellow light is like combining blue light with red and green light. The result of combining these three primary colors of light is to produce white light.
A fancart of mass 0.8 kg initially has a velocity of < 0.9, 0, 0 > m/s. Then the fan is turned on, and the air exerts a constant force of < -0.2, 0, 0 > N on the cart for 1.5 seconds. 1. What is the change in momentum of the fancart over this 1.5 second interval?(kg*m/s) 2.What is the change in kinetic energy of the fancart over this 1.5 second interval? (J) Thank you it is due tonight!
Answer:
Change in momentum: \(\langle -0.3,\, 0,\, 0\rangle\; {\rm kg \cdot m\cdot s^{-1}}\).
Change in kinetic energy: approximately \((-0.2)\; {\rm J}\).
Explanation:
Change in momentum \(\Delta p\) is equal to the net impulse \(J\) on the object. In order to find the net impulse \(J\!\), multiply the net force on the object \(F_{\text{net}\) by the duration \(\Delta t\):
\(\begin{aligned} J &= F_{\text{net}}\, \Delta t \\ &= (1.5)\, \langle -0.2,\, 0,\, 0\rangle\; {\rm N\cdot s} \\ &= \langle -0.3,\, 0,\, 0\rangle\; {\rm kg \cdot m\cdot s^{-1}} \end{aligned}\).
Since the change in momentum is equal to net impulse:
\(\Delta p = J = \langle -0.3,\, 0,\, 0\rangle\; {\rm kg \cdot m\cdot s^{-1}}\).
Divide the change in momentum by mass \(m\) to find the change in velocity \(\Delta v\):
\(\begin{aligned}\Delta v &= \frac{\Delta p}{m} \\ &= \frac{\langle -0.3,\, 0,\, 0\rangle}{0.8}\; {\rm m\cdot s^{-1}} \\ &\approx \langle -0.375,\, 0,\, 0\rangle\; {\rm m\cdot s^{-1}}\end{aligned}\).
Thus, velocity has changed from \(u = \langle 0.9,\, 0,\, 0\rangle\; {\rm m\cdot s^{-1}}\) to:
\(\begin{aligned} v &= u + \Delta v \\ &= \langle 0.9,\, 0,\, 0\rangle\; {\rm m\cdot s^{-1}} \\ &\quad + \langle -0.375,\, 0,\, 0\rangle\; {\rm m\cdot s^{-1}} \\ &= \langle 0.525,\, 0,\, 0\rangle\; {\rm m\cdot s^{-1}}\end{aligned}\).
The initial kinetic energy (a scalar) was:
\(\begin{aligned}(\text{KE, initial}) &= \frac{1}{2}\, m\, {(\| u\|_{2})}^{2} \\ &\approx \frac{1}{2}\, (0.9^{2})\; {\rm J} \\ &=0.324\; {\rm J}\end{aligned}\).
The new kinetic energy would be:
\(\begin{aligned}(\text{KE}) &= \frac{1}{2}\, m\, {(\| u\|_{2})}^{2} \\ &\approx \frac{1}{2}\, (0.525^{2})\; {\rm J} \\ &= 0.11025\; {\rm J}\end{aligned}\).
Hence, the change in kinetic energy would be:
\(\begin{aligned} &(\text{KE}) - (\text{KE, initial}) \\ \approx\; & 0.324\; {\rm J} - 0.11025\; {\rm J}\\ \approx \; & (-0.2)\; {\rm J} \end{aligned}\).
at saturation the capillary potential energy of a soil is zero. true or false
False. The capillary potential energy of a soil is not zero at saturation.The capillary potential energy of a soil refers to the energy associated with the capillary action, which is the ability of water to move through narrow spaces in soil against the force of gravity.
At saturation, the soil is fully saturated with water, meaning that all pore spaces are filled with water. In this state, the capillary potential energy is not zero. When soil is saturated, the capillary forces are at their maximum, resulting in the highest capillary potential energy. The water molecules in the soil are held together by cohesive forces and create capillary forces that resist the force of gravity. These capillary forces allow water to move upward in the soil, against gravity, and contribute to the overall energy of the system.
As the soil dries out and loses water, the capillary potential energy decreases, and eventually, when the soil reaches a point of complete dryness, the capillary potential energy becomes zero. At this stage, the soil can no longer support capillary action. However, at saturation, when the soil is fully saturated with water, the capillary potential energy is not zero.
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Each of four tires on an automobile has an area of 0.026 m2 in contact with the ground. The weight of the automobile is 2.6 x104 N. What is the pressure on the tires? what is the pressure on each tire ?
The pressure on the tyres of the automobile of weight 2.6 x104 N with a contact area of 0.026 m2 for each tyre is 250 KPa and the pressure on each tire is 62.5 KPa.
P = F / A
P = Pressure
F = Force
A = Area
F = W = 2.6 * \(10^{4}\) N
Area of one tyre = 0.026 m²
Total area, A = 0.026 * 4
A = 0.104 m²
P = ( 2.6 * \(10^{4}\) ) / 0.104
P = 25 * \(10^{4}\) Pa
P = 250 KPa
Total pressure of the tyres = 25 * \(10^{4}\) Pa
Assuming the pressure is same on all four tyres,
Pressure on each tyre = ( 25 * \(10^{4}\) ) / 4
Pressure on each tyre = 6.25 * \(10^{4}\) Pa
Pressure on each tyre = 62.5 KPa
Therefore,
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Anatomy and Physiology 4 questions..
Answer:
\(they \: are \: .....oil \: glands.... \: that \: secretes \: ...oil...\\thier \:function \: is \: in \:the \:secretion \: of \:sebum,\\ \: which \:contains \:fatty \: substances \)
Select all that apply.
The spectrum of Star S is compared to a reference hydrogen spectrum. What can be concluded about Star S?
Star S is moving away from Earth.
Star S is moving toward Earth.
Star S has transverse motion.
Star S has radial motion.
Answer:
Star S has radial motion
Explanation:
Because the radial motion stracture is kinda similar to hydrogen spectrum(I'm guessing,only lol)
The spectrum of Star S is compared to a reference hydrogen spectrum. It is concluded that Star S has transverse motion.
What is hydrogen spectrum?Hydrogen spectrum is used to show the quantized electronic structure of an atom.
If Star S is not showing radial motion. So, it is not moving away or towards the Earth.
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a &b
1 point
98. In the change in temperature
1°C > 1K
1°C < 1K
1°C = 1 K
1°C > 1.8K
a
Explanation:
1 degree celcious is the change
How do I solve this? I need this done asap
In an uniform gravitational field the center of gravity is equal to center of mass of a mass distribution. The center of mass of a colinear discrete mass distribution is given by:
\(x_{cm}=\frac{1}{M}\sum ^N_{i\mathop=1}m_ix_i\)where M is the total mass of the system, m_i the mass of each particle and xi is its position. In this case we have:
\(undefined\)A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity.
A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity is maximum.
Simple harmonic motion or SHM is the alternating motion of an object that passes through a certain balance point. SHM has a fixed frequency and amplitude and is periodic, namely movements that occur regularly and are repeated at the same time.
When a spring undergoes simple harmonic motion, the mass accelerates in a direction toward the equilibrium point, then the velocity of the object at the equilibrium point is maximum. The object is accelerating in a direction toward the equilibrium point. Acceleration caused by the force recovered.
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leah paid 42.90 for 5 gallons of gas what was the price per gallon of gas leah paid?
Answer:
the price per gallon of gas leah paid is 8.58
Explanation:
42.90/5=8.58
a particle of mass m makes a one-dimensional elastic collision with another particle initially at rest. the first particle rebounds with 25% of its initial kinetic energy. what is the mass of the second particle compared the first particle
A particle of mass m makes a one-dimensional elastic collision with another particle initially at rest. the first particle rebounds with 25% of its initial kinetic energy than a) v, v b) 2mv^2 and c) Elastic collion
What will be the velocity of the second particle after the collison?The velocity of the second particle after the collision is (v2x,v2y)=(v,−v). From momentum conservation in x-direction
Here x, y represent direction.They are not variable. 1 and 2 represent before and after.
2vm=v1xm+v2xm, we find v1x=v.
From momentum conservation in y-direction
0 =v1ym+v2ym, we findv1y=v.
By energy conservation principle
Before: K=1/2m(2v)^2=2mv^2.
After: K=1/2m(v^2(1x)+v^2(1y))+12m(v22x+v22y)=2mv^2
Therefore, The collision has been elastic.
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Initial State: Ball at rest at top of ramp.
Final State: Ball in motion at bottom of the ramp.
Notes: The system includes the ball and earth. Resistance forces are negligible.
Answer:
Initial: bring ek, eg and ech all to 2, in the end bring ek, eg up to 3 each
Explanation:
The initial state of the ball, the effect the ball might have on the Earth, and the balls final state. Ek stands for kinetic energy, Eg stands for gravitational potential energy, and Ech stands for chemical change (stored energy in food/fuel), Eint stands for internal energy change.
What is the kinetic energy and potential energy?Kinetic energy is the type of energy present in a body due to the property of its motion and potential energy is the kind of energy present in a body due to the property of its state.
Kinetic energy can be easily transferred from one body to another but potential energy is not transferable. Kinetic energy is relative with respect to nature and potential energy is non-relative with respect to nature.
As the ball is rolling down a ramp, its potential energy decreases and kinetic energy increases. The ball has the maximum potential energy when it is at the top, and this potential energy is transformed into both translational and rotational kinetic energy as it rolls down.
When the ball is at the topmost height, its gravitational potential energy is maximum and zero kinetic energy. When a ball reaches the bottom of the ramp, it will have zero potential energy and maximum kinetic energy.
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What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of
gravity only (9.8m/s²)?
Answer:
9800N
Explanation:
Since it is falling freely, the only force on it is its weight, w. w = m ⋅ g = 1000kg ⋅ 9.8ms2 = 9800N
in the median plane of an electric dipole is the electric field parallel or antiparallel to the electric dipole moment.explain.........
In the median plane of an electric dipole, the electric field is neither parallel nor antiparallel to the electric dipole moment. Instead, it is perpendicular to the electric dipole moment.
What is Dipole Moment?
Dipole moment is a concept in physics that describes the magnitude and direction of the separation of electric charge in a system with a dipole, such as a molecule or an object with an uneven distribution of charge. It is a measure of the polarity or asymmetry of a charge distribution.
The electric field lines in the median plane of an electric dipole form circular loops around the dipole axis. At points on the perpendicular bisector of the dipole (i.e., in the median plane), the electric field lines are symmetrically distributed around the dipole axis, and the electric field is directed perpendicular to the dipole moment vector.
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How has paul dirac contribution changed the ideas of their contemporaries and us?
Answer:
Dirac did more than any other scientist to reconcile Einstein's general theory of relativity to quantum mechanics. In 1933 he received the Nobel Prize in Physics, the youngest theoretical physicist ever to do so.
Explanation:
If I'm cold and want to warm up with an electric heater, which energy would I need in order to make the heater work?
a=light energy
b=electric energy
c=potential energy
d=mechanical energy
The answer would be B.) Electric Energy
Answer:
b.electric energy
we need electric energy to make the heater work.
calculate the velocity of a non-relativistic electron whose de broglie wavelength is 3.637 nm.
Answer:
The velocity of a non-relativistic electron can be calculated using the formula v = h / mλ, where h is Planck's constant, m is the mass of the electron, and λ is the de Broglie wavelength of the electron.
Assuming the mass of the electron is 9.11 x 10^-31 kg, the velocity of the electron can be calculated as follows:
v = (6.63 x 10^-34 m^2 kg / s) / (9.11 x 10^-31 kg * 3.637 x 10^-9 m)
This works out to be approximately 5.82 x 10^6 m/s.
However, it's important to note that the de Broglie wavelength of a particle is generally only considered to be a meaningful quantity when the particle is moving at speeds that are comparable to the speed of light. For non-relativistic particles, such as an electron moving at a low velocity, the de Broglie wavelength is not a well-defined concept. Therefore, it's not meaningful to calculate the velocity of an electron based on its de Broglie wavelength.
Explanation:
Answer: 2 x 10^5 m/s
Explanation:
de Broglie wavelength equation: λ = h / mv
v = h / m · λ
m = 9.11 x 10^-31 kg
h = 6.62 x 10^-34 J·s
λ = 3.637 x 10^-9 m
v = (6.62 x 10^-34 J·s) / (9.11 x 10^-31 kg) (3.637 x 10^-9 m)
v = 199800.3807 = 2 x 10^5 m/s