Why is the standard entropy of a substance in the gas state greater than its standard entropy in the liquid state?

Answer:

false i think

Explanation:

The three significant digits of Strontium-90 are is=3.5 gms

sample will remain= No/Nt= No/2^n

time= n*half life

t=n* t1/2

n=115.2/28.8=4

56/(2)^4= 56/16

sample will reamins = 3.5 gms  

29 years, Strontium-90 is the most prevalent isotope of this element. The half-life is the amount of time needed for a radioactive substance to decay and lose half of its radioactivity. With a half-life of 29 years, strontium-90 decays by releasing comparatively low-energy beta particles.

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Answer:

30

Explanation:

use the keep,change,change method.

19 + 11

19,keep, "-" change to addition, -11,change to positive

now use this

19 + 11 = (30 )

There are 1.81 × 10²⁴ molecules of sucrose in the given sample.

To calculate the number of molecules of sucrose in the given sample, we need to first determine the number of moles of carbon atoms present in the sample, and then use the molecular formula of sucrose to calculate the number of molecules.

Calculate the number of moles of carbon atoms in the sample:

We know that the sample contains 3.6 × 10²⁴ atoms of carbon. The molar mass of carbon is approximately 12 g/mol.

Therefore, the mass of carbon in the sample can be calculated as follows:

mass of carbon = number of atoms of carbon × molar mass of carbon

= 3.6 × 10²⁴ × 12 g/mol

= 4.32 × 10²⁵ g

To calculate the number of moles of carbon in the sample, we divide the mass of carbon by the molar mass of carbon:

number of moles of carbon = mass of carbon / molar mass of carbon

= 4.32 × 10²⁵ g / 12 g/mol

= 3.6 × 10²⁴ mol

Calculate the number of molecules of sucrose in the sample:

To calculate the number of molecules of sucrose in the sample, we can use the following formula:

number of molecules of sucrose = (number of moles of carbon / 12) × Avogadro's number

where;

Substituting the values, we get:

number of molecules of sucrose = (3.6 × 10²⁴ mol / 12) × 6.02 × 10²³ molecules/mol

= 1.81 × 10²⁴ molecules

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Hydra, a type of cnidarian, have equal survival rates through life because they are equally fit at all stages. Hydra are an example of an organism with a type I survivorship curve. Thus, the correct option is b. II.

Differences between how energy moves through an ecosystem compared to how chemicals move through the ecosystem. The fundamental difference between how energy moves through an ecosystem compared to how chemicals move through the ecosystem is that energy can not be recycled. Energy is obtained from the sun and is stored in organic molecules, and it flows through an ecosystem through metabolic processes. However, the number of chemicals like carbon, oxygen, nitrogen, water, and phosphorus remains constant in an ecosystem.

Tropical rainforest soils are usually nutrient-poor and low in organic matter. Therefore, option c. nutrient-poor and low in organic matter is the correct answer. The soil in the tropical rainforest is nutrient-poor because heavy rainfall washes away the nutrients, and the soil contains a high level of aluminum and iron, which are toxic to plants. Due to these reasons, there is slow decomposition of organic matter that makes the soil low in organic matter.

Thus, the correct option is b.

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Option B) n=4 to n=2 and C) n=2 to n=1  would emit a photon of light with the greatest energy.

The energy of a photon emitted during a hydrogen atom transition is determined by the difference in energy between the initial and final energy levels. This can be calculated using the equation:

ΔE = -13.6 eV * (1/n_f^2 - 1/n_i^2)

Where ΔE is the energy difference in electron volts (eV), and n_f and n_i are the final and initial energy levels, respectively.

Considering the given options, we can calculate the energy differences:

A) ΔE = -13.6 eV * (1/3^2 - 1/5^2) = -13.6 eV * (1/9 - 1/25) = 1.51 eV

B) ΔE = -13.6 eV * (1/2^2 - 1/4^2) = -13.6 eV * (1/4 - 1/16) = 10.2 eV

C) ΔE = -13.6 eV * (1/1^2 - 1/2^2) = -13.6 eV * (1 - 1/4) = 10.2 eV

D) ΔE = -13.6 eV * (1/4^2 - 1/5^2) = -13.6 eV * (1/16 - 1/25) = 0.858 eV

E) ΔE = -13.6 eV * (1/3^2 - 1/6^2) = -13.6 eV * (1/9 - 1/36) = 2.27 eV

Comparing the energy differences, we can see that option C) n=2 to n=1 and option B) n=4 to n=2 have the greatest energy differences. Therefore, these two transitions would emit photons of light with the greatest energy.
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Answer:

Lathanum

Explanation:

Answer:To determine the amount of water that can be produced from the reaction of 2.5 moles of H₂ and 4.5 moles of O₂, we first need to determine the limiting reagent. The limiting reagent is the reactant that runs out first and limits the amount of product that can be formed. In this reaction, the limiting reagent would be the reactant with the lowest stoichiometric ratio to the product, in this case, O₂.

Since 4.5 moles of O₂ is present, and the reaction requires 2 moles of O₂ for every 2 moles of H₂, only 2.5 moles of water can be produced. This means that 2.5 moles of H₂ is the limiting reagent, and the 4.5 moles of O₂ is the excess reagent.

In this reaction, 2.5 moles of water can be produced from the reaction of 2.5 moles of H₂ and 4.5 moles of O₂.

Explanation:

Actually, acetyl-CoA and OAA, a four-carbon molecule, unite to start the Krebs cycle (oxaloacetate). Citric acid, which has six carbon atoms, is the result of this

The Krebs cycle is sometimes known as the citric acid cycle for this reason.

Since citric acid is also the first byproduct of the Krebs cycle, it is present in nearly every living thing's metabolism.

Recall that the first stage of cellular respiration, glycolysis, yields two pyruvate molecules. These substances enter a mitochondrion's matrix, where they initiate the Krebs cycle.

Pyruvic acid produced during glycolysis initiates the Krebs cycle. The diagram's tiny circles stand in for one carbon atom. For instance, OAA (oxaloacetate) is a four carbon molecule, but citric acid is a six carbon molecule. As the cycle continues, pay attention to what happens to the carbon atoms. How many ATP molecules are created per one cycle turn? What number of NADH and FADH2 molecules are generated?

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Answer:pu-239

Explanation:

Pu-239 is regarded as the radioisotope requires long-term storage as the method of disposal, to protect living things from radiation exposure over time

Disposal of radioactive nuclear waste is often regarded as a problem.

The waste sources are:

Disposal of bomb-grade plutonium is often difficult.

The longer lived isotopes are:

The storage of the longer lived elements is through containment for the next several thousand of years.

The control or management of radioactive waste is a hard, multifaceted procedure.

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The synthesis of silver nanoparticles can involve various methods and conditions, but a general order of steps in a typical synthesis process might be as follows:

Preparation of the silver precursor: Silver nitrate (AgNO3) is commonly used as a silver precursor. It is dissolved in water or other suitable solvents to prepare a silver precursor solution.

Preparation of the reducing agent: A reducing agent, such as sodium borohydride (NaBH4) or sodium citrate, is prepared separately. The reducing agent will react with the silver precursor to form silver nanoparticles.

Mixing the silver precursor and reducing agent: The silver precursor solution and the reducing agent solution are mixed together under suitable conditions, such as controlled temperature and stirring, to allow the reduction reaction to occur.

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Size-exclusion chromatography (SEC) is a suitable chromatographic method for isolating pure a and b chains.

SEC is a technique that separates molecules based on their size. In this case, the a and b chains can be separated from other components based on their molecular weight. SEC columns have porous beads that allow smaller molecules to enter and travel through the beads, while larger molecules are excluded and elute first. By choosing an appropriate SEC column, the a and b chains, which typically have different molecular weights than other components, can be isolated and collected separately. This method ensures the purity of the isolated a and b chains.

Size-exclusion chromatography (SEC) is a useful chromatographic method for isolating pure a and b chains. The technique separates molecules based on their size, and by utilizing a suitable SEC column, the a and b chains can be separated from other components due to their distinct molecular weights. This approach guarantees the purity of the isolated a and b chains, making it an effective method for their isolation.

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Explanation:

i have done

see the picture

and please mark me brainiest

The system is not at equilibrium.

The reaction will proceed to the right to attain the equilibrium.

Let's consider the following reaction.

2 NOBr(g) ⇌ 2 NO(g) + Br₂(g)

The pressure equilibrium constant (Kp) is 60.6. To determine if the system is at equilibrium when the pressure of each component is 1.75 atm, we have to calculate the reaction quotient (Q) and compare it with Kp.

Q = [NO]².[Br₂] / [NOBr]²

Q = (1.75)².(1.75) / (1.75)²

Q = 1.75

Since Q ≠ Kp, the system is not at equilibrium.

Since Q < Kp, the reaction will proceed to the right to attain the equilibrium.

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Answer:

Soap and tomato juice :)

Explanation:

Using different types of pH levels may affect the results, so that is why I think this would be a good experiment to do. :)

Have an amzing day!!

Please rate and mark brainliest!!!

Answer:

Using litmus paper

Explanation:

Answer:

Atomic emission spectra are produced when excited electrons return to the ground state. When electrons return to a lower energy level, they emit energy in the form of light.

Explanation:

1/4  temperature must give Mass of nitrogen at 0°c heated so that both it volume and pressure will be double.​

To double both the volume and pressure of a given mass of nitrogen at 0°C, we can utilize the combined gas law, which relates the initial and final states of a gas. The combined gas law is expressed as:

(P1 * V1) / T1 = (P2 * V2) / T2

Where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.

Since we want to double both the volume and pressure, we can set P2 = 2P1 and V2 = 2V1. Plugging these values into the combined gas law equation, we get:

(2P1 * 2V1) / T1 = P1 * V1 / T2

Simplifying the equation, we find:

4P1V1 = P1V1 / T2

Cancelling out the common terms, we have:

4 = 1 / T2

Rearranging the equation, we find:

T2 = 1 / 4

Therefore, to double both the volume and pressure of the given mass of nitrogen at 0°C, it must be heated to a temperature of 1/4 or 0.25 times its initial temperature.

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question

mass = 0.5 kg

acceleration = 20 m/s²

We have

Force = 0.5 × 20

We have the final answer as

Hope this helps you

Answer:

\(\boxed {\tt 10 \ Newtons}\)

Explanation:

Force can be found by multiplying the mass by the acceleration.

\(F=m*a\)

The mass of the basketball is 0.5 kilograms.

The acceleration is 20 meters per second squared.

\(m= 0.5 \ kg \\a= 20 \ m/s^2\)

Substitute the values into the formula.

\(F= 0.5 \ kg * 20 \ m/s^2\)

Multiply.

\(F= 10 \ kg*m/s^2\)

A kilogram meter per second squared is equal to a Newton.

Therefore, 10 kilogram meters per second squared is equal to 10 Newtons.

\(F= 10 \ N\)

10 Newtons of force would be required.

Answer:

The new volume will be  

0.7 L

Explanation:

This is an illustration of Charles' law, some of the time called the temperature-volume law. It expresses that the volume of a gas is straightforwardly corresponding to the Kelvin temperature, while pressing factor and sum are held steady.  The condition is  V  1  T  1  =  V  2  T  2  , where  V  is volume and  T  is temperature in Kelvins.  Known  V  1  =  0.5 L  T  1  =  20  ∘  C  +  273.15  =  293 K  T  2  =  150  ∘  C  +  273.15  =  423 K  Obscure  V  2  Arrangement  Revise the condition to confine  V  2  . Substitute the known qualities into the condition and address.  V  2  =  V  1  T  2  T  1  V  2  =  (  0.5  L  ×  423  K  )  293  K  =  0.7 L  adjusted to one huge figure

Answer: jar for 1 team!!!!

Explanation:

Answer:

Hydrogen gas and a salt formed at the end of the reaction.

Explanation:

Hydrogen Gas has formed which inflated the balloon

Usually, metals and acids react to form a salt and Hydrogen Gas.

Here's what happened:

Zn (s) + 2HCl (aq) →  \(ZnCl_2\)(aq) +\(H_2\)(g)

Cheers :)

Answer:

One or more new substances formed.

Explanation:

This is an example of a chemical property because bubbles formed, and the mixture produced a gas which allowed the balloon to inflate. The production of bubbles is an indicator of a chemical change. When a chemical change occurs, one or more new substances form as a result.

- I took the quiz and got 100%

Hope this helps!

Answer:

If something were to weigh 30 kgs on Earth, they would also weigh around 66 pounds on Earth.

Explanation:

1 pound = 2.20462 kilograms.

Next, multiply 2.20462 and 30 and you should get 66.1386, or 66 pounds.

Answer: A.

Explanation: When light passes through a small hole, it creates an inverted image on the opposite side. In this case, since the arrow is pointing up, the inverted image will appear pointing down on the opposite wall. Furthermore, since the box has a hole on its left side, the inverted image will be shifted towards the left.

After transferring an electron, the ion that lost an electron, assuming it was neutral before, would be a cation. The atom that gained an electron would be an anion.

The ion is negatively charged because it has gained an ion, adding a negative charge to the atom's neutral state. Because it has no protons to cancel the charge, it gains 1 negative charge, making it an anion.

The symbol for a negative ion would be (-) and a positive would be (+)

For example, when oxygen is an ion, here's how it would look: O2-

Answer:

The Greeks called these particles atomos, meaning indivisible, and the modern word “atom” is derived from this term. Democritus proposed that different types and combinations of these particles were responsible for the various forms of matter.

Explanation:

hope it helps

The idea of indivisibility of the atom upheld by Dalton was largely derived from early Greek philosophers.

John Dalton was the first scientist to begin an empirical study of atomic theory. Before this time, all that was known about the atom were largely based on the speculation of Greek philosophers.

However, one recurring theme among Greek philosophers is that atoms are indivisible. This idea that atoms are indivisible became a very strong pivot of the Dalton's theory of the atom.

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Empirical formula of a compound can be determined using their number moles in the given weights. Thus number of moles of both gallium and phosphorous are 0.013 . Thus, empirical formula of this composition is GaP.

Empirical formula of a compound is derived from the number of moles of each element present in the compound. It will be different from the molecular formula of the compound.

Atomic mass of phosphorous = 31 g/mol

Atomic mass of gallium = 69.72 g/mol

Number of moles of 0.412 g of P = 0.412 g/31 g = 0.013.

No.of moles in 0.928 g of Ga = 0.928 / 69.72 = 0.013.

The ratio of their number of moles = 0.013 :0.013 = 1 :1.

Therefore, the empirical formula of the compound containing 0.928 g of gallium and 0.412 g of phosphorus is GaP.

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The fundamental nature of strategic management requires the awareness & understanding of outside forces & encourages strategic managers to adopt new ideas is known as Adaptation.

Three definitions of adaptability are connected. First, natural selection, a dynamic evolutionary process, adapts organisms to their environments, improving their evolutionary fitness. Second, it is a state that the populace has attained along that process. Thirdly, it is a phenotypic characteristic or adaptive trait that has been preserved and has evolved via natural selection and has a functional purpose in each individual organism.

History has recorded descriptions of adaptation going back to the time of the ancient Greek philosophers Empedocles and Aristotle. Natural theology of the 18th and 19th centuries saw adaptation as proof of the presence of a deity.

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Answer:

a) club soda is a compound

b) Club soda is a manufactured form of carbonated water, commonly used as a drink mixer. Sodium bicarbonate, potassium sulfate, potassium bicarbonate, potassium citrate, or sodium citrate is artificially added to replicate constituents commonly found in natural mineral waters