The correct description of the centripetal force on a pendulum is: The weight force w and the tension force T together form the centripetal force. option d is correct.
1)When a pendulum is swinging in a circular motion, there are two forces acting on it: its own weight (w) due to gravity, and the tension force (T) from the string holding it. These two forces work together to create the centripetal force that keeps the pendulum moving in a circular path.
2)To understand how these forces combine, let's break down their components. The weight force (w) can be divided into two components: one acting along the direction of the string (w_radial) and one acting perpendicular to the string (w_tangential). The tension force (T) always acts along the string.
3)The centripetal force required to keep the pendulum in circular motion is provided by the radial component of the weight force (w_radial) and the tension force (T). In other words, the centripetal force is the net force acting in the radial direction.
4)In summary, the centripetal force on a pendulum is not a separate, third force acting on the object. Instead, it is the combined effect of the radial component of the weight force and the tension force, both of which work together to keep the pendulum moving in a circular path.
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Note: The complete question would be as below,
When a pendulum is swinging circle on a string, its own weight w and the string tension force T act on it. Which of the following is the correct description of the centripetal force on the pendulum?
a)- The weight force w is the centripetal force.
b)- The tension force is the centripetal force.
c)- The tension force T is the centripetal force.
d)- The weight force w and the tension force т together form the centripetal force.
e)-The centripetal force is a 3rd force on the object other than the weight W and the tension force T
A student conducts an experiment to determine how the temperature of water affects the time for sugar to di solve. In each trial, the
student uses a different amount of sugar and a different temperature of water.
What is wrong with this experimental design?
The student changed too many variables
The student did not change enough variables
The student needs to perform more trials
The student does not have a dependent variable
Answer:
I think it's A
Explanation:
he shouldn't have changed the amount of sugar, because the whole point is to see which temperature dissolves sugar more quickly.
1. Imagine that you take a 200.0 km trip. You travel the first half of the trip at 100.0 km/hr. Your speed for the second half is 50.0 km/hr. How much time does the entire trip take?
2. In the above problem, what is your average speed in km/hr and m/s
Answer:
Explanation:
Speed = Distance/Time
Given
Distance = 200km
Total speed = 100+50 = 150km/hr
Time = Distance/Speed
Time = 200/150
Time = 1.33hr
b) Average speed in km/hr is 150km/hr
Convert to m/s
150km/hr = 150 * 1000 m/1 * 3600s
150km/hr = 150,000/360
150km/hr = 416.67m/s
Explain what causes seasons. What is the difference between winter solstice and summer solstice?
Answer: The axial tilt of the Earth
Explanation: The planet is tilted on its north-south axis by 23 degrees, making one hemisphere (out of northern and southern) closer to the sun than the other for half of the year. The hemisphere that's closer to the earth at any point experiences summer, and the one further away experiences winter.
Answer: The difference between the solstices is that one represents the point at which the hemisphere in question is closest to the sun (summer solstice) and furthest away (winter solstice)
A system is best defined as?
Answer:
a group of organs working together to perform a function.
Explanation:
A car with a mass of 1200kg is traveling west at 25 m/s collides head on with highway barrier. The car comes to rest in 0.35 seconds . What is the magnitude of the force and the impulse applied to the car
The magnitude of the force and the impulse applied to the car are 85714 N and 30000 N-s respectively.
What is force?
The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.
The magnitude of the force applied to the car = change in momentum/time interval
= (1200 kg × 25 m/s - 1200 kg×0)/0.35 second
= 85714 N.
The impulse applied to the car = change in momentum
= (1200 kg × 25 m/s - 1200 kg×0)
= 30000 N-s.
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A potential difference of 71 mV is developed across the ends of a 12.0-cm-long wire as it moves through a 0.27 T uniform magnetic field at a speed of 6.0 m/s. The magnetic field is perpendicular to the axis of the wire.
Required:
What is the angle between the magnetic field and the wire's velocity?
Answer:
Explanation: please see attached file I attached the answer to your question.
The angle between the magnetic field and the wire's velocity is 33.2 degrees.
Calculation of the angle:Since the potential difference = 71mv = 71 *10 ^-3 V
The length is 12 cm = 0.12m
The magnetic field i.e. B = 0.27T
The speed or v = 4 m/s
here we assume \(\theta\) be the angle
So,
e = Bvl sin\(\theta\)
So,
\(Sin\theta\) = e/bvl
= 71*10^-3 / 0.27 *4*0.12
= 0.5478
= 33.2 degrees
Therefore, the angle should be 33.2 degrees
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what does ARD or " a red " stand for
Answer:
Atmospheric Reentry Demonstrator
Explanation:
Of thats not right im sorry
In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue).
The top of a pool table is a height ℎ=2.75 ft from the floor. If a player's ball lands a distance =16.50 ft from the table edge, what is her break shot speed 0?
The break shot speed of the player is determined as 96.5 ft/s.
Time of motion of the playeruse the following kinematic equation to determine the time of motion of the player.
h = vt + ¹/₂gt²
h = 0 + ¹/₂gt²
h = ¹/₂gt²
t = √(2h/g)
t = √(2 x 2.75/32.17)
t = 0.171 s
break shot speedvx = x/t
vx = 16.5 ft / 0.171 s
vx = 96.5 ft/s
Thus, the break shot speed of the player is determined as 96.5 ft/s.
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An object is thrown down from a tall building with an initial velocity of 2 m/s. How fast is it going after 5 seconds of free fall?
Answer: Vf = Vi + A(t)
Vf= -2+ (-9.8)(5)
Vf = -51 m/s
Explanation:
The final velocity is equal to the initial velocity plus the acceleration multiplied by the time
(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth
-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.
The time of 5 was given in the question so you can plug it in for time
Answer:
Explanation:
Given:
V₀ = 2 m/s
g = 9.8 m/s²
t = 5 s
____________
V - ?
Axis OX direct vertically down. Then:
V = Vₓ = V₀ₓ + g·t
V = 2 + 9.8*5 = 51 m
What major difference was there in the US leadership during the Potsdam Conference?
A. Roosevelt was tougher on the Soviet Union and Germany
B. Truman was tougher on communism and less appeasing
C. Truman was more willing to compromise to make progress
D. Roosevelt began using atomic weapons as a bargaining threat
An object of mass m is oscillating with a period T. The position x of the object as a function of time is given by the equation x(t)=Acosωt . The maximum net force exerted on the object while it is oscillating has a magnitude F. Which of the following expressions is correct for the maximum speed of the object during its motion?
What the equation given?
x(t)=Acos\(\omega\)tMaximum velocity occurs at the equilibrium position
So
x=0Now
x(0)=Acos0\)x(0)=ANow
As we know the formula
\(\\ \rm\rightarrowtail V_max=A\omega\)
These expressions can be used
The maximum speed of the oscillating object will be given by \(V_{max}=Aw\)
What is oscillation?An oscillation is defined as the repitative periodic motion of any object about its mean or equilibrium position.
The given equation is as follows:
x(t)=Acost
Maximum velocity occurs at the equilibrium position x=0
x(0)=Acos0
x(0)=A
Hence the maximum velocity will be \(V_{max}=Aw\)
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Calculate the net force on the particle q1.
Answer:
-12.1
Explanation:
i’m almost sure this is it, i’m checking my old answers
if not let me know and i’ll give you some more answers
How long would it take a 90kg person to jump the same height as #3 but off Olympus Mons (the highest mountain on Mars)?
Answer:
Explanation:
Who is #3 and where is he/she jumping and with what conditions?
A figure skater glides along a circular path of radius 3.93 m. (a) If she coasts around one half of the circle, find the magnitude of the displacement vector. (b) If she coasts around one half of the circle, find what distance she skated. (c) What is the magnitude of the displacement if she skates all the way around the circle?
The magnitude of the displacement vector refers to the length or amount of the displacement vector. Displacement is the change in position of an object. Displacement is a vector quantity, which means it has both magnitude and direction. In this question, a figure skater is gliding along a circular path of radius 3.93 m.
If she coasts around one half of the circle, we have to find the magnitude of the displacement vector. The figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, then her final and initial position is on the same point. Therefore, the magnitude of the displacement vector is zero. Distance Skated Distance refers to the length covered by an object or an individual. In this question, the figure skater is gliding along a circular path of radius 3.93 m. If she coasts around one half of the circle, we have to find what distance she skated. The distance covered by an object or individual is determined by the formula:Distance = Circumference/2Given that the radius of the circle is 3.93 m, then:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 m.Therefore, the distance covered by the figure skater around half of the circle = 24.7 m/2 = 12.35 m. Therefore, she skated 12.35 m.Magnitude of DisplacementIf the figure skater skates all the way around the circle, then she covers the entire circumference of the circle. Therefore, the magnitude of the displacement vector is the same as the circumference of the circle, which is given as:Circumference of the circle = 2πr= 2 × 3.14 × 3.93= 24.7 mTherefore, the magnitude of the displacement vector when the figure skater skates all the way around the circle is 24.7 m.For such more question on magnitude
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Key Stage 3 Science - Physics
Question 19 of 35
Calculate the force applied in newtons) if a pressure of 150Pa is acting on an area of 25m².
Answer:
F = 3750 N
Explanation:
Given that,
Pressure, P = 150 Pa
Area, a = 25m²
We need to find the force applied. We know that, pressure is equal to the force acting per unit area. It can be given by :
\(P=\dfrac{F}{A}\\\\F=P\times A\\\\F=150\ Pa\times 25\ m^2\\\\F=3750\ N\)
So, the required force is 3750 N.
5. A 2-Me V neutron traveling in water has a head-on collision with an 160 nucleus. (a) What are the energies of the neutron and nucleus after the collision
Answer:
- Final energy of neutron is 1.557 Mev
- Final energy of nucleus is 0.443 Mev
Explanation:
Given the that;
for ¹⁶O, A = 16
we know that Energy of neutron and nucleus after collision = ( A - 1 / A + 1)² E₀
so we substitute
Fe = ( 16 - 1 / 16 + 1)² × 2
= (0.8823)² × 2
= 1.557 Mev
therefore Final energy of neutron is 1.557 Mev
Final energy of nucleus will be
2 - Final energy of neutron
= 2 - 1.5569
= 0.443 Mev
therefore Final energy of nucleus is 0.443 Mev
Who was Dr. Shirley Jackson?
Answer:
she is an American physicist, and the eighteenth president of Rensselaer Polytechnic Institute. She is also the second African-American woman in the United States to earn a doctorate in physics
Water flow at the rate of 0.1500kg/m through a tube and is heated by a heater dicsipating 25.2w. the in flow and out flow water temperatures are 15.2 degree Celsius and 17.4 degree Celsius respectively.when the rate of is increased to 0.2318kg/m and the rate of heating to 37.8w,the inflow and out flow temperatures are unaltered. find specific heat capacity of water and rate of loss of heat from tube
The specific heat capacity of water is 960 J/(kg·°C).
The rate of heat loss from the tube is 21.1 W.
How to solve this problem ?First we can use the formula for heat energy (Q) to solve this problem:
Q = m * c * ΔT
Where
Q is the heat energy transferredm is the mass of the water flowing through the tube per unit timec is the specific heat capacity of waterΔT is the change in temperature of the waterFor the first scenario, we have:
m = 0.1500 kg/m
Q = 25.2 W
ΔT = 17.4 °C - 15.2 °C = 2.2 °C
Substituting these values into the formula, we get:
25.2 W = 0.1500 kg/m * c * 2.2 °C
c = 960 J/(kg·°C)
Therefore, the specific heat capacity of water is 960 J/(kg·°C).
For the second scenario, we have:
m = 0.2318 kg/m
Q = 37.8 W
ΔT = 17.4 °C - 15.2 °C = 2.2 °C
Substituting these values into the formula, we get:
37.8 W = 0.2318 kg/m * 960 J/(kg·°C) * 2.2 °C + P
Where
P is the rate of heat loss from the tubeSimplifying, we get:
P = 37.8 W - 0.2318 kg/m * 960 J/(kg·°C) * 2.2 °C
P = 21.1 W
Therefore, the rate of heat loss from the tube is 21.1 W.
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WOODHAVEN MI AND SAGINAW MI
In a separate location, take notes from the sources you have identified. This will take place over two or more days. While taking notes, consider using these reading strategies. From your notes, select one piece of evidence describing a climate similarity or difference that you discovered between these two cities. Write it in the space provided.
Answer:
LOL PUEDO HABLAR CON
Explanation:
Answer:
Whats the anwser/????
Explanation:
What is the motion of an apple when it falls from a tree ? a)Constant b)accelerating c)decelerating d)zero
The motion of an apple when it falls from a tree is
b) Accelerating
The motion of apple is when it falls from a tree is the case of free fall.
During free fall , the initial velocity of the apple or any object is zero but it gains some velocity due to gravitatonal acceleration .
an object with an initial velocity of 5m/s has a constant acceleration of 2m/s2 when it is speed is 15m/s how far has us travelled
An object with an initial velocity of 5m/s has a constant acceleration of \(2m/s^2\) .The object has traveled a distance of 50 meters when it is speed is 15m/s how far has us travelled
To find the distance traveled by the object, we can use the equation:
\(v^2 = u^2 + 2as\)
where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled.
Given:
Initial velocity (u) = 5 m/s
Acceleration (a) = 2\(m/s^2\)
Final velocity (v) = 15 m/s
We need to solve for s.
Rearranging the equation, we have:
s =\((v^2 - u^2)\) / (2a)
Substituting the given values, we get:
s = \((15^2 - 5^2)\)/ (2 * 2)
s = (225 - 25) / 4
s = 200 / 4
s = 50 m
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What on earth is equal to 9.8m/s/s
Answer:
Acceleration due to gravity
A can of soda weighs 4.7 newtons (N) on Earth's surface. What will it weigh on Planet X where the acceleration due to gravity is 1.82 meters per second^2?
Explanation:
The mass of the soda can is
\(m = \dfrac{W}{g} = \dfrac{4.7\:\text{N}}{9.8\:\text{m/s}^2} = 0.48\:\text{kg}\)
The weight of this same soda can on Planet X is
\(W = mg_p = (0.48\:\text{kg})(1.82\:\text{m/s}^2) = 0.87\:\text{N}\)
what is microeconomics
Answer:
Microeconomics is a part of economics and the study of decisions made by people and businesses regarding the allocation of resources, and prices at which they trade goods and services.
Microeconomics helps business planning i.e. helps the business community to plan their costs, production, etc. in anticipation of demand in order to maximize profits. Microeconomics is useful in explaining how market mechanism determines the price in a free market economy.
what’s is the vertical colum of the elements in the periodic table called
it is called groups or families.
Answer:
groups or families
Explanation:
The vertical column of the periodic table are called groups or famileis because of their similar chemical behavior.
Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
You are traveling along a freeway at 65 mi/h. You suddenly skid to a stop because of congestion in traffic. Where is the energy that your car once had as kinetic energy before you stopped
The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:
The energy becomes:
An important part in work on discs. A part in non-conservative work due to friction.
Work is defined by the scalar product of force and displacement.
W = F . d
Where the bold indicate vectors, W is work, F is force and d is displacement.
The work energy theorem relates work and kinetic energy.
W = ΔK = \(K_f - K_o\)
In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:
W = - K₀
Therefore, the initial kinetic energy that the car has is converted into work in its brakes. In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.
In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:
The energy becomes:
An important part in work on the discs. A part in non-conservative work due to friction.
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24. A body A rests on a smooth horizontal table. Two bodies of mass 2 kg and 10 kg hanging freely, are attached to A by strings which pass over smooth pulleys at the edges of the table. The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 . Find the mass of A.
The two strings are taut. When the system is released from rest, it accelerates at 2 m/s2 then, Mass of A = 8m/5 kg.
Let the mass of the body A be ‘m’.
The two strings are taut so they exert a tension ‘T’ on body A.
Let ‘a’ be the acceleration produced in the system.
The free body diagram of body A is given below: mA + 2T = mA + ma = mA + m(2)mA + 10T = mA + ma = mA + m(2)
As the two strings are taut, we can say that tension in both strings is equal.
Therefore 2T = 10T or T = 5T As the body A is resting on a smooth horizontal table, there is no friction force acting on the body A.
The net force acting on body A is the force due to tension in the strings. ma = 2T – mg …(1)
As per the given problem, the system is released from rest.
Hence the initial velocity is zero.
Also, we are given that the system accelerates at 2 m/s2.
Therefore a = 2 m/s2 …(2)
From the equations (1) and (2), we get, m(2) = 2T – mg …(3)⇒ m(2) = 2×5m – mg⇒ 2m = 10m – g⇒ g = 8m/5
Thus, the mass of A is 8m/5 kg.
Answer: Mass of A = 8m/5 kg.
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Astronomers observe the motion of four planets that orbit a star similar to the Sun. Each planet follows an elliptical orbit around its star. The astronomers measure each planet's orbital period, as shown in the table.
Planet; Orbital Period (Earth days)
Planet W; 10
Planet X; 640
Planet Y; 80
Planet Z; 270
To determine the distance each planet is from the star, astronomers applied one of Kepler's three laws.
Kepler's first law: The path of each planet around a star is an ellipse, with the star at one focus. Kepler's second law: A planet sweeps out equal areas in equal amounts of time as it revolves around the star.
Kepler's third law: The square of the time for one revolution of a planet is proportional to the cube of the radius of its orbit.
Based on the table, identify the planet that is the farthest distance from the star, and indicate which of Kepler's three laws can be used to justify your answer. Enter your answer in the box provided.
Answer:
planet that is farthest away is planet X
kepler's third law
Explanation:
For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets
T² = (\(\frac{4\pi ^2}{ G M_s}\) a³ = K_s a³
Let's apply this equation to our case
a = \(\sqrt[3]{ \frac{T^2}{K_s} }\)
for this particular exercise it is not necessary to reduce the period to seconds
Plant W
10² = K_s \(a_{w}^3\)
a_w = \(\sqrt[3]{ \frac{100}{ K_s} }\)
a_w = \(\frac{1}{ \sqrt[3]{K_s} }\) 4.64
Planet X
a_x = \(\sqrt[3]{ \frac{640^3}{K_s} }\)
a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3
Planet Y
a_y = \(\sqrt[3]{ \frac{80^2}{K_s} }\)
a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6
Planet z
a_z = \(\sqrt[3]{ \frac{270^2}{K_s} }\)
a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8
From the previous results we see that planet that is farthest away is planet X
where we have used kepler's third law
Train A is moving North at 12 m/s and has a mass of 2000 kg.Train B is moving South at 8 m/s and has a mass of 4000 kg. Ifthe two trains collide and stick to each other, how fast dothey move after the collision, and in what direction?
Mass A = 2000 kg
velocity A = 12 m/s (North)
Mass B= 4000 kg
Velocity B= -8 m/s (South)
We adopt that North is positive and South is negative.
Conservation of momentum (p)
• Pi = Pf
• ma * va + mb*vb = (ma+mb) Vf
Where Vf is the final velocity after the collision.
Replacing:
(2000* 12 ) + (4000*-8)= (2000+4000) vf
24,000- 32,000 = 6,000 vf
-8,000 = 6,000 vf
-8,000 / 6,000 = vf
vf = -1.3334 m/s
vf = 1.3334 m/s , South