The shape of the relationship between coil voltage and relay status curve is typically sigmoidal (S-shaped) in nature. This phenomenon is called hysteresis.Hysteresis refers to the phenomenon where the rate of change of a system is not entirely dependent on its current state, but rather on its past states as well.
In the case of the relationship between coil voltage and relay status, this means that the relay status will not change immediately as soon as the coil voltage is increased or decreased. Instead, there will be a range of voltages within which the relay status will remain the same despite the change in voltage.Only after reaching a certain threshold voltage will the relay switch status change, either from open to closed or from closed to open. This can be seen on a graph where the curve has an S-shape.
As the coil voltage increases, the relay status remains the same until it reaches the threshold voltage, at which point the status changes abruptly. On the other hand, if the coil voltage is decreased, the relay status will remain the same until the threshold voltage is reached, at which point the status will change abruptly again. The presence of hysteresis in the relationship between coil voltage and relay status is important in the design of many control systems.
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in fig. 5-7, is the magnitude of the normal force fn greater than, less than, or equal to mg if the block and table are in an elevator moving upward (a) at constant speed and (b) at increasing speed?
When the block and table are in an elevator moving upward at a constant speed, the magnitude of the normal force (Fn) is equal to the weight (mg) of the block.
This is because there is no net force acting in the vertical direction, so Fn balances out the weight of the block.
If the elevator is moving upward at an increasing speed, the magnitude of the normal force (Fn) will be greater than the weight (mg) of the block. The additional upward acceleration of the elevator requires an additional upward force to accelerate the block. The normal force must be greater than mg to provide this extra force and maintain equilibrium.
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The temperature decreases 5°C in one hour and then decreases another 3°C in the next hour. Does this fit the definition of weather? Why or why not?
The temperature decreases 5°C in one hour and then decreases another 3°C in the next hour fits the description of weather.
What is Weather?This is defined as the atmospheric condition of a place within a short period of time and is influenced by a lot of factors in the environment.
In this scenario, the temperature was taken every hour which is a short period of time and is thereby denoted as weather.
On the other hand, climate is the condition of a place over a long period of time which is usually up to a year which is why weather fits the definition provided.
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ACTIVITY 4
Applying the equation learned, answer the following problems:
1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?
Given:
Find:
Formula:
Solution:
2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?
Given:
Find:
Formula:
Solution:
3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?
Given:
Find:
Formula:
Solution:
Subject Is Science
Good Perfect Complete=Brainlist
Copy Wrong Incomplete=Report
Good Luck Answer Brainly Users:-)
Answer:
1) 10 kg-m/s
2) 2 kg
3) 20 m/s
Explanation:
The momentum of an object can be calculated using the equation:
\(\large\boxed{p=mv}\)
where:
p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).\(\hrulefill\)
Question 1For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.
Given values:
m = 4.0 kgv = 2.5 m/sSubstitute the given values into the momentum formula and solve for p:
\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)
\(p=10\;\text{kg m/s}\)
Therefore, the momentum of the bowling ball is 10 kg-m/s.
\(\hrulefill\)
Question 2For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.
Given values:
p = 6.0 kg-m/sv = 3.0 m/sAs we want to find mass, rearrange the momentum formula to isolate m:
\(\large\boxed{m=\dfrac{p}{v}}\)
Substitute the given values into the formula and solve for m:
\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)
\(m=2\;\text{kg}\)
Therefore, the mass of the skateboard is 2 kg.
\(\hrulefill\)
Question 3For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.
Given values:
p = 10 kg-m/sm = 0.5 kgAs we want to find velocity, rearrange the momentum formula to isolate v:
\(\large\boxed{v=\dfrac{p}{m}}\)
Substitute the given values into the formula and solve for v:
\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)
\(v=20\;\text{m/s}\)
Therefore, the velocity of the baseball is 20 m/s.
A student collects 25 mL of gas at 96 kPa. What volume would this gas occupy at 101.325 kPa. There is no change in temperature or mass.
Answer:
The answer is 23.69 mLExplanation:
The new volume can be found by using the formula
\(P_1V_1 = P_2V_2\)
Since we are finding the new volume
\(V_2 = \frac{P_1V_1}{P_2} \\\)
From the question we have
101.325 kPa = 101325 Pa
96 kPa = 96000 Pa
From the question we have
\(V_2 = \frac{25 \times 96000}{101325} = \frac{2400000}{101325} \\ = 23.68615840...\)
We have the final answer as
23.69 mLHope this helps you
Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds
Given that the velocity at any time t is
\(v(t)=t^2-9t+18\)Also, the time interval is from t = 0 to t = 8 seconds
The position at time t = 0 s is s(0) = 1 m towards right of zero.
The initial time is t = 0 s, so the initial velocity will be
\(\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}\)The final time is t = 8 s, so the final velocity will be
\(\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}\)The average velocity will be
\(\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}\)Thus, the average velocity is 14 m/s.
Part II:
The instantaneous velocity at time t =5 s will be
\(\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}\)The instantaneous speed is the magnitude of instantaneous velocity.
Thus, the instantaneous speed will be 2 m/s.
Part III:
The particle will move towards the right when v(t) > 0
The time intervals will be
\(\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}\)Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.
Part IV :
The particle will move faster if the acceleration, a(t) > 0
The particle will slow down if the acceleration, a(t) < 0
So, first, we need to find the acceleration, it can be calculated as
\(\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}\)For the particle moving faster,
\(\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}\)For particle slowing down,
\(\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}\)The total distance can be calculated as
\(\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}\)Here, the negative symbol indicates it is towards the left from zero.
what does hydraulic mean?
Answer:
denoting, relating to, or operated by a liquid moving in a confined space under pressure.
Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F
The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.What is the triangle about?Note that from the image given;
NM // XZNY = transversal line∠YXZ ≡ ∠YNMSince ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.
The reflexive property is one that informs that any shape is regarded congruent to itself.
Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.
Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.
Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.
We have 2 angles Δ XYZ and Δ NYM:
Note that ∠YXZ ≡ ∠YNM
∠XYZ ≡ ∠NYM
So, ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.
Therefore, The prove of Angle XYZ- Angle NYM is given below:
∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.Learn more about triangles from
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Answer:
1. parrael
2. corresponding angles theorem
3. NYM
4. AA
Explanation:
just took it
Power is _________________the force required to push something the work done by a system the speed of an object the rate that the energy of a system is transformed the energy of a system
Answer:
[defined as]
Explanation:
it is the missing word
Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.
Answer:
15.1 m/s²
Explanation:
Step 1: Calculate the force exerted by the friction
Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.
Ff = μ × m × g
where,
μ: coefficient of kinetic friction
m: mass of the block
g: gravity
Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N
Step 2: Calculate the resulting force
The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.
R = F - Ff = R = 200 N - 49 N = 151 N
Step 3: Calculate the acceleration of the block
We will use Newton's second law of motion.
R = m × a
a = R/m
a = 151 N/10 kg = 15.1 m/s²
helen adjusts the armature of an electric generator by increasing the number of coils around the iron core. what is helen most likely trying to do? group of answer choices
A. maintain the direction of the current flow B. reverse the direction of the current flow
C. increase the amount of current D. decrease the amount of current
By increasing the number of coils around the iron core of an electric generator, Helen is most likely trying to increase the amount of current.
An electric generator works by converting mechanical energy into electrical energy. It does so by using a magnetic field to induce a current in a coil of wire. The coil of wire is wrapped around an iron core, which amplifies the magnetic field. As the coil spins within the magnetic field, it generates an electric current.
By increasing the number of coils around the iron core, Helen is increasing the amount of wire within the magnetic field. This means that more current will be induced in the coil as it spins. Therefore, by increasing the number of coils, Helen is most likely trying to increase the amount of current that the generator produces.
This is useful when more power is needed, such as in the case of powering larger devices or machinery. It is important to note that increasing the number of coils may also increase the resistance of the circuit, which can affect the overall efficiency of the generator.
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Which of the following summarizes cellular respiration?
Oxygen reacts with glucose to produce carbon dioxide and water, and release energy.
Light energy is changed into chemical energy.
Light energy is used to join water and carbon dioxide to make oxygen and glucose.
Chemical energy is changed into light energy.
The statement which summarizes cellular respiration is Oxygen reacts with glucose to produce carbon dioxide and water, and release energy.
What is cellular respiration?Cellular respiration is the process by which food, in the form of glucose is transformed into energy within cells.
The food is prepared by the plants by the process of photosynthesis in presence of sunlight. This food is in the form of glucose.
The respiration of plants is done by breaking of glucose by absorbing oxygen. This produces carbon- di- oxide and water along with the release of energy.
Thus, the cellular respiration is oxygen reacts with glucose to produce carbon dioxide and water, and release energy.
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What nuclear reaction is shown in the equation below?
A. Nuclear fusion
B. Nuclear fission
C. Positron emission
D. Beta decay
The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
What is a nuclear fusion?The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.
We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
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Answer:
A. Nuclear fusion
Explanation:
got it right, trust
scientists are concerned about the decrease in ozone is allowing more ultraviolet. (True or False)
The given statement "scientists are concerned about the decrease in ozone is allowing more ultraviolet" is true because ozone is a molecule made up of three oxygen atoms that exist in the Earth's atmosphere. It's a form of oxygen that absorbs almost all of the Sun's harmful ultraviolet light.
Ultraviolet rays are very harmful to humans, causing skin cancer, immune system breakdowns, and cataracts in the eyes. When the ozone layer is damaged or thinned, it can allow more ultraviolet rays to penetrate the atmosphere, which is why scientists are so concerned about ozone depletion.What are the impacts of ozone depletion?It is estimated that a 1% reduction in the ozone layer increases the incidence of non-melanoma skin cancer by 2%.A decrease of 10% in the ozone layer may result in a 20% increase in the incidence of skin cancer.The thinning of the ozone layer may result in a decrease in plant production, which may result in food supply shortages.A decrease in ozone may have an impact on phytoplankton, which play a crucial role in ocean food webs. These tiny creatures consume carbon dioxide and produce half of the world's oxygen. As phytoplankton numbers decline, ocean ecosystems may change, affecting everything from fish populations to weather patterns.
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in a following chapter we will be able to show, under certain assumptions, that the velocity v(t) of a falling raindrop at time t is v(t) = vt(1 − e−gt⁄vt)
The equation is given as v(t) = vt(1 − e^(-gt/vt)), where v(t) represents the terminal velocity of the raindrop, g is the acceleration due to gravity, and e is the base of the natural logarithm.
Under the assumptions made, we can establish the equation v(t) = vt(1 − e^(-gt/vt)) for the velocity of a falling raindrop at time t. This equation incorporates two key factors: the terminal velocity (v(t)) and the gravitational acceleration (g).
Terminal velocity is the maximum constant velocity achieved by an object falling through a fluid medium, such as air. It occurs when the drag force acting on the object equals the gravitational force pulling it downward.
The equation v(t) = vt(1 − e^(-gt/vt)) represents the variation of velocity with respect to time. As the raindrop falls, it accelerates due to the gravitational force. However, as it gains velocity, the air resistance opposing its motion increases until it reaches a point where the drag force matches the gravitational force.
At this point, the raindrop reaches its terminal velocity, denoted by v(t). The term (1 − e^(-gt/vt)) in the equation accounts for the decreasing effect of air resistance on the acceleration of the raindrop as it approaches terminal velocity.
Overall, this equation provides a mathematical representation of how the velocity of a falling raindrop changes over time, incorporating the effects of terminal velocity and gravitational acceleration.
It allows us to study and understand the behavior of raindrops as they descend through the atmosphere, considering the balance between gravity and air resistance.
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For six weeks in 1992, Akira Matsushima, from Japan, rode a unicycle more than 3000 mi across the United States. Suppose Matsushima is rid- ing through a city. If he travels 250.0 m east on one street, then turns counterclockwise through a 120.0° angle and proceeds 125.0 m north- west along a diagonal street, what is his resultant displacement?
The resultant displacement of Matsushima is 330.72 miles.
What is resultant displacement?
The resultant displacement of an object is the change in the position of the object. It can also be described as the shortest path connecting the initial position and final position of an object.
The resultant displacement of Matsushima is calculated by applying parallelogram law of vector addition as shown below.
d² = a² + b² - 2ab cos(θ)
where;
a is the initial position of Matsushimab is the final position of Matsushimaθ is the angle between the two positionsSubstitute the given parameters and solve for the resultant displacement of Matsushima as shown below.
d² = (250)² + (125)² - 2(250 x 125) cos(120)
d² = 109,375
d = √109,375
d = 330.72 mi
Thus, the resultant displacement of Matsushima depends on the initial position, final position and angle between the two position as shown in the parallelogram law of vector additions.
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- Widgets have a price elasticity of 1.75; widgets have
O elastic
O high
O price
Onone of the above
demand.
Answer:Given that widgets have a price elasticity of 1.75, any increase in widget price will B) decrease total revenue.
Explanation:
You drop your cell phone while in the bathroom in front of the mirror while the water is runring inthe sink below. If you are 0.45 meters above the sink, how long do you have before your cell phone isruined?
Answer:
0.303 seconds
Explanation:
We need to find the time that the cell phone takes to reach the sink. So, we will use the following equation
\(y=y_i+v_it+\frac{1}{2}at^2\)Where
yi is the initial position, so yi = 0.45 m
vi is the initial velocity. Since it is freefall, vi = 0 m/s
a is the acceleration due to gravity, so a = -9.8 m/s²
y is the final position, so y = 0 m
t is the variable that we need to find.
So, replacing the values, we get:
\(\begin{gathered} 0=0.45+0t+\frac{1}{2}(-9.8)t^2 \\ 0=0.45-4.9t^2 \end{gathered}\)Now, we can solve for t
\(\begin{gathered} -0.45=-4.9t^2 \\ \frac{-0.45}{-4.9}=t^2 \\ 0.09=t^2 \\ \sqrt[]{0.09}=t \\ 0.303\text{ s = t} \end{gathered}\)Therefore, you have 0.303 seconds before your cell phone is ruined.
what is physical properties of matter
Answer:
A quality of matter that is unrelated to a change in its chemical makeup is called a physical property.
Examples of physical properties of matter:
DensityColorHardnessMelting PointBoiling PointElectrical ConductivityPhysical properties are any qualities of matter that may be felt or seen without changing the sample's chemical composition.
Due to the wide range of features that make up physical attributes, they are further separated into intensive and extensive as well as isotropic and anisotropic categories.
Any characteristic that can be recognized and measured by sight, hearing, touch, smell, or other senses without evoking a chemical reaction is referred to as a physical property. Examples of physical traits are:
Color, Shape, Volume, Density, Calorific value, Boiling point, Viscosity, Pressure, Solubility, electrical current
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A 2.6 kg rock is dropped from a height of 10 m. With what speed will it strike the ground. Ignore air resistance. Solve using conservation of energy (start with Ebefore = Eafter).
Answer:
\(mgh = \frac{1}{2} m {v}^{2} \\ v = \sqrt{2gh} \\ = \sqrt{2 \times 9.8 \times 10} \: m. {s}^{ - 1} \)
Need help with number 1
a _____ has to do with the direction of a force
Answer:
The "solid force"? ... The direction of the force always seems to be coming out of the solid surface. A direction which is perpendicular to the plane of a surface is said to be normal. The force that a solid surface exerts on anything in the normal direction is called the normal force.
Explanation:
i think i hope this helps
A student performed an investigation into the refraction of light in a transparent material.
The results are shown below:
The angle of refraction of the refracted ray through the material shown is 32o .
Use this information to calculate the critical angle of the transparent material
The critical angle of the transparent material is 35.3 degrees.
What is the critical angle?The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:
sin(critical angle) = sin(90 degrees) / sin(angle of refraction)
sin(critical angle) = 1 / sin(32 degrees)
sin(critical angle) = 0.574
critical angle = arcsin(0.574)
critical angle = 35.3 degrees
Therefore, the critical angle of the transparent material is 35.3 degrees.
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Plzz help me fast
(There is both physics and chemistry question )
1) Write the molecular formula of the following by crisscross method :
1. Potassium sulphate
2. Sodium chloride
3. Ammonium chloride
4. Silver oxide
2) Prove that F=ma pl
Potassium Sulphate :-
\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf K}\put(0,0){\bf 1}\put(4,3){\sf SO_4}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)
\(\boxed{\sf K_2SO_4}\)
Sodium chloride:-
\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Na}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)
\(\boxed{\sf NaCl}\)
Ammonium Chloride
\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf NH_4}\put(0,0){\bf 1}\put(4,3){\sf Cl}\put(4,0){\bf -1}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)
\(\boxed{\sf NH_4Cl}\)
Silver Oxide
\(\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\put(0,3){\bf Ag}\put(0,0){\bf 1}\put(4,3){\sf O}\put(4,0){\bf -2}\put(0.2,2.9){\vector(4,-3){3.5}}\put(3.8,2.9){\vector(-4,-3){3.5}}\end{picture}\)
\(\boxed{\sf Ag_2O}\)
Two cars crash in a head-on collision and come to a stop. The crash analysts created the data table
below based on their observations from the scene. Based on their findings, what can be concluded
about the impact forces experienced by each vehicle?
Vehicle A
Vehicle B
Impact time
0.01 sec
0.01 sec
Mass of vehicle
3000kg
1000kg
velocity before impact
10 m/s
- 30 m/s
The impact force for Vehicle A was the same as the impact force for Vehicle B
The impact force for Vehicle A was greater than the impact force for Vehicle B
The impact force for Vehicle A was equal and opposite to the impact force for Vehicle B
The impact force for Vehicle A was less than the impact force for Vehicle B
The impact force for vehicle A was equal and opposite to the impact force for vehicle B.
The given parameters;
Vehicle A:
impact time of vehicle A, t = 0.01 smass of vehicle A, m = 3000 kgvelocity of vehicle A before impact, v = 10 m/sVehicle B:
impact time of vehicle A, t = 0.01 smass of vehicle A, m = 1000 kgvelocity of vehicle A before impact, v = -30 m/sThe impact force for vehicle A is calculated as follows;
\(F = ma = \frac{mv}{t} = \frac{3000 \times 10}{0.01} = 3,000,000 \ N\)
The impact force for vehicle B is calculated as follows;
\(F = ma = \frac{mv}{t} = \frac{1000 \times -30}{0.01} = - 3,000,000 \ N\)
Thus, we can conclude that the impact force for vehicle A was equal and opposite to the impact force for vehicle B.
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Velocity can be described as the same thing as speed but with _________________ included
Answer:
Direction
Explanation: Hope this helps!
Answer:
nvm its direction :))
Explanation:
Speed and velocity both represent a way to measure the change in position of an object relative to time. In fact, for a straight line motion, the speed and velocity of an object are the same (since distance and displacement will be the same). Speed and velocity are measured in the same units: meters per second or m/s.
Velocity is a measure of both speed and direction of motion. Velocity is a vector, which is a measurement that includes both size and direction. Velocity can be represented by an arrow, with the length of the arrow representing speed and the way the arrow points representing direction.
a hiker of mass 59 kg is going to climb to the top of mount tam, which has an elevation of 2,574 ft.part (a) if the hiker starts climbing at an elevation of 560 ft, what will their change in gravitational potential energy be, in joules, once they reach the top? assume the zero of gravitational potential energy is at sea level.
457280.13 8 J change in gravitational potential energy is needed.
where
m = 68 kj
H = 2574 ft
where = 32 5 ft
a )if Gravitational potential energy is zero at see level .
then at strating
point,
Equation
G. P . E ( Ui ) = mgh
Change in G PE ;
AU = UJ - Vi
= mgy- mgh = mg ( H-h)
= 68 x9.81 [2574 - 325 0.3048
AU = 457280' 138 Joules
at top
GPE ( Uf ) = mgy
P . E = 0
GPF = Gravitational potential Energy .
at Top ape = 0
b)then change in GPE ;
ΔU = U(top) - Vata
= 0 - [-mg ( 4-h )]
= mg ( H-h j
= 68 * 9 . 81 [ 257 4 - 325 ) 0.3048
ΔU = 45 7280 . 13 8 J.
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what do pitch and loudness have in common?
Answer:
both are subject to a person's interpretation.
Answer:
it is a subject to a person's interpretation.
Explanation:
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a form of energy conversion that captures heat energy from within Earth
Geothermal energy is heat that occurs deep within the earth. Geothermal energy is a clean, renewable resource that can be used for heat and electricity.
Humans can harvest geothermal energy in the following ways. A geothermal power plant uses heat from deep underground to generate steam and generate electricity. Geothermal heat pumps use heat from near the surface to heat water or heat buildings. Geothermal power plants uses the steam to generate electricity. The steam comes from reservoirs of hot water several miles or more underground. The steam spins turbines and drives generators to generate electricity. These are the features of geothermal energy within the earth.
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Which statement accurately describes the outer planets?
Pluto is one of the outer planets.
The outer planets are also called rocky planets.
The outer planets have thin atmospheres.
The outer planets have a high gravity due to their large size.
Answer:
D or the one that is boldExplanation:
Which statement accurately describes the outer planets?
Pluto is one of the outer planets.
The outer planets are also called rocky planets.
The outer planets have thin atmospheres.
The outer planets have a high gravity due to their large size.
The outer planets have a high gravity due to their large size is the statement that accurately describes the outer planets, therefore the correct answer is option D
What is a solar system?It is a system that collection of all the planets and spatial bodies revolving around the sun because of the gravitational pull of the sun.
Our Solar System is based on a heliocentric model in which the Sun is assumed to reside at the central point of the planetary system.
In general, the outer planets are larger than the inner planets. They have extremely large and dense atmospheres and are made of gases. These planets have stronger gravitational pulls because they are larger overall and have more mass.
Thus, The statement that most accurately describes the outer planets is "The outer planets have a high gravity due to their large size," so option D is the appropriate response.
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If there is a 1st quarter moon on july 9, what is the approximate date of the next new moon?.
The next new moon will likely occur on July 31 if there is a first quarter moon on July 9 otherwise. The First Quarter Moon is a new Moon phase during which just half of the new Moon surface is illuminated.
Depending on where on Earth you are, it could be either the left or right half. first quarter Apart from the Sun, new Moon is the only other astronomical object that is clearly visible in the sky during the day. Around midday and midnight, the First Quarter Moon rises and sets. Unlike a Third Quarter Moon, which rises in the midst of the night and sets in the middle of the day, first quarter this moon is not in its third quarter.
It's usually best to view other planets during New Moon evenings because they're dark.
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