what is the molarity (mol/l) of a sodium hydroxide (naoh) solution containing 30 mg/l? atomic weights: na

Answer:

having a smooth or lubricated surface may help decrease friction.

Explanation:

Answer:

Option B - in the outermost region of the solar system, beyond Neptune.

Explanation:

The Oort Cloud is an extended shell of icy objects that exist in the outermost reaches of the solar system.

Answer:

b

Explanation:

i took the test

The  Lewis dot structure of SO₃  with oxygen and sulfur atoms is attached in the image below .

Lewis dot structures are also called as electron dot structures and can be drawn if the molecular formula of a compound is known. It provides information regarding the nature of bond and the position of atoms .

They are also capable of exhibiting the lone pair if any present in a molecule or compound.Lewis defined a base to be an electron pair donor and an acid to be an electron pair acceptor.

They are capable of reflecting electronic structure of elements and even the pairing of electrons . In the diagram, each dot represents an electron while a pair of dots represent a bond between the atoms.

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Answer:

Global winds are the main belts of wind that move in a particular direction across the earth

Answer:

Global winds are the main belts of wind that move in particular directions across the Earth.

Explanation:

All wind is caused by the uneven heating of Earth's surface, which sets convection currents in motion. Convection currents on a large scale cause global winds; convection currents on a small scale cause local winds.

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Minerals with covalent bonding, such as diamond, are typically very hard. Metallic bonding results in minerals that are malleable and ductile, but not necessarily hard.

Van der Waals bonding is weaker and results in minerals that are relatively soft and have a low melting point.

The four types of bonding that are important in minerals are covalent, metallic, Van der Waals. The property of a mineral's resistance to scratching is called hardness.

Hardness is a physical property of minerals that describes their resistance to scratching by other minerals or materials. The Mohs scale is a way of ranking minerals according to their hardness.

The scale runs from 1 (the softest mineral, talc) to 10 (the hardest mineral, diamond). Minerals with covalent bonding, such as diamond, are typically very hard. Metallic bonding results in minerals that are malleable and ductile, but not necessarily hard.

Van der Waals bonding is weaker and results in minerals that are relatively soft and have a low melting point.

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An equilibrium constant expression is a mathematical representation of the equilibrium between reactants and products in a chemical reaction. The correct answer would be A, D, and F.

An equilibrium constant expression is a mathematical representation of the equilibrium between reactants and products in a chemical reaction. It is written using the concentrations of the reactants and products at equilibrium. The equilibrium constant expression includes only the species that are present in the reaction mixture in the gaseous or aqueous state. Therefore, the terms that would be included in an equilibrium constant expression are N2(g), NH3(g), and H2O(g). NaCI(s) and H2O(s) are solids and are not included in the expression as their concentrations do not change during the reaction. H20( is not a species and cannot be included in the equilibrium constant expression. Therefore, the correct answer would be A, D, and F. It is important to note that the equilibrium constant expression may differ depending on the chemical reaction and the specific conditions of the reaction.

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The equilibrium concentration of phosphate ions in pure water caused by the dissociation of Ca₃(PO₄)₂(s) is 1.63 × 10⁻⁶ mol/L or 0.156 mg/L.

The equilibrium constant expression for the dissociation of Ca₃(PO₄)₂(s) is given by;

Ksp = [Ca²⁺]³[PO₄³⁻]²

We can use this expression to find the equilibrium concentration of PO₄³⁻ in pure water. Since we are starting with solid Ca₃(PO₄)₂, we can assume that the initial concentration of Ca²⁺ and PO₄³⁻ is zero. At equilibrium, let x be the concentration of PO₄³⁻. Then, the concentration of Ca²⁺ will be 3x (due to the stoichiometry of the reaction).

Substituting these values into the Ksp expression and solving for x, we get;

Ksp = (3x)³(x)² = 2.07 × 10⁻²⁶

Simplifying this expression, we get;

27x⁵ = 2.07 × 10⁻²⁶

x⁵ = 7.67 × 10⁻²⁸

Taking the fifth root of both sides, we get:

x = 1.63 × 10⁻⁶ mol/L

To convert this to mg/L, we can use the molar mass of PO₄³⁻, which is 95.97 g/mol;

1.63 × 10⁻⁶ mol/L × 95.97 g/mol = 0.156 mg/L

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Since 1750, the greenhouse gas with the greatest percentage increase is methane.

Methane (CH₄) is a potent greenhouse gas, primarily released from agricultural activities, waste management, and fossil fuel extraction. Its warming potential is much stronger than carbon dioxide, although its atmospheric concentration is lower. Methane concentrations have more than doubled since pre-industrial times, resulting in a significant impact on climate change.

While carbon dioxide (CO₂) remains the most abundant greenhouse gas, its percentage increase is lower than methane's. Nitrous oxide (N₂O) and ozone (O₃) have also experienced increases, but not as substantial as methane. Water vapor is a natural greenhouse gas that varies based on temperature and other factors, so its increase cannot be compared directly with the other gases.

In summary, among the listed greenhouse gases, methane has experienced the greatest percentage increase since 1750, contributing significantly to climate change.

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Answer:

0.35 M

Explanation:

HCl + NaOH --> NaCl + H2O

Since the ratio HCl : NaOH is 1:1, you can apply the formula:

Ma x Va = Mb x Vb

Vb = 14 ml (based on the table)

Va = 10 ml

Mb = 0.25 M

Ma = (Mb x Vb)/Ma = (14 x 0.25)/ 10 = 0.35 M

Answer:

I think he was right but not explaining

Explanation:

I think it is C cause.... the volume of a material is the amount of matter that matterial can hold. it should the the amount of space the whole material takes up.

so C is the answer.

pls make this the brainliest.

not because it is, but because I asked.

Answer:5.45×10^21

Explanation:

Use:f=c/λ

The three methods of thermal energy transfer conduction, convection, and radiation involve the movement of heat energy, while the three methods of sound energy transfer conduction, convection, and transmission involve the transfer of sound energy.

Thermal energy transfer: In conduction, thermal energy is transferred through direct contact between particles within a medium. Sound energy transfer: In the context of sound, conduction refers to the transfer of sound energy through solid materials by direct particle contact.

Thermal energy transfer: Convection involves the transfer of thermal energy through the movement of a fluid (liquid or gas). Sound energy transfer: Convection in the context of sound refers to the transfer of sound energy through fluid mediums.

Thermal energy transfer: Radiation is the transfer of thermal energy through electromagnetic waves. It does not require a medium and can occur in vacuum or transparent materials. Sound energy transfer: Unlike thermal energy, sound energy is not transferred through radiation. Therefore, radiation does not play a significant role in sound energy transfer.

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The relative abundance of isotopes is the number of atoms of a particular isotope divide by the total number of atoms of all isotopes of that element, multiplied 100 percent.

The relative abundance of an isotope is the percentage of atoms with a specific atomic mass found in a naturally occurring sample of an element.

Also relative abundances refers to the relative proportions of the stable isotopes of each element. They are most often quoted as atom percentages

To calculate the percent abundance of each isotope in a sample of an element,  the number of atoms of a particular isotope is usually divide by the total number of atoms of all isotopes of that element and then multiply the result by 100 since it is expressed in percentage.

Mathematically, the formula for relative abundance is given as;

R.A = ( number of atoms of isotope / total number of atoms ) x 100%

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Answer:

i think you mean what is the kingdom of plants, but its "Kingdom Plantae".

Kingdom Plantae traits: eukaryotic/have nucleus, multicellular and autotrophic. (they photosynthesis)

2nd largest kingdom

Answer:

Introduction: All the plants are placed in the Kingdom- Plantae, according to the five-kingdom classification by R.H. Whittaker. The Kingdom- Plantae consists of multicellular plants with eukaryotic organization and chlorophyllous cells.

Explanation:

What is the kingdom for plants called?

What are the 3 plant kingdoms?

Kingdom Plantae Organisms

Ferns: They fall under the division Pteridophyta and are known to have vascular tissue. ...

Mosses: They fall under the division Bryophyta and have no vascular system. ...

Cone-bearing plants: They fall under the division Spermatophyta, sub-division gymnosperms

Answer:

1 atom of zirconium

Explanation:

Zirconium sulfide or zirconium disulphide can be written as ZrS2.

It is important to tare the flask before adding the solution to accurately measure the amount of solution being added.

Taring is the process of setting the balance to zero when there is an empty container on it, so that only the weight of the substance being added is measured.

This ensures that the weight of the container itself is not included in the measurement, providing a more precise measurement of the solution.

This is particularly important when adding small quantities of solution, as even a slight deviation in measurement can significantly affect the outcome of the experiment or analysis.

Taring helps to ensure consistency and accuracy in experimental procedures and enables researchers to obtain reliable results.

In summary, taring the flask before adding the solution is a crucial step in laboratory procedures that helps to maintain accuracy and precision.

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The equilibrium temperature will be 19.3 °C. We can calculate this using the specific heat capacities of all materials involved (copper, aluminum, and water).

We can calculate the equilibrium temperature by comparing the amount of heat (Q) released by the block of copper and the amount of heat absorbed by aluminum and water.

Q = (t₁ - t₂) * c * m

t₂ - starting temperature

t₁ - final temperature (X)

c - specific heat capacity (0.389 J/g°C for copper, 0.903 J/g°C, 4.186 J/g°C for water)

m - mass of the substance

Q(released) = (290 C - X) * 0.389 J/g°C * 229 g

Q(released) = 25833.49 J - 89.081 J/°C * X

Q(absorbed) = (X - 12.6 °C) * (0.903 J/g°C * 136 g + 4.186 J/g°C * 835 g)

Q(absorbed) = (X - 12.6 °C) * 3618.118 J/°C

Q(absorbed) = 3618.118 J/°C * X - 45588.2868 J

We know that the amount of heat released is equal to the amount of fear absorbed, so we will use that:

25833.49 J - 89.081 J/°C * X = 3618.118 J/°C * X - 45588.2868 J

71421.7768 J = 3707.199 J/°C * X

X = 71421.7768 J / 3707.199 J/°C

X = 19.3 °C

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Approximately 3.04 grams of magnesium would be required to react with 0.25 moles of hydrochloric acid.

To determine the mass of Mg required, we need to use the balanced chemical equation for the reaction between hydrochloric acid (HCl) and magnesium (Mg):

2HCl + Mg → MgCl2 + H2

From the balanced equation, we can see that 2 moles of HCl react with 1 mole of Mg. Therefore, if 0.25 mol of HCl reacts, we would need half of that amount, which is 0.125 mol of Mg.

To calculate the mass of Mg required, we need to multiply the number of moles of Mg by its molar mass. The molar mass of Mg is given as 24.31 g/mol. Therefore, the mass of Mg required can be calculated as follows:

Mass of Mg = Number of moles of Mg × Molar mass of Mg

Mass of Mg = 0.125 mol × 24.31 g/mol

Mass of Mg = 3.04 g

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Answer:

\(\large \boxed{\text{2.20 g Pb}}\)

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

            2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

2. Calculate the moles of each reactant

\(\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}\)

3. Calculate the moles of Pb from each reactant

\(\textbf{From PbS:}\\\text{Moles of Pb} = \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}\)

4. Calculate the mass of Pb

\(\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}\)

The final volume of the gas at 89 KPa and 120 °C, given that it occupies 1.75 L at 675 °C and 1.45 atm, is 1.20 L

First, we shall list out the given parameters from the question:

The final volume of the gas can be obtained by using the combined gas equation states as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

(1.45 × 1.75) / 948 = (0.878 × V₂) / 393

Cross multiply

948 × 0.878 × V₂ = 1.45 × 1.75 × 393

Divide both side by (948 × 0.878)

V₂ = (1.45 × 1.75 × 393) / (948 × 0.878)

= 1.20 L

Thus, from the above calculation, we can conclude that the final volume of the gas is 1.20 L

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Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.

Average atomic mass = sum of masses of isotopes multiply by  % of abundance

Cu - 63, mass =  62.9298 amu,   % abundance = 69.09 %

Cu - 65, mass m2 = ?   % abundance = 30.91 %

average atomic mass = 63.546 amu

average atomic mass = ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )

63.546 =  ( 62.9298 × 0.6909 ) + ( m2 × 0.3091 )

m2 = 64.93 amu

Thus, Copper used in electric wires comes in two flavors (isotopes): Cu-63 and Cu-65. Cu-63 has an atomic mass of 62.9298 amu and an abundance of 69.09%. The other isotope, Cu-65, has an abundance of 30.91%. The average atomic mass between these two isotopes is 63.546 amu is 64.93 amu.

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The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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Answer:

\(\boxed {\boxed {\sf B. \ 0.5 \ M}}\)

Explanation:

Molarity is a measure of concentration in moles per liter. The formula for calculating molarity is:

\(molarity= \frac{moles \ of \ solute}{ liters \ of \ solution}\)

There are 2 moles of a compound or the solute. There are 4 liters of water or the solution.

Substitute the values into the formula.

\(molarity = \frac{ 2 \ mol}{ 4 \ L}\)

Divide.

\(molarity= 0.5 \ mol /L\)

1 mole per liter is equal to 1 Molar, so the solution's molarity of 0.5 mol/L is equal to 0.5 M.

\(molarity = 0.5 \ M\)

The molarity of the solution is 0.5 Molar and choice B is correct.

The steps needed to prepare phenylacetylene C₆H₅C≡CH from C₆H₅CH₂CHBr₂ is as follows:

C₆H₅CH₂CHBr₂ + 2Na⁺ + ⁻NH₂ → C₆H₅C≡CH + 2HBr

The process involves two steps. Firstly, the alkyl halide is converted into alkynes with the help of a base (NaNH₂)  which proceeds via an elimination reaction. The alkyne molecule is synthesized from the vicinal dihalides by two E₂ elimination reactions consecutively along with two equivalents of hydrogen halide.

In the second step synthesis of specified chemicals take place.

Phenylacetylene (C₆H₅C≡CH), is an alkyne hydrocarbon which has a colorless and thick appearance. It is more convenient for use in reactions than acetylene gas.

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The third law of thermodynamics describes the entropy of a: solid.

The third law of thermodynamics states that the entropy of a pure crystalline substance approaches zero as the temperature approaches absolute zero (0 Kelvin or -273.15 degrees Celsius). This law implies that at absolute zero, a perfectly ordered and pure crystalline solid will have zero entropy.

The third law of thermodynamics is not specific to liquids or gases but applies to solids. In a solid, the molecules are highly ordered and have fixed positions in a regular lattice structure. As the temperature decreases towards absolute zero, the thermal motion of the molecules reduces, and the system becomes more ordered, resulting in a decrease in entropy.

In contrast, liquids and gases have higher entropy compared to solids at absolute zero because their molecules have more freedom of movement and are not as tightly arranged. Therefore, the third law of thermodynamics specifically addresses the entropy of solids and does not apply to liquids or gases.

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Answer:

A: Control Group

Explanation:

The control group is part of an expierment left untouched by anything that could possibly alter it, in the case of this question, the students have two groups of plants that have drops of liquid that could alter them, in order to see the growth, and to see if the liquid actually did anything, in order to do so, you would have to have a untouched plant, that shows what it looks like with out any alteration from researchers. So the answer would be control group.

Answer:

i think control group?

Explanation:

meow x3 UwU

The correct answer is (c) SO3.

The empirical formula shows the simplest possible ratio of elements present in a compound. By converting the given percentages of S and O into their corresponding mass, then dividing the mass by their respective atomic masses, the mole ratio between S and O atoms in the compound can be found. That mole ratio can be expressed as a whole number ratio and used to determine the empirical formula.

For the given percentages, we can find the empirical formula of the compound as follows:

a) The mass of sulfur in a 100 g sample of the compound is 40.05 g, and the mass of oxygen is 59.95 g. Using the atomic masses of sulfur and oxygen (32.06 g/mol and 15.99 g/mol, respectively), we can find the number of moles of each element in the compound: moles of S = 40.05 g / 32.06 g/mol = 1.249 moles moles of O = 59.95 g / 15.99 g/mol = 3.747 moles To find the simplest whole number ratio between S and O atoms, we divide each value by the smaller one: moles of S / 1.249 = 1 moles of O / 1.249 = 3Therefore, the empirical formula is SO3.

b) To find the empirical formula for S02, we would need to have the percentage composition by mass of the elements in that compound. The given percentages of 40.05% S and 59.95% O do not correspond to the compound S02.

c) Similarly, the given percentages do not correspond to SO4 either. d) The given percentages do not correspond to S04 either.

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