Write a quadratic function in standard form that passes through (5,0) (9,0) (7,-20)

If the distance is 45 miles and speed of both cyclist is 14 and 16 miles per hour then they will take time of 1.5 hour to meet.

Given First cyclist is riding at 14 miles per hour and second at 16 miles per hour. The distance is 45 miles.

We know that speed is the distance covered by an object in a particular period of time.

Speed=distance/time.

It is expressed as kilometers per hour or miles per hour, etc.

If both riders are riding towards each other then the speed will be 16+14 =30 miles per hour.

Distance=45 miles.

Time =distance/speed

=45/30

=1.5

Hence if first cyclist is riding at 14 miles per hour and second is riding at 14 miles per hour and the distance is 45 miles then they will meet after 1.5 hours.

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Largest even integer which cannot be written as the sum of two odd composite numbers is 38 if it is divisible by at least one positive integer other than 1 and itself.

The positive even integers which cannot be expressed as the sum of 2 composite odd numbers are: 2,4,6,8,10,12,14,16,20,22,26,28,32,38. This sequence is A118081.

All we have to do now is check the even numbers smaller than  44

. The largest,  42 is a multiple of  3 so it’s handled as  42=9+33 and the next one down,  40 is handled as  40=25+15.But the next one down is our culprit:  38 is not the sum of two odd composite numbers, as you can readily check.

First, what are these “odd composite numbers” anyway? The number  1is considered neither prime nor composite (it’s a unit), so it’s out.  3,5 and  7 are prime. The smallest odd composite number is, therefore,  9 and the next one is  15 .So we have  18=9+9 24=9+1 and  30=15+15 as some even numbers which can be written as a sum of two odd composites, but so far it doesn’t look promising: plenty of even numbers, like  10 or  20 or  32 cannot be so written.

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explica  e rspuetas

a8

The space C1(S1) is a Banach space, which means it is a complete normed vector space, equipped with the norm ||f|| = sup{|f(θ)| + |f'(θ)| : θ ∈ S1}.

The space C1(S1) is the space of continuously differentiable real-valued functions defined on the unit circle S1, which is a subset of the complex plane given by the equation |z| = 1, where z is a complex number.

Specifically, a function f: S1→R belongs to C1(S1) if it has a continuous first derivative f': S1→R that also belongs to C(S1), the space of continuous real-valued functions defined on S1.

Formally, we can define the space C1(S1) as follows:

C1(S1) = {f: S1→R | f is continuously differentiable on S1 and f' belongs to C(S1)}

Here, f' denotes the first derivative of f, which is defined as the limit:

f'(θ) = lim [f (θ + h) - f(θ)]/h

h→0

for all θ in S1

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Answer:

60 miles/hour

Step-by-step explanation:

I'm not a hundred percent, but half the miles you'd go in an hour would e 20. Cause 40 divided by 2 (Half) is 20. So you'd put 40 miles first, cause that's how much there is in an hour, and then you add 20 miles, cause it's half of an hour and half of 40. I'm sorry if this doesn't make sense, I tried my best, lol.

The derivative of F(x) is \(F'(x) = x^{(1/3)\).

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output.

To find the derivative of the given function F(x), we will apply the fundamental theorem of calculus and differentiate the integral with respect to x.

Let's compute F'(x):

F(x) = ∫[0 to x] \(t^{(1/3)} dt\)

To differentiate the integral with respect to x, we'll use the Leibniz integral rule:

F'(x) = d/dx ∫[0 to x] \(t^{(1/3)} dt\)

According to the Leibniz integral rule, we have to apply the chain rule to the upper limit of the integral.

\(F'(x) = x^{(1/3)} d(x)/dx - 0^{(1/3)} d(0)/dx\)   [applying the chain rule to the upper limit]

Since the upper limit of the integral is x, the derivative of x with respect to x is 1, and the derivative of 0 with respect to x is 0.

\(F'(x) = x^{(1/3)} (1) - 0^{(1/3)} (0)\)

\(F'(x) = x^{(1/3)\)

Therefore, the derivative of F(x) is \(F'(x) = x^{(1/3)\).

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Given that the particle moves along the curve y=e^(2x) and the magnitude of its velocity is v=5ft/s.A particle moving along a curve is given by:y = e^(2x)Taking the derivative of this function with respect to time t will give the velocity function as follows;dy/dt = 2e^(2x) dx/dt ............................... (1)We know that the magnitude of velocity is constant v = 5ft/s.

Therefore, we can use the velocity function to solve for dx/dt and dy/dt as shown below;dx/dt = v/√(4e^(4x)) = v/(2e^(2x)) ................ (2)Substituting equation (2) into (1), we get;dy/dt = 2e^(2x) dx/dt = 2e^(2x) * v/(2e^(2x))=v = 5 ft/sHence, the y-component of velocity when the particle is at y = 8 ft is 5 ft/s.

Therefore, we can use the slope of the curve at point y = 8 ft to find the angle of the slope, then use trigonometry to solve for the x-component of velocity.

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The required probability is 0.132 .

What is normal approximation?

The sampling distribution of averages or proportions from a large number of independent trials approximately and the expectation of a sample proportion or average is the corresponding population value.

On solving using mean sampling method, we get

P(E) = 0.132

Hence, the required probability is 0.132 .

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The equation that represent the relationship of the coffees is 3x + 5y = 68.

At a coffee shop, two sizes of coffee are sold. A medium coffee costs $3, and a large coffee costs $5.

The equation that represent the relationship between the number of medium coffees sold, x, and the number of large coffees sold, y, in an hour where sales totalled $68 is as follows:

where

Therefore, the equation is as follows:

3x + 5y = 68

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The arithmetic rule for the number of candies given to Augustus on the nth day as: an = 10 + (n-1) * 10

The Gloop's plan involves giving Augustus candies in an arithmetic sequence, where each term is 10 more than the previous term. The first term is 10, and the common difference between terms is 10.

Therefore, we can write the arithmetic rule for the number of candies given to Augustus on the nth day as:

an = 10 + (n-1) * 10

where n is the day number and an is the number of candies given on that day.

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False : The product of two imaginary values can include both real and imaginary parts, depending on the specific values involved in the multiplication. It is important to note that if either of the values being multiplied is zero, the product will be entirely real, with no imaginary component.

False. The product of two imaginary values is not necessarily an imaginary value. Imaginary numbers are expressed in the form of "bi," where "b" is a real number and "i" represents the imaginary unit (√-1). When multiplying two imaginary numbers, the result can be a combination of real and imaginary components.

Consider the multiplication of two imaginary numbers, such as (a + bi) * (c + di), where "a," "b," "c," and "d" are real numbers. Expanding this expression, we get ac + adi + bci + bdi^2. Simplifying further, we have ac + (ad + bc)i - bd. The resulting expression consists of a real component (ac - bd) and an imaginary component (ad + bc)i.

Therefore, the product of two imaginary values can include both real and imaginary parts, depending on the specific values involved in the multiplication. It is important to note that if either of the values being multiplied is zero, the product will be entirely real, with no imaginary component.

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Given information: Mass of dolphin, m = 1800 N; Height of jump, h = 2.10 m.

The gravitational potential energy of the dolphin can be calculated as follows: Gravitational potential energy = mgh where, m is the mass of the dolphin, g is the acceleration due to gravity, and h is the height of the jump.

Given that the dolphin jumps from the water, its initial potential energy is zero. Hence, the total energy of the dolphin is equal to the potential energy at the highest point. At this point, the kinetic energy of the dolphin is also zero. Therefore, the energy conservation equation can be written as follows: mg h = (1/2)mv²where, v is the velocity of the dolphin just before it jumps out of the water.  

Solving for v, we get v = sqrt(2gh)where sqrt denotes the square root, g is the acceleration due to gravity, and h is the height of the jump. Substituting the given values, we get v = sqrt(2 x 9.8 x 2.10)v = 6.22 m/s Therefore, the dolphin must be moving at a speed of 6.22 m/s as it leaves the water in order to jump to a height of 2.10 m.

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The c is equal to half of the definite integral of the function over the interval [0, 2].

To determine c such that f(c) is the average value of the function on the interval [0, 2], we can use the formula for the average value of a function:

avg = 1/(b-a) * ∫(a to b) f(x) dx

In this case, a = 0 and b = 2, so the formula becomes:

avg = 1/2 * ∫(0 to 2) f(x) dx

We want to find the value of c such that f(c) = avg, so we can set these two expressions equal to each other and solve for c:

f(c) = avg
f(c) = 1/2 * ∫(0 to 2) f(x) dx

We can then use calculus to solve for c by finding the derivative of both sides with respect to c and setting them equal to each other:

f'(c) = 1/2 * (f(2) - f(0))

Solving for c gives us:

c = (1/2) * ∫(0 to 2) f(x) dx

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Answer:

(x+6), (y+9)

Step-by-step explanation:

The x coordinate of J goes from -7 to -1, so it is translated x+6

The y coordinate of j goes from -8 to 1, which is a difference of 9, so it's translated y + 9

Answer: i think C correct me if i am wrong

Step-by-step explanation:

Answer:

5=1

4=5

i don't really know for the third one sorry but it's more than 11

Step-by-step explanation:

The value of the variable x is found to be x = 9.

A bisected angle divides the two sides in equals.

JKM = LKM

As, both are equal.

Then, each of these angles are 1/2 the angle JKL.

1/2 JKL = MKL

1/2 ×( 92) = 5x + 1

Further simplifying;

46 = 5x+1

Subtract 1 from each side

46-1 = 5x

45 = 5x

Divide each side by 5

45/5 = 5x/5

x = 9

Thus, the value of the unknown variable is found to be x = 9 units.

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we have given that

Angle = 30

Then, sin 30° = opposite side / hypotenuse

=> 1/2 = AC/BC = x / 2x

& By pythagoras law, BC2 = AB2 + AC2

=> BC2 = x2 + x2 = 4x2

=> BC = 2x

Hence, ratio of the lengths of AB:AC:BC

=1: √3:2

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Answer:

3+7 = 3

Step-by-step explanation:

Given question is based on reasoning:

2+3=1

2+3 = 5 and 5 × (2) first digit = 10, digit place reverse = 01

Similarly

4+5=63

4+5 = 9 and 9 × (4) first digit = 36, digit place reverse = 63

6+8=48

6+8 = 14 and 14 × (6) first digit = 84, digit place reverse = 48

So,

3+7=

3+7 = 10 and 10 × (3) first digit = 30, digit place reverse = 03

Therefore, 3+7 = 3

\(625=5^{7x-3}\implies 5^4=5^{7x-3}\implies 4=7x-3 \\\\\\ 7=7x\implies \cfrac{7}{7}=x\implies 1=x\)

When A'B'C' is reflecting in origin, A" (4, 1), B" (0, -7), and C" are the coordinates of the vertices' pictures (-2, -5).

The vertices of ABC are A (4, -1), B (0, 7), and C (-2, 5), respectively.

The coordinates of the points for ABC will be A' (-4, -1), B' (0, 7), and C' after reflecting in the y-axis (2, 5).

Once more, when "A'B'C" is reflecting in origin, "A" will be at (4, 1), "B" will be at (0, -7), and "C" will be at (4, 1). (-2, -5).

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Answer:

−10r +10

Step-by-step explanation:

Let's simplify step-by-step.

−5−5r+10−5−5r+10

=−5+−5r+10+−5+−5r+10

Combine Like Terms:

=−5+−5r+10+−5+−5r+10

=(−5r+−5r)+(−5+10+−5+10)

=−10r+10

Answer:

−5r+5

Step-by-step explanation:

Answer:

5/12

Step-by-step explanation:

15÷3/36 ÷3

the answer is 5/12

Answer:

5/12

Step-by-step explanation:

15/36 ÷ 3

5/12

mark mope brainliest

Answer:

1800

Step-by-step explanation:

Answer:

1/12

Step-by-step explanation:

Answer:

16s+2

Step-by-step explanation:

I hope this helps ig