A car starting from rest accelerates in a straight line path at a constant rate of 2.5m/s².how far will it travel in 12 seconds

Answer:

C. The net force acting on it.

Answer:

Joule, a 19th-century physicist, believed in the conservation of energy, which contradicted the beliefs of his peers at the time. His contemporaries believed that energy was a substance that could be created or destroyed. In contrast, Joule believed that energy could only be transformed from one form to another but could never be created or destroyed. He demonstrated this through a series of experiments where he showed that heat and mechanical work were equivalent forms of energy and that the total amount of energy in a closed system remained constant.

Joule's ideas challenged the established scientific beliefs of his time. They paved the way for the development of the first law of thermodynamics, which states that the total energy in a closed system is constant and cannot be created or destroyed. By proposing and demonstrating these ideas, Joule made significant contributions to the development of classical physics and helped lay the foundations of modern energy science.

Answer:

James Prescott Joule was a 19th-century British physicist who made significant contributions to the study of thermodynamics. One of his beliefs that contradicted the beliefs of his peers was the idea that heat was a form of energy.

At the time, the prevalent belief was that heat was a fluid-like substance called "caloric" that flowed from hot objects to cold objects. Joule challenged this idea and proposed that heat was actually a form of energy that could be transformed into other forms of energy, such as mechanical energy.

Joule's work showed that heat was a conserved quantity, much like energy, and that it could be quantified in terms of work done. This was a significant departure from the prevailing ideas of the time and helped lay the foundation for the study of thermodynamics.

Answer:

OPTION 3

Explanation:

Velocity specifies speed, while speed incluedes a specific direction

Suppose you released them from rest at the top of the ramp at same time, All has same kinetic energy when it gets to the bottom of the ramp.

In physics, kinetic energy is the energy that an object has as a result of motion. It is defined as the effort necessary to move a mass-based body from rest to the given velocity. In the absence of a change in speed, the body retains the kinetic energy it obtained during acceleration. Kinetic energy is the power that an object has as a result of motion. Applying force is necessary if we wish to accelerate an object. We have to put forth work to apply a force. After the job is finished, the object will be travelling at a new, constant motion because energy has been transferred to it. When an object is at rest, it is said to have potential energy.

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Answer:

23 cm from the mirror

Explanation:

The a prior justification for assuming that recombination-generation is negligible throughout the depletion region is based on the concept of intrinsic carrier concentration and the behavior of semiconductor materials.

In a semiconductor, the intrinsic carrier concentration represents the equilibrium concentration of electrons and holes in the absence of any external influences such as doping or applied bias. In the depletion region of a semiconductor, where there is a lack of majority carriers (electrons in N-type or holes in P-type), the concentration of carriers is significantly reduced.

Therefore, based on the understanding of intrinsic carrier concentration and the behavior of semiconductors, it is reasonable to assume that recombination-generation is negligible throughout the depletion region. This assumption simplifies the analysis and calculations of semiconductor devices, allowing for easier modeling and prediction of device behavior.

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The total volume of the silo as a function of r is given as 8/3  π r^3

Given data

height of cylinder = h

radius of cylinder = r

total height of silo = 1.5h

radius of cylinder = radius of hemisphere = r = height of silo

total height of silo = 1.5h = height of cylinder + height of silo

1.5h = h + r

r = 0.5h

h = 2r

total volume of silo = volume of cylinder + volume of hemisphere

total volume of silo = π r^2 h + 2/3 πr^3

plugging in h = 2r

total volume of silo = π r^2 ( 2r ) + 2/3 πr^3

total volume of silo = 2π r^3  + 2/3 πr^3

total volume of silo = 2π r^3  + 2/3 πr^3

total volume of silo = ( 2 + 2/3 ) π r^3

total volume of silo = ( 8/3 ) π r^3

total volume of silo = 8/3  π r^3

Therefore the total volume of the silo as a function of r is given as 8/3  π r^3

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As the distance between charged tape and charged rod decreases, the force of interaction between them increases.

The force of interaction between the charged tape and charged rod is governed by Coulomb's Law.

This law states that the force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

So, as the distance between the charged tape and charged rod decreases, the force of interaction increases.

This is because the charges on the objects are now closer to each other, allowing for a stronger attraction or repulsion, depending on the nature of the charges (like charges repel, opposite charges attract).

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The acceleration vector is parallel to the net force vector and the velocity vector is perpendicular to both.

The definition of "uniform" in a uniform circular motion is the same as in a uniform straight motion, i.e., the velocity vector's module (or speed) is constant. Now, if the object were not on a circular trajectory, it would move in a straight line at a constant speed if no other forces were acting on it. If an external force is acting on it and causing it to follow a circular trajectory, this force affects his direction rather than the instantaneous value of the velocity. Even when the orientation changes, it always remains perpendicular to the trajectory due to the fact that the body must keep moving in a straight line at a constant speed down a line that is tangent to the circle if the force ever disappears.

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Answer:

True

Explanation:

Answer:

True.

Explanation:

Hope this helps!!! <3

Answer:

0

Explanation:

When water is pumped out of well A, it causes a drop of 7 inches at point C; if water is pumped from well B into well A (at the same rate the water is pumped out of well A), then it will give a rise of 7 inches at well C. Therefore the net drawdown at well C is:

S = 7-7 = 0

Answer:

B.rate of convection

Explanation:

The answer is yes

They are isotopes.

Convex lens of focal length 15cm from real image at 25cm from the lens. The object distance, Magnification and size of the image if object size is 2cm are 29.17 cm,  -0.514,  -1.03 cm respectively.

A convex lens has a positive focal length. The distance between the object and the lens is referred to as the object distance and is represented by u, while the distance between the lens and the image is referred to as the image distance and is represented by v. The magnification, m, is the ratio of the image height, h', to the object height, h.

Object distance u = ?

Magnification m = ?

Size of the image h' = ?

Convex lens focal length f = 15 cm

Real image distance v = -25 cm (since the image is real, it is on the opposite side of the lens from the object)

The lens equation is:1/f = 1/v − 1/u where, ƒ is the focal length of the lens.

If the object is far away (i.e., the rays are parallel to the principal axis), then u is equivalent to infinity, and the lens equation becomes: 1/v = 1/fso,v = f

For this problem: v = f = 15 cm

Using the lens formula, we can solve for the object distance.

1/f = 1/v − 1/uu = 29.17 cm

The magnification is given by: m = -v/um = -15/29.17 ≈ -0.514

The image size can be found using the magnification equation:m = h'/h

Solving for h':h' = m × hh' = -0.514 × 2 cm = -1.03 cm

Since the magnification is negative, the image is inverted. However, the negative sign indicates that the image is inverted and reversed in position. The magnitude of the magnification shows that the image is smaller than the object (since m is less than one).

To find the size of the image, we multiply the object size by the magnitude of the magnification. The image size is -1.03 cm, indicating that the image is smaller than the object.

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Hi there!

Using the Impulse-Momentum theorem:

I = Δp = mΔv

Where:

I = Impulse (Ns)

m = mass of object (kg)

Δv = change in velocity (vf - vi, m/s)

Plug in the given values and solve:

60 = 5Δv

Δv = 12 m/s

Answer:

Actually, 4.5cm could be marked at the darker line between 4&5 in the ruler,

Or you can count 5 lines from 4 towards 5(towards your right) and the fifth line you count will be 4.5 and you can mark that as the asnwer

Answer:

Knees to Chest

Be consistent. Setting and committing to a regular practice of yoga is absolutely essential if you want to make improvements. ..

Answer: Dog pose was really easy, but tree pose was really difficult because it was hard to balance.

The change in momentum of the ball after it rebounds from the wall at 2.5 m/s is -1.0 kg.m/s.

The change in the momentum of the ball can be calculated using the formula:

change in momentum = final momentum - initial momentum

To find the initial momentum, we multiply the mass of the ball (2.0 kg) by its initial velocity (3.0 m/s):

initial momentum = 2.0 kg × 3.0 m/s = 6.0 kg*m/s

To find the final momentum, we multiply the mass of the ball (2.0 kg) by its final velocity (2.5 m/s):
final momentum = 2.0 kg × 2.5 m/s = 5.0 kg*m/s

Therefore, the change in momentum of the ball is:
change in momentum = final momentum - initial momentum
change in momentum = 5.0 kg*m/s - 6.0 kg*m/s
change in momentum = -1.0 kg*m/s

The negative sign indicates that the momentum of the ball decreased during the collision with the wall.

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Answer:

Recessive alleles only show their effect if the individual has two copies of the allele.  

Explanation:

Dominant and Recessive Alleles If your allele pair is FF or Ff, you will have freckles. The only way you can escape a freckled face is to inherit the recessive gene from each parent, giving you the ff allele pair. In general, recessive alleles show up in your phenotype only if you have two of them.

Answer:

    E = -4000 N / C

Explanation:

The potential and electric field are related

         V = - E s

          E = - V / s

we reduce the magnitudes to the SI system

          s = 4 mm (1 m / 1000 mm) = 0.004 m

we calculate

          E = - 16 /0.004

          E = -4000 N / C

The vector tangential to the circle because the vector indicates the direction of the force on the object.

Centripetal force is the force acting on an object in circular motion directed towards the axis of rotation.

In a circular motion, the direction of the velocity vector is the same as the direction of the object's motion, the velocity vector is directed tangent to the circle as well.

It also indicate the direction of the centripetal force.

Thus, the vector tangential to the circle because the vector indicates the direction of the force on the object.

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Sinclair Processing is using Lockout to put pressure on the union.

Sinclair Processing Inc. is using a lockout strategy to put pressure on the union. A lockout is a labor management tactic in which the employer, in response to a labor dispute or failed negotiations, prohibits employees from entering the workplace and performing their duties. By shutting down its manufacturing unit and preventing union members from working, Sinclair Processing aims to exert pressure on the union to reach a favorable agreement or make concessions. A lockout is a proactive measure taken by the employer to gain leverage in labor negotiations and shift the balance of power in their favor. It is typically employed as a bargaining tactic to put economic pressure on the union and demonstrate the employer's resolve in the labor dispute.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

easy  how you would die from a plastic bag being over your head is by sufacation the oxegen you breath with soon become carbon dioxide and kill you is it gets to your cellular reperation atory

Explanation:

Given:

Speed = 3.2 m/s²

Direction, θ = 42 degrees north of west.

Let's solve for the following:

(a) How far west has the sailboat traveled in 25 minutes.

We have the free body diagram below:

To find the distance, let's first find the x-component and y-component of the velocity.

x-component:

y-component:

To find the distance travelled west, we are to find the distance in the x direction.

Apply the formula:

Where:

|Vx| = |-2.378 m/s| = 2.378 m/s

t is the time is seconds = 25 x 60 = 1500 seconds

Thus, we have:

The distance traveled west in 25 minutes is 3.6 km.

• (b) How far north has the sailboat traveled in 25 minutes.

Here, we are to find the vertical distance using the y-component.

Apply the formula:

Where:

Vy = 2.141 m/s

t = 1500 seconds

Thus, we have:

The sailboat traveled 3.2 km in the north direction.

ANSWER:

(a) 3.6 km

(b) 3.2 km

Answer:

no emtiendo 98989

Explanation:

F =

t = 0.17 s

Impulse (J) = 20,000 N

J = F x t

F = J / t = 20,000 Ns / 0.17 s = 117,647.0588 N

Answer:

My answer will be (D) . A few thousand years

Explanation:

Carbon-14 is a radioactive isotope of carbon, containing 6 protons and 8 neutrons, that is present in the earth's atmosphere in extremely low concentrations.2

It is naturally produced in the atmosphere by cosmic rays (and also artificially by nuclear weapons), and continually decays via nuclear processes into stable nitrogen atoms.

Suppose we have a sample of a substance containing some carbon-14. Let m be the mass of carbon-14 in nanograms after t years. 3

It turns out that, if the sample is isolated, then m and t approximately 4 satisfy the differential equation

dmdt=−0.000121m.

Suppose our sample initially contains 100 nanograms of carbon-14. Let's investigate what happens to the sample over time.

First, we can solve the differential equation. Since m has a continuous decay rate of −0.000121, a general solution to the differential equation is

m(t)=Ce−0.000121t,

where C is a constant. Substituting the initial condition t=0, m=100 gives C=100, so

m(t)=100e−0.000121t.

With this formula, we can calculate the amount m of carbon-14 over the years.

Mass of carbon-14 in sample

t (years) m (ng to 4 decimal places)

0 100.0000

100 98.7973

1000 88.6034

2000 78.5056

5000 54.6074

10 000 29.8197

20 000 8.8922

Every year, the mass m of carbon-14 is multiplied by e−0.000121≈0.999879. After 100 years, 98.7973 nanograms still remain. After 1000 years, we still have 88.6034 nanograms. But after 5000 years, however, almost half of the carbon-14 has decayed.

Graph showing the decay of 100 nanograms of Carbon-14.

Detailed description

half-life of carbon-14  

Example

How long does it take for precisely half of the carbon-14 in the sample to decay; that is, when does m=50? Give the answer to three significant figures.

Solution

The mass of carbon-14 in our sample is given by

m(t)=100e−0.000121t.

So we solve 50=100e−0.000121t, which gives e−0.000121t=12. Hence,

t=loge12−0.000121≈5730 years (to three significant figures).

The time period calculated in this example is called the half-life of carbon-14. In fact over any period of 5730 years, the amount of carbon-14 in an isolated sample will decay by half. This fact is used in radiocarbon dating to determine the age of fossils up to 60 000 years old. Roughly speaking, while an organism is alive, its interactions with its environment maintain a constant ratio of carbon-14 to carbon-12 in the organism; but after it dies, the carbon-14 is no longer replenished, and the ratio of carbon-14 to carbon-12 decays in a predictable way. (See Wikipedia Open new window for more on radiocarbon dating.)

Exercise 1

Explain why the mass of carbon-14 in the sample is given (approximately) by

m(t)=100(12)t5730,

and hence explain why the amount of carbon-14 in the sample decays by half over any period of 5730 years.

Half-life in general

In general, whenever a quantity x(t) obeys an exponential decay equation

x(t)=Cekt,

where the continuous decay rate k is negative, then the quantity x has a half-life T. After any time period of length T, the quantity x decreases by half. Let us see why.

As k is negative, the factor ekt decreases from 1 (at t=0) towards 0 (as t approaches ∞). Therefore there is a time t=T such that

ekT=12.

We now solve for T and obtain

kT=loge12=−loge2,

so

T=−1kloge2.

This T is the half-life. From time t=0 to time t=T, the factor ekt decreases from e0=1 to ekT=12, that is, decreases by half. Similarly, over any time period of length T, the term ekt decreases by half. 5

Note that, when k=−0.000121, we obtain T=5730, in agreement with our calculation for carbon-14.

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